I would like to use an opentype feature in my font, I'm creating in FontLab, that would transform all the numbers to roman notation. This is the OpeType Feature code I'm using:
feature liga{
sub #arabic by #roman1;
sub #roman1' #roman1 by #roman2;
sub #roman2' #roman2 by #roman3;
sub #roman3' #roman3 by #roman4;
} liga;
Classes 'arabic' and 'roman1-4' all contain numbers from 0 to 9, where roman1 contains: [empty symbol], I, II... IX, roman2: [empty smbol], X, XX... XC, etc.
Numbers up to 99 are working as they should, but above 100 only roman2 glyphs are being repeated, so instead 111 being 'CXI', I get 'XXI'. I'm not sure what the right syntax for opentype features should look like and where exactly is the problem.
So I have solved my problem already. The reason why it wasn't working was that all the rules were run in a single pass of the word as one rule instead of them being run one after another through whole word. This is the correct solution:
feature liga{
lookup rOne {
sub #arabic by #roman1;
} rOne;
lookup rTwo {
sub #roman1' #roman1 by #roman2;
} rTwo;
lookup rThree {
sub #roman2' #roman2 by #roman3;
} rThree;
lookup rFour {
sub #roman3' #roman3 by #roman4;
} rFour;
} liga;
P.S.: To clarify, this code is for FontLab's OpenType features coding
Related
I have a UI that I am creating that replicated Android Studio's (IntelliJ) design system for text as code. What I am trying to achieve is a text that changes it's color multiple times when certain words or patterns happen, such as Kotlin keywords (orange text), extension methods(yellowish text) and variables (purple text).
What do I mean? the following functions text design is what I want to achieve, and they are examples of using all 3 colors -
So I tried to implement it using a buildAnnotatedString { } block and things got A) very messy and B) didn't even reach my goal. Here is my current code of trying to implement keywords and extensions -
// A dummy function that represents only the text part of my entire screen, everything else is irrelevant for the question
#Composable
fun TextAsIntellij(solution : String) {
Text(text = buildAnnotatedString {
val kotlinKeywords = mutableListOf("fun", "val", "var", "if", "return", "null", ",", "class", "while", "break", "continue")
val kotlinExtensions = mutableListOf("forEachIndexed") // will add more as needed
solution.split(" ", ".").forEach { string ->
if (kotlinKeywords.contains(string)) {
withStyle(
style = SpanStyle(
color = Orange
)
) {
append(string)
append(' ')
}
return#forEach
} else if (kotlinExtensions.contains(string)) {
withStyle(
style = SpanStyle(
color = Yellow
)
) {
append(string)
append(" ")
}
return#forEach
}
append(string)
append(' ')
}
})
}
The results in the UI are the following -
As you can see, in the first question I have a problem that before an extension I put a redundant space because I used split() method to identify all words by spaces and dots. For the 2nd picture, I don't yet have a proper solution for identifying varibles from an "object", because I have already split my String using spaces and dots, so diving deeper into another split would make my code really inefficient and I though better can be done. 😁
Hopefully someone has a good idea...any Jetbrains spy in the crowd? ;)
I have a sharepoint list. One of the fields in it(called DocNumber) is the document number including version. It will look like this ESI-1234-1.0
Basically the rule is, it should start with the text ESI-, then a number, followed by another hipen(-), followed by version number, then a dot(.), and a subversion number
How do i write the 'Column validation' for this. I'm using Sharepoint Online(365 I guess), so there's a placeholder in field level settings to write this formula. I searched online but the syntax is so difficult that I'm finding it hard to customize the formula -
I need something like this, but i don't want to indicate position because the numbers there could be of any length(its a serial number, currently we are at 1600, so we should support 1 to 5 digits atleast and version could be any number from 1 to 99)
=AND(
IF(ISERROR(FIND("ESI-",DocNumber,1)),FALSE,(FIND("ESI-",DocNumber)=1)),
IF(ISERROR(FIND("-",DocNumber,4)),FALSE,(FIND("-",DocNumber,4)=4)))
Thankyou for your help!
