In Excel, I have these kind of fields (in the second and the third column):
Fecha/Hora inicio Fecha/Hora finalización
02/01/2017 21:32 03/01/2017 6:02
02/01/2017 6:02 03/01/2017 7:32
03/01/2017 7:38 04/01/2017 13:47
I want to know the time difference between the first and the second field in hours. For instance, in the second case, the difference is 25.5 hours.
I was trying to calculate it manually but I'm sure there is an automatic way.
VBA has a function called DateDiff which measures the difference between two dates in terms of a specified unit (anything from years to seconds). For this case, we will need to measure in minutes because we want to measure fractions of an hour and then divide by 60 to get back to hours. If we only wanted whole hours then we could measure in hours instead.
The following should provide the required result:
MsgBox DateDiff("n", "02/01/2017 6:02", "03/01/2017 7:32") / 60
"n" is the interval specifier for minutes in the DateDiff function
Related
I am attempting to find any gaps calculated in minutes between a start and stop date/time range. Essentially time when there are no appointments in the schedule, this is a 24hr service and I am looking for "dead" time when there isn't a customer in the office.
Currently I was attempting to use the =SUMPRODUCT((A2<B$2:B$19)*(B2>A$2:A$19))>1 to find overlaps and the issue I am running into is if there are any overlap in start or stop it disqualifies and does not truly identify the space between appointments just if that appointment is double booked at all.
Here is a new version of the Gap and Island solution to this problem, using Excel 365 functionality:
=LET(start,A2:A19,
end,B2:B19,
row,SEQUENCE(ROWS(start)),
maxSoFar,SCAN(0,row,LAMBDA(a,c,IF(c=1,INDEX(start,1),IF(INDEX(end,c-1)>a,INDEX(end,c-1),a)))),
SUM(IF(start>maxSoFar,start-maxSoFar,0)))
The algorithm is very simple:
- Sort data by start time if necessary, then for each pair of times:
- Record the latest finish time so far (maxSoFar) (not including the present appointment)
- If the start time (start) is greater than maxSoFar, add start-maxSoFar to the total.
The first time interval is a special case - initialise maxSoFar to the first start time.
It can be seen that there are only two gaps in the appointments, from 4:15 to 7:31 (3 hours 16 minutes) and from 11:48 to 14:17 (3 hours 29 minutes) totalling 5 hours 45 minutes.
Why didn't I just use Max to make the code shorter? I don't know:
=LET(start,A2:A19,
end,B2:B19,
row,SEQUENCE(ROWS(start)),
maxSoFar,SCAN(0,row,LAMBDA(a,c,IF(c=1,INDEX(start,1),MAX(INDEX(end,c-1),a)))),
SUM(IF(start>maxSoFar,start-maxSoFar,0)))
To find the gaps between appointments in a schedule, you can try using the following formula:
=SUM(B2:B19)-SUMPRODUCT((A2<B$2:B$19)*(B2>A$2:A$19))
You can then convert the duration to minutes by multiplying the result by 1440 (the number of minutes in a day).
=1440*(SUM(B2:B19)-SUMPRODUCT((A2<B$2:B$19)*(B2>A$2:A$19)))
Let's say i logged in today 9:00 AM and end up 5:00 PM i have to produce 4000 items i know it will exceed the time because my software will stop working at 5 PM so tomorrow when i start working again what would be date and time of completion work
What i did
bring working hour =SUM(B2-A2)
total complete work=ROUND(D2/C2, 2)
If i understood correctly you can use the simple difference of times and correct formatting for the time cells to get the remaining hours
The Formula in cell C5 is simple =C1-C3
The formatting applied to the cells is as below
10.95 hours is equal to 10 hours and 57 (95% of 60) minutes
You can write 10:57:00 instead of 10.95
To convert the time to again a number you can divide the time by 0.041666667 and set the format to general
I have a date with hours and minutes like 2/3/2019 10:30 am , and I do the following to find the diffence in hours which I already formatted like ( h )
=now() - date
I want to check if the difference is more than 12 ( where I mean 12 hours) to do something.
if(actual difference>12; "hello"; "bye")
But is not checking the actual difference but the serial difference
How can I check the actual difference in hours?
Dates are stored as numbers where the integer part is the number of days since 1899-12-31. The fractional part measures the time within a day. So, 24 * (now() - date) will give you the number of hours elapsed.
NB: the formatting is only a question of display and won't influence what's done by the formulas.
