I am using logstash to push data from filebeat to elasticsearch. My data has time as hh:mm:ss a (05:21:34 AM). I want to add today's date to it.
This is filter of logstash config
filter{
grok{ some grok pattern to get time}
date {
locale => "en"
match => ["time", "hh:mm:ss a"]
target => "#timestamp"
}
}
But data converted as 2016-01-01T05:21:34.000Z
How can I change it to 2016-10-14T05:21:34.000Z?
I think logstash is smart enough to use the current year (as you're seeing), but it's not defaulting the other fields.
You should make a new field with the full datetime string you want. Something like this should work between your grok and date:
grok { }
mutate {
add_field => { "datetime" => "%{+YYYY.MM.dd} %{time}" }
}
date { }
Be sure to change your date{} pattern to use the new datetime field and its format. If you don't want the datetime field after date{} is called, you can either use a metadata field instead, or remove_field as part of date{}.
Related
How does someone replace #timestamp field in a Logstash pipeline without converting DateTime to a string and then doing a date filter on that column?
mutate {
convert => ["datetime", "string"]
}
date {
match => ["datetime", "ISO8601"]
}
To avoid multiple filters, it's possible to perform a simple rename to a field, doing it as follows:
mutate {
id => "sample-rename-timestamp"
rename => {
"datetime" => "#timestamp"
}
}
This will replace message arrival #timestamp with your provided field.
Because the jdbc output field datetime is a date type, so we can copy it as #timestamp field.
filter {
mutate {
copy => { "datetime" => "#timestamp" }
}
}
I'm trying to parse some epoch timestamps to be something more readable.
I looked around for how to parse them into a normal time, and from what I understand all I should have to do is something like this:
mutate
{
remove_field => [ "..."]
}
grok
{
match => { 'message' => '%{NUMBER:time}%{SPACE}%{NUMBER:time2}...' }
}
date
{
match => [ "time","UNIX" ]
}
An example of a message is: 1410811884.84 1406931111.00 ....
The first two values should be UNIX time values.
My grok works, because all of the fields show in Kibana with the expected values, and all the values fields I've removed aren't there so the mutate works too. The date section seems to do nothing.
From what I understand the match => [ "time","UNIX" ] should do what I want (Change the value of time to be a proper date format, and have it show on kibana as a field.) . So apparently I'm not understanding it.
The date{} filter replaces the value of #timestamp with the data provided, so you should see #timestamp with the same value as the [time] field. This is typically useful since there's some delay in the propagation, processing, and storing of the logs, so using the event's own time is preferred.
Since you have more than one date field, you'll want to use the 'target' parameter of the date filter to specify the destination of the parsed date, e.g.:
date {
match => [ "time","UNIX" ]
target => "myTime"
}
This would convert the string field named [time] into a date field named [myTime]. Kibana knows how to display date fields, and you can customize that in the kibana settings.
Since you probably don't need both a string a date version of the same data, you can remove the string version as part of the conversion:
date {
match => [ "time","UNIX" ]
target => "myTime"
remove_field => [ "time" ]
}
Consider also trying with UNIX_MS for milliseconds.
date {
timezone => "UTC"
match => ["timestamp", "UNIX_MS"]
target => "#timestamp"
}
My application produces logs, without a timestamp.
Is there a way in logstash to append timestamp to the logs on processing
something like,
mutate {
add_field => { "timestamp" => "%{date}" }
}
Logstash adds a #timestamp field by default. You don't need to set anything additional. Logstash will take the time an event is received and add the field for you.
For example if you try this command:
LS_HOME/bin/logstash -e 'input { stdin {} } output { stdout { codec => rubydebug } }'
You will see an automatically created #timestamp field in your result:
"#timestamp": "2015-07-13T17:41:13.174Z"
You can change the format and timezone using the date filter or you can match a timestamp of your event (e.g. a syslog timestamp) using other filters like grok or json.
My input has timestamp in the format of Apr20 14:59:41248 Dataxyz.
Now in my output i need the timestamp in the below format:
**Day Month Monthday Hour:Minute:Second Year DataXYZ **. I was able to remove the timestamp from the input. But I am not quite sure how to add the new timestamp.
I matched the message using grok while receiving the input:
match => ["message","%{WORD:word} %{TIME:time} %{GREEDYDATA:content}"]
I tried using mutate add_field.but was not successful in adding the value of the DAY. add_field => [ "timestamp","%{DAY}"].I got the output as the word ´DAY´ and not the value of DAY. Can someone please throw some light on what is being missed.
You need to grok it out into the individual named fields, and then you can reference those fields in add_field.
So your grok would start like this:
%{MONTH:month}%{MONTHDAY:mday}
And then you can put them back together like this:
mutate {
add_field => {
"newField" => "%{mday} %{month}"
}
}
You can check with my answer, I think this very helpful to you.
grok {
match => { "message" => "%{TIMESTAMP_ISO8601:time} \[%{NUMBER:thread}\] %{LOGLEVEL:loglevel} %{JAVACLASS:class} - %{GREEDYDATA:msg}" }
}
if "Exception" in [msg] {
mutate {
add_field => { "msg_error" => "%{msg}" }
}
}
You can use custom grok patterns to extract/rename fields.
You can extract other fields similarly and rearrange/play arounnd with them in mutate filter. Refer to Custom Patterns for more information.
I have the following format for my logs:
201407022000.log:2014-07-02 20:00;10.112.64.250;3;972819;ULC Primeline
Since it's a csv I could split the first parts pretty easily like this:
csv {
columns => ["fulldate","ip","port","electricity","customer"]
separator => ";"
remove_field => "message"
}
Now I want to split my fulldate field into a "whatever comes before the date" ( 201407022000.log: ) and the actual date field ( 2014-07-02 20:00 )
I tried to use the date filter like this:
date {
match => [ "fulldate", "YYYY-MM-dd HH:mm" ]
timezone => "Europe/Berlin"
}
I receive the following error:
Failed parsing date from field {:field=>"date",
:value=>"201407022000.log:2014-07-02 20:00",
:exception=>java.lang.IllegalArgumentException: Invalid format:
"201407022000.log:2014-07-02 20:00" is malformed at
"000.log:2014-07-02 20:00", :level=>:warn}
Unfortunately this is not working logstash fails parsing.
The reason it is failing is that you are trying to parse this:
201407022000.log:2014-07-02 20:00
With a filter that would match the format:
"YYYY-MM-dd HH:mm"
What you could do would be to use a grok on that field before parsing it:
filter {
grok {
match => { "fulldate" => "[0-9.]+log:%{TIMESTAMP_ISO8601:date}" }
}
}
If you also want to capture the filename at the start, you could create a new pattern like (that would go in a file in your pattern directory, normally /opt/logstash/patterns in UNIX based systems) this:
LOGFILENAMEPATTERN [0-9.]+log
Then your grok would become:
filter {
grok {
match => [ "fulldate" => "%{LOGFILENAMEPATTERN:filename}:%{TIMESTAMP_ISO8601:date}" ]
}
}
Finally your date pattern would become:
date {
match => [ "date", "yyyy-MM-dd HH:mm" ]
timezone => "Europe/Berlin"
}
Note, that I have changed the name of the field you are matching against, as I renamed it in the grok, and I have replaced YYYY with yyyy, as Y is Year of Era, y is year, they are not the same (according to the documentation)