Little issue I'm having that I'm hoping someone can help me with please?
So I have 3 columns in Excel. Each Column (A/B/C) contains either "high" / "Medium" / "Low" scored issues. However, if you have 3 Low issues, this is grouped together, and this becomes 1 Medium Issue for example.
The difficulty I'm having is writing a formula that will do this for me. Obviously I could just divide the number of Low issues I have by 3, but in the case where I have 7 Low issues, It should result with 2 Mediums and 1 remaining Low. I've tried using the "Mod" function, but that only returns the remainder.
What I need is a formula that will say "If you have 7 Low Issues, (3 low = 1 medium), therefore you have 2 medium and 1 Low). The medium issues would then be added to the Medium Column (Col B), and the remaining low issue is counted in the Low issue column (Col C).
I hope this explanation makes sense, fingers crossed one of you might be able to help me! Thank you in advance
As requested, a screenshot!
If I understand you correctly, I think you should be able to adapt the following formulas to meet your needs.
To get the number of occurrences of the word "Low" in column A:
=COUNTIF(A:A, "=Low")
To get the number of "Mediums" from 3 occurrences of "Low" in column A, round down the above number divided by 3:
=FLOOR(COUNTIF(A:A, "=Low")/3,1)
To get the remaining "Lows" after groupings of 3 into "Mediums", use MOD:
=MOD(COUNTIF(A:A, "=Low"),3)
Putting this into a worksheet:
Values
Formulas
Finally, if you wanted one "Mediums" count, i.e. adding the remaining "Mediums" which aren't grouped into "Highs", you would use a combination of the above formulas for what is left after grouping to "Highs" with what is gained from grouping of "Lows".
Edit:
Now you've included an image, I can show how these formulas are directly applicable...
Values
Formulas
Sounds like you were already nearly there with using =MOD() just needed a little tweak:
For the high column:
=COUNTA(A2:A8)+FLOOR(COUNTA(B2:B8)/3,1)
For the medium column:
=FLOOR(COUNTA(C2:C8)/3,1)+MOD(COUNTA(B2:B8),3)
For the low column:
=MOD(COUNTA(C2:C8),3)
It's exactly like a long addition that you do at school where each column carries over to the one to the left of it (except base 3 instead of base 10). I'm not clear that existing answers cover the case where there is a carry from one column and that causes a further carry from the next column so here is another answer
In the totals row (e.g. for the medium column) in (say) C12
=COUNTA(C2:C10)+INT(D12/3)
Then use mod as before
=MOD(C12,3)
except that in the high column you don't want to use MOD so it's just
=B12
Related
I do not want to know the traditional frequency or the traditional averages; so I'll give an example below:
I have this data:
1
3
5
5
2
3
5
5
1
3
The analysis that I would like to obtain is the following:
for example number 1 appears once every eight rows, number 3 appears once every four rows, number 5 appears twice every two rows....
I did it by hand, but now I have more than 21000 rows of data and I'm stuck.
I searched but I can not find a function that does it; But before I started developing my own, I decided to ask for a guide on how to achieve it.
I believe that I was able to achieve the desired result:
The formula is:
Or, if you want to copy/paste:
=IF(CONCATENATE("1-",MATCH(D1,INDIRECT(ADDRESS(MATCH(D1,A1:A17,0)+1,1,4)&":A17"),0))="1-1",CONCATENATE("2-",MATCH(D1,INDIRECT(ADDRESS(MATCH(D1,A1:A17,0)+2,1,4)&":A17"),0)-1),CONCATENATE("1-",MATCH(D1,INDIRECT(ADDRESS(MATCH(D1,A1:A17,0)+1,1,4)&":A17"),0)))
Note that the IF function solves the duplicates (like the number 5). In case you have triplicates you will have to add another instance of IF and adjust the formula accordingly.
Hope that helps!
