Here is the code open.py (main file) that opens a login page that has a button which when clicked closes the login page and opens a menu page:
from PyQt4 import QtGui
import sys
from loginpage import Ui_loginPage
from menu import Ui_Menu
class Form1(QtGui.QWidget, Ui_loginPage):
def __init__(self,parent=None):
QtGui.QWidget.__init__(self,parent)
self.setupUi(self)
self.login.clicked.connect(self.handleButton)
self.window2 = None
def handleButton(self):
self.close()
if self.window2 is None:
self.window2 = menu(self)
self.window2.show()
sys.exit(app.exec_())
class menu(QtGui.QWidget, Ui_Menu):
def __init__(self,parent=None):
QtGui.QWidget.__init__(self,parent)
self.setupUi(self)
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
window = Form1()
window.show()
sys.exit(app.exec_())
The code runs fine without any error, but when i click the login button, the login page closes but the menu page doesn't appear. It just doesn't show at all.
If the menu window is a child of the Form1 window, it will be hidden when the Form1 window is closed - so don't give it a parent. You also shouldn't be calling sys.exit(app.exec_()) again, so your code should look like this:
class Form1(QtGui.QWidget, Ui_loginPage):
...
def handleButton(self):
self.close()
if self.window2 is None:
self.window2 = menu()
self.window2.show()
PS: please see this answer for a more complete example of how to implement a login dialog in PyQt.
Related
I have written the below code to which I finally managed to add menu but connecitn menu to a function doesnt seem to work:
import os
from PyQt5 import uic
from PyQt5 import QtWidgets
from PyQt5 import QtCore
FILE_LOCATION = os.path.dirname(os.path.realpath(__file__))
class MainDialogWindow(QtWidgets.QDialog):
def __init__(self):
super(MainDialogWindow,self).__init__()
ui_file = os.path.join(FILE_LOCATION, "example.ui")
self._ui = uic.loadUi(ui_file, self)
self.registerCallbacks()
self.initUI()
def initUI(self):
"""Initialize the UI.
"""
self.textBrowser.setContextMenuPolicy(QtCore.Qt.CustomContextMenu)
def registerCallbacks(self):
self.textBrowser.customContextMenuRequested.connect(self.context_menu)
# self.connect(self.textBrowser, QtCore.Signal('customContextMenuRequested(const QPoint &)'), self.context_menu)
def context_menu(self, pos):
menu = QtWidgets.QMenu(self)
action = menu.addAction("clear")
menu.exec_(self.mapToGlobal(pos))
action.trigered.connect(self.clear)
def clear(self):
"""Slot to claer text.
"""
print("clear")
if __name__ == '__main__':
import sys
app = QtWidgets.QApplication(sys.argv)
window = MainDialogWindow()
window.show()
window.setGeometry(500, 300, 300, 300)
sys.exit(app.exec_())
please helpp,, I want call the clear function from the right click menu
I don't seem to understand how the menu.exec_() method works, that method blocks the execution of sequential tasks until the user selects a QAction from the QMenu. In your case, for example, until when you press "clear" and the triggered signal is emitted (note: you have a typo), but at that moment there is no connection, so the clear method will not be called. The solution is to make the connection before invoking the QMenu exec_():
def context_menu(self, pos):
menu = QtWidgets.QMenu(self)
action = menu.addAction("clear")
action.triggered.connect(self.clear)
menu.exec_(self.mapToGlobal(pos))
I have written python pyqt code to open a new window with a label from another window on a button click. The issue is ,new window exits as soon as it opens.How do i fix this.
The code I wrote is
import sys
from PyQt4 import QtGui,QtCore
class Window(QtGui.QWidget):
def __init__(self):
super(Window,self).__init__()
self.btn=QtGui.QPushButton('button',self)
self.btn.clicked.connect(display)
self.show()
class display(QtGui.QWidget):
def __init__(self):
super(display,self).__init__()
self.lab=QtGui.QLabel()
self.lab.setText("hi")
self.show()
def main():
App=QtGui.QApplication(sys.argv)
Gui=Window()
sys.exit(App.exec_())
main()
You need to keep a reference to the QWidget object for your second window. Currently when you click the button, the clicked signal is fired and it calls disp1. That creates the widget, but then it is immediately garbage collected.
Instead do this to keep a reference:
import sys
from PyQt4 import QtGui,QtCore
class Window(QtGui.QWidget):
def __init__(self):
super(Window,self).__init__()
self.btn=QtGui.QPushButton('button',self)
self.btn.clicked.connect(self.open_new_window)
self.show()
def open_new_window(self):
# creates the window and saves a reference to it in self.second_window
self.second_window = disp1()
class displ(QtGui.QWidget):
def __init__(self):
super(displ,self).__init__()
self.lab=QtGui.QLabel()
self.lab.setText("hello")
self.show()
def main():
App=QtGui.QApplication(sys.argv)
Gui=Window()
sys.exit(App.exec_())
main()
When passing a function as parameter, maybe it's better not to include the parentheses? Try
sys.exit(App.exec_)
Instead of
sys.exit(App.exec_())
EDIT : I've come up with a solution, and it's much more straightforward than I thought. Original code and question at the top. My solution after "The Question" below..