In order to check conditionaly the difference in the hours unit between two times we can do if(hour(actual difference)>12; "hello"; "bye")
We put the function hour() as noted in
https://support.office.com/en-us/article/calculate-the-difference-between-two-times-e1c78778-749b-49a3-b13e-737715505ff6
I am doing some work in Excel and am running into a bit of a problem. The instruments I am working with save the date and the time of the measurements and I can read this data into Excel with the following format:
A B
1 Date: Time:
2 12/11/12 2:36:25
3 12/12/12 1:46:14
What I am looking to do is find the difference in the two date/time stamps in mins so that I can create a decay curve from the data. So In Excel, I am looking to Make this (if the number of mins in this example is wrong I just calculated it by hand quickly):
A B C
1 Date: Time: Time Elapsed (Minutes)
2 12/11/12 2:36:25 -
3 12/12/12 1:46:14 1436.82
I Have looked around for a bit and found several methods for the difference in time but they always assume that the dates are the same. I exaggerated the time between my measurements some but that roll over of days is what is causing me grief. Any suggestions or hints as to how to go about this would be great. Even If I could find the difference between the date and times in hrs or days in a decimal format, I could just multiple by a constant to get my answer. Please note, I do have experience with programming and Excel but please explain in details. I sometimes get lost in steps.
time and date are both stored as numerical, decimal values (floating point actually). Dates are the whole numbers and time is the decimal part (1/24 = 1 hour, 1/24*1/60 is one minute etc...)
Date-time difference is calculated as:
date2-date1
time2-time1
which will give you the answer in days, now multiply by 24 (hours in day) and then by 60 (minutes in hour) and you are there:
time elapsed = ((date2-date1) + (time2-time1)) * 24 * 60
or
C3 = ((A3-A2)+(B3-B2))*24*60
To add a bit more perspective, Excel stores date and times as serial numbers.
Here is a Reference material to read up.
I would suggest you to use the following:
Combine date to it's time and then do the difference. So it will not cause you any issues of next day or anything.
Please refer to the image with calculations. You may leave your total minutes cell as general or number format.
MS EXCEL Article: Calculate the difference between two times
Example as per this article
Neat way to do this is:
=MOD(end-start,1)*24
where start and end are formatted as "09:00" and "17:00"
Midnight shift
If start and end time are on the same day the MOD function does not affect anything. If the end time crosses midnight, and the end is earlier then start (say you start 23PM and finish 1AM, so result is 2 hours), the MOD function flips the sign of the difference.
Note that this formula calculates the difference between two times (actually two dates) as decimal value. If you want to see the result as time, display the result as time (ctrl+shift+2).
https://exceljet.net/formula/time-difference-in-hours-as-decimal-value
get n day between two dates, by using days360 function =days360(dateA,dateB)
find minute with this formula using timeA as reference =(timeB-$timeA+n*"24:00")*1440
voila you get minutes between two time and dates
I think =TEXT(<cellA> - <cellB>; "[h]:mm:ss") is a more concise answer. This way, you can have your column as a datetime.
I I'm have small headache caused today by excel and the way it takes control of everything. I have two time values I need to add together then divide by a value I got charged for that time to work out how much it cost me an hour.
so say I was charged day on for 12:30:00
on day 2 I was charged for 13:20:00
and day 3 I was charged for 20:30:00
In total it cost me £1000
The calculation would be
£1000 / (12:30:00 + 13:20:00 + 20:30:00 = 46:20:00)
I would guess to get the answer I would
1000 / Sum(12:30:00+13:20:00+20:30:00) = price per hour
But it doesn't...
I guess I need some sort of convert function on the time or to divide it by 24 to get hours but I'm stuck
Help would be hugely appreciated!
Excel represents times as fractional days, so your function is actually representing the rate per day.
Assuming your times are in cells A1:A3, you can adjust your function to something like:
1000 / Sum(A1:A3) / 24
which will give you the rate per hour (by my calculations, £21.58/hr).
As others have mentioned, you will need to set the cell to a currency format.
Excel should be performing the calculation correctly, but it is just showing as a time. Format the result cell as "number" instead.
You can use the HOUR and MINUTE functions to get the hour and minute portions of the time values, however as lc mentions, you do need to ensure that the formatting of the cell is set to Number, as it will default to a time.
Assuming you have your hh:mm:ss values running down the page (column A), in the next column put the formula
=(A1-INT(A1))*24
underneath this you can put your formula
= 1000 / SUM(A1:A3)
but don't forget to format it as Number.