How can I detect when a thread was ended (in a platform independent way)?
I have to store copies of objects for every thread and I want to know when I can dispose or redistribute it.
It's possibly via RAII and local_thread mechanism. We create a class that do usefull work in destructor.
class ThreadEndNotifer
{
public:
~ThreadEndNotifer()
{
// Do usefull work
useFullWork();
}
}
Next, we create local_thread variable. It can be global or class feild(thread_local class field is implicit static).
class Foo
{
private:
// Remember about initialization like static feild
thread_local ThreadEndNotifer mNotifer;
}
So, the useFullWork will be called every time when any thread are ending.
I like to create one global variable and init it only if needed, in this way I avoid overhead.
With multiple threads, in order to detect any one of them was ended, you need:
A shared condition_variable for notification, a shared mutex to lock, and shared variables for conditions of all threads.
void call_me_at_the_end_of_a_thread(int index_of_thread){
std::unique_lock<std::mutex> l(the_global_mutex);
array_of_bools[index_of_thread] = true;
num_of_dead_threads++; // global integer only for the convenience of checking before wait
std::notify_all_at_thread_exit(the_global_condition_variable, std::move(l));
}
You may use an array of bool or vector<bool> for checking which threads was ended. You may prefer notify_all to notify_all_at_thread_exit if you don't care about the timing of notifying after current thread has finished "completely".
void call_me_to_detect_thread_was_ended(void){
static int copy_of_num_of_dead_threads;
std::unique_lock<std::mutex> l(the_global_mutex);
while(num_of_dead_threads==copy_of_num_of_dead_threads)
the_global_condition_variable.wait(l);
std::cout<<num_of_dead_threads - copy_of_num_of_dead_threads<<" threads finished.\n";
copy_of_num_of_dead_threads=num_of_dead_threads;
}
num_of_dead_threads is only for simplicity. Check the array_of_bools to find out which threads have already finished.
Related
I am using multithreading in my QT program. I need to pass data to the worker object that lives in the worker thread from the main gui thread. I created a setData function in a QObject subclass to pass all the necessary data from the main gui thread. However I verified the function is called from the main thread by looking at QThread::currentThreadId() in the setData function. Even though the worker object function is called from the main thread does this ensure that the worker thread still has its own copy of the data as is required for a reentrant class? Keep in mind this is happening before the worker thread is started.
Also if basic data types are used in a class without dynamic memory and no static global variables is that class reentrant as long as all of its other member data is reentrant? (it's got reentrant data members like qstrings, qlists etc in addition the the basic ints bools etc)
Thanks for the help
Edited new content:
My main question was simply is it appropriate to call a QObject subclass method living in another thread from the main gui thread in order to pass my data to the worker thread to be worked on (in my case custom classes containing backup job information for long-pending file scans and copies for data backup). The data pass all happens before the thread is started so there's no danger of both threads modifying the data at once (I think but I'm no multithreading expert...) It sounds like the way to do this from your post is to use a signal from the main thread to a slot in the worker thread to pass the data. I have confirmed my data backup jobs are reentrant so all I need to do is assure that the worker thread works on its own instances of these classes. Also the transfer of data currently done by calling the QObject subclass method is done before the worker thread starts - does this prevent race conditions and is it safe?
Also here under the section "Accessing QObject Subclasses from Other Threads" it looks a little dangerous to use slots in the QObject subclass...
OK here's the code I've been busy recently...
Edited With Code:
void Replicator::advancedAllBackup()
{
updateStatus("<font color = \"green\">Starting All Advanced Backups</font>");
startBackup();
worker = new Worker;
worker->moveToThread(workerThread);
setupWorker(normal);
QList<BackupJob> jobList;
for (int backupCount = 0; backupCount < advancedJobs.size(); backupCount++)
jobList << advancedJobs[backupCount];
worker->setData(jobList);
workerThread->start();
}
The startBackup function sets some booleans and updates the gui.
the setupWorker function connects all signals and slots for the worker thread and worker object.
the setData function sets the worker job list data to that of the backend and is called before the thread starts so there is no concurrency.
Then we start the thread and it does its work.
And here's the worker code:
void setData(QList<BackupJob> jobs) { this->jobs = jobs; }
So my question is: is this safe?
There are some misconceptions in your question.
Reentrancy and multithreading are orthogonal concepts. Single-threaded code can be easily forced to cope with reentrancy - and is as soon as you reenter the event loop (thus you shouldn't).