In the formula property of column You may use JSON structure like this:
{
"elmType": "div",
"txtContent": {
"operator": "+",
"operands": [
"ESI-",
"[$ID]",
"-",
"[$_UIVersionString]"
]
}
}
here we make a custom view in a div HTML element with text inside. The Text is static string "ESI-" then we add ID column then we add "-" then we add version number column as string
the result should be something like this
... I hope this will be of any help
Hi I would like to extract dynamically the numbers from string in Excel.
I have the following strings and I would like to have only the numbers before ". pdf". taken out of the string into the next column.
As you can see the number of characters varies from line to line.
I have invented something like this:
=MID(M20;SEARCH("_";M20);20)
But this takes out only the numbers after "_" and .pdf after this....
How to make it the way I like?
D:\Users\xxxx\Desktop\1610\ts25b_4462.pdf
D:\Users\xxx\Desktop\1610\ts02b_39522.pdf
D:\Users\xxxxx\Desktop\1610\ts02b_except_39511.pdf
D:\Users\xxxx\Desktop\1610\ts02b_except_39555.pdf
D:\Users\xxxx\Desktop\1610\ts22b_6118.pdf
So that I have just :
4462
39522
39511
39555
6118
and so on...
Thank you!!!
With VBA, try to do it like this:
Public Function splitThings(strInput As String) As String
splitThings = Split(Split(strInput, "_")(1), ".")(0)
End Function
Concerning your formula, try to use =LEFT(MID(M20;SEARCH("_";M20);20),K), where K is the difference of the length of ts22b_6118.pdf and 4 (.pdf). 4 is the length of .pdf.
Something like this should do the work:
=LEFT(MID(I3,SEARCH("_",I3)+1,LEN(I3)),LEN(MID(I3,SEARCH("_",I3),LEN(I3)))-5)
You should do it using Excel formula. For example:
=SUBSTITUTE(LEFT(A1,FIND(".pdf",A1)-1),LEFT(A1,FIND("_",A1)),"")
Using the first line as an example, with LEFT(A1,FIND(".pdf",A1)-1) you will have D:\Users\xxxx\Desktop\1610\ts25b_4462 and with the LEFT(A1,FIND("_",A1)) D:\Users\xxxx\Desktop\1610\ts25b_, if you SUBSTITUTE the first part by "" you will have 4462.
Hope this can help.
With this formula, you should be able to get the numbers you want:
=MID(A1,FIND("|",SUBSTITUTE(A1,"_","|",LEN(A1)-LEN(SUBSTITUTE(A1,"_",""))))+1,FIND(".",A1)-FIND("|",SUBSTITUTE(A1,"_","|",LEN(A1)-LEN(SUBSTITUTE(A1,"_",""))))-1)
Basically, this is the initial fomula:
=MID(A1,FIND("_",A1)+1,FIND(".",A1)-FIND("_",A1)-1)
But since there may be two _ in the string so this is the one to find the 2nd _:
=SUBSTITUTE(A1,"_","|",LEN(A1)-LEN(SUBSTITUTE(A1,"_","")))
Now just replace this SUBSTITUTE with A1 above and you get that long formula. Hope this helps.
This will return the number you want regardless of extension (could be .pdf, could be .xlsx, etc) and regardless of the number of underscores present in the filename and/or filepath:
=TRIM(LEFT(RIGHT(SUBSTITUTE(SUBSTITUTE(M20,".",REPT(" ",LEN(M20))),"_",REPT(" ",LEN(M20))),LEN(M20)*2),LEN(M20)))
I have seen some questions (like this one) here asking about if a cell in Excel can be formatted by NPOI/POI as if formatted by Excel. As most of you, I have to deal with issues with Currency and DateTime. Here let me ask how the formatting can be achieved as if it has been formatted by Excel? (I will answer this question myself as to demonstrate how to do it.)
Setting: Windows 10, English, Region: Taiwan
Excel format: XLSX (version 2007 and later)
(Sorry about various edit of this question as I have pressed the 'Enter' button at unexpected time.)
