I’m wondering if someone can tell me how to count the number of duplicates that occur between 2 rows in excel? I’ve read lots of posts about counting duplicates in general, but it’s not quite what I’m looking for.
In the below example, I want to indicate how many numbers are repeated from the previous row. For example, Row 1 has 3 numbers repeating from Row 2. Row 2 has 1 number repeating from Row 3. Row 3 has 2 numbers repeating from Row 4. I don’t need to know what numbers or how many times each number was repeated, I just need to know how many occurrences of duplicates there are. Each number would be in its own cell. Is this even possible?
Row 1> 20 22 40 41 42 47
Row 2> 3 37 40 41 47 49
Row 3> 1 2 3 4 5 6
Row 4> 2 5 17 20 25 30
Use COUNTIF() wrapped in a SUM() as an array formula:
=SUM(COUNTIF(A2:F2,A1:F1))
Being an array formula it needs to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode. If done correctly Excel will put {} around the formula.
Put the formula in the first desired output cell, Hit Ctrl-Shift-Enter. Then copy down.
Related
I need to calculate a column having many cells but I want to not calculate particular cells on condition. For example:
Scenario:
Sr No Marks
1 46
2 33
3 44
4 32
5 11
6 99
7 27
8 98
I want to get the sum of marks but only those cells should be added whom marks are more than 50. What formula should use?
We can use SUMIF here:
=SUMIF(B2:B9, ">50")
This assumes that your Marks column is in column B, and that the first data point is on the second row.
Edit:
If you want to take the average value of marks, where the mark is over 50, then we can also use COUNTIF:
=SUMIF(B2:B9, ">50") / COUNTIF(B2:B9, ">50")
I am using Hlookup to find in a row where the value is "A", and then subsequently take a binary value in the same column and use this as the selected cells value.
I am only using the formula bar for this part. The cells formula is:
"=HLOOKUP("A",A13:Z19,1)"
Row 13: SNPHUATVBKWJZYMQGXFCROEILD (Each character is assigned to an individual cell).
In row 19, each cell is taken up by 5 binary digits, so to keep things tidy I will write the decimal numbers:
10 3 2 20 18 6 24 2 12 21 30 4 6 26 19 22 9 13 5 24 0 31 12 15 24 9
The issue is that, while my formula should return 6, as that is the corresponding value within the same column as the letter "A", it returns 9, which is the first cell on the top right of the search criteria table.
Also worth noting is that if I post in a different cell a similar formula but perhaps change the search criteria to a different character such as "H", then the same error will occur, returning a 9.
Thank you so much in advance!
There are 11 numbers in a column.
5
5
5
5
12
13
5
9
2
5
10
I need to build a formula that tells me how many times occurs the following situation: Number is bigger than each of previous four numbers.
In this case the situation occurs 3 times. By:
12 bigger than 5;5;5;5
13 bigger than 12;5;5;5
10 bigger than 5;2;9;5
Assuming your data starts in A1 you can use if() and max() to do this. Add this to B5 (next to the 12 in your example):
=IF(MAX(A1:A4)<A5, 1, "")
This will put a 1 next to 12. You can copy this formula down to find the other values where this is true.
This works by looking at the MAX() value of the previous 4 values. IF() they are higher than the current value, then it prints a 1.
I am dealing with a large data set in Excel and need to search a for two neighboring cells in the same column. Usually I would just go through this quickly row by row, but there are around 30,000 rows and probably 1% of those are the neighbors I am looking for. The data is organized temporally, meaning I cannot just sort.
Anyone have an idea if/how this can be done?
You could drag down this formula in column next to your data.
For example, in B3 where column A has data:
=IF(AND(A3<>"",A2<>""),"neighbour above","")
So:
Row A B
1 Data Check
2 10
3 20 neighbour above
4
5 40
6 50 neighbour above
7 60 neighbour above
8
9
10 90
Note B2 first position has no formula. This will highlight neighbouring cells within the column.
How many?
To count how many neighbours, use a countif. so in C1 you can have:
=COUNTIF(B:B, "neighbour above")
which will return 3 in this case above. pairs 10 and 20, 40 and 50, 50 and 60.
You can choose other marker text to flag the neighbour, besides "neighbour above". Just put it in the IF statement.
I am currently using the following formula i.e. =IF(COUNTIF($A$1:A2,A2)>4,A2+1,A2) to change the number when I drag this formula downsdie of the rows.
For Example: in this case for every five rows number will change i.e. A1 to A5 it will 1 and A6 to A10 it will be 2 and A11 to A15 it will be 3 etc.
Just wanted to know is it possible to extend the same formula, so along with adding 1 number for every five rows it should also skip 2 numbers for every 60 rows.
For Example: if the 60 row is number 12, then 61st row should be 15 and 120 row will be 26 and 121 row should be 124 etc.
Can someone please help me with this formula?
Thanks for your help in advance.
Number starts at one.
Then get the cell's row number and subtract one. Divide that number by 5 and discard the fractional part (or the remainder). So numbers from 0 to 4 (which are rows 1 through 5) all get an increment of 0, 5 to 9 get 1, and so on. Similar logic with multiples of 60 except that the counting is doubled.
=1 + floor((row()-1)/5, 1) + floor((row()-1)/60, 1) * 2