How to get this in excel
excel table
F column is the result column
For the following answer I am going to assume you only ever have two numbers in any row, but they can be in any cell along the row and they are always greater than 0.
If you just wish to find the difference between the two numbers without worrying about which number is bigger, a simple equation using maximum and minimum can be used, eg in Cell F1 you would have
=MAX(A1:E1)-MIN(A1:E1)
However, from your example, it seems more likely that you want to know the difference between the first number and the second number.
The difficulty here, is that the cells in columns B, C and D could contain either the first number, the second number, or no number! The solution is to use the following equation in Cell F1
=(MAX(A1:E1)-MIN(A1:E1))*IF(MAX(A1:E1)=INDEX(A1:E1,MATCH(0,A1:E1,-1)),-1,1)
This formula works as follows:
We still start off with the simple difference between the max and min, and then this is multiplied by 1 or -1 depending on which way around the numbers are.
MATCH(0,A1:E1,-1)
This part of the equation looks along the row for a 0, and assumes they are in descending order, so it will return the position of the second number.
This is then inserted into the INDEX function and checked to see if it is the same as the maximum number and the IF function returns either -1 or 1 as required.
Paste this formula on F1, then copy to F2 and F3
=INDEX(A1:E1,MATCH(TRUE,INDEX(A1:E1<>"",),0)) - LOOKUP(9.99E+307,A1:E1)
Related
I have a huge amount of data to process in which 4 points with a related prefix needs to be subtracted from each other.
Data consists of ID and x value
Example
ID = 290.12, 290.03, 290.06, 290.09, 300.12, 300.03, 300.06, 300.09, 301.12, 301.03, 301.06, 301.09
(let's call prefix a "ring number" and suffix time on the clock)
X value = any numerical value for each ID assigned
What I'm hoping to do is to search for the first number before the dot i.e. 300 and then subtract the value of 300.06-300.12 in one cell and in another cell 300.03-300.09.
(The subtraction is just an example, how I need to manipulate with the numbers is slightly more complicated, but I got this one under control)
This is my actual Data and what I need to produce is to the right of the raw data. At the moment, I'm doing it manually for each set of "rings"
Anyone knows how to approach this? I'm thinking vlookup, but I'm not very proficient in excel.
New Excel
I tried vlookup, but I don't know how to construct the formula and I run out of ideas.
Edit:
I found out that REDUCE is no requirement in this case, so it can be shortened to:
=SQRT(SUM(((INDEX(B:D,XMATCH(I3+0.09,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(I3+0.03,A:A),SEQUENCE(1,3)))^2)))
You could change +0.09 and +0.03 to your needs and may reference them using LET() for easy maintaining:
=LET(id,I3,
_id1,0.09,
_id2,0.03,
SQRT(SUM(((INDEX(B:D,XMATCH(id+_id1,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(id+_id2,A:A),SEQUENCE(1,3)))^2))))
Previous answer:
=LET(
id,I3,
_id1,0.09,
_id2,0.03,
SQRT(
REDUCE(0, SEQUENCE(1,3),
LAMBDA(x, y,
x+((INDEX(B:D,XMATCH(id+_id1,A:A),y)
-INDEX(B:D,XMATCH(id+_id2,A:A),y))
^2)))))
This formula looks for the matching value of the id value I3 + _id1 minus the matching value of id value + _id2 for columns B to D and adds the ^2 results per column. Then it calculates it's square root.
You can change _id1 and _id2 to your needs.
To calculate the Delta (as shown) at once you could use:
=LET(id,I3,
_id1,0.09,
_id2,0.03,
_id3,0.12,
_id4,0.06,
x,SQRT(SUM((INDEX(B:D,XMATCH(id+_id1,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(id+_id2,A:A),SEQUENCE(1,3)))^2)),
y,SQRT(SUM((INDEX(B:D,XMATCH(id+_id3,A:A),SEQUENCE(1,3))-INDEX(B:D,XMATCH(id+_id4,A:A),SEQUENCE(1,3)))^2)),
(x-y)*1000)
You can have a column of unique values of the integers and a new column where you reference these values as id and drag down the formula to get your row by row result
In another column you can refer to these columns and sort per the second column using SORTBY()
My worksheet contains orders from clients. The orders are all wooden panels.
Every order is assigned a number which is led by the letter Q.
Column B contains the number of parts in the order.
Column C contains the total m² in the order.
Orders that contain one or more parts that are 2.8 x 0.0735 m will get a row of their own.
