I have a string (46318g_orchidpinkminisneakpead) Here i want to chop off the part till "_" and give me the result. So my result should be "orchidpinkminisneakpead" now what expression should I use to get this value in ssrs and the chopped string size do differ sometimes it can be 7 char sometimes it can be 8,9 also.
I am building the report using a cube so no changes can be done on the back-end.
Try:
=MID(Fields!YourField.Value,
InStr(Fields!YourField.Value,"_")+1,
LEN(Fields!YourField.Value)
)
In your case,
=MID(
"46318g_orchidpinkminisneakpead",
InStr("46318g_orchidpinkminisneakpead","_")+1,
LEN("46318g_orchidpinkminisneakpead")
)
should produce orchidpinkminisneakpead
Let me know if this helps.
Related
I have had to look up hundreds (if not thousands) of free-text answers on google, making notes in Excel along the way and inserting SAS-code around the answers as a last step.
The output looks like this:
This output contains an unnecessary number of blank spaces, which seems to confuse SAS's search to the point where the observations can't be properly located.
It works if I manually erase superflous spaces, but that will probably take hours. Is there an automated fix for this, either in SAS or in excel?
I tried using the STRIP-function, to no avail:
else if R_res_ort_txt=strip(" arild ") and R_kom_lan=strip(" skåne ") then R_kommun=strip(" Höganäs " );
If you want to generate a string like:
if R_res_ort_txt="arild" and R_kom_lan="skåne" then R_kommun="Höganäs";
from three variables, let's call them A B C, then just use code like:
string=catx(' ','if R_res_ort_txt=',quote(trim(A))
,'and R_kom_lan=',quote(trim(B))
,'then R_kommun=',quote(trim(C)),';') ;
Or if you are just writing that string to a file just use this PUT statement syntax.
put 'if R_res_ort_txt=' A :$quote. 'and R_kom_lan=' B :$quote.
'then R_kommun=' C :$quote. ';' ;
A saner solution would be to continue using the free-text answers as data and perform your matching criteria for transformations with a left join.
proc import out=answers datafile='my-free-text-answers.xlsx';
data have;
attrib R_res_ort_txt R_kom_lan length=$100;
input R_res_ort_txt ...;
datalines4;
... whatever all those transforms will be performed on...
;;;;
proc sql;
create table want as
select
have.* ,
answers.R_kommun_answer as R_kommun
from
have
left join
answers
on
have.R_res_ort_txt = answers.res_ort_answer
& have.R_kom_lan = abswers.kom_lan_answer
;
I solved this by adding quotes in excel using the flash fill function:
https://www.youtube.com/watch?v=nE65QeDoepc
I have two Fields, with partly different strings. FieldA:= "String1" FieldB:= "String1; String2" (So, the main difference between the two fields is the "; String2" in FieldB). The result i want to see is also "String1; String2", but the first half i want from FieldA, and the second half i want from FieldB. Is there any way using Access SQL/VBA function to solve this problem?
With the assumption that your values will always contain a semi-colon, you could also use the Split function in the following way:
[FieldA] & ";" & Split([FieldB],";")(1)
Yes. Use string manipulation functions. This is a relatively simple case for string manipulation, assuming the strings are consistent with the examples given. Consistency is critical to string manipulation. Assuming there is a space following the semi-colon, try:
[FieldA] & "; " & Mid([FieldB], InStr([FieldB], ";") + 2)
Expression can be used in query or textbox or VBA.
Suggest you do some research and learn about these and other string functions.
I have a string field with mostly numeric values like 13.4, but some have 13.4%. I am trying to use the following expression to remove the % symbols and retain just the numeric values to convert the field to integer.
Here is what I have so far in the expression definition of Cognos 8 Report Studio:
IF(POSITION('%' IN [FIELD1]) = NULL) THEN
/*** this captures rows with valid data **/
([FIELD1])
ELSE
/** trying to remove the % sign from rows with data like this 13.4% **/
(SUBSTRING([FIELD1]), 1, POSITION('%' IN [FIELD1])))
Any hints/help is much appreciated.
