i keep trying and trying but nothing always N/A
photo added.
i tried to put e:\onedrive\ubuy
but still didn't work.
i need that the left workbook in cell C2 will be vlookup of cell A2 in the right workbook from D2 cell
enter image description herel 2 to AA cell 400.
and will show me in C2 the value at AA.
Ty :[
command that i did
=VLOOKUP(A2,'[מחירון פריטים - עסקית.xlsx]xl_PriceList'!$D$2:$AA$375,23,FALSE)
Without changing your data, you can edit your formula to this:
=VLOOKUP(TEXT(A2, "#"),'[מחירון פריטים - עסקית.xlsx]xl_PriceList'!$D$2:$AA$375,23,FALSE)
The text(A2, "#") converts your lookup value to text format (same as the data you're searching) on the fly, so you don't need to edit your data.
Related
I am writing a formula to run a matching analysis on some elements of a spreadsheet. The column containing the formula already has values filled in, but I need to run the formula on the blank cells. The formula is working but overwriting the current info I have within the filled cells.
I have tried a VBA code which got too complicated and did not work. With VBA I tried inserting the formula into only the blank spaces but was having some issues. I have also tried a basic excel formula.
=IF(COUNTIFS(A:A,A2,BU:BU,"CLOUD")=0,"Not Cloud",IF(COUNTIFS(A:A,A2,BU:BU,"NOT CLOUD")=0,"Cloud","Hybrid"))
VBA Code I tried:
If (IsEmpty(Bucket) Or Bucket = "" Or Bucket = vbNullString) And _
(GetCellValue(.Cells(i, "BU")) = "CLOUD") Then
Range("CC:CC").Formula = "=IF(COUNTIFS(A:A,A2,BU:BU,""CLOUD"")=0,"Not Cloud", _
IF(COUNTIFS(A:A,A2,BU:BU,"NOT CLOUD")=0,"Cloud"","Hybrid"))"
A reminder this is a high-level version
I want that formula to only run in the cells that do not have a value already in place. It should not overwrite the data from the VBA script that I previously ran before doing the formula. The disposition column should be completely full of values. The formula needs to run in only the blank cells.
You could achieve this with an additional column.
In the column to the right of Disposition (insert one if necessary) write the following formula (example for row 2, assuming Disposition is Column C):
=IF(C2=""; [Your formula here]; C2)
This will provide you with a column full of values, anytime you put a value into column C it will override the formula.
Edit: You can then copy this formula down the entire column to achieve the desired effect.
I am stuck...
I have a 100 Row sheet with 10 Columns. This list is broken into classes simply by inline headers. I have definitions of the blocks of data under each head, for example:
UNASSOCIATED A2 A19
HOSTS A21 A32
ROOF A34 A100
I compute those ranges as they may change from time to time. I need
first: Define Name of each group by formula
Second: From time to time select the defined group
I am unable to get a formula to work which will allow me to use the "Content" of the cell as opposed to the cell location to define these ranges.
I'm stuck.
Suggestions would be appreciated.
Regards,
RHD
This cannot be done in a cell formula. You'll need to create a macro (VBA) to do this. Essentially, what you need is to grab the value of a cell then use that value as if it were a cell address.
Take a look at the example macro below. If cell A1 contains the characters "B22", then x will become the value of A1 (which is "B22") and "test" will be written to cell B22. This cannot be done in with cell formulas.
Sub test()
Dim x As String
x = Range("A1").Value
Range(x).Value = "test"
End Sub
A good amount of adaptation will been needed to incorporate this technique, and you'll need to play with this a bit. Ping this community to help answer more specific questions as they come up.
I'm looking automatically to calculate the average of 40 values that come from a .csv file, which I have managed to do.
My problem is I would like it to take the values from any separate workbook based on the cell value from the original workbook, so this can automatically calculate the average from any one of a number of available spreadsheets.
This is the formula I'm using currently:
=Sample1.csv!C1
And this is the what I tried, which obviously doesn't work:
=B4.csv!C1
With B4 containing the word Sample1 or any other Sample Number.
