I'm trying to write a code that will return common values from a dictionary based on a list of words.
Example:
inp = ['here','now']
dict = {'here':{1,2,3}, 'now':{2,3}, 'stop':{1, 3}}
for val in inp.intersection(D):
lst = D[val]
print(sorted(lst))
output: [2, 3]
The input inp may contain any one or all of the above words, and I want to know what values they have in common. I just cannot seem to figure out how to do that. Please, any help would be appreciated.
The easiest way to do this is to just count them all, and then make a dict of the values that are equal to the number of sets you intersected.
To accomplish the first part, we do something like this:
answer = {}
for word in inp:
for itm in word:
if itm in answer:
answer[itm] += 1
else:
answer[itm] = 1
To accomplish the second part, we just have to iterate over answer and build an array like so:
answerArr = []
for i in answer:
if (answer[i] == len(inp)):
answerArr.append(i)
i'm not certain that i understood your question perfectly but i think this is what you meant albeit in a very simple way:
inp = ['here','now']
dict = {'here':{1,2,3}, 'now':{2,3}, 'stop':{1, 3}}
output = []
for item in inp:
output.append(dict[item])
for item in output:
occurances = output.count(item)
if occurances <= 1:
output.remove(item)
print(output)
This should output the items from the dict which occurs in more than one input. If you want it to be common for all of the inputs just change the <= 1 to be the number of inputs given.
Related
I'm looking for a way to convert a list to a dictionary as shown below. Is this possible? Thanks in advance.
list = ["1/a", "2/b", "3/c"]
dict = {"1": "a", "2": "b", "3": "c"}
Of course it is possible.
First, you can split an element of the list with e.split("/"), which will give a list for example splitted = ["1", "a"].
You can assign the first element to the key and the second to the value:
k = splitted[0]
v = splitted[1]
or another way to express that:
k,v = splitted
Then you can iterate over your list to build your dict, so if we wrap this up (you should not call a list list because list is a type and an already existing identifier:
d = {}
for e in elements:
k,v = e.split("/")
d[k] = v
You can also do that in one line with a dict comprehension:
d = {k:v for k,v in [e.split("/") for e in elements]}
Yes you can.
If you want to have everything after the '/' (i.e. 2nd char), you can do:
dict = {c[0]:c[2:] for c in list}
If you want to have everything after the '/' (but may not be the 2nd char), you can do:
dict = {c[0]:c.split('/')[1] for c in list}
It really dependes on the input you have and what output you want
You can do like this.
lista = ["1/a", "2/b", "3/c"]
new_dict = {}
for val in lista:
new_dict.update({val[0]:val[2]})
print(new_dict)
Try this
list = ["1as/aasc", "2sa/bef", "3edc/cadeef"]
dict = {i.split('/')[0]:i.split('/')[1] for i in list}
Answer will be
{'1as': 'aasc', '2sa': 'bef', '3edc': 'cadeef'}
I have given a different test case. Hope this will answer your question.
I am currently learning python, I just have one little question over here.
I used for loop and getting a result below.
Here is my code:
def psuedo_random(multiplier, modulus, X_0, x_try):
for i in range(x_try):
place_holder = []
count = []
next_x = multiplier * X_0 % modulus
place_holder.append(next_x)
X_0 = next_x
for j in place_holder:
j = j/modulus
count.append(j)
print(count)
Result:
[0.22021484375]
[0.75439453125]
[0.54443359375]
[0.47705078125]
Can we somehow change it into something like this?
[0.22021484375, 0.75439453125, 0.54443359375, 0.47705078125]
After you initialized a list, you can use append function in the loop.
initialize a list where you want to list these numbers
mylist = []
use this function in your for loop
for i in .....:
mylist.append(i)
It's simple. Do not initialize your list inside the loop. Just place it outside.
The task is:
User enters a number, you take 1 number from the left, one from the right and sum it. Then you take the rest of this number and sum every digit in it. then you get two answers. You have to sort them from biggest to lowest and make them into a one solid number. I solved it, but i don't like how it looks like. i mean the task is pretty simple but my code looks like trash. Maybe i should use some more built-in functions and libraries. If so, could you please advise me some? Thank you
a = int(input())
b = [int(i) for i in str(a)]
closesum = 0
d = []
e = ""
farsum = b[0] + b[-1]
print(farsum)
b.pop(0)
b.pop(-1)
print(b)
for i in b:
closesum += i
print(closesum)
d.append(int(closesum))
d.append(int(farsum))
print(d)
for i in sorted(d, reverse = True):
e += str(i)
print(int(e))
input()
You can use reduce
from functools import reduce
a = [0,1,2,3,4,5,6,7,8,9]
print(reduce(lambda x, y: x + y, a))
# 45
and you can just pass in a shortened list instead of poping elements: b[1:-1]
The first two lines:
str_input = input() # input will always read strings
num_list = [int(i) for i in str_input]
the for loop at the end is useless and there is no need to sort only 2 elements. You can just use a simple if..else condition to print what you want.