An easy way to do this is to use the trim() function. The following will remove any trailing % characters:
TRIM(trailing '%',[FIELD1])
The approach you are using is feasable. However, the syntax you are using is not compatible with the version of the ReportStudio that I'm familiar with. Below you will find an updated expression which works for me.
IF ( POSITION( '%'; [FIELD1]) = 0) THEN
( [FIELD1] )
ELSE
( SUBSTRING( [FIELD1]; 1; POSITION( '%'; [FIELD1]) - 1 ) )
Since character positions in strings are 1-based in Cognos it's important to substract 1 from the position returned by POSITION(). Otherwise you would only cut off characters after the percent sign.
Another note: what you are doing here is data cleansing. It's usually more advantageous to push these chores down to a lower level of the data retrieval chain, e.g. the Data Warehouse or at least the Framework Manager model, so that at the reporting level you can use this field as numeric field directly.
I currently have an assignemnt where i have to handle data from a lot of countries. My customer have given me a list of acceptable characters, lets call it:
'aber =*'
All other characters should just be changed to '_'.
I know the conversion for my country's specific chars (æøå), easily done with something like
select replace ('Ål', 'Å', 'AA') from dual;
But how would i go about removing all unwanted "noise" without splitting it up in char-by-char comparison?
For example "bear*2 = fear" should become "bear*_ = _ear" as 2 and f are not in the accepted list.
Oracle 10g and up. As one of the approaches, you can use regular expression function regexp_replace():
select regexp_replace('bear*2 = fear', '[^aber =*]', '_') as res
from dual
res
------------------------------
bear*_ = _ear
Find out more about regexp_replace() function.
As I asked in my previous question(Link) about concatenating a multipart string of variable lengths, I used the method answered there by rkhayrov and now, my function looks like this:
local sToReturn = string.format( "\t%03s\t%-25s\t%-7s\n\t", "S. No.", "UserName", "Score" )
SQLQuery = assert( Conn:execute( string.format( [[SELECT username, totalcount FROM chatstat ORDER BY totalcount DESC LIMIT %d]], iLimit ) ) )
DataArray = SQLQuery:fetch ({}, "a")
i = 1
while DataArray do
sTemp = string.format( "%03s\t%025s\t%-7d", tostring(i), DataArray.username, DataArray.totalcount )
sToReturn = sToReturn..sTemp.."\n\t"
DataArray = SQLQuery:fetch ({}, "a")
i = i + 1
end
But, even now, the value of score is still not following the order as required. The max length of username is 25. I've used %025s inside the while loop because I want the usernames to be right-justified, while the %-25s is to make the word UserName centre justified.
EDIT
Current output:
Required Output:
Displaying the list of top 5 chit-chatters.
S. No. UserName Score
1 Keeda 9440
2 _2.2_™ 7675
3 aim 7057
4 KGBRULES 6770
5 Guddu 6322
I think it's because of difference in fonts, but since most of the clients have Windows 7 default fonts(Tahoma/Verdana at 11px), I need optimum result for at-least that.
I think it's because of difference in fonts
It is. string.format formats by inserting whitespace. That only works for a fixed width fonts (i.e. all characters have the same width, including whitespace).
since most of the clients have Windows 7 default fonts(Tahoma/Verdana at 11px)
In what? How are they viewing your output? Do you write it to a textfile, that they then open in the editor of their choice (likely Notepad)? Then this approach will simply not work.
Don't know enough about your output requirements to steer you any futher, but it's worth noting that everyone has a browser so HTML output is very portable.
string.format doesn't truncate - the width of the field is minimum, not maximum. You'll have to truncate the strings to 25 characters yourself with something like DataArray.username:sub(0,25).
I'd remove the tabs from the string.format; and use the justification provided by %25s only. Won't be perfect but will probably be closer.
Use a fixed-width font if you can.