Is it possible to export a variable from a parent shell script to its children ?
Trying the execute the two following scripts it always returns to me 0 but I want it to return 3. I`ve also tried to export, set and add the variable error to the .bash_profile without success...
test.sh
$ cat test.sh
#!/bin/bash
error=0
./envtest.sh
echo $error
envtest.sh
$ cat envtest.sh
#!/bin/bash
source ./test.sh
test=3
error=$test
echo $error
Like #chepner commented, no.
When you invoke ./envtest.sh from within test.sh, a new process is created to run /bin/bash ./envtest.sh, and that process's environment is initialized with a copy of every environment variable from the parent process. No matter what you do inside envtest.sh, it can only impact the variables within its own environment; it cannot touch the variables in the parent's environment.
I need to increment an environmental variable by these steps:
envar=1
export envar
sh script_incrementation
echo $envar
where script_incrementation contains something like this:
#! /bin/sh
envar=$[envar+1] #I've tried also other methods of incrementation
export envar
Whatever I do, after exiting the script the variable remains with its initial value 1.
THanks for your time.
A shell script executes in its own shell, so you cannot affect the outer shell unless you source it. See this question for details of that discussion.
Consider the following script, which I will call Foo.sh.
#!/bin/bash
export HELLO=$(($HELLO+1))
Suppose in the outer shell, I define an environmental variable:
export HELLO=1
If I run the script like this, it run inside its own shell and will not affect the parent.
./Foo.sh
However, if I source it, it will just execute the commands in the current shell, and will achieve the desired affect.
. Foo.sh
echo $HELLO # prints 2
Your script can not change the environment of the calling process (shell), it merely inherits it.
So, if you export foo=bar, and then invoke sh (a new process) with your script, the script will see the value of $foo (which is "bar"), and it will be able to change its own copy of it – but that is not going to affect the environment of the parent process (where you exported the variable).
You can simply source your script in the original shell, i.e. run
source increment_script.sh
or
. increment_script.sh
and that will then change the value of the variable.
This is because sourceing a script avoids spawning a new shell (process).
Another trick is to have your script output the changed environment, and then eval that output, for example:
counter=$[counter+1]
echo "counter=$counter"
and then run that as
eval `increment_script.sh`
I have a Perl script which has a variable like my $name. Can we set the contents of $name as an environment variable which we can import and use in other files?
I tried like $ENV{NAME}=name, but this is not working.
If you want to affect the environment of your process or your child processes, just use the %ENV hash:
$ENV{CVSROOT}='<cvs>';
If you want to affect the environment of your parent process, you can't. At least not without cooperation of the parent process. The standard process is to emit a shell script and have the parent process execute that shell script:
#!/usr/bin/perl -w
print 'export CVSROOT=<cvs>';
... and call that script from the shell (script) as:
eval `myscript.pl`
Environment variables are specific to a process. When a child process is spawned, it inherits copies of its parent's environment variables, but any changes it makes to them are restricted to itself and any children it spawns after the change.
So no, you can't set an environment variable for your shell from within a script you run.
What is export for?
What is the difference between:
export name=value
and
name=value
export makes the variable available to sub-processes.
That is,
export name=value
means that the variable name is available to any process you run from that shell process. If you want a process to make use of this variable, use export, and run the process from that shell.
name=value
means the variable scope is restricted to the shell, and is not available to any other process. You would use this for (say) loop variables, temporary variables etc.
It's important to note that exporting a variable doesn't make it available to parent processes. That is, specifying and exporting a variable in a spawned process doesn't make it available in the process that launched it.
To illustrate what the other answers are saying:
$ foo="Hello, World"
$ echo $foo
Hello, World
$ bar="Goodbye"
$ export foo
$ bash
bash-3.2$ echo $foo
Hello, World
bash-3.2$ echo $bar
bash-3.2$
It has been said that it's not necessary to export in bash when spawning subshells, while others said the exact opposite. It is important to note the difference between subshells (those that are created by (), ``, $() or loops) and subprocesses (processes that are invoked by name, for example a literal bash appearing in your script).
Subshells will have access to all variables from the parent, regardless of their exported state.
Subprocesses will only see the exported variables.
What is common in these two constructs is that neither can pass variables back to the parent shell.
$ noexport=noexport; export export=export; (echo subshell: $noexport $export; subshell=subshell); bash -c 'echo subprocess: $noexport $export; subprocess=subprocess'; echo parent: $subshell $subprocess
subshell: noexport export
subprocess: export
parent:
There is one more source of confusion: some think that 'forked' subprocesses are the ones that don't see non-exported variables. Usually fork()s are immediately followed by exec()s, and that's why it would seem that the fork() is the thing to look for, while in fact it's the exec(). You can run commands without fork()ing first with the exec command, and processes started by this method will also have no access to unexported variables:
$ noexport=noexport; export export=export; exec bash -c 'echo execd process: $noexport $export; execd=execd'; echo parent: $execd
execd process: export
Note that we don't see the parent: line this time, because we have replaced the parent shell with the exec command, so there's nothing left to execute that command.