I'm trying to count the number of times that this part occurs in a list of more than a thousand rows.
So if I divide the total m² by the m² of the part I'm looking for and divide this by the amount of parts in the order, I should get exactly 1 as a result.
If I take the sum of all the number of parts that result in a 1, I get my total.
Now I'd like to put this in one formula for the entire worksheet, but SUMIF doesn't work the way I'm trying. (It's in Dutch)
=SOM.ALS(B:B;(C:C/(2,8*0,0735)/B:B)=1)
I can't seem to use this formula as a criterium in the SUMIF.
For now I use a helping column that gives the right amount per row. Then take the total SUM of these.
Is it possible to put this in a single formula?
Yes, it is possible. Try this one:
{=SUM(--(B:B=C:C/(2.8*0.0735))*IF(ISERROR(1/B:B),0,1))}
Remember to enter it as an array function with CNTRL + SHIFT + ENTER.
The first half of the formula is just a logical test, after the asterisk it tests if 1/B results in an error (thereby omitting text, zeroes, and blanks) and returns a zero if there is an error.
These are then summed and the result displayed.
In Dutch and English:
{=SOMPRODUCT(--(B:B=(ALS(ISTEKST(C:C);1;C:C))/(2,8*0,0735));B:B)}
{=SUMPRODUCT(--(B:B=(IF(ISTEXT(C:C),1,C:C))/(2.8*0.0735)),B:B)}
is working perfectly. (Enter with Ctrl-Shift-Enter)
The first bit is the logical test, which will check if B:B = C:C / (2.8*0.0735)
It got stuck on #VALUE! because there is text in C:C.
The IF(ISTEXT)) eliminates text by converting them to numeric values, in this case 1, but it can be any numeric value.
The logical test will return TRUE(1) or FALSE(0) because of the double dash or unary operator and this will be multiplied by their respective B:B value.
Because the row with text has no value in B:B, it will result as zero.
I have a range that I want to sum, which is A2:M35. However, if column 'N' has the number 1 in it, I want to exclude that entire row from the sum. So, If N3 contains 1 I want to exclude the range A3:M3 from the sum calculation. Is this possible?
UPDATE:
I should also include that the 1 or 0 in column N is a flag to state whether this row should be excluded or not (1 = yes, 0 = no). However, this value is derived by checking whether any values in that row = "excluded". So, the additional complication here appears to be that even though the rows with "excluded" in them should be excluded, the sum calculation will show '#VALUE' as it believes some of the values are of the wrong data type (even though they shouldn't be included).
SIMPLE SOLUTION (with helper column)
If you can, to keep it simple, I'd just add a helper column.
So In cell O2:
=IF($N2=1,0,SUM($A2:$M2))
Drag that down to cell O35.
Then you can simply:
=SUM($O$2:$O$35)
COMPLEX SOLUTION (no helper column)
If you would like to avoid having to have a helper column cluttering up your sheet, you could use a SUMPRODUCT formula:
=SUMPRODUCT($A$2:$M$35,(LEN($A$2:$M$35)-LEN($A$2:$M$35))+NOT($N$2:$N$35))
HOW IT WORKS:
The first range (A2:M35) is the array (or in this case a range of excel cells) that you want to sum.
The SUMPRODUCT is going to take each value in that array and multiply it by each corresponding value in the next array we supply, then sum all the results together.
The problem is that the first array is a table, 13 values across and 34 values down. The second array (column N) is only 1 value across. SUMPRODUCT requires that all arrays are the same size.
To do this, we first create an array the correct size:
(LEN(A2:M35)-LEN(A2:M35))
LEN returns an array containing the number of characters in each cell supplied to it. If we take it away from it's self, we are left with an array of the correct size, filled with zeros.
We can then add the values in our smaller array (column N) to the zeros in the array of the correct size, this will fill all the columns with the correct value.
+NOT(N2:N35))
The NOT is there because we want to sum the rows which have a zero. All it is doing is swapping the zeros and ones in column N. So, all 1's become 0's and vice versa.
I hope you can follow my explanation. If not, please let me know and I will elaborate.
How do I average a list of numbers whose values are greater than 0? I know I can use AVERAGEIF function in Excel
My data is located in A2, A5, A6, A10, A17.
I only want to average it if the data is greater than 0.
Since my data is not an range, I am not able to use AVERAGEIF Function range.
Need some help on this.
