I am looking for generating alpha numeric series of 3 digits as below:
0A0 to 9Z9
i.e. 0A0, 0A1,... 0A9, 0B0.... 9Z9
Is there any way in excel to generate the above sequence?
I tried many formulas but not able to do with alpha numeric.
You can try, in some cell:
=INT((ROWS($1:1)-1)/260)&CHAR(MOD(INT((ROWS($1:1)-1)/10),26)+65)&MOD(ROWS($1:1)-1,10)
Then fill down to a total of 2600 rows
EDIT: If you want to repeat the sequence after 2600 rows, then try:
=MOD(INT((ROWS($1:1)-1)/260),10)&CHAR(MOD(INT((ROWS($1:1)-1)/10),26)+65)&MOD(ROWS($1:1)-1,10)
It's easy!
You're trying to =CONCATENATE() a series made of random integers and random strings.
a RANDOM INTEGER from 0 to 9 --------------- =RANDBETWEEN(0;9)
a RANDOM CHARACTER from A to Z --------- =CHAR(RANDBETWEEN(65;90)) ¹
a RANDOM INTEGER from 0 to 9 --------------- =RANDBETWEEN(0;9)
¹ See more at ASCII Character Map
Final Formula:
=CONCATENATE(RANDBETWEEN(0;9);CHAR(RANDBETWEEN(65;90));RANDBETWEEN(0;9))
So, we used:
=CONCATENATE()
=RANDBETWEEN()
=CHAR()
An ASCII Character Map
Or if you're not interested in random numbers and chars, should be easy to create a column with the necessary numbers to generate a specific sequence.
But.... if you want all combinations possible using these variables, or in numbers, all the 2500 combinations possible, you should create a macro. I mean... it's doable using formulas, but is way easier to accomplish this using vba.
Related
I have an array that looks like this
11100100110
essentially, an array of fixed size with each item being a 1 or 0 with the last item always equal to 0.
Consider each set of consecutive 1's to be a "bucket". I'd like a formula to determine the size of each bucket. So the output of this formula for the above sequence should be
312
as an array. Ideally this works in both excel and google sheets.
If you are interested this is the result of a list of stars and bars configurations where the 0's in my sequence represent bars and the 1's represent stars (the final value is a dummy 0 to make things easier to work with). I want the size of each non-empty bucket in a given configuration of stars and bars.
Thanks, in advance.
You could also use the standard method with Frequency which will work with Excel 365 and GS:
=FILTER(FREQUENCY(IF(A1:A11=1,ROW(A1:A11)),IF(A1:A11=0,ROW(A1:A11))),FREQUENCY(IF(A1:A11=1,ROW(A1:A11)),IF(A1:A11=0,ROW(A1:A11))))
try:
=INDEX((JOIN(, LEN(SPLIT(A1, 0)))))
update:
=INDEX(IFERROR(1/(1/SUBSTITUTE(FLATTEN(QUERY(TRANSPOSE(IFERROR(1/(1/
LEN(SPLIT(SUBSTITUTE(FLATTEN(QUERY(
TRANSPOSE(A1:K),, 9^9)), " ", ), 0))))),, 9^9)), " ", ))))
Assuming A2:A9 contains the data,
=ARRAYFORMULA(QUERY(FREQUENCY(IF(A2:A9,ROW(A2:A9)),IF(NOT(A2:A9),ROW(A2:A9))),"where Col1>0",))
FREQUENCY(data,classes) to get the frequency of data in classes
Make sequence of row numbers as data, if 1
Make sequence of row numbers as classes, if not 1
QUERY to get rid of zeros
I need to split(like divide) by 5, however each value should balance maximum possible way to each part
Example
6= 3,3 is ok. but 6= 5,1 is wrong
18= 5,5,4,4 is ok. but 18= 5,5,5,3 is wrong
21= 5,4,4,4,4 is ok. but 21= 5,5,5,5,1 is wrong
The underlying math for this is as follows. Number have to split will be split into repeats of two numbers. The smaller number is given by
=QUOTIENT(NUMBER_HAVE_TO_SPLIT,SPLIT_BY_PARTS)
and the larger number is given by
=QUOTIENT(NUMBER_HAVE_TO_SPLIT,SPLIT_BY_PARTS)+1
FYI the QUOTIENT worksheet function does integer division, e.g, QUOTIENT(13,4)=3.
The number of times the larger number is repeated is given by:
=MOD(NUMBER_HAVE_TO_SPLIT,SPLIT_BY_PARTS)
and the number of times the smaller number is repeated is given by:
=SPLIT_BY_PARTS - MOD(NUMBER_HAVE_TO_SPLIT,SPLIT_BY_PARTS)
The remaining task is to return the results in the formats you suggest. To get the comma-delimited format 3,4,4:
Convert both smaller number and larger number to text using TEXT(number,0)
Prepend each with a comma to give the strings ,3 and ,4
Use the REPT function to repeat each the appropriate number of times to give ,3 and ,4,4
Concatenate these two strings and use SUBSTITUTE to remove the first comma
A somewhat messy formula to accomplish the above is:
=SUBSTITUTE(REPT(","&TEXT(QUOTIENT(A2,B2),"0"),B2-MOD(A2,B2))&REPT(","&TEXT(QUOTIENT(A2,B2)+1,"0"),MOD(A2,B2)),",","",1)
where NUMBER_HAVE_TO_SPLIT and SPLIT_BY_PARTS are in A2 and B2, respectively.
