I have the following formula:
=IF(AND(A1=0,A3="","1 item"),
IF(AND(A1=0,A3="Exclude","1 item"),
IF(AND(A1=1,A3="Exclude","1 item","2 items"))))
3 combinations of cell values in A1 and A3 return text which I'm calling "1 item"
Only 1 combination of cells value returns text which I'm calling "2 items".
The only combination to return "2 items" is where A1=1 AND A3="".
The formatting is wrong but I'm not sure where.
Any help would be greatly appreciated.
this is the correct formula -
brackets of AND() were not properly closed.
=IF(AND(A1=0,A3=""),"1 item",IF(AND(A1=0,A3="Exclude"),"1 item",IF(AND(A1=1,A3="Exclude"),"1 item","2 items")))
Excel's IF expects three parameters: Condition, What to do if condition is TRUE, and what to do if condition is FALSE.
I'll re-format your formula so you can see where the error is:
IF( AND(A1=0,A3="","1 item") ,
IF(AND(A1=0,A3="Exclude","1 item"),
IF(AND(A1=1,A3="Exclude","1 item","2 items")
)
)
)
As you can see
For the first IF you are not providing what to do if condition is FALSE,
The same for the second IF,
The third IF has no definition of what to do if the condition is TRUE or FALSE.
Hope this helps you.
UPDATE
Following your comment (which is still not clear to me), hereinafter I'm providing simple rules you may use to construct your formula correctly:
Write your formula as a piece of text (like the example I show above) so that you can easily read, edit and verify it,
Remember that Excel's IF has three parameters: Condition, result when condition is TRUE and result when condition is FALSE,
Within any of these three parameters, you can include whatever you want PROVIDED that the result is compliant with what the function expects for that parameter; for instance, writing for the first parameter 3=8 is completely legal since the result is FALSE (while 4=2*2 would yield TRUE).
Having this in mind, here is the formula I think you are looking for (WARNING!!! I'm not sure I understood what you need, but if not, changing it should be very easy for you now):
IF(AND(A1=1,A3=""),"2 items","1 item")
This is based on your wording: The only combination to return "2 items" is where A1=1 AND A3="".
Related
I am trying to validate a combination of char and numbers that looks like this XXXX0000000.
I have tried this formula; =OR((LEFT(B2,3)="XXXX",LEN(B2)=11),AND(LEFT(B2,3)="XXXX",LEN(B2)=11).
The error message I receive is as follows:
excel error message
Title: "Excel customer data validation for chars and numbers"
...I have the feeling it's not just about validating XXXX0000000 but it's about the pattern of characters and numbers. Therefor try:
Formula in B1:
=IF(ISERROR(FILTERXML("<t><s>"&A1&"</s></t>","//s[translate(substring(.,1,4), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ','')=''][string-length()=11][substring(.,5)*0=0]")),"Invalid","Valid")
Where:
//s[translate(substring(.,1,4), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ','')=''] - Check if when we translate the first 4 characters to nothing this also equals empty string;
[string-length()=11] - Check that node is 11 characters long;
[substring(.,5)*0=0] - Check that substring from 5th position onwards equals zero when multiplied by zero.
Note: FILTERXML() is case sensitive and is currently checking for uppercase alpha-chars.
EDIT:
To use this in data-validation; Ditch the IF() since you don't need that in validation and nest the remainder in NOT():
=NOT(ISERROR(FILTERXML("<t><s>"&A1&"</s></t>","//s[translate(substring(.,1,4), 'ABCDEFGHIJKLMNOPQRSTUVWXYZ','')=''][string-length()=11][substring(.,5)*0=0]")))
When you select your range, make sure the validation rule has the topleft cell in the reference.
You have two formulas but no joining of them
IE you have an OR formula
=OR((LEFT(B2,3)="XXXX",LEN(B2)=11)
Which will return a true/false answer
You also have an AND formula
=AND(LEFT(B2,3)="XXXX",LEN(B2)=11)
Which will return a true/false answer
when you work through it you are being given a return of:
=True(or false), true (or false)
That isn't a formula and is causing the error output
I think you want to use an IF statement to join them and get an output as desired:
E.g.