EDIT
For example,
I tried with three numbers:
1) 98.068 and 98.954 and 0 so my forumla looked like this:
=AVERAGE(IF(N(OFFSET(A2,{0,5,10},))>0,N(OFFSET(A2,{0,5,10},))))
The answer came out as 99.106. Not sure why.
A few options:
1)=SUM(SUMIF(INDIRECT({"A2","A5","A6","A10","A17"}),">0"))/SUM(COUNTIF(INDIRECT({"A2","A5","A6","A10","A17"}),">0"))
2)=AVERAGE(IF(N(INDIRECT({"A2","A5","A6","A10","A17"}))>0,N(INDIRECT({"A2","A5","A6","A10","A17"}))))
3)
=AVERAGE(IF(N(OFFSET(A2,{0,3,4,8,15},))>0,N(OFFSET(A2,{0,3,4,8,15},))))
2) and 3) must be committed as array formulas**
Regards
(0) A simple method
=SUM(A2*(A2>0),A5*(A5>0),A6*(A6>0),A10*(A10>0),A17*(A17>0))/SUM(A2>0,A5>0,A6>0,A10>0,A17>0)
(4) A more general method
=SUM((A1:A20>0)*A1:A20*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))/
SUM((A1:A20>0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))
The second one is an array formula and must be entered with CtrlShiftEnter
If it's possible to have text in the cells rather than numbers, then this should replace the first formula:-
=SUM(N(A2)*(A2>0),N(A5)*(A5>0),N(A6)*(A6>0),N(A10)*(A10>0),N(A17)*(A17>0))/SUM(N(A2)>0,N(A5)>0,N(A6)>0,N(A10)>0,N(A17)>0)
(I haven't used N in the > brackets in the numerator because I reason that if A2 etc. is text, the product will always be zero)
I can't persuade N to work with arrays in the second formula, so at the moment I have the rather lengthy
=SUM((IF(ISNUMBER(A1:A20),A1:A20,0)>0)*IF(ISNUMBER(A1:A20),A1:A20,0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))/
SUM((IF(ISNUMBER(A1:A20),A1:A20,0)>0)*(ADDRESS(ROW(A1:A20),1,4)={"A2","A5","A6","A10","A17"}))
but I have tested it on text values and negative numbers and it does seem fine.
The only exception is if one of the cells contains TRUE. In this case the first formula will count it as 1, the second formula will ignore it.
I'm creating a revenue model on a simple spreadsheet. On the top, I have a variable cell (C5) that is the "number of weeks between transactions". Below that, I have a simple weekly revenue model.
Problem: What I would like is to be able to tweak the fields in yellow and have it apply dynamically to the model below so that it applies the sales amount from C4 every X weeks to the model below, where X is C5.
My initial guess was to use OFFSET, such as F10 =SUM(OFFSET(C10,0,$C$5)), but I've never used this function before and the more I think about it, I'm not sure if I'm approaching this correctly at all.
I created a mock desired results image to show what I would like to have happen if I enter 3 in C5 and then change it to 2.
May not be quite right but hopefully 'configurable' to suit. Assumes $500 is entered in C10 and (at least for the time being) 1 will not be entered in C5. Please try in D10 and copied across to suit:
=IF(MOD(COLUMN()-3,$C5)<MOD(COLUMN()-4,$C5),$C10,"")
A quick fix for the above failing to populate all cells when C5 is 1 is to wrap the formula in the condition =IF($C5=1,$C10,....)
MOD "returns the remainder after a number is divided by a divisor". The remainder being 0 when the number is an exact multiple of the divisor. If we take the first example (every third column) a suitable divisor is 3. Put =MOD(Column(),3) in A1 and copy across and the result is 1, 2, 0, 1, 2, 0, 1, ..... (Column() returns a number representing the column letter, with 1 for A, 2 for B etc., or the actual Column Heading where R1C1 reference style is checked under Working with formulas, in Formulas within Excel Options.)
So that establishes a series where every third position is identifiable as returning a value from MOD that is less than that of the immediately preceding cell. For the second example (every second column) with a divisor of 2 =MOD(Column(),2) in A1 copied across results in 1, 0, 1, 0, 1, ... so again the reduction in the remainder signals the position required for the formula to output the requisite value.
We are comparing the result of calculating the remainder for one column relative to the result of the same calculation performed on the previous column, hence -3, -4. Other (suitably paired) values might work equally well, it just seemed easier to 'start from zero' when in the first column for the formula (ColumnD or 4).
(If anybody would like to provide a proper explanation please feel free to edit!)