If you format a cell as Currency, you have 4 choices:
The internal format of each style is as follow:
-NT$1,234.10
<numFmt formatCode=""NT$"#,##0.00" numFmtId="164"/>
[RED]NT$1,234.10
<numFmt formatCode=""NT$"#,##0.00;[Red]"NT$"#,##0.00" numFmtId="164"/>
-NT$1,234.10
<numFmt formatCode=""NT$"#,##0.00_);("NT$"#,##0.00)" numFmtId="7"/>
[RED]-NT$1,234.10
<numFmt formatCode=""NT$"#,##0.00_);[Red]("NT$"#,##0.00)" numFmtId="8"/>
Note: There is a pair of double quote (") comes before and after NT$.
(To get internal format of XLSX, just unzip it. The Style information is available in <unzip dir>\xl\Styles.xml Check out this answer if you need more information.)
(FYI: In formatCode, the '0' represent a digit. The '#' also represent a digit, but will not appear if the number is not large enough. So any number less than 1000 will not have the comma inside it. The '_' is a space holder. In format 3, '1.75' appears as 'NT$1.75 '. The last one is a space.)
(FYI: In numFmtId, for case 1 and case 2, number 164 is for user-defined. For case 3 and 4, number 7 and 8 are build-in style.)
For developers using POI/NPOI, you may find out if you format your currency column using Build In Format using 0x7 or 0x8, you can get only the third or fourth choice. You cannot get the first or second choice.
To get the first choice, you build upon style 0x7 "$#,##0.00);($#,##0.00)". You need to add the currency symbol and the pair of double quotes in front of it.
styleCurrency.DataFormat = workbook.CreateDataFormat().GetFormat("\"NT$\"#,##0.00");
Apply this format to a cell with number. Once you open the Excel result file, right click to check formatting, you will see the first choice.
Please feel free to comment on this post.
var cell5 = row.CreateCell(5, CellType.Numeric);
cell5.SetCellValue(item.OrderTotal);
var styleCurrency = workbook.CreateCellStyle();
styleCurrency.DataFormat= workbook.CreateDataFormat().GetFormat(string.Format("\"{0}\"#,##0.00", item.CurrencySymbol));//styleCurrency;
cell5.CellStyle = styleCurrency;
styleCurrency = null;
Iterate over loop for multiple currency.
Function to GetCurrencySymbol against currency Code on C#
private string GetCurencySymbol(string isOcurrencyCode)
{
return CultureInfo.GetCultures(CultureTypes.AllCultures).Where(c => !c.IsNeutralCulture)
.Select(culture =>
{
try
{
return new RegionInfo(culture.LCID);
}
catch
{
return null;
}
})
.Where(ri => ri != null && ri.ISOCurrencySymbol == isOcurrencyCode)
.Select(ri => ri.CurrencySymbol).FirstOrDefault();}
I've run into a strange problem. I have a string with a value containing 'AA'.
I'm trying to find IndexOf the first accouring A. When I ask if the string Contains("A") it returns true. When using IndexOf("A") I keeps getting the default value -1! (se the picture below)
So far i tested there is only a problem with 'A' and 'a'.
When putting 3 a's in the string I get the index of number 3, as if the first two doesn't exsist.
When adding an extra a to the string, I get the default value -1 again.
I don't know what is causing this, I have a suspision that it's somehow connected to some langauge setting. I'm from denmark, and the use of the letters aa is a synonym for å.
Have anyone else experinced a simular problem or have a suggestion how to avoid it?
System information:
Windows 7 Ultimate (English)
Visual Studio 10 Premium
'aa' is handled as an entity if the culture is da-DK. The question is sort of a duplicate, see String StartsWith() issue with Danish text.
Hmmm I have tried the same now. It works...
static void XYZ()
{
string a = "aaa";
string b = "AAA";
if(a.Contains("a"))
{
Console.WriteLine(a.IndexOf("a"));
}
if(b.Contains("A"))
{
Console.WriteLine(b.IndexOf("A"));
}
}
But wouldn't it be the best to seach for a "aa" and "AA"? I can speak danish and I know that there are single a's too ;-)