The question you are asking, with correction, is thus: Are the class's methods thread-safe if the data members support multithreaded access? The answer is yes. But it's a mostly useless answer, because you're mistaken that the data types you use support such access. They most likely don't!
In fact, you're very unlikely to use multithread-safe data types unless you explicitly seek them out. POD types aren't, most of the C++ standard types aren't, most Qt types aren't either. Just so that there are no misunderstandings: a QString is not multithread-safe data type! The following code is has undefined behavior (it'll crash, burn and send an email to your spouse that appears to be from an illicit lover):
QString str{"Foo"};
for (int i = 0; i < 1000; ++i)
QtConcurrent::run([&]{ str.append("bar"); });
The follow up questions could be:
Are my data members supporting multithreaded access? I thought they did.
No, they aren't unless you show code that proves otherwise.
Do I even need to support multithreaded access?
Maybe. But it's much easier to avoid the need for it entirely.
The likely source of your confusion in relation to Qt types is their implicit sharing semantics. Thankfully, their relation to multithreading is rather simple to express:
Any instance of a Qt implicitly shared class can be accessed from any one thread at a given time. Corollary: you need one instance per thread. Copy your object, and use each copy in its own thread - that's perfectly safe. These instances may share data initially, and Qt will make sure that any copy-on-writes are done thread-safely for you.
Sidebar: If you use iterators or internal pointers to data on non-const instances, you must forcibly detach() the object before constructing the iterators/pointers. The problem with iterators is that they become invalidated when an object's data is detached, and detaching can happen in any thread where the instance is non-const - so at least one thread will end up with invalid iterators. I won't talk any more of this, the takeaway is that implicitly shared data types are tricky to implement and use safely. With C++11, there's no need for implicit sharing anymore: they were a workaround for the lack of move semantics in C++98.
What does it mean, then? It means this:
// Unsafe: str1 potentially accessed from two threads at once
QString str1{"foo"};
QtConcurrent::run([&]{ str1.apppend("bar"); });
str1.append("baz");
// Safe: each instance is accessed from one thread only
QString str1{"foo"};
QString str2{str1};
QtConcurrent::run([&]{ str1.apppend("bar"); });
str2.append("baz");
The original code can be fixed thus:
QString str{"Foo"};
for (int i = 0; i < 1000; ++i)
QtConcurrent::run([=]() mutable { str.append("bar"); });
This isn't to say that this code is very useful: the modified data is lost when the functor is destructed within the worker thread. But it serves to illustrate how to deal with Qt value types and multithreading. Here's why it works: copies of str are taken when each instance of the functor is constructed. This functor is then passed to a worker thread to execute, where its copy of the string is appended to. The copy initially shares data with the str instance in the originating thread, but QString will thread-safely duplicate the data. You could write out the functor explicitly to make it clear what happens:
QString str{"Foo"};
struct Functor {
QString str;
Functor(const QString & str) : str{str} {}
void operator()() {
str.append("bar");
}
};
for (int i = 0; i < 1000; ++i)
QtConcurrent::run(Functor(str));
How do we deal with passing data using Qt types in and out of a worker object? All communication with the object, when it is in the worker thread, must be done via signals/slots. Qt will automatically copy the data for us in a thread-safe manner so that each instance of a value is ever only accessed in one thread only. E.g.:
class ImageSource : public QObject {
QImage render() {
QImage image{...};
QPainter p{image};
...
return image;
}
public:
Q_SIGNAL newImage(const QImage & image);
void makeImage() {
QtConcurrent::run([this]{
emit newImage(render());
});
}
};
int main(int argc, char ** argv) {
QApplication app...;
ImageSource source;
QLabel label;
label.show();
connect(source, &ImageSource::newImage, &label, [&](const QImage & img){
label.setPixmap(QPixmap::fromImage(img));
});
source.makeImage();
return app.exec();
}
The connection between the source's signal and the label's thread context is automatic. The signal happens to be emitted in a worker thread in the default thread pool. At the time of signal emission, the source and target threads are compared, and if different, the functor will be wrapped in an event, the event posted the label, and the label's QObject::event will run the functor that sets the pixmap. This is all thread-safe and leverages Qt to make it almost effortless. The target thread context &label is critically important: without it, the functor would run in the worker thread, not the UI thread.
