Mongoose array elements ALL $in array - node.js

Question

I have an array like this:
{
"_id" : ObjectId("581b7d650949a5204e0a6e9b"),
"types" : [
{
"type" : ObjectId("581b7c645057c4602f48627f"),
"quantity" : 4,
"_id" : ObjectId("581b7d650949a5204e0a6e9e")
},
{
"type" : ObjectId("581ca0e75b1e3058521a6d8c"),
"quantity" : 4,
"_id" : ObjectId("581b7d650949a5204e0a6e9e")
}
],
"__v" : 0
},
{
"_id" : ObjectId("581b7d650949a5204e0a6e9c"),
"types" : [
{
"type" : ObjectId("581b7c645057c4602f48627f"),
"quantity" : 4,
"_id" : ObjectId("581b7d650949a5204e0a6e9e")
}
],
"__v" : 0
}
And I want to create a query that will return me the elementswhere the array of types ALL match a $in array.
For example:
query([ObjectId("581b7c645057c4602f48627f"), ObjectId("581ca0e75b1e3058521a6d8c")])
should return elements 1 and 2
query([ObjectId("581b7c645057c4602f48627f")])
should return element 2
query([ObjectId("581ca0e75b1e3058521a6d8c")])
should return nothing
I tried
db.getCollection('elements').find({'types.type': { $in: [ObjectId("581ca0e75b1e3058521a6d8c")]}})
But it returns the elements if only one types matches

Answer 1

You may have to use aggregation as $in and $elematch will return only matching elements. Project stage does set equals to create a all match flag and matches in the last stage with true value.
aggregate([ {
$project: {
_id: 0,
isAllMatch: {$setIsSubset: ["$types.type", [ObjectId("581b7c645057c4602f48627f")]]},
data: "$$ROOT"
}
}, {
$match: {
isAllMatch: true
}
}])
Sample Output
{
"isAllMatch": true,
"data": {
"_id": ObjectId("581b7d650949a5204e0a6e9c"),
"types": [{
"type": ObjectId("581b7c645057c4602f48627f"),
"quantity": 4,
"_id": ObjectId("581b7d650949a5204e0a6e9e")
}],
"__v": 0
}
}
Alternative version:
This version combines both project and match stages into one $redact stage with $cond operator to decide whether to keep or prune the elements.
aggregate([{
"$redact": {
"$cond": [{
$setIsSubset: ["$types.type", [ObjectId("581b7c645057c4602f48627f")]]
},
"$$KEEP",
"$$PRUNE"
]
}
}])