The formula you can use to refer to a cell on another sheet
=INDIRECT(B1 & "!C1")
Where B1 has the sheet name and you get the value of cell C1 from it.
It can be used to get data from another workbook , so long as the other workbook is open.
eg
=INDIRECT("[Book1.xlsx]a.csv!$A$1")
=INDIRECT("[" & B1 & "]!$A$1")
Where B1 has the name of the workbook
In practise you might use:
=INDIRECT(B1 & "!" & C1)
Where C1 contains (ie stores as a value!) the address of the cell you want to reference. Thsi is useful as it allows you to copy the formulas such that the addresses change.
It is better to use the CELL function as follows which uses CELL to get the Address of A1 as text eg "$A$1". This means the formula can easily be copied and pasted into the cells you want it to be in.
=INDIRECT(B1 & "!" & CELL("address",A1)
Enjoy.
You can use the Indirect() function to have Excel interpret a text string as a cell reference, and this string can be constructed with the text values from one (or more) cells.
So in your example use:
=INDIRECT(B4 & "!C1")
which retrieves the value "Sample1" from B4 and concatenates this with the second part of the string to give "Sample1!C1" that Indirect() then uses as an address & retrieves the value from there.
I have formatted a cell in Excel as Scientific with 1 decimal place then I inserted a number in it like (0.41). After pressing enter the result displayed is (4.1E-01). My aim is to put this result in a cell with text format so that when I double click the cell, I can copy/modify the text (4.1E-01) as I want.
I tried to format that cell as text but the result gets back to 0.41. I also tried to copy the cell and paste the value only using "Special Paste" into a text-formatted cell but the result keeps returning to 0.41. Do you have a suggestion on how to solve this issue?
Thanks in advance
This is a bit of a work around unless you want to use VBA. In an adjacent cell type this formula:
=TEXT(A1,"0.00E+00")
Now you can copy that cell and paste values only and get just the text:
2.22E+27
If your okay with VBA use this:
Range("A2").Value = Range("A1").Text
Say I've got cells A1-A10 populated with numbers. My initial formula in cell B1 is =A1-A6. However, I'd like to strike-out cell A3 (keeping the contents visible underneath the strike-out if possible), and I'd like the formula in B1 to recognise that change, and then automatically adjust itself to =A1-A7 (the idea being that I'd like A1 subtracted by the number in the cell 5 "non-struck out" cells below it). And then if I strike out cell A5 I'd like the formula to adjust itself to =A1-A8 and so on. Does anyone know how to do this?
(EDIT#1: misread the input, sorry)
A bit straightforward, but will do the job: type =A1-INDIRECT("A"&SMALL(IF(A:A<>"",ROW(A:A),""),6)) and press CTRL+SHIFT+ENTER instead of usual ENTER - this will define an ARRAY formula and will result in {} brackets around it (but do NOT type them manually!).
To speed up calculation you may replace A:A to any limited range.
Sample file (resulting formula is yellow-marked): https://www.dropbox.com/s/sy7zkg71xtfgib9/Subtract5th.xlsx
(EDIT#2: misread the "strike-out", sorry)
Font styles (as well as similar cell properties) may NOT be read by default Excel functions, that's why you need to add UDF called StrikeOut:
Press ALT-F11 - thiss will open VBA editor.
Insert new module: Insert > Module.
Paste the code to added module:
Function StrikeOut(R As Range) As Long
Dim c As Range
StrikeOut = 0
For Each c In R.Cells
If c.Font.Strikethrough = True Then StrikeOut = StrikeOut + 1
Next
End Function
Add the formula to B1: =A1-INDIRECT("A"&(6+StrikeOut(A2:A10)))
Set strikethrough font to any cells in A1:A10.
Unfortunately, cell format change does NOT trigger any change event, so you need either press F9 or change any cell value on the sheet to recalculate and therefore update result in B1.
Sample file is shared: https://www.dropbox.com/s/n9o7tn3ks3x8nza/StrikeOut.xlsm
P.S. at least for me that was extremely useful)))