This is my structure:
class Imprint_Location(models.Model):
_name = 'imprint.location'
name = fields.Char()
product_id = fields.Many2one('product.template')
class Imprint_Charges(models.Model):
_name = 'imprint.charge'
_rec_name = 'location_id'
product_id_c = fields.Many2one('product.template', required=True)
location_id = fields.Many2one('imprint.location', required=True)
#api.multi
#api.onchange('product_id_c', 'location_id')
def product_filter(self):
res = {}
print '\n\n-------\n\n', self, self.product_id_c, '\n\n-------\n\n'
if self.product_id_c:
res['domain'] = {'location_id': [('product_id', '=', self.product_id_c.id)]}
print res
return res
class Product_Template(models.Model):
_inherit = 'product.template'
imprint_location_ids = fields.One2many('imprint.location', 'product_id')
sale_imprint_charge_ids = fields.One2many('imprint.charge', 'product_id_c')
Now i have defined a page in product.template and inside the page is sale_imprint_charge_ids which is in <tree editable="bottom"> and i am not selecting the product_id_c field[also this field doesn't show up in the tree defined].
Now my problem here is that when i select this from the form view which i defined for imprint.charge the method product_filter works fine, but when i enter from the product.template then i get a error saying
TypeError: <odoo.models.NewId object at 0x7fbb8bc21b90> is not JSON serializable
Because from product.template if passes the object <odoo.models.NewId object at 0x7fbb8bc21b90> , so if print self.product_id_c then it prints product.template(<odoo.models.NewId object at 0x7fbb8bc21b90>) so this is not serializable. i have tried doing self.product_id_c.ids which give output empty list [].
So how do get the product.template id from the object or pass the id itself overriding some method.
You should improve couple of following points.
res['domain'] = {'location_id': [('product_id', '=', self.product_id_c.id)]}
return res
study some search() method of ORM
Try with following code:
#api.multi
#api.onchange('product_id_c', 'location_id')
def product_filter(self):
res = {}
if self.product_id_c:
self.location_id = False
#search product_template in imprint.locationwith table and limit we will get only record if related record found
location_id = self.env['imprint.location'].search([('product_id', '=', self.product_id_c.id)], limit=1)
if location_id:
#location_id.ids will give you something like [2] so we need to set value as 2
self.location_id = location_id.ids[0]
EDIT:
As per your first comment, you need a list of related location then we should following trick.
Remove product_filter() method
Add domain in imprint.charge object view file
For example:
<field name="location_id" domain="[('product_id', '=', product_id_c)]"/>
Afterwards, Restart Odoo server and upgrade your custom module.
When creating a brand new record Odoo creates that wierd <odoo.models.NewId object at 0x7fbb8bc21b90> object. After you have written the record this id gets turned into the normal ids that you are used to (an integer). In this situation you have a function which (not unreasonably) expects a real id value at a point when no such value really exists. You need to provide a fallback, such as evaluating if the id is an integer and providing an alternate value in that circumstance. Although your function seems to return an object which I dont quite know what you are expecting to happen. If you wish to modify the value of one of your fields I would modify the values of the self object rather that returning an object.
Related
I need to delete an object from the list of objects based on the condition.
In the selectDoctor method, I need to remove the object from the list in which its docid is equal to the given id and return the removed list.
class Doctor:
def __init__(self, docid, docname, deptname):
self.docid = docid
self.docname = docname
self.deptname = deptname
class Hospital:
def selectDoctor(id,doclist):
for i in range(0, len(doclist)):
if doclist[i].docid==id: //in this condition I need to remove that object from list
doclist.remove(i) //by removing like this it is showing error
return doclist
for i in range(5):
docid=int(input())
docname=input()
deptname=input()
doclist.append(Doctor(docid,docname,deptname)
id=int(input())
res=Hospital.selectDoctor(id,doclist)
print(res)
Using list in Python3, it,s easy to achieve this using following statements(you have at least three possibilities):
Remove by specifying the item index
doclist.pop(i)
OR
Remove by specifying the item(s) index(es) (also range of indexes also allowed e.g. del doclist[0:2] for removing first three items of given list) using the keyword del
del doclist[i]
Remove by specifying the item itself
doclist.remove(doclist[i])
Reference: https://docs.python.org/3.8/tutorial/datastructures.html
Feel free to upvote the answer after fixing your error...
