I'd like to return in one cell the number of decimal places from another cell and I can't seem to figure out a formula to include the trailing zeros so that 1.50 returns 2 instead of 1.
Here's what I have:
=IF(LEN(AF443)-LEN(INT(AF443)) = 0, 0, LEN(AF443)-LEN(INT(AF443))-1)
Not all the decimal places are the same and some have to keep zeros for consistency (e.g. 9.00).
Assuming your number is in cell B2 try this formula:
=RIGHT(CELL("format",B2),-1+LEN(CELL("format",B2)))
Related
I have the following 4 rows and I wish to find the decimal length (aka scale) of that decimal value. Do note that I'm importing all of the decimal data in Excel whose cell is formatted in a "Text" format (hence the trailing zeros even after the decimal values). And I do not want to convert it into decimal. I just need to find the scale of that decimal number.
Decimal Number
Scale (Formula?)
106.520000
2
0.080100
4
15.000010
5
265.000000
0
Been struggling for a very long time now. I'd appreciate any lead on this.
This is what I have tried,
• Formula used in cell B2
=LEN(MID(NUMBERVALUE(A2),FIND(".",A2)+1,255))
You could try:
Formula in B2:
=MAX(LEN(-A2)-LEN(INT(A2))-2,0)
Note: I use a decimal comma but it shouldnt matter for you.
Trying to figure out how to count the number of leading zeros in an excel cell. The value within the cell can be comprised of both numbers and letters or just numbers or just letters. The column is formatted as a text column.
So far I have been able to use
=MIN(FIND({1,2,3,4,5,6,7,8,9},A1&"123456789"))-1
This gets me all the leading zeros correctly for cells containing only numbers but when it is a combination of both digits and letters it also counts the letters.
eg. 00012 = 3 (correct) 000ab = 5 (should be 3)
Is there a way that I can adapt this formula to not count letters?
Try:
=SEARCH(LEFT(SUBSTITUTE(TEXT(A1,"#"),"0",""),1),A1)-1
Try looking for the first digit/character that isn't a zero and subtract 1.
=AGGREGATE(15, 7, ROW($1:$9)/(MID(A2, ROW($1:$9), 1)<>"0"), 1)-1
I need a formula in Excel, not VBA please, forbidden to have such functions on my work machine. My situation is I need a number from cell A, which is a result from Today(), combined with a number from cell B, which is a result from Now(), combined with a number from cell C which is a text number, to output as a single number.
Example:
Cell A1 Cell A2 Cell A3
Formula: TODAY() NOW() 17709
Displays: 1011 1423 17709
Needed: 1011142317709
What I'm trying is this, which is a fail: =TEXT(O21,yy-mm)&""&TEXT(P21,hh,mm)&"""&VALUE(Q21)
=TEXT(O21,"yymm")&""&TEXT(P21,"hhmm")&""&VALUE(Q21)
Placed in quotes the number format and removed extra quote though not sure why you are adding null to the string.
To match the sample output OP provided the formula would be:
=TEXT(A1,"mmdd")&""&TEXT(B1,"hhmm")&VALUE(C1)
If you do not need leading zeroes to fill 5 digit placeholders for the value in Q21,
=TEXT(NOW(),"yymmhhmm")&TEXT(Q21, "0")
'possibly,
=TEXT(NOW(),"mmddhhmm")&TEXT(Q21, "0")
If you do need leading zeroes to fill 5 digit placeholders for the value in Q21,
=TEXT(NOW(),"yymmhhmm")&TEXT(Q21, "00000")
'possibly,
=TEXT(NOW(),"mmddhhmm")&TEXT(Q21, "00000")
I need to count the numbers of decimals places of a number.
The A1 cell value is:
123456.78.
The formula in B1 is:
=LEN(MOD(A1,1))
The results of MOD(A1,1) is:
0.78
I expected the LEN to be 4 (LEN(0.78)=4).
The Excel formula calculates 17 because the forumula returns:
0.779999999998836
Should I try a different approach? For example looking for the separator char?
=LEN(A1)-FIND(".",A1)
Try this:
=LEN(RIGHT(A1;LEN(A1)-FIND(",";A1)))
A better formula managing a non decimal entry and different decimal separators:
=IF(ISNUMBER(FIND(".";A1));LEN(A1)-FIND(".";A1);IF(ISNUMBER(FIND(",";A1));LEN(A1)-FIND(",";A1)))
I see that the Len function is causing the math function to return the incorrect value for some reason (Len(Mod(123456.78, 1)) is returning 17 not 4, whereas Len(Mod(6.78,1) correctly returns 4).
You can add the TEXT function to your formula to change it to text, with a format of "General" to preserve the decimal precision, before calculating the length: LEN(TEXT(MOD(A1,1), "General")).
For those wanting to use this to calculate the number of decimal places without the leading "0.", simply subtract 2 from the result.
I have 3 numbers in excel.
A1. 498
A2. 899
A3. 5209
I want the numbers as the followings:
B1. 49800
B2. 89900
B3. 52090
I am still finding the solutions via online but most of the resource is discussing about leading zeros.
Please, could you kindly give me any ideas? Thanks.
I hope this formula may be of some use:
=A1 & REPT("0"; 5 - LEN(A1))
Thought this does not set the format of the cell itself (which I doubt can be done as you are changing the value of the cell by adding the zeros)
The formula only works if you are dealing with numbers as text, so you may need to convert them to text in the formula (TEXT(A1; "0") instead of A1)
you can do this one quite easily without VBA - using an IF and the very handy REPT function:
=IF(LEN(H13)<5,H13&REPT(0,5-LEN(H13)),H13)
Essentially - if the length is less than 5 - you repeat 0 up to the amount of times that its missing.
Seems like simple math to me. Essentially you want to shift left (base 10) a certain number of times. We can do this by:
Calculate the ceiling of the base-10 logarithm of the value to get it's "length"
Subtract the result from the target "length" of 5, this is the number of places we want to shift
Take 10 to this power and multiply back by the value.
In other words, where x represents the value in column A you want to transform:
In Excel, this would be expressed as:
=A1*POWER(10,(5-CEILING(LOG10(A1),1)))