I need to search for multiple pattern of files and check their mtime and if it morethan 30 days then delete all the files. I am using the below command but it's deleting only one pattern of file and not all. Kindly let me know where is the mistake in my command.
find /root -type f \( -name "*.tgz" -o -name "*.bz2" \) -mtime +30 -print -exec rm '{}' +
Try escaping parentheses in the command and adding a wildcard character:
find /root -type f \( -name "*.tgz" -o -name "*.bz2" \) -mtime +30 -exec rm {} \+
Related
First one :
We found several files and we have to copy that to kat4 and here is code, but it doesn't seem to work corectly
find /home/imk-prac/ -type f -size -13c -name '*\?plik\?*' -exec cp {} /home/inf-19/aduda/\*kat1\*/\*kat2\*/\*kat4\*/ \; 2> /dev/null
'cp' I assume that it is copy, but I don't know what 'exec' and '{}' do.
Second one:
find /home/imk-prac/ \( -type f -size -13c -name '*\?plik\?*' \) -o\( -type d -name '\[Kolo1\]*' \)2> /dev/null
Generally,I understand this line (except for '2' and '-o') , but I want to add looking for files which were modificated in less that 30 days and here is what I wanted to combine with upper command :
find /home/imk-prac/ -type f -mtime -30 -exec ls -l {} \; > /dev/null
As a result I wrote it down as:
find /home/imk-prac/ \( -type f -size -13c -name '*\?plik\?' -mtime -30 -exec ls -l{}\) -o \( -type d -name '\[Kolo1\]*' \) 2> /dev/null
but it doesn't work
Moreover, I wanted to add looking for files with speciefied quantity of symbols and I found this command:
grep -Po '(^|\s)\S{64}(\s|$)' file
But I have no idea how to combine all of those 3 upper commands.
I will be grateful for any help, thank you for your time!
How to remove all files without the .txt and .exe extensions recursively in the current working directory? I need a one-liner.
I tried:
find . ! -name "*.txt" "*.exe" -exec rm -r {} \
find -type f -regextype posix-extended -iregex '.*\.(txt|exe)$'
Try this.
find . -type f ! -name "*.exe" ! -name "*.txt" -exec rm {} \;
The above command will remove all the files other than the .exe and .txt extension files in the current directory and sub directory recursively.
If you have GNU find with the -delete action:
find . -type f ! \( -name '*.txt' -o -name '*.exe' \) -delete
And if not:
find . -type f ! \( -name '*.txt' -o -name '*.exe' \) -exec rm -f {} +
using -exec ... {} + to execute rm as few times as possible, with the arguments chained.
Try the following:
rm -f $(find . -type f ! \( -name "*.txt" -o -name "*.exe" \))
This will first recursively find all files that do not end with .txt or .exe extensions, and then delete all of these files.
I am able to delete lets say all regular files in a folder older than 7 days via:
find /path/to/dir -type f -mtime +7 -exec rm {} \;
with a single problem. There is a file here (.gitignore) which I want to keep. I tried using regex but apparently findutils regex does not have support for negative lookahead (?!gitignore)
Any other ideas?
Use ! -name .gitignore
find /path/to/dir ! -name .gitignore -type f -mtime +7 -exec rm {} \;
You can group multiple arguments within escaped parentheses. Example, to remove all files except .gitignore and javascript files (ending in .js):
find /path/to/dir ! \( -name ".gitignore" -o -name "*.js" \) -type f -mtime +7 -exec rm {} \;
-o means or
I'm using this command to go through all files, directories and subdirectories to change any mentions of oldurl.com to newurl.org:
find . -type f -name '*.php' -exec sed -i 's|oldurl.com|newurl.org|g' {} +
It works fine, however, I need to exclude three sub-directories from ANY CHANGES: /cache, /archive and /etc as changing the urls with the above command in these paths breaks other scripts.
Haven't had much luck finding an answer... Is it even possible?
Many thanks for any suggestions/help.
Use finds -not Option:
find . -type f -name '*.php' -not \( -path './etc/*' -o -path './cache/*' -o -path './archive/*' \) -exec sed -i 's|oldurl.com|newurl.org|g' {} \;
In the following command i want to search only only the directories which are non hidden how can i do this using the following command .Iwant to ignore hidden directories while searching the log file
find /home/tom/project/ -name '.log.txt'
ls /home/tom/project/
dir1
dir2
.backup
.snapshot/
.ignore/
Try
find /home/tom/project -type d -name '.*' -prune -o -name .log.txt -print
This will find all files but ignore those that start with a dot so hidden files.
find /home/tom/project/ -type f \( -iname ".log.txt" ! -iname ".*" \)
EDIT:
If the above those not work, this should do the trick. It has a better regex.
find /home/tom/project/ \( ! -regex '.*/\..*' \) -type f -name ".log.txt"
EDIT2:
The following will exclude hidden folders but will search for the hidden files that have the requested pattern:
find /home/tom/project/ \( ! -regex '.*/\..*/..*' \) -type f -name ".log.txt"
EDIT3:
The grep solution :) if this doesn't work i'm lost :)
find /home/tom/project/ \( ! -regex '.*/\..*/..*' \) -exec grep -l ".log.txt" {} \;
EDIT4:
Have you tried the simple solutions?
find /home/tom/project/ -type f -name ".log.txt"
OR
find /home/tom/project/ -type f -name "*" -exec grep -l ".log.txt" {} \;