Can anyone please suggest how to add multiple file extensions with the glob.sync method.
Something like:
const glob = require('glob');
let files = glob.sync(path + '**/*.(html|xhtml)');
Thank you :)
You can use this (which most shells support as well):
glob.sync(path + '**/*.{html,xhtml}')
Or one of these:
glob.sync(path + '**/*.+(html|xhtml)')
glob.sync(path + '**/*.#(html|xhtml)')
Related
1)TOPDIR =/../../
2)/ABC/path/
3)name=os.os.environ['ABC'].lower()
4).yaml
I want to Concatenate all four things in one like
Tried below solution :
[TOPDIR + "/ABC/path/" + name .yaml] appending this in Generartor
Not working. Can anyone give solution for this.
TOPDIR = '/../../'
name = os.environ['ABC'].lower()
print([TOPDIR + "/ABC/PATH/" + name + '.yaml'])
This should work.
What's the error it throws actually?
Perhaps you have a typo "os.enviorn" should be "os.environ"
I'm writing a CLI that runs off nodejs and the basic usage scenario is that one would pass in a number of files, and/or folders, and/or glob patterns; eg:
my-cli file.foo file2.foo
my-cli folder/ folder2/
my-cli folder/**/*.foo folder2/**/*.foo
my-cli file.foo folder/ folder/**/*.foo
And so on. I'm wondering what's the most efficient way of handling whatever file/folder/glob style input? I'm using Optimist to get the argv._ (all the args) and this is my coffeescript (sorry) code handling the different variantions of the input:
_ = require 'lodash'
fs = require 'fs'
glob = require 'glob'
module.exports = (files) ->
htmlFiles = []
ext = 'html'
files = _.flatten files
_.forEach files, (file) ->
fileExt = file.split('.').pop()
if fileExt isnt ext
if fs.lstatSync(file).isDirectory()
file = if file.charAt(file.length - 1) isnt '/' then file + '/' else file
htmlFiles.concat glob.sync file + '**/*.' + ext
else
htmlFiles.push file
I feel this is a bit messy and I'm hoping that there's a nice library somewhere in npm that I could use or make use of some other tricks?
I've written a vanilla server (using Node.js and Express) to browse files and directories (based off the directory middleware). On a Windows machine, it gets confused by the backslashes, and quickly breaks by providing invalid/broken links as you navigate -- links becomes a soup of forward and backslashes, with dir names incorrectly repeated over and over in them, etc.
So or example, going to localhost:8888, clicking on 'lib' folder, then '..', gives me:
/ \lib / \\lib\..\ /
Here's the code.
var express = require('express');
var server = express();
server.configure(function(){
server.use(express.static('./stuff'));
server.use(express.directory('./stuff'));
});
server.listen(8888);
What do I need to do to get this to work on a Windows machine?
#verybadalloc and #user2524973 found a bug in the express directory.js middleware that caused this problem. In the comments to the original question they also provided a fix.
Find the lines that says
return '<li><a href="' + join(dir, file) + '" class="' + classes.join(' ') + '"' + ' title="' + file + '">'
It should be around line number 176. Change it to:
return '<li><a href="' + join(dir, file).replace(/\\/g, '/') + '" class="' + classes.join(' ') + '"' + ' title="' + file + '">'
... and it should work better on Windows.
It seems like this fix was added to the main repository, but later removed, so this fix might have some unforeseen consequence? Works for me anyway, I'm just using it to list my music folder.
I posted this answer since I almost missed that they had solved it in the comments. Thanks.
I'm looking to monkey-patch require() to replace its file loading with my own function. I imagine that internally require(module_id) does something like:
Convert module_id into a file path
Load the file path as a string
Compile the string into a module object and set up the various globals correctly
I'm looking to replace step 2 without reimplementing steps 1 + 3. Looking at the public API, there's require() which does 1 - 3, and require.resolve() which does 1. Is there a way to isolate step 2 from step 3?
I've looked at the source of require mocking tools such as mockery -- all they seem to be doing is replacing require() with a function that intercepts certain calls and returns a user-supplied object, and passes on other calls to the native require() function.
For context, I'm trying to write a function require_at_commit(module_id, git_commit_id), which loads a module and any of that module's requires as they were at the given commit.
