I have a file with a list of file names. I want to find each of those files and copy it to some directory, is this possible in linux?
ListOfFileNames.txt
xyz.txt
ags.txt
shd.txt
...
Directory_to_be searched
dsf.txt
xyz.txt
shd.txt
...
Empty_new_directory
So copy xyz.txt, ags.txt, shd.txt and place them in Empty_new_directory
Any help will be appreciated
xargs cp -t /app/dest/ < ListOfFileNames.txt
Does not work?
Maybe use of find command
If there's no nesting, then you can use a simple loop with cp:
SOURCE='Directory_to_be_searched'
TARGET='Empty_new_directory'
cat File.txt | while read filename; do
cp "${SOURCE}/${filename}" "${TARGET}/${filename}"
done
Related
So I have a text file containing the names of ~1000 folder names, and a directory with around ~30,000 folders. What I need to do is to find a bash command that will read the text file for the folder names, and grep those folders from the directory and copy them to a new destination. Is this at all possible?
I am new to coding, my apologies if this isn't worded well.
you can use a bash scrit like this one:
fileList=$(cat nameFIle)
srcDir="/home/ex/src"
destDir="/home/ex/dest"
for name in fileList
do
cp -r "${srcDir}/${name}" "${destDir}"/
done
Definitely possible - and you don't even need grep. Assuming your text file has one file per line.
cp -r `cat filenames.txt` path_to_copy_location/
I would write:
xargs cp -t /destination/directory < file.of.dirnames
When i am trying to run below code it is giving error of cp: target "Featurespath" is not a directory
I have tried multiple option but not working.
Featurespath=/permanent/jag/media-*/*/print/cooked/*Features.xml
for file in $(ls $Featurespath);
do
cat $Featurespath | sed "/pB-/s/Direction=\"unidir\"/Direction=\"bidir\"/" $Featurespath > /permanent/jag/temp.xml
cp -rf /permanent/jag/temp.xml $Featurespath
rm /permanent/jag/temp.xml
done
i want modified xml to be pasted in same xml file.
The error you received was because of the cp line: bash expands$Featurespath into a list of files. When cp sees more than 2 parameters, it assumes the last parameter to be a directory, which is not in this case. Here is my suggested fix:
Featurespath=/permanent/jag/media-*/*/print/cooked/*Features.xml
for file in $Featurespath
do
sed "/pB-/s/Direction=\"unidir\"/Direction=\"bidir\"/" "$file" > /permanent/jag/temp.xml
mv -f /permanent/jag/temp.xml "$file"
done
Notes
Do not use ls: bash can expand the wildcards just fine
Within the loop, you are now dealing with individual files $file, not the list of file $Featurespath
Do not need to use the cat command, the sed command can take a file name
sed has an inline editing option, which eliminate the need for temp file. You might want to look into it.
Replace cp/rm combination with mv
Ultimately, like others have said, sed is not the right tool to edit XML contents, but it might work for simple cases
I have some files located in one directory /home/john
I want to copy all the files with *.text extension from this directory and save them as *.text.bkup, again in the same directory, i.e. /home/john
Is there a single command with which I can do that?
Also, with extension of the same idea, is it possible to copy all the files with multiple extentions (e.g. *.text & *.doc) as *.text.bkup & *.doc.bkup repectively (again in the same directory)?
This is best accomplished with a Shell loop:
~/tmp$ touch one.text two.text three.doc four.doc
~/tmp$ for FILE in *.text *.doc; do cp ${FILE} ${FILE}.bkup; done
~/tmp$ ls -1
four.doc
four.doc.bkup
one.text
one.text.bkup
three.doc
three.doc.bkup
two.text
two.text.bkup
What happens in the code above is the shell gets all .text and .doc files and then loops through each value one by one, assigning the variable FILE to each value. The code block between the "do" and the "done" is executed for every value of FILE, effectively copying each file to filename.bkup.
You can achieve this easily with find:
find /home/john -iname '*.text' -type f -exec cp \{} \{}.backup \;
No, there is no single/simple command to achieve this with standard tools
But you can write a script like this to do it for you.
for file in *.text
do
cp -i "${file}" "${file}.bkup"
done
with -i option you can confirm each overwriting operation
I sort of use a roundabout way to achieve this. It involves a Perl script and needs additional steps.