Well this doesn't exactly reproduce your results, but you could start by looking at the max and min separation of the numbers:
=IF(COUNTIF(A$1:A$10,C2)<=1,"",MIN(IF((ROW(A$1:INDEX(A$1:A$10,COUNTIF(A$1:A$10,C2)+1))>1)
*(ROW(A$1:INDEX(A$1:A$10,COUNTIF(A$1:A$10,C2)+1))<=COUNTIF(A$1:A$10,C2)),
FREQUENCY(IF(A$1:A$10<>C2,ROW(A$1:A$10)),IF(A$1:A$10=C2,ROW(A$1:A$10)))))+1)
=IF(COUNTIF(A$1:A$10,C2)<=1,"",MAX(IF((ROW(A$1:INDEX(A$1:A$10,COUNTIF(A$1:A$10,C2)+1))>1)
*(ROW(A$1:INDEX(A$1:A$10,COUNTIF(A$1:A$10,C2)+1))<=COUNTIF(A$1:A$10,C2)),
FREQUENCY(IF(A$1:A$10<>C2,ROW(A$1:A$10)),IF(A$1:A$10=C2,ROW(A$1:A$10)))))+1)
This gives the min or max number of rows between each occurrence of the particular number.
Must be entered as an array formula using CtrlShiftEnter
You could add other statistics (like mean, standard deviation) the same way although the average could be calculated just by (lastrow-firstrow)/(count-1) e.g. for 5 it would be (8-3)/(4-1)=5/3.
So this is the simplified question I broke down from a former question I had here: Excel help on combination of Index - match and sumifs? .
For this one, I have Table1 (the black-gray one) with two or more columns for adjustments for various order numbers. See this image below:
What I want to achieve is to have total adjustments for those order numbers that contain the numbers in Total Adjustment column in the blue table, each of which will depend on the cell beside it.
Example: Order number 17051 has two products: 17051A (Apple) and 17051B (Orange).
Now what I want to achieve in cell C10 is the sum of adjustment for both 17051A and 17051B, which will be: Apple Adjustment (5000) + Orange Adjustment (4500) = 9500.
The formula I used below (and in the image) kept giving me error messages, and this happens even before I add the adjustment for Orange.
=SUMIF(Text(LEFT(Table1[Order Number],5),"00000"),text(B10,"00000"),Table1[Apple Adjustment])
I have spent the whole day looking for a solution for this and didn’t even come close to find any. Any suggestion is appreciated.
Assuming your headers always have the text "adjustment" in them, you could use:
=SUMPRODUCT((LEFT($B$4:$B$7,5)=B10&"")*(RIGHT($C$3:$F$3,10)="adjustment")*$C$4:$F$7)
In C10 you could add two sumproducts. This assumes that products are always 5 numbers long at the start. If not swop the 5 to use the length of the product reference part you are matching on.
=SUMPRODUCT(--(1*LEFT($B$4:$B$7,5)=$B10),$D$4:$D$7)+SUMPRODUCT(--(1*LEFT($B$4:$B$7,5)=$B10),$F$4:$F$7)
Which with table syntax is:
=SUMPRODUCT(--(1*LEFT(Table1[Order Number],5)=$B10),Table1[Apple Adjustment])+SUMPRODUCT(--(1*LEFT(Table1[Order Number],5)=$B10),Table1[Orange Adjustment])
Using LEN
=SUMPRODUCT(--(1*LEFT(Table1[Order Number],LEN($B10))=$B10),Table1[Apple Adjustment])+SUMPRODUCT(--(1*LEFT(Table1[Order Number],LEN($B10))=$B10),Table1[Orange Adjustment])
I am multiplying by 1 to ensure Left, 5 becomes numeric.
I'm involved with a youth football tournament on the referee side, with assessing/coaching the referees. I've just taken over doing the data entry for the referees assessment scores which we then use to determine who gets finals etc and am looking to extract more usable information from the data to help us identify trends.
I've got (up to) 200 referees, each receiving from none to two assessment scores each day for 5 days. The scores are entered as both the raw mark and the weighted mark based on match difficulty (along with a host of other data about the match that isn't relevant to this issue.
