How to change input shape in Sequential model in Keras - keras

Question

I have a sequential model that I built in Keras.
I try to figure out how to change the shape of the input. In the following example
model = Sequential()
model.add(Dense(32, input_shape=(500,)))
model.add(Dense(10, activation='softmax'))
model.compile(optimizer='rmsprop',
loss='categorical_crossentropy',
metrics=['accuracy'])
let's say that I want to build a new model with different input shape, conceptual this should looks like this:
model1 = model
model1.layers[0] = Dense(32, input_shape=(250,))
is there a way to modify the model input shape?

Answer 1

Somewhat related, so hopefully someone will find this useful: If you have an existing model where the input is a placeholder that looks like (None, None, None, 3) for example, you can load the model, replace the first layer with a concretely shaped input. Transformation of this kind is very useful when for example you want to use your model in iOS CoreML (In my case the input of the model was a MLMultiArray instead of CVPixelBuffer, and the model compilation failed)
from keras.models import load_model
from keras import backend as K
from keras.engine import InputLayer
import coremltools
model = load_model('your_model.h5')
# Create a new input layer to replace the (None,None,None,3) input layer :
input_layer = InputLayer(input_shape=(272, 480, 3), name="input_1")
# Save and convert :
model.layers[0] = input_layer
model.save("reshaped_model.h5")
coreml_model = coremltools.converters.keras.convert('reshaped_model.h5')
coreml_model.save('MyPredictor.mlmodel')

Answer 2

Think about what changing the input shape in that situation would mean.
Your first model
model.add(Dense(32, input_shape=(500,)))
Has a dense layer that really is a 500x32 matrix.
If you changed your input to 250 elements, your layers's matrix and input dimension would mismatch.
If, however, what you were trying to achieve was to reuse your last layer's trained parameters from your first 500 element input model, you could get those weights by get_weights. Then you could rebuild a new model and set values at the new model with set_weights.
model1 = Sequential()
model1.add(Dense(32, input_shape=(250,)))
model1.add(Dense(10, activation='softmax'))
model1.layers[1].set_weights(model1.layers[1].get_weights())
Keep in mind that model1 first layer (aka model1.layers[0]) would still be untrained

Answer 3

Here is another solution without defining each layer of the model from scratch. The key for me was to use "_layers" instead of "layers". The latter only seems to return a copy.
import keras
import numpy as np
def get_model():
old_input_shape = (20, 20, 3)
model = keras.models.Sequential()
model.add(keras.layers.Conv2D(9, (3, 3), padding="same", input_shape=old_input_shape))
model.add(keras.layers.MaxPooling2D((2, 2)))
model.add(keras.layers.Flatten())
model.add(keras.layers.Dense(1, activation="sigmoid"))
model.compile(loss='binary_crossentropy', optimizer=keras.optimizers.Adam(lr=0.0001), metrics=['acc'], )
model.summary()
return model
def change_model(model, new_input_shape=(None, 40, 40, 3)):
# replace input shape of first layer
model._layers[1].batch_input_shape = new_input_shape
# feel free to modify additional parameters of other layers, for example...
model._layers[2].pool_size = (8, 8)
model._layers[2].strides = (8, 8)
# rebuild model architecture by exporting and importing via json
new_model = keras.models.model_from_json(model.to_json())
new_model.summary()
# copy weights from old model to new one
for layer in new_model.layers:
try:
layer.set_weights(model.get_layer(name=layer.name).get_weights())
except:
print("Could not transfer weights for layer {}".format(layer.name))
# test new model on a random input image
X = np.random.rand(10, 40, 40, 3)
y_pred = new_model.predict(X)
print(y_pred)
return new_model
if __name__ == '__main__':
model = get_model()
new_model = change_model(model)