Note that we didn't even have to move the object to a worker thread: in fact, moving a QObject to a worker thread should be avoided unless the object does need to react to events and does more than merely generate a piece of data. You'd typically want to move e.g. objects that deal with communications, or complex application controllers that are abstracted from their UI. Mere generation of data can be usually done using QtConcurrent::run using a signal to abstract away the thread-safety magic of extracting the data from the worker thread to another thread.
In order to use Qt's mechanisms for passing data between threads with queues, you cannot call the object's function directly. You need to either use the signal/slot mechanism, or you can use the QMetaObject::invokeMethod call:
QMetaObject::invokeMethod(myObject, "mySlotFunction",
Qt::QueuedConnection,
Q_ARG(int, 42));
This will only work if both the sending and receiving objects have event queues running - i.e. a main or QThread based thread.
For the other part of your question, see the Qt docs section on reentrancy:
http://doc.qt.io/qt-4.8/threads-reentrancy.html#reentrant
Many Qt classes are reentrant, but they are not made thread-safe,
because making them thread-safe would incur the extra overhead of
repeatedly locking and unlocking a QMutex. For example, QString is
reentrant but not thread-safe. You can safely access different
instances of QString from multiple threads simultaneously, but you
can't safely access the same instance of QString from multiple threads
simultaneously (unless you protect the accesses yourself with a
QMutex).
I want to create a thread-safe singleton using only MFC. I prefer to avoid boost::thread, and I can't use std::thread on VS2010.
Also, VS 2010 has C++11 limitations (if not, it would be much easier since I think it supports thread-safe static variable initialization).
So far, I have tried this solution but I'm not sure how thread-safe it is.
From my understanding, a problem would be that the static CCriticalSection was initialized after the singleton instance is created and some trouble would appear if two threads get an instance and generate two singleton objects.
In my case there will be only two threads running simultaneously, one main thread and one worker thread. The main thread will get the first instance, and the worker threads will get instances from time to time afterwards.
In this scenario, is this class thread-safe enough? Am I missing something?
In case that there's no way to do a thread-safe enough singleton class with MFC only I'll consider boost. Any advice or suggestion is highly appreciated.
// Singleton.h
class CSingleton
{
static CCriticalSection m_cs;
public:
static CSingleton& GetInstance()
{
m_cs.Lock();
static CSingleton instance;
m_cs.Unlock();
return instance;
}
virtual ~CSingleton(){};
private:
CSingleton(){}; // Constructor
CSingleton( CSingleton const& ); // Don't Implement
void operator=( CSingleton const& );
}
// Singleton.cpp
// Initialize Critical Section
CCriticalSection CSingleton::m_cs;
I have a multithreaded app that has to read some data often, and occasionally that data is updated. I have problems with writing by using unique_lock and problems with reading by using upgrade_lock
There is examples of my problems:
void unlock(){
test.stream = 0;
test.mtx.unlock();
}
void lock_mtx(int i){
boost::unique_lock<boost::shared_mutex> lock(test.mtx);
test.stream = i;
boost::this_thread::sleep_for(boost::chrono::milliseconds(10000));
unlock();
boost::this_thread::sleep_for(boost::chrono::milliseconds(1000));
}
When I destruct lock , mutex is already unlocked by this thread, and sometimes it is locked by another thread, but destructor make it free again. After destruction of lock (in the first thread) third thread take mutex and I have two writers at the one moment
void lock_mtx(int i){
boost::upgrade_lock<boost::shared_mutex> lock(test.mtx);
read_from_locked();
boost::this_thread::sleep_for(boost::chrono::milliseconds(5000));
boost::upgrade_to_unique_lock<boost::shared_mutex> uniqueLock(lock);
write_to_locked();
boost::this_thread::sleep_for(boost::chrono::milliseconds(10000));
}
The second problem, is that when some thread takes upgrade_lock, other threads can't read shared objects
Both of problems occur in MS VisualStudio 2013 and Windows8 x64
void lock_mtx(int i)
{
{
boost::unique_lock<boost::shared_mutex> lock(test.mtx);
test.stream = i;
boost::this_thread::sleep_for(boost::chrono::milliseconds(10000));
}
boost::this_thread::sleep_for(boost::chrono::milliseconds(1000));
}
The purpose of unique_lock and lock_guard is to automatically unlock the mutex when it goes out of scope. This pattern is known as RAII.
