I am trying to renumber the lines 2,$ in a file using vim a command, I know the command cat -n of nl, I can number the lines, but I didn't get the expected output:
I tried this :2,$s/^\([^,]\)// | 2,$!cat -n
input:
#,Name,Types,Total,HP,Attack,Weaknesses,Strength
493,Arceus,Normal,720,120,120,Fighting,strong
483,Dialga,Steel;Dragon,680,100,120,Fighting;Ground,strong
250,Ho-oh,Fire;Flying,680,106,130,Electric;Water;Rock,strong
.... moer 100 lines
expected output:
#,Name,Types,Total,HP,Attack,Weaknesses,Strength
1,Arceus,Normal,720,120,120,Fighting,strong
2,Dialga,Steel;Dragon,680,100,120,Fighting;Ground,strong
3,Ho-oh,Fire;Flying,680,106,130,Electric;Water;Rock,strong
....
You can use \= to use a sub-replace-expression, and line('.') to get the current line number:
" The parenthesis around `line('.')-1` are not needed, but it seems clearer to me
:2,$s/^/\=(line('.')-1).','/
Edit: just realized you're actually replacing your first column, so you might actually want
:2,$s/^\d\+/\=line('.')-1/
I have a file called test, I open it using vi as such:
vi test
Now I want to insert a line through a shell command, for simplicity I use a printf:
:r! printf %s hello
However the line that is entered is
tests
i.e. the name of the file with a s appended.
If I enter the same command in terminal directly, it works fine.
What I want to do is ultimately be able to encode a string in base64 and enter it on the same line as where my cursor is in vi, so that I won't have to copy the string in a separate terminal, encode it, and copy it back into vi. How can I do this? What am I doing wrong?
The first stage of processing a command line in vim is expanding it. % is expanded to the name of the current file — test in your case. %s is expanded to tests.
To avoid expanding protect the special character with a backslash:
:r! printf \%s hello
I want to create a new file using vi editor from command line and add a string to it multiple times say 100. Using vi -S command.script file.txt is supposed to do the trick where a new file file.txt will be created and the commands given in command.script file can write to this file. My command.script contains
:%100a hello world
:wq
But its's not working, what I am doing wrong?
If you interactively execute :%100a hello world in a Vim session, you'll get E488: Trailing characters. Looking up :help :a:
:{range}a[ppend][!] Insert several lines of text below the specified
line. If the {range} is missing, the text will be
inserted after the current line. [...]
These two commands will keep on asking for lines, until you type a line
containing only a ".".
tells you that the text has to be put in following lines (and concluded by a line with only a . character).
Or did you mean to use the normal mode a command? (That one takes a [count] to multiply; your %100 range is wrong, too!)
You can also use the low-level function append(), repeating the string with repeat().
summary
$append
hello world
[...]
hello world
.
execute "$normal! 100ahello world\<CR>"
" Easier with o instead of a:
$normal! 100ohello world
call append('$', repeat(['hello world'], 100))
non-Vim alternatives
But honestly, if that is your real use case (and not just a simplified toy example), you don't need Vim at all for this. Here's one example for the Bash shell:
$ for i in $(seq 100); do echo "hello world" >> file.txt; done
What is the special character which indicate first ?
if we do
$ vi .bashrc
$ source !$
this !$ will replaced by .bashrc
because ! means previous line(am I correct?), $ means last word (for sure)
then what is first?
I want to insert some string in every line in vi editor using
:%s/find-key-word/replaced-keyword/g
in here, if I put
:%s/$/example/g
in vi editor, it will append in all lines with example.
I want to insert all in front of all string every line.
I know I can use visual block (ctrl+v) and select all front lines and insert (shift+i) insert some word and escape(esc) will do the same... but I want to do in one shot..
please let me know how to do..
Thanks in advance
There are two questions, so you are getting two kinds of answers :)
The bash command history has only a passing similarity to the vi regular expression syntax.
^ is the beginning of line in vi. $ is the end of line in vi.
!!:0 is one way of accessing the first word of the previous command in bash
!$ is one way of accessing the last word of the previous command in bash
To indicate beginning of line, the symbol used is:
^
See an example:
$ cat a
hello!
this is me
testing some
stuff
$ sed 's/^/XXX/' a
XXXhello!
XXXthis is me
XXXtesting some
XXXstuff
The character you are looking for is ^.
For example, :%s/^/example/g will prepend all lines with the string example.
In bash, !^ refers to the first argument of the previous command, and !$ the last argument.
I got a file that looks like this:
G:\some_folder
file1.avi
file2.wav
E:\some_folder2
fileABC.avi
fileDEF.wav
I would like to transfer the file into:
G:\some_folder
G:\some_folder file1.avi
G:\some_folder file2.wav
E:\some_folder2
E:\some_folder2 fileABC.avi
E:\some_folder2 fileDEF.wav
So in other words this might work like this:
look for ^[A-Z]: copy whole line and add it at the beginning to next lines till you find ^[A-Z]:
is it possible to do that in VIM? If yes, how.
thank you
Radek
I would iterate over all lines with :global; Vim will position the cursor on the beginning of each line. Depending on which kind of line it is, I'd either yank the folder path, or paste it in front:
:%g/^/execute 'normal!' getline('.') =~ '^\S' ? 'y$' : 'P'