=If(OR(LEFT(B2,3)="XXXX",LEN(B2)=11),AND(LEFT(B2,3)="XXXX",LEN(B2)=11), DO SOEMTHING IF TRUE, DO SOMETHING IF FALSE)
I suggest this:
OR(LEFT(B2,3)="XXX",LEN(B2)=11,AND(LEFT(B2,3)="XXX",LEN(B2)=11))
It corrects the number of characters error and sorts the logic.
Hoping someone smarter than myself can help:
Column F contains either of the words below, and I want to excel formula to return whether the data is "White" or "Pink"
Ban
Bandearg
=IF(ISNUMBER(SEARCH("Ban",F2)),"White",IF(ISNUMBER(SEARCH("Bandearg",F2)),"Pink")
The problem is that everything returns as "White" as it is finding "Ban" in both. Presume I am using the formula wrong.
Bán is the Irish for White and Bándearg is the Irish for Pink!
As per my comment, simply swap them around:
=IF(ISNUMBER(SEARCH("Bandearg",F2)),"Pink",IF(ISNUMBER(SEARCH("Ban",F2)),"White"))
ISNUMBER checks wheather or not SEARCH returns a number (meaning the substring is found starting at that index/position) or an #VALUE error. In the first case, it will return TRUE, otherwise FALSE continueing with the second nested IF. Note that this formula will return FALSE if "Ban" isn't found at all.
Maybe just simply add a space behind the criteria and the result value, and your formula become :
=IF(ISNUMBER(SEARCH("Ban ",F2&" ")),"White",IF(ISNUMBER(SEARCH("Bandearg ",F2&" ")),"Pink"))
If those words are all that the cell contains, you can simply use:
=IF(A1="Ban","White",IF(A1="Bandearg","Pink",""))
or, in later versions of Excel (2019+ or O365):
=IFS(A1="Ban","White",A1="Bandearg","Pink",TRUE,"")
All of the methods that I've used have 2 answer values (True or False).
How can I get the following with a formula?
If A1=1 then it's 11, if A1=2 the answer is 22, if A1=3 then it's 33, if A1=4 it's 44.
If the value your are evaluating is in cell A1, then the nested function would be as follows:
IF(A1=1,11,IF(A1=2,22,IF(A1=3,33,IF(A1=4,44,""))))
I put the 2 double commas at the end so the formula returns a blank instead of false.
I don't know if that's what you are asking about, but you can make multiple (nested) IF statements in one. For example:
IF(1=2;TRUE;IF(2=2;TRUE;FALSE))
You just put another IF in the FALSE part of IF statement. If that's not it, can you give a piece of the statement you tried and precise more what do you want?
=IF(AND(INT(A1)=A1,A1<=4,A1>=1),A1*11,"")
Now the above works for the condition you placed in your example, however if one were to go by your title alone you have a couple of options you could go with.
You first Option would be nested IF statements. Like you said each IF function has TRUE or FALSE. The trick is to put another IF function in for the TRUE result and another in for the FALSE results
IF(CHECK1, IF(CHECK2, TRUE2, FALSE2),IF(CHECK3, TRUE3, FALSE3))
The above give 4 potential results based on only 3 checks. Another option would be to do a check and supply a value for a TRUE result and another IF for a false result. Keep repeating the process. Conversely you could go the same route flipping TRUE FALSE option. It might look something like this:
IF(CHECK1, TRUE1, IF(CHECK2, TRUE2, IF(CHECK3, TRUE3, FALSE3)))
FALSE3 would be the result of all previous checks failing.
So for your case, your nested IF could look like (assuming the only valid entries are 1, 2, 3 and 4):
IF(A1=1,11,IF(A1,2,22,IF(A1=3,33,44)))
OR
IF(ISODD(A1),IF(A1=1,11,33),IF(A1=2,22,44))
and there are other options to work through the logic. there are also other checks you could be doing and results being displayed if your entries in A1 were not limited to the integers 1,2,3 and 4.
