Finding a regex patterned text inside a python variable - python-3.x

Question

# Ex1
# Number of datasets currently listed on data.gov
# http://catalog.data.gov/dataset
import requests
import re
from bs4 import BeautifulSoup
page = requests.get(
"http://catalog.data.gov/dataset")
soup = BeautifulSoup(page.content, 'html.parser')
value = soup.find_all(class_='new-results')
results = re.search([0-9][0-9][0-9],[0-9][0-9][0-9], value
print(value)
The code is above .. I want to find a text in the form on regex = [0-9][0-9][0-9],[0-9][0-9][0-9]
inside the text inside the variable 'value'
How can i do this ?
Based on ShellayLee's suggestion i changed it to
import requests
import re
from bs4 import BeautifulSoup
page = requests.get(
"http://catalog.data.gov/dataset")
soup = BeautifulSoup(page.content, 'html.parser')
value = soup.find_all(class_='new-results')
my_match = re.search(r'\d\d\d,\d\d\d', value)
print(my_match)
STILL GETTING ERROR
Traceback (most recent call last):
File "ex1.py", line 19, in
my_match = re.search(r'\d\d\d,\d\d\d', value)
File "/Library/Frameworks/Python.framework/Versions/3.6/lib/python3.6/re.py", line 182, in search
return _compile(pattern, flags).search(string)
TypeError: expected string or bytes-like object

Answer 1

You need some basics of regex in Python. A regex in Python is represented in as a string, and re module provides functions like match, search, findall which can take a string as an argument and treat it as a pattern.
In your case, the pattern [0-9][0-9][0-9],[0-9][0-9][0-9] can be represented as:
my_pattern = r'\d\d\d,\d\d\d'
then used like
my_match = re.search(my_pattern, value_text)
where \d means a digit symbol (same as [0-9]). The r leading the string means the backslaches in the string are not treated as escaper.
The search function returns a match object.
I suggest you walk through some tutorials first to get rid of further confusions. The official HOWTO is already well written:
https://docs.python.org/3.6/howto/regex.html