You don't need a loop to sum a slice of a list. You can also use join to concatenate a list of strings without looping. This implementation converts to string before sorting (the result would be the same). You could convert to string after sorting using map(str,...)
farsum = b[0] + b[-1]
closesum = sum(b[1:-2])
"".join(sorted((str(farsum),str(closesum)),reverse=True))
(Im using python on Jupiter Notebook 5.7.8)
I have a project in which are 3 lists, and a list(list_of_lists) that refer to those 3.
I want my program to receive an input, compare this input to the content of my "list_of_lists" and if find a match I want to store the match in another variable for later use.
Im just learning, so here is the code I wrote:
first = ["item1", "item2","item3"]
second = ["item4","item5","item6"]
list1 = [first,second]
list2 = ["asd","asd","asd"]
list_of_lists = [list1,list2]
x = input("Which list are you going to use?: ")
for item in list_of_lists:
if item == x:
match = item
print(match)
print('There was a match')
else:
print('didnt match')
I expect a match but it always output "the didnt match",
I assume it fail to compare the contect of the input with the list inside the list_of lists. The question is also why and how to do it properly(if possible), thanks.
input in python3 returns a string. if you want to convert it into a list, use ast.literal_eval or json.loads or your own parsing method.
list_str = input("Which list are you going to use?: ")
user_list = ast.literal_eval(list_str)
assert isinstance(user_list, list)
...
# do your thing...
So here i tried this code, and it does what i desire, I dont know if its too rudimentary and if there is another way to achieve this.
Here I use a second list to catch the moment when there is a match, after I give to that list the value of my true list and from there print it to be used.
I was wondering if there is a way to take out of the ressults the symbols "[]" and the quotes '', so I can have a clean text format, thanks for the help
first = ["item1", "item2","item3"]
second = ["item4","item5","item6"]
list1 = [first,second]
list2 = ["asd","asd","asd"]
list3 = ["qwe","qwe","qwe"]
list_of_lists = [list1,list2,list3]
reference_list = ["list1","list2","list3"]
count = -1
x = input('Which list are you going to use? ')
for item in reference_list:
count += 1
if x == item:
reference_list = list_of_lists
print(reference_list[count])
I was programming at CodeWars using Kata, when i got this error:
Traceback:
in
in title_case
IndexError: list index out of range
Here is my code:
def title_case(title, minor_words=1):
string = title.split()
outList = []
if minor_words != 1:
split = minor_words.split()
minor = [x.lower() for x in split]
out = ""
for i in range(0, len(string)):
word = ""
for j in range(0,len(string[i])):
elem = ""
elem += string[i][j]
if j == 0:
word += elem.upper()
else:
word += elem.lower()
if i != len(string)-1:
outList.append(word+" ")
else:
outList.append(word)
list = [x.lower() for x in outList]
print ((list[0]))#Just for debug
if minor_words != 1:
for i in range(0, len(outList)):
if (list[i] in minor):
print("OI")#Just for debug
out += list[i]
else:
out += outList[i]
return out
Well, this happened when trying to execute the code, of course!
One way to initialize this function would be:
title_case('a clash of KINGS', 'a an the of')
Well the 0 elemeny exists, but it says it doesn't, I don't know why, because when I write "print(list)" it shows me the elements of list, in this case, "['a', 'clash', 'of', 'kings']".
What can I do?
Okay, so based on reading this code I think the result you desire from:
title_case('a clash of KINGS', 'a an the of') is:
A Clash of Kings
So it looks like you are stepping through a lot of hoops trying to get there. While I was going through the code it took me a while to see what was actually happening. I also took the liberty to make your variables more consistently named. Rather than mixing caseLetter and case_letter randomly I made it consistent. I also made your loops easier to read. Also for the minorWords argument. Might as well have it passed as a list rather than converting it to a list inside the function. Anyway, I hope this is of help.
def titleCase(title, minorWords=[]):
titleList = [x.lower() for x in title.split()]
outList = []
for Word in titleList:
if Word not in minorWords:
Word = Word.capitalize()
outList.append(Word)
return " ".join(outList)
TitleCased = titleCase("a clash of KINGS", ["an", "the", "of"])
print (TitleCased)
Which outputs A Clash of Kings, which I believe, based on your question and how I understood your code is what you wanted to achieve? Or if you include a in your minorWords, it would be:
a Clash of Kings
Regardless, hope this answers your question!