Step 1:
Copy the names of all the text files into a text file.
find -maxdepth 1 -type f -name '*.txt' > file_name1.txt
Step 2:
Make a duplicate of the copied file.
cp file_name1.txt file_name2.txt
Now open the file_name2.txt in vi editor and do a simple string substitution.
%s/.text/.text.backup/g
Step 3: Merge the source and destination file names into a single file separated by a comma.
paste -d, file_name1.txt file_name2.txt > file_name.txt
Step 4: Run the below perl script to achieve the desired results
open(FILE1,"<file_name.txt") or die'file doesnt exist'; #opens a file that has source and destination separated beforhand using commas
chomp(#F1_CONTENTS=(<FILE1>)); # copies the content of the file into an array
close FILE1;
while()
{
foreach $f1 (#F1_CONTENTS)
{
#file_name=split(/,/,$f1); # separates the file content based on commas
print "cp $file_name[0] $file_name[1]\n";
system ("cp $file_name[0] $file_name[1]"); # performs the actual copy here
}
last;
}
I want to write a script that do specific thing:
I have a txt file e.g.
from1/from2/from3/apple.file;/to1/to2/to3;some not important stuff
from1/from2/banana.file;/to1/to5;some not important stuff
from1/from10/plum.file;/to1//to5/to100;some not important stuff
Now i want to copy file from each line (e.g. apple.file), from original directory tree to new, non existing directories, after first semicolon (;).
I try few code examples from similar questions, but nothing works fine and I'm too weak in bash scripting, to find errors.
Please help :)
need to add some conditions:
file not only need to be copy, but also rename. Example line in file.txt:
from1/from2/from3/apple.file;to1/to2/to3/juice.file;some1
from1/from2/banana.file;to1/to5/fresh.file;something different from above
so apple.file need to be copy and rename to juice.file and put in to1/to2/to3/juice.file
I think thaht cp will also rename file but
mkdir -p "$to"
from answer below will create full folder path with juice.file as folder
In addidtion after second semicolon in each line will be something different, so how to cut it off?
Thanks for all help
EDIT: There will be no spaces in input txt file.
Try this code..
cat file | while IFS=';' read from to some_not_important_stuff
do
to=${to:1} # strip off leading space
mkdir -p "$to" # create parent for 'to' if not existing yet
cp -i "$from" "$to" # option -i to get a warning when it would overwrite something
done
Using awk
(run the awk command first and confirm the output is fine, then add |sh to do the copy)
awk -F";" '{printf "cp %s %s\n",$1,$2}' file |sh
Using shell (get updated that need manually create folder, base on alfe's
while IFS=';' read from to X
do
mkdir -p $to
cp $from $to
done < file
I had this same problem and used tar to solve it! Posted here:
tmpfile=/tmp/myfile.tar
files="/some/folder/file1.txt /some/other/folder/file2.txt"
targetfolder=/home/you/somefolder
tar --file="$tmpfile" "$files"
tar --extract --file="$tmpfile" --directory="$targetfolder"
In this case, tar will automatically create all (sub)folders for you! Best,
Nabi
I'm encountering many files with the same content and the same name on some of my servers. I need to quarantine these files for analysis so I can't just remove the duplicates. The OS is Linux (centos and ubuntu).
I enumerate the file names and locations and put them into a text file.
Then I do a for statement to move the files to quarantine.
for file in $(cat bad-stuff.txt); do mv $file /quarantine ;done
The problem is that they have the same file name and I just need to add something unique to the filename to get it to save properly. I'm sure it's something simple but I'm not good with regex. Thanks for the help.
Since you're using Linux, you can take advantage of GNU mv's --backup.
while read -r file
do
mv --backup=numbered "$file" "/quarantine"
done < "bad-stuff.txt"
Here's an example that shows how it works:
$ cat bad-stuff.txt
./c/foo
./d/foo
./a/foo
./b/foo
$ while read -r file; do mv --backup=numbered "$file" "./quarantine"; done < "bad-stuff.txt"
$ ls quarantine/
foo foo.~1~ foo.~2~ foo.~3~
$
I'd use this
for file in $(cat bad-stuff.txt); do mv $file /quarantine/$file.`date -u +%s%N`; done
You'll get everyfile with a timestamp appended (in nanoseconds).
You can create a new file name composed by the directory and the filename. Thus you can add one more argument in your original code:
for ...; do mv $file /quarantine/$(echo $file | sed 's:/:_:g') ; done
Please note that you should replace the _ with a proper character which is special enough.