I have an unique constraint for my code field. When I click on the 'duplicate' option in the dropdown action I'm getting the validate error.
Is there any way to use 'duplicate' even if the field code is unique?
class sample(models.Model):
_name = 'sample'
code=fields.Char('Code',required=True)
name=fields.Char('Name',required=True)
_sql_constraints = [
('code_uniq', 'unique (code)', 'The code must be unique !')
]
Yes, it is. You have two ways to do this. When you duplicate a record, copy method is called, and it creates a new record with the values of the original record (it only copies the values of the fields whose argument copy=True -by default is True-). So you can change that argument in the code field declaration, or modify the copy method to avoid the identical replication.
Way 1: modifying the copy argument of the code field
This way would be the easiest one, but it will give you an error if code field is required.
class sample(models.Model):
_name = 'sample'
code = fields.Char('Code', required=False, copy=False)
name = fields.Char('Name', required=True)
_sql_constraints = [
('code_uniq', 'unique (code)', 'The code must be unique !')
]
Way 2: modifying the copy method of the model sample
This is the way you're looking for if code must be required.
class sample(models.Model):
_name = 'sample'
code = fields.Char('Code', required=True)
name = fields.Char('Name', required=True)
_sql_constraints = [
('code_uniq', 'unique (code)', 'The code must be unique !')
]
#api.one
def copy(self, default=None):
if default is None:
default = {}
new_code = (self.code + ' (copy)') if self.code else ''
default.update({
'code': new_code,
})
new_sample = super(sample, self).copy(default=default)
return new_sample
What I want to do seems simple : I have a MultipleChoiceField in a django form which proposes the id and pseudo of all books in a model named Dico :
class FiltreMonoForm(forms.Form):
dico_choices = []
for dic in Dico.objects.all().order_by('pseudo'):
dico_choices.append((dic.id, dic.pseudo))
dico_choices=tuple(dico_choices)
dicos = forms.MultipleChoiceField(required=False, widget=forms.CheckboxSelectMultiple, choices=dico_choices, initial=[c[0] for c in dico_choices], label="Diccionaris sorsas")
I get this form back in a view :
def monollist(request):
if request.GET:
getcopy = request.GET.copy()
form = FiltreMonoForm(getcopy)
dicos = form.cleaned_data['dicos']
else:
form = FiltreMonoForm()
I would like to have all the books checked if the user have checked none of them. Something like :
if request.GET:
getcopy = request.GET.copy()
form = FiltreMonoForm(getcopy)
dicos = form.cleaned_data['dicos']
for dic in Dico.objects.all().order_by('pseudo'):
dico_choices.append((dic.id, dic.pseudo))
dico_choices=tuple(dico_choices)
if len(dicos)==0:
form['dicos']=dico_choices
But I can't find how to change the value of the MultipleChoicesField. I tried with
form.data['dicos']=dico_choices
but it seems that I can only give one value to form.data['dicos'], it won't accept lists nor tuples.
I tried to override the __init__ method in my form in adding
self.data.update(dicos=dico_choices)
but I have the same issue, it works only if dico_choices is a single value.
Do you have any idea how to override my MultipleChoiceField with multiple values ?
Thanks
if 'dicos' not in getcopy:
for dic in Dico.objects.all():
getcopy.update({'dicos': dic.id})
I have a snippet for countrycodes and I want to define localized country names on the root pages for each localized site.