Rule of thumb: Never manually call lock()/unlock() on your (Basic|Shared)Lockable objects. It's an antipattern because
It's extremely hard to get right (think of exception safety)
It usually indicates a code smell (locks being held across different method calls). If you even need this, consider making the RAII lock guard (lock_guard or unique_lock) a member of the containing class, or return the unique_lock so the caller has the option to explicitly adopt the lock, or to just let it be automatically released by the guard.
If a mutex is defined within a function, does its lock apply to functions called from that function? ie
void f () {
Mutex mutex;
g();
}
Does the lock still apply to any data modifications in g()?
Also, am I right to say that a lock defined in a class method will only apply to specific instances of that class? Meaning:
Class Foo;
Foo foo1, foo2;
(In thread 1) foo1.bar();
(In thread 2) foo2.bar();
Would each call be able to occur concurrently?
It would be a nice bonus if someone could explain / point out links that explain the mechanism behind mutexes. Thanks! I am currently working with the Qt Thread library, if that information helps.
In your example you don't actually lock the mutex, so it will not prevent different threads to access the function at the same time. Also you declare the mutex locally inside the function, so that each function call uses a different local mutex object. Even if this mutex would be locked, each function call would lock a different mutex object, not preventing simultaneous access.
A better strategy would be a setup like this:
class A {
QMutex mutex;
void f() {
QMutexLocker ml(mutex); // Acquire a lock on mutex
g();
// The lock on the mutex will be released when ml is destroyed.
// This happens at the end of this function.
}
// ...
};
In this case mutex is locked as long as ml exists, so also during the time the thread spends inside g(). If another thread would call f() during this time it would block in the creation of its ml object until the first thread left the function and the new thread can get the lock on mutex.
A mutex is something you grab, and will stop any other threads trying to grab it until you release it from the grabbing thread.
In your question, you have a function f allocating a Mutex instance. That is not enough to lock it. You have to specifically call mutex.lock() (in Qt, but also in general, unless you use pthread, in that case use pthread_mutex_lock and have fun with low level, platform dependent stuff. Qt abstracts it very well).
here is an example with Qt
void MyClass::doStuff( int c )
{
mutex.lock();
a = c;
b = c * 2;
mutex.unlock();
}
Once you get the lock, the call to g() will be done from the thread who got the lock, so it will be alone in that call assuming that you are not calling g() from other threads from another part of the code. Locking does not mean that it will stop all the other threads. It will stop threads trying to get the same lock, until the lock is released.
If that is the only way for your threads to reach g(), then you are synchronized on that access.
For the second part of your question, If the mutex is an instance attribute, then they will be two different mutexes. You will have to declare and instantiate a class mutex instance and refer to it foro your locking. In that case, any attempt to call a method in the class that locks the class mutex will be effectively synchronized, meaning that no two threads will execute that method together.
For example (I don't have Qt, so I cannot compile this code, and I stopped coding with it 2 years ago, so it could not work)
class Foo {
public:
void method(void) {
mutex.lock();
cout << "method called";
// long computation
mutex.unlock();
}
private:
QMutex mutex;
};
Ok, in this case, suppose you have two threads, 1 and 2, and two instances of the class Foo, a and b. Suppose that thread 1 calls a.method() and thread 2 calls b.method(). In this case, the two mutexes are different instances, so each thread will execute the call, independently, and run in parallel.
Suppose you have two threads, 1 and 2, and one instance of the class Foo which is shared between the two threads. if thread 1 calls a.method() and then thread 2 calls a.method(), thread 2 will stop and wait until the mutex lock is released.
Finally,
class Foo {
public:
void method(void) {
mutex.lock();
cout << "method called";
// long computation
mutex.unlock();
}
private:
static QMutex mutex;
};
QMutex Foo::mutex;
In this case, the mutex is a class static variable. You have only one instance of the mutex for each object instance. Suppose you had the same situation as the first case above: two threads, and two instances. In this case, when the second thread tries to call b.method() it will have to wait for a.method() to be completed by the first thread, as the lock is now unique and shared among all instances of your class.
For more info, Qt has a nice tutorial on multithreading
https://doc.qt.io/qt-5/threads.html
Your mutex is instatiated locally, on the stack. So a call to f() from one thread will be lock its own instance of the mutex. Any other call to f() from another thread will lock its own. So a race condition could occur with data accessed from g() ! Even tough you call it on the same class instance:
MyClass foo;
(In thread 1) foo->f();
(In thread 2) foo->f();
How to better handle lock depends on what you want to do. According to what you told I guess a better policy would be to modify g() implementation directly: it must lock a mutex declared as global for instance, or as being static in g() to be shared among any call to g(). As long as I understand you want to lock your data globally?