This answer is wrong but retained for historical purposes. See 2nd edit below.
Others have answered that export makes the variable available to subshells, and that is correct but merely a side effect. When you export a variable, it puts that variable in the environment of the current shell (ie the shell calls putenv(3) or setenv(3)).
The environment of a process is inherited across exec, making the variable visible in subshells.
Edit (with 5 year's perspective):
This is a silly answer. The purpose of 'export' is to make variables "be in the environment of subsequently executed commands", whether those commands be subshells or subprocesses. A naive implementation would be to simply put the variable in the environment of the shell, but this would make it impossible to implement export -p.
2nd Edit (with another 5 years in passing).
This answer is just bizarre. Perhaps I had some reason at one point to claim that bash puts the exported variable into its own environment, but those reasons were not given here and are now lost to history. See Exporting a function local variable to the environment.
export NAME=value for settings and variables that have meaning to a subprocess.
NAME=value for temporary or loop variables private to the current shell process.
In more detail, export marks the variable name in the environment that copies to a subprocesses and their subprocesses upon creation. No name or value is ever copied back from the subprocess.
A common error is to place a space around the equal sign:
$ export FOO = "bar"
bash: export: `=': not a valid identifier
Only the exported variable (B) is seen by the subprocess:
$ A="Alice"; export B="Bob"; echo "echo A is \$A. B is \$B" | bash
A is . B is Bob
Changes in the subprocess do not change the main shell:
$ export B="Bob"; echo 'B="Banana"' | bash; echo $B
Bob
Variables marked for export have values copied when the subprocess is created:
$ export B="Bob"; echo '(sleep 30; echo "Subprocess 1 has B=$B")' | bash &
[1] 3306
$ B="Banana"; echo '(sleep 30; echo "Subprocess 2 has B=$B")' | bash
Subprocess 1 has B=Bob
Subprocess 2 has B=Banana
[1]+ Done echo '(sleep 30; echo "Subprocess 1 has B=$B")' | bash
Only exported variables become part of the environment (man environ):
$ ALICE="Alice"; export BOB="Bob"; env | grep "ALICE\|BOB"
BOB=Bob
So, now it should be as clear as is the summer's sun! Thanks to Brain Agnew, alexp, and William Prusell.
It should be noted that you can export a variable and later change the value. The variable's changed value will be available to child processes. Once export has been set for a variable you must do export -n <var> to remove the property.
$ K=1
$ export K
$ K=2
$ bash -c 'echo ${K-unset}'
2
$ export -n K
$ bash -c 'echo ${K-unset}'
unset
export will make the variable available to all shells forked from the current shell.
As you might already know, UNIX allows processes to have a set of environment variables, which are key/value pairs, both key and value being strings.
Operating system is responsible for keeping these pairs for each process separately.
Program can access its environment variables through this UNIX API:
char *getenv(const char *name);
int setenv(const char *name, const char *value, int override);
int unsetenv(const char *name);
Processes also inherit environment variables from parent processes. Operating system is responsible for creating a copy of all "envars" at the moment the child process is created.
Bash, among other shells, is capable of setting its environment variables on user request. This is what export exists for.
export is a Bash command to set environment variable for Bash. All variables set with this command would be inherited by all processes that this Bash would create.
More on Environment in Bash
Another kind of variable in Bash is internal variable. Since Bash is not just interactive shell, it is in fact a script interpreter, as any other interpreter (e.g. Python) it is capable of keeping its own set of variables. It should be mentioned that Bash (unlike Python) supports only string variables.
Notation for defining Bash variables is name=value. These variables stay inside Bash and have nothing to do with environment variables kept by operating system.
More on Shell Parameters (including variables)
Also worth noting that, according to Bash reference manual:
The environment for any simple command or function may be augmented
temporarily by prefixing it with parameter assignments, as described
in Shell Parameters. These assignment statements affect only the
environment seen by that command.
To sum things up:
export is used to set environment variable in operating system. This variable will be available to all child processes created by current Bash process ever after.
Bash variable notation (name=value) is used to set local variables available only to current process of bash
Bash variable notation prefixing another command creates environment variable only for scope of that command.
The accepted answer implies this, but I'd like to make explicit the connection to shell builtins:
As mentioned already, export will make a variable available to both the shell and children. If export is not used, the variable will only be available in the shell, and only shell builtins can access it.
That is,
tango=3
env | grep tango # prints nothing, since env is a child process
set | grep tango # prints tango=3 - "type set" shows `set` is a shell builtin
Two of the creators of UNIX, Brian Kernighan and Rob Pike, explain this in their book "The UNIX Programming Environment". Google for the title and you'll easily find a pdf version.
They address shell variables in section 3.6, and focus on the use of the export command at the end of that section:
When you want to make the value of a variable accessible in sub-shells, the shell's export command should be used. (You might think about why there is no way to export the value of a variable from a sub-shell to its parent).
