My code appears like this:
shop = input("Do you want to enter the shop?")
if shop == "y":
print ("["+shopownername+"]: Welcome to my store.")
sleep(1)
print ("["+shopownername+"]: Here are the items for sale:")
for x in shopitems:
print (x)
sleep(1)
print ("You have "+str(gold)+" gold.")
sleep(1)
choice = 0
while choice != "exit":
choice = input("What would you like to buy? Type 'exit' and enter to leave.")
if choice == "a":
purchase = "a"
confirm = input("Are you sure you want to buy "+purchase+"? (y/n)")
if confirm == "y":
if "a" in weapons:
print ("You already have that.")
break
elif gold < shopitems[purchase]:
print ("You do not have enough gold for that.")
break
else:
gold = gold - shopitems[purchase]
weapons.append("a")
print ("You have purchased the "+purchase+".")
print ("You now have "+str(gold)+" gold.")
break
elif choice == "b":
purchase = "b"
confirm = input("Are you sure you want to buy "+purchase+"? (y/n)")
if confirm == "y":
if "b" in weapons:
print ("You already have that.")
break
elif gold < shopitems[purchase]:
print ("You do not have enough gold for that.")
break
else:
gold = gold - shopitems[purchase]
weapons.append("b")
print ("You have purchased the "+purchase+".")
print ("You now have "+str(gold)+" gold.")
break
else:
print ("["+shopownername+"]: Thank you for coming.")
else:
print ("You did not enter the shop.")
What it is supposed to do is that in any case until you exit the shop, you will be able to buy items. However, in this system, it breaks the while as well, and proceeds to the next piece of code. What I should be able to do is try to buy a, and no matter if I cannot afford it, already own it, or have bought it, can both attempt to buy b or try to re-buy a.
What should I do?
Related
import random
replay = 1
while replay == 1:
replay = replay - 1
target = random.randint(1, 100)
guess = int(input("Guess the number 1-100: "))
count = 0
score = 0
while count == 0:
score = score + 1
if guess < target:
print ("The number is higher. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess > target:
print ("The number is lower. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess == target:
print ("You guessed Correctly!")
print ("Your score was:", score)
again = str(input("Play again? (yes or no)"))
if again == "yes" or "YES":
replay = replay + 1
elif again == "no" or "NO":
break
This is my code, except it doesn't do what I want it to do. After you guess the correct number, it doesn't see to properly loop through the game again when you say yes or no. It just goes through the final if statement again.
Why won't it go through the entire program again?
Your code will always be evaluated to true
if again == "yes" or "YES":
Change it to:
if again.lower() == "yes":
Or
if again in ("YES", "yes", "y",..)
When it is true, you need to break from you second loop:
if again.lower() == "yes":
replay = replay + 1
break
When it is false, don't break but exit the program using:
exit()
Since replay is only used to exit your code, you don't need it if you use exit().
Code would then be:
import random
while True:
target = random.randint(1, 100)
guess = int(input("Guess the number 1-100: "))
score = 0
while True:
score = score + 1
if guess < target:
print ("The number is higher. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess > target:
print ("The number is lower. Try again.")
guess = int(input("Guess the number 1-100: "))
elif guess == target:
print ("You guessed Correctly!")
print ("Your score was:", score)
again = str(input("Play again? (yes or no)"))
if again.lower() == "yes":
break
elif again.lower() == "no":
exit()
Here is my code (for hangman game):
import random, os
def main():
print("******THIS IS HANGMAN******")
print("1. Play Game ")
print("2. Quit Game ")
choice = input("Please enter option 1 or 2")
if choice == "1":
words = ["school", "holiday", "computer", "books"]
word = random.choice(words)
guess = ['_'] * len(word)
guesses = 7
while '_' in guess and guesses > 0:
print(' '.join(guess))
character = input('Enter character: ')
if len(character) > 1:
print('Only enter one character.')
continue
if character not in word:
guesses -= 1
for i, x in enumerate(word):
if x == character:
guess[i] = character
if guesses == 0:
print('You LOST!')
break
else:
print('You have only', guesses, 'chances left to win.')
else:
print('You won')
elif choice == "2":
os.system("cls")
main()
else:
print("that is not a valid option")
main()
I have tried os.system("clear") but it doesn't clear the screen, I want it to clear the entire screen but instead (cls) makes it print my menu again and (clear) does nothing except clear the 2. If I'm missing something obvious it's probably because I'm new to python.