I want this function because I want to be able to write certain functions that a) rely on various parts of my codebase, and b) are guaranteed to not change as I evolve my codebase. I want to "freeze" my code at various points in time, so thought this might be an easy way of avoiding having to package 20 copies of my codebase (an alternative would be to have "my_code_v1": "git://..." in my package.json, but I feel like that would be bloated and slow with 20 versions).
Update:
So the source code for module loading is here: https://github.com/joyent/node/blob/master/lib/module.js. Specifically, to do something like this you would need to reimplement Module._load, which is pretty straightforward. However, there's a bigger obstacle, which is that step 1, converting module_id into a file path, is actually harder than I thought, because resolveFilename needs to be able to call fs.exists() to know where to terminate its search... so I can't just substitute out individual files, I have to substitute entire directories, which means that it's probably easier just to export the entire git revision to a directory and point require() at that directory, as opposed to overriding require().
Update 2:
Ended up using a different approach altogether... see answer I added below
You can use the require.extensions mechanism. This is how the coffee-script coffee command can load .coffee files without ever writing .js files to disk.
Here's how it works:
https://github.com/jashkenas/coffee-script/blob/1.6.2/lib/coffee-script/coffee-script.js#L20
loadFile = function(module, filename) {
var raw, stripped;
raw = fs.readFileSync(filename, 'utf8');
stripped = raw.charCodeAt(0) === 0xFEFF ? raw.substring(1) : raw;
return module._compile(compile(stripped, {
filename: filename,
literate: helpers.isLiterate(filename)
}), filename);
};
if (require.extensions) {
_ref = ['.coffee', '.litcoffee', '.md', '.coffee.md'];
for (_i = 0, _len = _ref.length; _i < _len; _i++) {
ext = _ref[_i];
require.extensions[ext] = loadFile;
}
}
Basically, assuming your modules have a set of well-known extensions, you should be able to use this pattern of a function that takes the module and filename, does whatever loading/transforming you need, and then returns an object that is the module.
This may or may not be sufficient to do what you are asking, but honestly from your question it sounds like you are off in the weeds somewhere far from the rest of the programming world (don't take that harshly, it's just my initial reaction).
So rather than mess with the node require() module, what I ended up doing is archiving the given commit I need to a folder. My code looks something like this:
# commit_id is the commit we want
# (note that if we don't need the whole repository,
# we can pass "commit_id path_to_folder_we_need")
#
# path is the path to the file you want to require starting from the repository root
# (ie 'lib/module.coffee')
#
# cb is called with (err, loaded_module)
#
require_at_commit = (commit_id, path, cb) ->
dir = 'old_versions' #make sure this is in .gitignore!
dir += '/' + commit_id
do_require = -> cb null, require dir + '/' + path
if not fs.existsSync(dir)
fs.mkdirSync(dir)
cmd = 'git archive ' + commit_id + ' | tar -x -C ' + dir
child_process.exec cmd, (error) ->
if error
cb error
else
do_require()
else
do_require()
I have a directory with a bunch of XML documents and want to put all of them into a container.
In other words, I need to do something like this:
dbxml> putDocument tests/*.xml
I have written a GUI program to do that but the host server does not have X-windows installed, so must be in command line.
I do a similar thing when reloading certain XML docs into my current application DB. It helps if all of the files sharing a common naming convention. In python you would could use the following script to add doc001.xml to doc009.xml:
from bsddb3.db import *
from dbxml import *
#Load source files 001 - 009
sourceDir = 'C:/directory-containing-xml-docs'
fileRange = range(1,10)
for x in fileRange:
mycontainer = mymgr.openContainer("myDB.dbxml")
xmlucontext = mymgr.createUpdateContext()
xmlinput = mymgr.createLocalFileInputStream(sourceDir + "doc00" + str(x) + ".xml")
mycontainer.putDocument("doc00" + str(x) + ".xml", xmlinput, xmlucontext)
print 'Added: ' + str(x)
del mycontainer
print '1 - 9 Added'
Hope that helps
You could have a shell script write the list of XML files to another file and then call dbxml_load_container with the -f option.
Ended up using a script that lists files and puts everything into the DB.