A mutex is a programming concept that is frequently used to solve multi-threading problems. My question to the community:
What is a mutex and how do you use it?
When I am having a big heated discussion at work, I use a rubber chicken which I keep in my desk for just such occasions. The person holding the chicken is the only person who is allowed to talk. If you don't hold the chicken you cannot speak. You can only indicate that you want the chicken and wait until you get it before you speak. Once you have finished speaking, you can hand the chicken back to the moderator who will hand it to the next person to speak. This ensures that people do not speak over each other, and also have their own space to talk.
Replace Chicken with Mutex and person with thread and you basically have the concept of a mutex.
Of course, there is no such thing as a rubber mutex. Only rubber chicken. My cats once had a rubber mouse, but they ate it.
Of course, before you use the rubber chicken, you need to ask yourself whether you actually need 5 people in one room and would it not just be easier with one person in the room on their own doing all the work. Actually, this is just extending the analogy, but you get the idea.
A Mutex is a Mutually exclusive flag. It acts as a gate keeper to a section of code allowing one thread in and blocking access to all others. This ensures that the code being controlled will only be hit by a single thread at a time. Just be sure to release the mutex when you are done. :)
Mutual Exclusion. Here's the Wikipedia entry on it.
The point of a mutex is to synchronize two threads. When you have two threads attempting to access a single resource, the general pattern is to have the first block of code attempting access to set the mutex before entering the code. When the second code block attempts access, it sees that the mutex is set and waits until the first block of code is complete (and unsets the mutex), then continues.
Specific details of how this is accomplished obviously varies greatly by programming language.
When you have a multi-threaded application, the different threads sometimes share a common resource, such as a variable or similar. This shared source often cannot be accessed at the same time, so a construct is needed to ensure that only one thread is using that resource at a time.
The concept is called "mutual exclusion" (short Mutex), and is a way to ensure that only one thread is allowed inside that area, using that resource etc.
How to use them is language specific, but is often (if not always) based on a operating system mutex.
Some languages doesn't need this construct, due to the paradigm, for example functional programming (Haskell, ML are good examples).
What is a Mutex?
The mutex (In fact, the term mutex is short for mutual exclusion) also known as spinlock is the simplest synchronization tool that is used to protect critical regions and thus prevent race conditions. That is a thread must acquire a lock before entering into a critical section (In critical section multi threads share a common variable, updating a table, writing a file and so on), it releases the lock when it leaves critical section.
What is a Race Condition?
A race condition occurs when two or more threads can access shared data and they try to change it at the same time. Because the thread scheduling algorithm can swap between threads at any time, you don't know the order in which the threads will attempt to access the shared data. Therefore, the result of the change in data is dependent on the thread scheduling algorithm, i.e. both threads are "racing" to access/change the data.
Real life example:
When I am having a big heated discussion at work, I use a rubber
chicken which I keep in my desk for just such occasions. The person
holding the chicken is the only person who is allowed to talk. If you
don't hold the chicken you cannot speak. You can only indicate that
you want the chicken and wait until you get it before you speak. Once
you have finished speaking, you can hand the chicken back to the
moderator who will hand it to the next person to speak. This ensures
that people do not speak over each other, and also have their own
space to talk.
Replace Chicken with Mutex and person with thread and you basically have the concept of a mutex.
#Xetius
Usage in C#:
This example shows how a local Mutex object is used to synchronize access to a protected resource. Because each calling thread is blocked until it acquires ownership of the mutex, it must call the ReleaseMutex method to release ownership of the thread.
using System;
using System.Threading;
class Example
{
// Create a new Mutex. The creating thread does not own the mutex.
private static Mutex mut = new Mutex();
private const int numIterations = 1;
private const int numThreads = 3;
static void Main()
{
// Create the threads that will use the protected resource.
for(int i = 0; i < numThreads; i++)
{
Thread newThread = new Thread(new ThreadStart(ThreadProc));
newThread.Name = String.Format("Thread{0}", i + 1);
newThread.Start();
}
// The main thread exits, but the application continues to
// run until all foreground threads have exited.
}
private static void ThreadProc()
{
for(int i = 0; i < numIterations; i++)
{
UseResource();
}
}
// This method represents a resource that must be synchronized
// so that only one thread at a time can enter.
private static void UseResource()
{
// Wait until it is safe to enter.