It prints the menu again because you call main() again instead of just stopping there. :-)
elif choice == "2":
os.system("cls")
main() # <--- this is the line that causes issues
Now for the clearing itself, os.system("cls") works on Windows and os.system("clear") works on Linux / OS X as answered here.
Also, your program currently tells the user if their choice is not supported but does not offer a second chance. You could have something like this:
def main():
...
while True:
choice = input("Please enter option 1 or 2")
if choice not in ("1", "2"):
print("that is not a valid option")
else:
break
if choice == "1":
...
elif choice == "2":
...
main()
using a nested if statement and my indentation seems correct thru out yet still reviving a syntax error.thank you
# FIGHT Dragons
if ch3 in ['y', 'Y', 'Yes', 'YES', 'yes']:
# WITH SWORD
if sword == 1:
print ("You only have a sword to fight with!")
print ("You quickly jab the Dragon in it's chest and gain an advantage")
time.sleep(2)
print ("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~")
print (" Fighting... ")
print (" YOU MUST HIT ABOVE A 5 TO KILL THE DRAGON ")
print ("IF THE DRAGON HITS HIGHER THAN YOU, YOU WILL DIE")
print ("~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~")
time.sleep(2)
fdmg1 = int(random.randint(3, 10))
edmg1 = int(random.randint(1, 5))
print ("you hit a", fdmg1)
print ("the dragon hits a", edmg1)
time.sleep(2)
if edmg1 > fdmg1:
print ("The drgon has dealt more damage than you!")
complete = 0
return complete
this is where i run into a syntax error
elif fdmg1 < 5:
print ("You didn't do enough damage to kill the drgon, but you manage to escape")
complete = 1
return complete
else:
print ("You killed the drgon!")
complete = 1
return complete
Your return must be at the end of the if...elif...else statement. This works :
if edmg1 > fdmg1:
print ("The drgon has dealt more damage than you!")
complete = 0
elif fdmg1 < 5:
print ("You didn't do enough damage to kill the drgon, but you manage to escape")
complete = 1
else:
print ("You killed the drgon!")
complete = 1
return complete
Note that if the first if-condition is True, Python won't check for the subsequent ones.
I am making a rock, paper, scissors game for a programming class. This is where I got and then PowerShell spits out that error. I don't understand what is wrong (I am a beginning Python programmer). My programming teacher is not much help and prefers the "Figure it out" approach to learning. I am genuinely stuck at this point. Any help is appreciated, thank you!
import random
def rps():
computer_choice = random.randint(1,3)
if computer_choice == 1:
comuter_choice_rock()
elif computer_choice == 2:
comuter_choice_paper()
else:
comuter_choice_scissors()
def computer_choice_rock():
user_choice = input("1 for Rock, 2 for Paper, 3 for Scissors: ")
if user_choice == "1":
print ("It's a Tie!")
try_again()
if user_choice == "2":
print ("You Win! Paper covers Rock!")
try_again()
if user_choice == "3":
print ("I Win and You Lose! Rock crushes Scissors!")
try_again()
else:
print ("Please type in 1, 2, or 3")
computer_choice_rock()
def computer_choice_paper():
user_choice = input("1 for Rock, 2 for Paper, 3 for Scissors: ")
if user_choice == "1":
print ("I Win and You Lose! Paper covers Rock!")
try_again()
if user_choice == "2":
print ("It's a Tie!")