The snippet looks like this:
#register_snippet
class Country(models.Model):
iso_code = models.CharField(max_length=2, unique=True)
panels = [
FieldPanel('iso_code'),
]
def get_iso_codes():
try:
countries = Country.objects.all()
result = []
for country in countries:
result.append((country.iso_code,country.iso_code))
return result
except Country.DoesNotExist:
return []
Now I want to call the function get_iso_codes when creating a choiceblock and fill the choices from the snippet.
The block looks like this
class CountryLocalizedBlock(blocks.StructBlock):
iso_code = blocks.ChoiceBlock(choices=Country.get_iso_codes(), unique=True)
localized_name = blocks.CharBlock(required=True)
However, when calling manage.py makemigrations I get the following error:
psycopg2.ProgrammingError: relation "home_country" does not exist
LINE 1: ..."."iso_code", "home_country"."sample_number" FROM "home_coun...
I can bypass this by commenting out 'Country.objects.all()' and then running makemigrations and later readding the line again to the code, however I would prefer a solution that does not require this workaround (also it fails when I run 'manage.py collectstatic' when building before deployment and I don't know how to work around this and am stuck)
I found a solution based on Wagtail, how do I populate the choices in a ChoiceBlock from a different model?
The country class remains untouched (except that the get_iso_codes method is now superflous). I've just extended Chooserblock and use Country as my target_model:
class CountryChooserBlock(blocks.ChooserBlock):
target_model = Country
widget = forms.Select
def value_for_form(self, value):
if isinstance(value, self.target_model):
return value.pk
else:
return value
And used the CountryChooserBlock instead of the ChoiceBlock:
class CountryLocalizedBlock(blocks.StructBlock):
iso_code = CountryChooserBlock(unique=True)
localized_name = blocks.CharBlock(required=True)
I'm working with Flask/Mongoengine-MongoDB for my latest web application.
I'm familiar with Pymongo, but I'm new to object-document mappers like Mongoengine.
I have a database and collection set up already, and I basically just want to query it and return the corresponding object. Here's a look at my models.py...
from app import db
# ----------------------------------------
# Taking steps towards a working backend.
# ----------------------------------------
class Property(db.Document):
# Document variables.
total_annual_rates = db.IntField()
land_value = db.IntField()
land_area = db.IntField()
assessment_number = db.StringField(max_length=255, required=True)
address = db.StringField(max_length=255, required=True)
current_capital_value = db.IntField
valuation_as_at_date = db.StringField(max_length=255, required=True)
legal_description = db.StringField(max_length=255, required=True)
capital_value = db.IntField()
annual_value = db.StringField(max_length=255, required=True)
certificate_of_title_number = db.StringField(max_length=255, required=True)
def __repr__(self):
return address
def get_property_from_db(self, query_string):
if not query_string:
raise ValueError()
# Ultra-simple search for the moment.
properties_found = Property.objects(address=query_string)
return properties_found[0]
The error I get is as follows: IndexError: no such item for Cursor instance
This makes complete sense, since the object isn't pointing at any collection. Despite trolling through the docs for a while, I still have no idea how to do this.
Do any of you know how I could appropriately link up my Property class to my already extant database and collection?
The way to link a class to an existing collection can be accomplished as such, using meta:
class Person(db.DynamicDocument):
# Meta variables.
meta = {
'collection': 'properties'
}
# Document variables.
name = db.StringField()
age = db.IntField()
Then, when using the class object, one can actually make use of this functionality as might be expected with MongoEngine:
desired_documents = Person.objects(name="John Smith")
john = desired_documents[0]
Or something similar :) Hope this helps!
I was googling this same question and i noticed the answer has changed since the previous answer:
According to the latest Mongoengine guide:
If you need to change the name of the collection (e.g. to use MongoEngine with an existing
database), then create a class dictionary attribute called meta on your document, and set collection to the
name of the collection that you want your document class to use:
class Page(Document):
meta = {'collection': 'cmsPage'}
The code on the grey did the trick and i could use my data instantly.