How to parse a URL to fetch it's parameters in groovy? - groovy

Question

I am new to groovy scripting and looking on to parse the URL and print it's parameter.
This url is : https://www.google.com/?aaa=111&bbb=222&ccc=33&dd=1484088989_b23f248ac6e5d9a9b47475526bb92ee1
How can i fetch dd parameter from the URL?
I appreciate your help!

Answer 1

You need to add a groovy script.
def groovyUtils = new com.eviware.soapui.support.GroovyUtils( context );
def testCase = context.testCase;
def testStep = testCase.getTestStepByName("NAME_TESTStepRequest");
def endpoint =testStep.getPropertyValue('Endpoint');
log.info endpoint;
def url = new URL(endpoint)
//def url = new URL("https://www.google.com/?aaa=111&bbb=222&ccc=33&dd=1484088989_b23f248ac6e5d9a9b47475526bb92ee1")
// get all query params as list
def queryParams = url.query?.split('&') // safe operator for urls without query params
// transform the params list to a Map spliting
// each query param
def mapParams = queryParams.collectEntries { param -> param.split('=').collect { URLDecoder.decode(it) }}
// assert the expected values
log.info mapParams['aaa']
//assert mapParams['aaa'] == '111'
log.info mapParams['bbb']
//assert mapParams['bbb']== 'abc'
log.info mapParams['dd']
//assert mapParams['dd']=='023423'
Please you check this post.Get query params from request url soapui using groovy