The Example
from PyQt4 import QtGui, QtCore
from example_Ui import Ui_MainWindow
from filler_Ui import Form
class TabFiller(Form):
def __init__(self, parent=None):
Form.__init__(self, parent)
def TabButtonClicked(self):
print("Tab button pressed.")
def LineEditChanged(self):
print("LineEdit contents edited in tab page!")
class MainWindow(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.setupUi(self)
tab_filler = [] # create empty list for tab contents
tab_page = [] # create empty list for tab page
tab_count = 0
def CreateNewTab(self):
tab_title = "New Tab : " + str(self.tab_count)
self.tab_filler.append(TabFiller())
self.tab_filler[self.tab_count].label.setText(tab_title)
self.tab_page.append(self.tab_filler[self.tab_count])
self.tabWidget.addTab(self.tab_page[self.tab_count], tab_title)
self.tab_count += 1
def MainButtonPressed(self):
self.CreateNewTab()
if __name__ == '__main__':
import sys
app = QtGui.QApplication(sys.argv)
window = MainWindow()
window.show()
sys.exit(app.exec_())
MainWindow contains a QTabWidget, which is a Button. clicked() signal has been defined in QtDesigner to be sent to the MainButtonPressed() function inside the MainWindow class.
Form widget also created in QTdesigner. Used to fill additional Tab Pages.
This contains a Button widget, and a LineEdit Widget.
The Question
I can't get my head around how I can tell which widget has been clicked or edited in each tab.
I know that each Tab Page is stored in the list called tab_page.
Within the MainWindow class, how would I receive a clicked() or finishedEditing() signal for a given widget in a currently active tab?
A Solution
import sys
from PyQt4.QtGui import *
from PyQt4.QtCore import *
from PyQt4 import QtGui
from example_Ui import Ui_MainWindow
from filler_Ui import Form
class MainWindow(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.setupUi(self)
tab_index = 1 # 1 because we already made a default tab in QtDesigner
def LineEditChanged(self):
findWidget = self.tabWidget.widget(self.tabWidget.currentIndex()).findChildren(QtGui.QLineEdit, "lineEdit")
if findWidget[0].isModified() == True:
print("LineEdit contents edited in tab page!")
print("Name of page edited :", "'", self.tabWidget.tabText(self.tabWidget.currentIndex()),"'")
def TabButtonPressed(self):
print("YOU DID IT!")
print("Current Tab Index = ", self.tabWidget.currentIndex())
def CreateNewTab(self, tabNum):
tab_title = "New Tab : " + str(self.tab_index)
self.tabWidget.addTab(Form(), tab_title)
def MainButtonPressed(self):
self.CreateNewTab(self.tab_index)
findWidget = self.tabWidget.widget(self.tab_index).findChildren(QtGui.QPushButton, "tabButton")
findWidget[0].clicked.connect(self.TabButtonPressed)
findWidget = self.tabWidget.widget(self.tab_index).findChildren(QtGui.QLineEdit, "lineEdit")
findWidget[0].editingFinished.connect(self.LineEditChanged)
self.tab_index += 1
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
window = MainWindow()
window.show()
sys.exit(app.exec_())
Using this there's no need for storing each tab page object in a list. You basically use the QTabWidget to index your pages, and off you go.
If anyone has a more elegant way than this, please inform ;)
As outlined in my edited question, I did find the solution to this, which is to use the QTabWidget to "index" each dynamically created tab page.
In QtDesigner I created a main window with one QTabWidget and one button thusly;
Here's the object tree for that;
NOTE: I added a signal/slot for the "Click Me!" button in QtDesigner, so that when that button is clicked, the MainButtonPressed function is called.
To fill the tab pages, I also created a Form in QtDesigner, with a button and a QLineEdit widget;
And the object tree for that;
I'll reproduce the code here. NOTE: I've now updated this answer to use findChild rather than findChildren above:
import sys
from PyQt4.QtGui import *
from PyQt4.QtCore import *
from PyQt4 import QtGui
from example_Ui import Ui_MainWindow
from filler_Ui import Form
class MainWindow(QtGui.QMainWindow, Ui_MainWindow):
def __init__(self, parent=None):
super(MainWindow, self).__init__(parent)
self.setupUi(self)
tab_index = 1 # 1 because we already made a default tab in QtDesigner
def LineEditChanged(self):
findWidget = self.tabWidget.widget(self.tabWidget.currentIndex()).findChild(QtGui.QLineEdit, "lineEdit")
if findWidget.isModified() == True:
print("LineEdit contents edited in tab page!")