I can extract the average mark (raw and weighted) across all referees without issues and have done so using the below formula, which is the raw average mark:
=AVERAGE(Working!AK4:AK200,Working!BK4:BK200,Working!CL4:CL200,Working!DL4:DL200,Working!EM4:EM200,Working!FM4:FM200,Working!GN4:GN200,Working!HN4:HN200,Working!IO4:IO200,Working!JO4:JO200)
But I also want to extract the average mark (raw and weighted) across two subsets - Academy and non academy referees, to help plot trends and determine where resources need to be utilised.
I've attempted to use an AVERAGEIF formula, but am getting a #VALUE! return. This is the formula that I've attempted to use to return the average raw mark for those referees in the academy:
=AVERAGEIF(Working!G4:G200,Working!G4:G200="Yes",(Working!AK4:AK200,Working!BK4:BK200,Working!CL4:CL200,Working!DL4:DL200,Working!EM4:EM200,Working!FM4:FM200,Working!GN4:GN200,Working!HN4:HN200,Working!IO4:IO200,Working!JO4:JO200))
If I do the same formula as above, but without the brackets around the [average_range], I get a 'you've used too many arguments, and it highlights BK200.
From what I've been able to find so far online, it seems that the formula I'm trying to use would only work if ALL the cells in (Working!G4:G200) returned "Yes". However if there are only 50 academy referees as indicated by "Yes" in G column, then I want those specific scores to be averaged, and the inverse for the non-academy referees.
I thought about having another sheet, which would simply contain populate from Column G (a simple =G4 and then populated down to =G200 next to all of the scores), consolidated into a block of raw marks columned under Assessment 1, 2, 3, 4.... and then the same for all of the weighted marks which would populate from the equivalent cell on the working sheet, but there's a lot of filtering, and re-sorting that goes on on the working sheet, and I'm not 100% certain that that wouldn't cause issues.
Any feedback on how to work through this problem, so that I can display the overall average mark for academy and non-academy referees in both raw and weighted form would be much appreciated, and I apologize if this post is rather convoluted.
I don't think there is a neat solution if the scores are in several columns which are not consecutive.
My suggestion is:-
(1) Work out the sum for each column separately and total them up
(2) Work out the count for each column separately and total them up
(3) Divide Sum by Count to get Average.
In my small example below with 3 referees and 3 columns:-
(1) In K2:-
=SUMIF(H2:H4,"Yes",B2:B4)+SUMIF(H2:H4,"Yes",D2:D4)+SUMIF(H2:H4,"Yes",F2:F4)
(2) In K3:-
=COUNTIFS(B2:B4,">=0",H2:H4,"Yes")+COUNTIFS(D2:D4,">=0",H2:H4,"Yes")+COUNTIFS(F2:F4,">=0",H2:H4,"Yes")
(3) In K4:
=K2/K3
This would include any zero scores (if this is possible) but exclude any blanks.
You can then scale it up to your data.
Beyond this, you would have to change the data structure either
(1) Add a row to label the columns that you want to average e.g.
Score 1 Score 2 Score 3
3 0 3
so you could pick up only the columns labelled 3 say
Here's how it would be in my small example:-
In K3:-
=SUM((B$2:F$2=3)*($H3:$H5="Yes")*B3:F5)
Which is an array formula and must be entered with Ctrl-Shift-Enter
In K4:-
=SUM((B$2:F$2=3)*($H3:$H5="Yes")*(B3:F5<>""))
another array formula
In K5:-
=K3/K4
This is how the columns you want are labelled with a 3 in row 2, so it ignores the other columns:-
(2) Consolidate them into another sheet as you suggest.
I have two columns. One with positive values and one with negative values. I need to find the absolute difference between the two columns.
What I am currently doing is the following: First of all, I edit both the columns to make all the values positive. Then I subtract the first column with the second column. I change any negative value to the positive one. Is this the same as the absolute difference?