Console.WriteLine("{0} is requesting the mutex",
Thread.CurrentThread.Name);
mut.WaitOne();
Console.WriteLine("{0} has entered the protected area",
Thread.CurrentThread.Name);
// Place code to access non-reentrant resources here.
// Simulate some work.
Thread.Sleep(500);
Console.WriteLine("{0} is leaving the protected area",
Thread.CurrentThread.Name);
// Release the Mutex.
mut.ReleaseMutex();
Console.WriteLine("{0} has released the mutex",
Thread.CurrentThread.Name);
}
}
// The example displays output like the following:
// Thread1 is requesting the mutex
// Thread2 is requesting the mutex
// Thread1 has entered the protected area
// Thread3 is requesting the mutex
// Thread1 is leaving the protected area
// Thread1 has released the mutex
// Thread3 has entered the protected area
// Thread3 is leaving the protected area
// Thread3 has released the mutex
// Thread2 has entered the protected area
// Thread2 is leaving the protected area
// Thread2 has released the mutex
MSDN Reference Mutex
There are some great answers here, here is another great analogy for explaining what mutex is:
Consider single toilet with a key. When someone enters, they take the key and the toilet is occupied. If someone else needs to use the toilet, they need to wait in a queue. When the person in the toilet is done, they pass the key to the next person in queue. Make sense, right?
Convert the toilet in the story to a shared resource, and the key to a mutex. Taking the key to the toilet (acquire a lock) permits you to use it. If there is no key (the lock is locked) you have to wait. When the key is returned by the person (release the lock) you're free to acquire it now.
In C#, the common mutex used is the Monitor. The type is 'System.Threading.Monitor'. It may also be used implicitly via the 'lock(Object)' statement. One example of its use is when constructing a Singleton class.
private static readonly Object instanceLock = new Object();
private static MySingleton instance;
public static MySingleton Instance
{
lock(instanceLock)
{
if(instance == null)
{
instance = new MySingleton();
}
return instance;
}
}
The lock statement using the private lock object creates a critical section. Requiring each thread to wait until the previous is finished. The first thread will enter the section and initialize the instance. The second thread will wait, get into the section, and get the initialized instance.
Any sort of synchronization of a static member may use the lock statement similarly.
To understand MUTEX at first you need to know what is "race condition" and then only you will understand why MUTEX is needed. Suppose you have a multi-threading program and you have two threads. Now, you have one job in the job queue. The first thread will check the job queue and after finding the job it will start executing it. The second thread will also check the job queue and find that there is one job in the queue. So, it will also assign the same job pointer. So, now what happens, both the threads are executing the same job. This will cause a segmentation fault. This is the example of a race condition.
The solution to this problem is MUTEX. MUTEX is a kind of lock which locks one thread at a time. If another thread wants to lock it, the thread simply gets blocked.
The MUTEX topic in this pdf file link is really worth reading.
Mutexes are useful in situations where you need to enforce exclusive access to a resource accross multiple processes, where a regular lock won't help since it only works accross threads.
Mutex: Mutex stands for Mutual Exclusion. It means only one process/thread can enter into critical section at a given time. In concurrent programming multiple threads/process updating the shared resource (any variable, shared memory etc.) may lead to some unexpected result. ( As the result depends upon the which thread/process gets the first access).
In order to avoid such an unexpected result we need some synchronization mechanism, which ensures that only one thread/process gets access to such a resource at a time.
pthread library provides support for Mutex.
typedef union
{
struct __pthread_mutex_s
{
***int __lock;***
unsigned int __count;
int __owner;
#ifdef __x86_64__
unsigned int __nusers;
#endif
int __kind;
#ifdef __x86_64__
short __spins;
short __elision;
__pthread_list_t __list;
# define __PTHREAD_MUTEX_HAVE_PREV 1
# define __PTHREAD_SPINS 0, 0
#else
unsigned int __nusers;
__extension__ union
{
struct
{
short __espins;
short __elision;
# define __spins __elision_data.__espins
# define __elision __elision_data.__elision
# define __PTHREAD_SPINS { 0, 0 }
} __elision_data;
__pthread_slist_t __list;
};
#endif
This is the structure for mutex data type i.e pthread_mutex_t.
When mutex is locked, __lock set to 1. When it is unlocked __lock set to 0.
This ensure that no two processes/threads can access the critical section at same time.