I want to manipulate this string:
"Roger:Rabbit:22:California"
and display the output as follows:
Name: Roger Rabbit
Age: 22
State: California
I am wondering what will be the best approached to this?
For this you may use the String split() method. Mention your delimiter as :. Then you want to make sure you create an array out of the output of your split method with the different strings split. In your System.out.println() you can mention the array index of your newly created array elements as System.out.println("Name" + myIndex[0]).
Resource: https://www.tutorialspoint.com/java/java_string_split.htm
Related
I am brand new to Scala and having a tough time figuring this out.
I have a string like this:
a = "The dog crossed the street"
I want to create a list that looks like below:
a = List("The","dog","crossed","the","street")
I tried doing this using .split(" ") and then returning that, but it seems to do nothing and returns the same string. Could anyone help me out here?
It's safer to split() on one-or-more whitespace characters, just in case there are any tabs or adjacent spaces in the mix.
split() returns an Array so if you want a List you'll need to convert it.
"The dog\tcrossed\nthe street".split("\\s+").toList
//res0: List[String] = List(The, dog, crossed, the, street)
I am fairly new to Puppet and Ruby. Most likely this question has been asked before but I am not able to find any relevant information.
In my puppet code I will have a string variable retrieved from the fact hostname.
$n="$facts['hostname'].ex-ample.com"
I am expecting to get the values like these
DEV-123456-02B.ex-ample.com,
SCC-123456-02A.ex-ample.com,
DEV-123456-03B.ex-ample.com,
SCC-999999-04A.ex-ample.com
I want to perform the following action. Change the string to lowercase and then replace the
-02, -03 or -04 to -01.
So my output would be like
dev-123456-01b.ex-ample.com,
scc-123456-01a.ex-ample.com,
dev-123456-01b.ex-ample.com,
scc-999999-01a.ex-ample.com
I figured I would need to use .downcase on $n to make everything lowercase. But I am not sure how to replace the digits. I was thinking of .gsub or split but not sure how. I would prefer to make this happen in a oneline code.
If you really want a one-liner, you could run this against each string:
str
.downcase
.split('-')
.map
.with_index { |substr, i| i == 2 ? substr.gsub(/0[0-9]/, '01') : substr }
.join('-')
Without knowing what format your input list is taking, I'm not sure how to advise on how to iterate through it, but maybe you have that covered already. Hope it helps.
Note that Puppet and Ruby are entirely different languages and the other answers are for Ruby and won't work in Puppet.
What you need is:
$h = downcase(regsubst($facts['hostname'], '..(.)$', '01\1'))
$n = "${h}.ex-ample.com"
notice($n)
Note:
The downcase and regsubst functions come from stdlib.
I do a regex search and replace using the regsubst function and replace ..(.)$ - 2 characters followed by another one that I capture at the end of the string and replace that with 01 and the captured string.
All of that is then downcased.
If the -01--04 part is always on the same string index you could use that to replace the content.
original = 'DEV-123456-02B.ex-ample.com'
# 11 -^
string = original.downcase # creates a new downcased string
string[11, 2] = '01' # replace from index 11, 2 characters
string #=> "dev-123456-01b.ex-ample.com"
Sorry if question is vague.
I have a string that I want to format in a certain way
Currently it gets outputted like this
Could I output this like this?
With a new line for after each deliminator?
The common deliminator is the pipe (|) for these.
You can do this with a combination of the split() function to turn the strings into arrays of elements, and UNNEST, to convert each element in the array into a separate row:
WITH t(column, text) AS (
VALUES
('column1', 'text1|text2|text3'),
('column2', 'text3|text4|text4')
)
SELECT t.column, u.item
FROM t, UNNEST(split(t.text, '|')) u(item)
I'm new to Scala and unsure of how to achieve the following
I have the String
val output = "6055039\n3000457596\n3000456748\n180013\n"
I want to extract the numbers separated by \n and store them in an Array
output.split("\n").map(_.toInt)
Or only
output.split("\n")
if you want to keep the numbers in String format. Note that .toInt throws. You might want to wrap it accordingly.
I have a dataframe with a list of strings in it
df$a
=========
"4343-2"
"7889-5"
"4-3456"
"334-45"
"8765-4"
I'd like to perform a string operation on the list to remove the dash sign, so I did this..
df$a <- lapply(df$a, sub, "-","", df$a)
..which only produces a set of completely empty strings. What did I get wrong?
you can just use sub directly.
df$a <- sub('-', '', df$a)
Instead of the convoluted lapply you're doing since sub is "vectorized". You can also use gsub if you think there may be more than one dash per entry.