Why not just use the ABS function
=ABS(B1-A1)
It sounds like what you're doing is actually
=ABS(ABS(B1)-ABS(A1))
which is not the same as
=ABS(B1-A1)
for example if you have -3 and 1 the first would give you 2 and the second would give 4. I don't know which one you want.
This works no matter which value is positive or negative:
=MAX(A1,B1) - MIN(A1,B1)
OK, so here's a pretty clunky workaround, but it is something where I can understand what's going on and works every time.
Here is my scenario where I needed to solve this problem. I had a system stock list showing 1 of these 10 of those but also showing -10 of these and 5 of those, and once entering my physical data from doing a stock take, I had pluses and minuses all over the place, so the data looked like this:
Physical stocktake value system value
0 0
1 0
1 2
0 -1
1 -1
Effectively all the different connotations of pluses and minuses.
so column 'a' is actual, column b is system
I created columns c,d,e,f ..... I warned you it was a little clunky, but it is sound in the result.
formula in column c = '=IF(A1>B1,A1+B1,A1-B1'
formula in column D = '=IF(B1+C1<>A1,A1-B1,C1)'
formula in column E = '=IF(D1>C1,C1,D1)'
Column E is the data you want, it rationalises all of the pluses and Minuses in your data to show a true difference (independent of positive and negative location) for the values you require.
Someone much cleverer than I will condense this down into a singular equation, but i read up on it, tried the current solutions/advise, and didn't have a clue what the techs were going on about, so came up with this faultless solution.
It does work and it s simply a transpose the A1's and B1's for your data content.
Hope it helps (a little).
I for one will check back, just to pick up on what the clever guys and gals come back with, just a case of life is to short to drive into this level of detail for a simple solution. Sometimes simple is best.
Yeah ok, set myself up for that one ..... so I'm simple, but I know what I'm doing and understand it ........
I have a requirement in Excel to spread small; i.e. pennies, monetry rounding errors fairly across the members of my club.
The error arises when I deduct money from members; e.g. £30 divided between 21 members is £1.428571... requiring £1.43 to be deducted from each member, totalling £30.03, in order to hit the £30 target.
The approach that I want to take, continuing the above example, is to deduct £1.42 from each member, totalling £29.82, and then deduct the remaining £0.18 using an error spreading technique to randomly take an extra penny from 18 of the 21 members.
This immediately made me think of Reservoir Sampling, and I used the information here: Random selection,
to construct the test Excel spreadsheet here: https://www.dropbox.com/s/snbkldt6e8qkcco/ErrorSpreading.xls, on Dropbox, for you guys to play with...
The problem I have is that each row of this spreadsheet calculates the error distribution indepentently of every other row, and this causes some members to contribute more than their fair share of extra pennies.
What I am looking for is a modification to the Resevoir Sampling technique, or another balanced / 2 dimensional error spreading methodology that I'm not aware of, that will minimise the overall error between members across many 'error spreading' rows.
I think this is one of those challenging problems that has a huge number of other uses, so I'm hoping you geniuses have some good ideas!
Thanks for any insight you can share :)
Will
I found a solution. Not very elegant, through.
You have to use two matrix. In the first you get completely random number, chosen with =RANDOM() and in the second you choose the n greater value
Say that in F30 you have the first
=RANDOM()
cell.
(I have experimented with your sheet.)
Just copy a column of n (in your sheet 8) in column A)
In cell F52 you put:
=IF(RANK(F30,$F30:$Z30)<=$A52, 1, 0)
Until now, if you drag left and down the formulas, you have the same situation that is in your sheet (only less elegant und efficient).
But starting from the second row of random number you could compensate for the penny esbursed.
In cell F31 you put:
=RANDOM()-SUM(F$52:F52)*0.5
(pay attention to the $, each random number should have a correction basated on penny already spent.)
If the $ are ok you should be OK dragging formulas left and down. You could also parametrize the 0.5 and experiment with other values. With 0,5 I have a error factor (the equivalent of your cell AB24) between 1 and 2