print("Name of page edited :", "'", self.tabWidget.tabText(self.tabWidget.currentIndex()),"'")
def TabButtonPressed(self):
print("YOU DID IT!")
print("Current Tab Index = ", self.tabWidget.currentIndex())
def CreateNewTab(self, tabNum):
tab_title = "New Tab : " + str(self.tab_index)
self.tabWidget.addTab(Form(), tab_title)
def MainButtonPressed(self):
self.CreateNewTab(self.tab_index)
findWidget = self.tabWidget.widget(self.tab_index).findChild(QtGui.QPushButton, "tabButton")
findWidget.clicked.connect(self.TabButtonPressed)
findWidget = self.tabWidget.widget(self.tab_index).findChild(QtGui.QLineEdit, "lineEdit")
findWidget.editingFinished.connect(self.LineEditChanged)
self.tab_index += 1
if __name__ == '__main__':
app = QtGui.QApplication(sys.argv)
window = MainWindow()
window.show()
sys.exit(app.exec_())
When run, pressing the "Click Me!" button on the main tab page creates a new tab, and adds the contents of the "filler" page to it.
The variable tab_index keeps track of how many tabs there are and allows you to reference the contents of each tab.
To find a widget in a tab, you use the findChild function of Qt;
findWidget = self.tabWidget.widget(self.tab_index).findChild(QtGui.QPushButton, "tabButton")
Finding a specific widget is straightforward. You specify the type of widget you're looking for (QtGui.QPushButton) , and the name you assigned it in QtDesigner (tabButton)
In this case the found widget can be referenced by the variable findWidget.
You can then connect signals to function slots as usual;
findWidget.clicked.connect(self.TabButtonPressed)
In this case I used the new-style signal connection method to connect the clicked() signal to a function named TabButtonPressed in my program.
Rinse and repeat for each widget on the Tab Page you wish to do something with.
After that, it really is plain sailing ;)
I hope this information helps others in their GUI endeavours. You can probably use the same technique with the QToolBox widget.
I have designed 2 widgets - one is the main application widget and a custom widget which would allow me to set the preferences in my main application. They are named - main and child.
Now, I can't get the child widget to show when I click the button in the main application.
Tried to learn from the Rapid GUI programming using Python and Qt book, but the example given there is for a hand coded form and not designed using QtDesigner. I am getting confused. Kindly help.
My code so far is this-
import serial, sys
from PyQt4.QtCore import *
from PyQt4.QtGui import *
from main import Ui_Form # main.py and child.py are the ui
from child import Ui_Form as Child_Form # files generated using pyuic4
class Main(QMainWindow):
def __init__(self, parent = None):
super(Main, self).__init__(parent)
self.ui = Ui_Form()
self.ui.setupUi(self)
self.connect(self.ui.btnLaunch, SIGNAL("clicked()"), self.show)
def show(self):
dialog = QDialog()
dialog.ui = Child_Form()
dialog.ui.setupUi(self)
if __name__ == "__main__":
app = QApplication(sys.argv)
myapp = Main()
myapp.show()
sys.exit(app.exec_())
However, nothing happens when I try to launch this program.
Instead of this code:
self.connect(self.ui.btnLaunch, SIGNAL("clicked()"), self.show)
def show(self):
dialog = QDialog()
dialog.ui = Child_Form()
dialog.ui.setupUi(self)
try with this, it should work:
self.connect(self.ui.btnLaunch, SIGNAL("clicked()"), self.showDialog)
def showDialog(self):
dialog = QDialog()
dialog.ui = Child_Form()
dialog.ui.setupUi(self)
dialog.show()
I've got a simple tray icon application, but "About" context menu item doesn't work at all.
I'm definitly mising something simple, but important here.
The question is what should i fix to see "About" menu item working?
import sys
from PyQt4 import QtCore
from PyQt4 import QtGui
class SystemTrayIcon(QtGui.QSystemTrayIcon):
def __init__(self, parent=None):
QtGui.QSystemTrayIcon.__init__(self, parent)
self.setIcon(QtGui.QIcon("icon.png"))
self.iconMenu = QtGui.QMenu(parent)
appabout = self.iconMenu.addAction("About")
appexit = self.iconMenu.addAction("Exit")
self.setContextMenu(self.iconMenu)
self.connect(appabout,QtCore.SIGNAL('triggered()'),self.showAbout)
self.connect(appexit,QtCore.SIGNAL('triggered()'),self.appExit)
self.show()
def showAbout(self):
QtGui.QMessageBox.information(self, self.tr("About app"), self.tr("My text here."))
def appExit(self):
sys.exit()
if __name__ == "__main__":
app = QtGui.QApplication(sys.argv)
trayIcon = SystemTrayIcon()
trayIcon.show()
sys.exit(app.exec_())
My solution is
def showAbout(self):
QtGui.QMessageBox.information(QtGui.QWidget(), self.tr("About Tunarium"), self.tr("Your text here."))