Now because you example is using the sequential integers 1,2,3 and 4 you could also use the CHOOSE function. Alternatively if you can make your criteria evaluate to sequential integers stating at 1 the CHOOSE function would work as well. Supply choose with an integer as the first argument and it will return the corresponding argument in the list that follows
CHOOSE(ARGUMENT,RESULT1, RESULT2,...,RESULTn-1, RESULTn)
In your case it would look something like:
CHOOSE(A1,11,22,33,44)
If you can not get sequential numbers for whatever reason and the gap is numbers is small and you are in the low integer count, you could leave a gap in results by providing "", or 0). lets say you has 1,3 and 4 as potential arguments, then your choose might look like:
CHOOSE(A1,11,"",33,44)
=IF(A1<>"",INDEX({11;22;33;44},A1),"")
=IF(AND(ISNUMBER(A1),A1<=4),A1*11,"")
I have this IF statement:
=IF(AG3<=7,"1",IF(15<=AG3<=21,"2",IF(22<=AG3<=28,"3",IF(29<=AG3<=35,"4",IF(36<=AG3<=42,"5",IF(43<=AG3<=49,"6",IF(50<=AG3<=56,"7")))))))
but either it gives me a 1 or "FALSE"
All the values are within the ranges and should be showing various numbers
Excel does not use 50<=AG3<=56. The way Excel will read this is it will resolve AG3<=56 which will resolve to TRUE or FALSE which have the values of 1 and 0 respectively. And since 50 is greater than both those it will always return FALSE and since you did not specify a final false argument Excel returns FALSE
It needs to be AND(50<=AG3, AG3<=56)
Also "1" returns a number as text and not a true number, remove the quotes.
So:
=IF(AG3<=7,1,IF(AND(15<=AG3,AG3<=21),2,IF(AND(22<=AG3,AG3<=28),3,IF(AND(29<=AG3,AG3<=35),4,IF(AND(36<=AG3,AG3<=42),5,IF(AND(43<=AG3,AG3<=49),6,IF(AND(50<=AG3,AG3<=56),7,"Value not in specs")))))))
But based on your criteria you could use:
=IF(OR(AND(AG3>=8,AG3<=14),AG3>56),"Not to Spec",MATCH(AG3,{-1E+99,15,22,29,36,43,40}))
Don't use Nested IFs if you can avoid it. Instead, use a banded VLOOKUP: it's many times more efficient, and a heck of a lot simpler to troubleshoot. Something like the answer here:
Excel IF statement Not returning the appropriate Value
In your case, here's your lookup list:
Note that since you haven't specified what should happen between 8 and 14 or over 57 I have simply put =NA() in those bands.
And here's the result for a range of numbers:
...and here's the formula that was used in the second column of that second table (using table notation):
=VLOOKUP([#Value],Table3,2,TRUE)
I understand nesting IF/AND statements but when my criteria is a list {} I'm not getting the desired results. Is there anyway to correct this without creating a "helper cell"?
=IF(AND(C2="CBHNP",F2="CHAM"),"CBHNP-Franklin Fulton",IF(AND(C2="CBHNP",F2<>"CHAM"),"CBHNP-Capital Region",IF(AND(C2="CCBH",F2={"RPSY","RDG","CSBERKS"}),"CCBH-Berks",IF(AND(C2="CCBH",F2={"YORK","YORK-P","CSYORK"}),"CCBH-YORK",IF(AND(C2="CCBH",F2<>{"YORK","YORK-P","CSYORK","RPSY","RDG","CSBERKS"}),"CCBH-North Central",B2)))))
Briefly: AND(A1={1,2,3})is always False, since it is the same as AND(A1=1,A1=2,A1=3), and A1 can only have 1 value at a time.
So, following the same principle, AND(C2="CCBH",F2={"RPSY","RDG","CSBERKS"}) is also always False, because it is the same as writing AND(C2="CCBH",F2="RPSY",F2="RDG",F2="CSBERKS") and F2 can only have 1 value. If you use an OR though... AND(C2="CCBH",OR(F2={"RPSY","RDG","CSBERKS"})) can be True, in the same way that OR(A1={1,2,3}) can be. It can also be re-written as OR(AND(C2="CCBH",F2="RPSY"), AND(C2="CCBH",F2="RDG"), AND(C2="CCBH",F2="CSBERKS"))
Thus:
=IF(AND(C2="CBHNP",F2="CHAM"),"CBHNP-Franklin Fulton",IF(AND(C2="CBHNP",F2<>"CHAM"),"CBHNP-Capital Region",IF(AND(C2="CCBH",OR(F2={"RPSY","RDG","CSBERKS"})),"CCBH-Berks",IF(AND(C2="CCBH",OR(F2={"YORK","YORK-P","CSYORK"})),"CCBH-YORK",IF(AND(C2="CCBH",F2<>{"YORK","YORK-P","CSYORK","RPSY","RDG","CSBERKS"}),"CCBH-North Central",B2)))))