Here's yet another example:
VARTEST="value of VARTEST"
#export VARTEST="value of VARTEST"
sudo env | grep -i vartest
sudo echo ${SUDO_USER} ${SUDO_UID}:${SUDO_GID} "${VARTEST}"
sudo bash -c 'echo ${SUDO_USER} ${SUDO_UID}:${SUDO_GID} "${VARTEST}"'
Only by using export VARTEST the value of VARTEST is available in sudo bash -c '...'!
For further examples see:
http://mywiki.wooledge.org/SubShell
bash-hackers.org/wiki/doku.php/scripting/processtree
Just to show the difference between an exported variable being in the environment (env) and a non-exported variable not being in the environment:
If I do this:
$ MYNAME=Fred
$ export OURNAME=Jim
then only $OURNAME appears in the env. The variable $MYNAME is not in the env.
$ env | grep NAME
OURNAME=Jim
but the variable $MYNAME does exist in the shell
$ echo $MYNAME
Fred
By default, variables created within a script are only available to the current shell; child processes (sub-shells) will not have access to values that have been set or modified. Allowing child processes to see the values, requires use of the export command.
As yet another corollary to the existing answers here, let's rephrase the problem statement.
The answer to "should I export" is identical to the answer to the question "Does your subsequent code run a command which implicitly accesses this variable?"
For a properly documented standard utility, the answer to this can be found in the ENVIRONMENT section of the utility's man page. So, for example, the git manual page mentions that GIT_PAGER controls which utility is used to browse multi-page output from git. Hence,
# XXX FIXME: buggy
branch="main"
GIT_PAGER="less"
git log -n 25 --oneline "$branch"
git log "$branch"
will not work correctly, because you did not export GIT_PAGER. (Of course, if your system already declared the variable as exported somewhere else, the bug is not reproducible.)
We are explicitly referring to the variable $branch, and the git program code doesn't refer to a system variable branch anywhere (as also suggested by the fact that its name is written in lower case; but many beginners erroneously use upper case for their private variables, too! See Correct Bash and shell script variable capitalization for a discussion) so there is no reason to export branch.
The correct code would look like
branch="main"
export GIT_PAGER="less"
git log -n 25 --oneline "$branch"
git log -p "$branch"
(or equivalently, you can explicitly prefix each invocation of git with the temporary assignment
branch="main"
GIT_PAGER="less" git log -n 25 --oneline "$branch"
GIT_PAGER="less" git log -p "$branch"
In case it's not obvious, the shell script syntax
var=value command arguments
temporarily sets var to value for the duration of the execution of
command arguments
and exports it to the command subprocess, and then afterwards, reverts it back to the previous value, which could be undefined, or defined with a different - possibly empty - value, and unexported if that's what it was before.)
For internal, ad-hoc or otherwise poorly documented tools, you simply have to know whether they silently inspect their environment. This is rarely important in practice, outside of a few specific use cases, such as passing a password or authentication token or other secret information to a process running in some sort of container or isolated environment.
If you really need to know, and have access to the source code, look for code which uses the getenv system call (or on Windows, with my condolences, variations like getenv_s, w_getenv, etc). For some scripting languages (such as Perl or Ruby), look for ENV. For Python, look for os.environ (but notice also that e.g. from os import environ as foo means that foo is now an alias for os.environ). In Node, look for process.env. For C and related languages, look for envp (but this is just a convention for what to call the optional third argument to main, after argc and argv; the language lets you call them anything you like). For shell scripts (as briefly mentioned above), perhaps look for variables with uppercase or occasionally mixed-case names, or usage of the utility env. Many informal scripts have undocumented but discoverable assignments usually near the beginning of the script; in particular, look for the ?= default assignment parameter expansion.
For a brief demo, here is a shell script which invokes a Python script which looks for $NICKNAME, and falls back to a default value if it's unset.
#!/bin/sh
NICKNAME="Handsome Guy"
demo () {
python3 <<\____
from os import environ as env
print("Hello, %s" % env.get("NICKNAME", "Anonymous Coward"))
____
}
demo
# prints "Hello, Anonymous Coward"
# Fix: forgot export
export NICKNAME
demo
# prints "Hello, Handsome Guy"
As another tangential remark, let me reiterate that you only ever need to export a variable once. Many beginners cargo-cult code like
# XXX FIXME: redundant exports
export PATH="$HOME/bin:$PATH"
export PATH="/opt/acme/bin:$PATH"
but typically, your operating system has already declared PATH as exported, so this is better written
PATH="$HOME/bin:$PATH"
PATH="/opt/acme/bin:$PATH"
or perhaps refactored to something like
for p in "$HOME/bin" "/opt/acme/bin"
do
case :$PATH: in
*:"$p":*) ;;
*) PATH="$p:$PATH";;
esac
done
# Avoid polluting the variable namespace of your interactive shell
unset p
which avoids adding duplicate entries to your PATH.
Although not explicitly mentioned in the discussion, it is NOT necessary to use export when spawning a subshell from inside bash since all the variables are copied into the child process.