A formula to generate the 3=1 and 4=2 format is
=TEXT(QUOTIENT(A2,B2),0)&"="&TEXT(B2-MOD(A2,B2),"0")&IF(MOD(A2,B2)>0," and "&TEXT(QUOTIENT(A2,B2)+1,0)&"="&TEXT(MOD(A2,B2),"0"),"")
I have a series of values such as:
10RP
2.5R
5R
7.5R
10R
2.5YR
5YR
I want to convert the string portion to a number based on this table:
0 R
10 YR
20 Y
30 GY
40 G
50 BG
60 B
70 PB
80 P
90 RP
I then want to create two columns so that:
2.5YR
becomes:
2.5 10
In a third column I will add the two numbers together.
Can this be done just using formulas? I want to avoid using VBA if I can.
Thanks.
Here's another approach.
seq is a defined name referring to an array constant ={1,2,3,4,5}
If you might have numbers that encompass more than five characters, just extend the constant appropriately.
Number part: =LOOKUP(9E+307,--MID(A1,1,seq))
Letter portion converted to number:
=VLOOKUP(MID(A1,LOOKUP(2,1/ISNUMBER(-MID(A1,1,seq)),seq)+1,9),$F$1:$G$10,2,FALSE)
Where your table is in F1:G10 and reversed so that the letters are in the first column
This might not be the most efficient but should work
=IFERROR((LEFT(F3,LEN(F3)-2)+VLOOKUP(RIGHT(F3,2),$A$3:$B$12,2,0)),
(LEFT(F3,LEN(F3)-1)+VLOOKUP(RIGHT(F3,1),$A$3:$B$12,2,0)))
Where your lookup table is A3:B12 with the letters in the left-most column
Check for the two-letter combinations before the single-letter ones.
In excel I am using the left,mid and Right functions to pull the 'suffix' of a string.
Example:
1234-1234567-1234
The prefix is 4 digits long
The Base is 7 or 8 digits long
and the Suffix is either 3 or 4 digits long.
I have the right formula as: =RIGHT(A6,LEN(A6)-FIND("-",A6)-8) to handle the varying lengths of the suffix
I need the MID formula that pulls the base section that can handle the varying lengths of the base and suffix.
Given
The prefix is 4 digits long The Base is 7 or 8 digits long....
then you can use this formula
=MID(A1,6,8-ISERR(MID(A1,13,1)+0))
Please try:
=MID(A1,1+FIND("-",A1),FIND("-",MID(A1,1+FIND("-",A1),9))-1)
(just for the part between the hyphens).
But Text to Columns with - as delimiter might be more convenient.
You could try:
=MID(A1,6,FIND("-",A1,6)-FIND("-",A1,1)-1)
I have an Excel spreadsheet with over 2000 entries:
Field B1: CustomerID as 000012345
Field B2: CustomerID as 0000432
Field C1: CustomerCountry as DE
Field C2: CustomerCountry as IT
I need to build codes 13 digits long including "CustomerCountry" + "CustomerID" without leading 0 + random number (can be 6 digits, more or less, depends in length of CustomerID).
The results should be like this: D1 Code as DE12345967895 or D2 Code as IT43274837401
How to do it with Excel functions?
UPDATED:
I tried this one. My big problem is to say that random number should be long enough to get 13 characters in all. Sometimes CustomerID is just 3 or 4 digits long, and concatenation of three variables can be just 10 or 9 characters. But codes have to be always 13 characters long.
Use & to concatenate strings.
Use VALUE(CustomerID) to trim the leading zeroes from the ID
Use RAND() to add a random number between 0 and 1 or RANDBETWEEN(x,y) to create one between x and y.
Combine the above and there you are!
If you always want 13 digits you can use LEFT(INT(RAND()*10^13);(13-LEN(CustomerCountry)-LEN(VALUE(CustomerID)))) for the random number to ALWAYS be the right length.
total formula
= CustomerCountry
& VALUE(CustomerID)
& LEFT(INT(RAND()*10^13);(13-LEN(CustomerCountry)-LEN(VALUE(CustomerID))))
=C1 & TEXT(B1,"0") & RIGHT(TEXT(RANDBETWEEN(0,99999999999),"00000000000"),11 - LEN(TEXT(B1,"0")))
that should do it
I don’t understand what is where and OP has accepted answer so have not bothered testing:
=LEFT(RIGHT(C1,2)&VALUE(MID(B1,15,13))&RANDBETWEEN(10^9,10^10),13)
(but I might revert to this if no one else picks the flaws in it first!)