try_again()
if user_choice == "3":
print ("You Win! Scissors cut Paper!")
try_again()
else:
print ("Please type in 1, 2, or 3")
computer_choice_paper()
def computer_choice_paper():
user_choice = input("1 for Rock, 2 for Paper, 3 for Scissors: ")
if user_choice == ("1"):
print ("You Win! Rock crushes Scissors")
try_again()
if user_choice == "2":
print ("I Win! Scissors cut Paper!")
try_again()
if user_choice == "3":
print ("It's a Tie!")
try_again()
else:
print ("Please type in 1, 2, or 3")
computer_choice_paper()
def try_again():
choice = input("Would you like to play again? Y/N: ")
if choice == "Y" or choice == "y" or choice == "Yes" or choice == "yes":
rps()
elif choice == "n" or choice == "N" or choice == "No" or choice == "no":
print ("Thanks for Playing!")
quit()
else:
print ("Please type Y or N")
try_again()
rps()
You have a typo in you code
if computer_choice == 1:
comuter_choice_rock()
elif computer_choice == 2:
comuter_choice_paper()
else:
comuter_choice_scissors()
Comuter
Your code can be simplified to an extreme degree. See the following example program. To replace either of the players with a NPC, set player_1 or player_2 with random.choice(priority). If you want to, you could even have the computer play against itself.
priority = dict(rock='scissors', paper='rock', scissors='paper')
player_1 = input('Player 1? ')
player_2 = input('Player 2? ')
if player_1 not in priority or player_2 not in priority:
print('This is not a valid object selection.')
elif player_1 == player_2:
print('Tie.')
elif priority[player_1] == player_2:
print('Player 1 wins.')
else:
print('Player 2 wins.')
You could also adjust your game so people can play RPSSL instead. The code is only slightly different but shows how to implement the slightly more complicated game. Computer play can be implemented in the same way as mentioned for the previous example.
priority = dict(scissors={'paper', 'lizard'},
paper={'rock', 'spock'},
rock={'lizard', 'scissors'},
lizard={'spock', 'paper'},
spock={'scissors', 'rock'})
player_1 = input('Player 1? ')
player_2 = input('Player 2? ')
if player_1 not in priority or player_2 not in priority:
print('This is not a valid object selection.')
elif player_1 == player_2:
print('Tie.')
elif player_2 in priority[player_1]:
print('Player 1 wins.')
else:
print('Player 2 wins.')
import sys
print('Do you want a cup of tea?')
user_input_tea = input().lower()
if user_input_tea == 'yes':
print("You feel the thirst for a nice cup of tea, now it's time to make it.")
else:
print('You feel a cup of tea is not for you.')
sys.exit(0)
equipment = []
def equipment_find(item):
if item == str(item):
print("You have acquired the " + str(item) + " , now it's time to proceed.")
equipment.append(item)
print(equipment)
else:
print("You did not enter: " + str(item))
while True:
print("Please input: " str(item))
if item == str(item):
equipment.append(item)
print(equipment)
break
print("You are going to need a kettle for this tea making process, please input kettle to acquire the kettle")
kettle = input().lower()
equipment_find(kettle)
The code above is what I have. I want it so I have the variables with user input already made, is there anyway i could automate the function to trigger with a for loop or something.
Here is a simplified example of what I think you are looking to accomplish. We specify a list of required ingredients and ask user to enter items until they have all of them. I am using set() during comparison as we don't care about order in which the items were entered.
requiredItemsList = ['kettle', 'water', 'spoon', 'sugar']
enteredItmesList = []
print("You feel the thirst for a nice cup of tea, now it's time to make it.")
while set(requiredItemsList) != set(enteredItmesList):
item = input('Enter an item: ')
if item in requiredItemsList and item not in enteredItmesList:
print('You have acquired the', item, ", now it's time to proceed.")
enteredItmesList.append(item)
else:
print('The item you entered is not valid. Please try again.')
print('You have aquired all needed items!')
print(enteredItmesList)