Can't parse a string with brace expansion operations into a command - linux

Question

have some problem with shell script.
In our office we set up only few commands, that available for devs when they are trying ssh to server. It is configured with help of .ssh/authorized_keys file and available command for user there is bash script:
#!/bin/sh
if [[ $1 == "--help" ]]; then
cat <<"EOF"
This script has the purpose to let people remote execute certain commands without logging into the system.
For this they NEED to have a homedir on this system and uploaded their RSA public key to .ssh/authorized_keys (via ssh-copy-id)
Then you can alter that file and add some commands in front of their key eg :
command="/usr/bin/dev.sh",no-port-forwarding,no-X11-forwarding,no-agent-forwarding,no-pty
The user will do the following : ssh testuser#server tail testserver.example.com/2017/01/01/user.log
EOF
exit 0;
fi
# set global variable
set $SSH_ORIGINAL_COMMAND
# set the syslog path where the files can be found
PATH="/opt/syslog/logs"
# strip ; or any other unwanted signs out of the command, this prevents them from breaking out of the setup command
if [[ $1 != "" ]]; then
COMMAND=$1
COMMAND=${COMMAND//[;\`]/}
fi
if [[ $2 != "" ]]; then
ARGU1=$2
ARGU1=${ARGU1//[;\`]/}
fi
if [[ $3 != "" ]]; then
ARGU2=$3
ARGU2=${ARGU2//[;\`]/}
fi
if [[ $4 != "" ]]; then
ARGU3=$4
ARGU3=${ARGU3//[;\`]/}
fi
# checking for the commands
case "$COMMAND" in
less)
ARGU2=${ARGU1//\.\./}
FILE=$PATH/$ARGU1
if [ ! -f $FILE ]; then
echo "File doesn't exist"
exit 1;
fi
#echo " --------------------------------- LESS $FILE"
/usr/bin/less $FILE
;;
grep)
if [[ $ARGU2 == "" ]]; then
echo "Pls give a filename"
exit 1
fi
if [[ $ARGU1 == "" ]]; then
echo "Pls give a string to search for"
exit 1
fi
ARGU2=${ARGU2//\.\./}
FILE=$PATH/$ARGU2
/usr/bin/logger -t restricted-command -- "------- $USER Executing grep $ARGU1 \"$ARGU2\" $FILE"
if [ ! -f $FILE ]; then
echo "File doesn't exist"
/usr/bin/logger -t restricted-command -- "$USER Executing $#"
exit 1;
fi
/bin/grep $ARGU1 $FILE
;;
tail)
if [[ $ARGU1 == "" ]]; then
echo "Pls give a filename"
exit 1
fi
ARGU1=${ARGU1//\.\./}
FILE=$PATH/$ARGU1
if [ ! -f $FILE ]; then
echo "File doesn't exist"
/usr/bin/logger -t restricted-command -- "$USER Executing $# ($FILE)"
exit 1;
fi
/usr/bin/tail -f $FILE
;;
cat)
ARGU2=${ARGU1//\.\./}
FILE=$PATH/$ARGU1
if [ ! -f $FILE ]; then
echo "File doesn't exist"
exit 1;
fi
/bin/cat $FILE
;;
help)
/bin/cat <<"EOF"
# less LOGNAME (eg less testserver.example.com/YYYY/MM/DD/logfile.log)
# grep [ARGUMENT] LOGNAME
# tail LOGNAME (eg tail testserver.example.com/YYYY/MM/DD/logfile.log)
# cat LOGNAME (eg cat testserver.example.com/YYYY/MM/DD/logfile.log)
In total the command looks like this : ssh user#testserver.example.com COMMAND [ARGUMENT] LOGFILE
EOF
/usr/bin/logger -t restricted-command -- "$USER HELP requested $#"
exit 1
;;
*)
/usr/bin/logger -s -t restricted-command -- "$USER Invalid command $#"
exit 1
;;
esac
/usr/bin/logger -t restricted-command -- "$USER Executing $#"
The problem is next:
when i try to exec some command, it takes only first argument, if i do recursion in files by using {n,n1,n2} - it doesn't work:
[testuser#local ~]$ ssh testuser#syslog.server less srv1838.example.com/2017/02/10/local1.log |grep 'srv2010' | wc -l
0
[testuser#local ~]$ ssh testuser#syslog.server less srv2010.example.com/2017/02/10/local1.log |grep 'srv2010' | wc -l
11591
[testuser#local ~]$ ssh testuser#syslog.server less srv{1838,2010}.example.com/2017/02/10/local1.log |grep 'srv2010' | wc -l
0
[testuser#local ~]$ ssh testuser#syslog.server less srv{2010,1838}.example.com/2017/02/21/local1.log |grep 'srv2010' | wc -l
11591
Could someone help me, how can i parse\count command arguments to make it work?
Thank you and have a nice day!

Answer 1

The number of arguments for a bash script would be $#. As a quick example:
#!/bin/bash
narg=$#
typeset -i i
i=1
while [ $i -le $narg ] ; do
echo " $# $i: $1"
shift
i=$i+1
done
gives, for bash tst.sh a b {c,d}
4 1: a
3 2: b
2 3: c
1 4: d
In your script, the command to execute (cat, less, ...) gets explicitly only the second argument to the script. If you want to read all arguments, you should do something like this (note: only a hint, removed all sorts of checks etc..)
command="$1"
shift
case $command in
(grep) pattern="$1"
shift
while [ $# -gt 0 ] ; do
grep "$pattern" "$1"
shift
done
;;
esac
note: added some quotes as comment suggested, but, being only a hint, you should carefully look at quoting and your checks in your own script.

Answer 2

Less command working now:
case "$COMMAND" in
less)
if [[ $ARGU1 == "" ]]; then
echo "Pls give a filename"
exit 1
fi
FILES_LIST=${#:2}
FILE=(${FILES_LIST//\.\./})
for v in "${FILE[#]}";do
v=${v//[;\']/}
if [ ! -f $v ]; then
echo "File doesn't exist"
fi
/usr/bin/less $PATH/$v
done;;
tail command works too with 2 and more files, but i can't execute tail -f command on two files unfortunately.