sample input
in parsing a text file .txt = ["'blah.txt'", "'blah1.txt'", "'blah2.txt'" ]
the expected output in another text file out_path.txt
blah.txt
blah1.txt
blah2.txt
Code that I tried, this just appends "[]" to the input file. While I also tried perl one liner replacing double and single quotes.
read_out_fh = open('out_path.txt',"r")
for line in read_out_fh:
for word in line.split():
curr_line = re.findall(r'"(\[^"]*)"', '\n')
print(curr_line)
this happens because while you reading a file it will be taken as string and not as a list even if u kept the formatting of a list. thats why you getting [] while doing re.for line in read_in_fh: here you are taking each letters in the string thats why you are not getting the desired output. so iwrote something first to transform the string into a list. while doing that i also eliminated "" and '' as you mensioned. then wrote it in to a new file example.txt.
Note: change the file name according to your files
read_out_fh = open('file.txt',"r")
for line in read_out_fh:
line=line.strip("[]").replace('"','').replace("'",'').split(", ")
with open("example.txt", "w") as output:
for word in line:
#print(word)
output.write(word+'\n')
example.txt(outputfile)
blah.txt
blah1.txt
blah2.txt
The code below works out for your example you gave in the question:
# Content of textfile.txt:
asdasdasd=["'blah.txt'", "'blah1.txt'", "'blah2.txt'"]asdasdasd
# Code:
import re
read_in_fh = open('textfile.txt',"r")
write_out_fh = open('out_path.txt', "w")
for line in read_in_fh:
find_list = re.findall(r'\[(".*?"*)\]', line)
for element in find_list[0].split(","):
element_formatted = element.replace('"','').replace("'","").strip()
write_out_fh.write(element_formatted + "\n")
write_out_fh.close()
I need to search for a name in a file and in the line starting with that name, I need to replace the fourth item in the list that is separated my commas. I have began trying to program this with the following code, but I have not got it to work.
with open("SampleFile.txt", "r") as f:
newline=[]
for word in f.line():
newline.append(word.replace(str(String1), str(String2)))
with open("SampleFile.txt", "w") as f:
for line in newline :
f.writelines(line)
#this piece of code replaced every occurence of String1 with String 2
f = open("SampleFile.txt", "r")
for line in f:
if line.startswith(Name):
if line.contains(String1):
newline = line.replace(str(String1), str(String2))
#this came up with a syntax error
You could give some dummy data which would help people to answer your question. I suppose you to backup your data: You can save the edited data to a new file or you can backup the old file to a backup folder before working on the data (think about using "from shutil import copyfile" and then "copyfile(src, dst)"). Otherwise by making a mistake you could easily ruin your data without being able to easily restore them.
You can't replace the string with "newline = line.replace(str(String1), str(String2))"! Think about "strong" as your search term and a line like "Armstrong,Paul,strong,44" - if you replace "strong" with "weak" you would get "Armweak,Paul,weak,44".
I hope the following code helps you:
filename = "SampleFile.txt"
filename_new = filename.replace(".", "_new.")
search_term = "Smith"
with open(filename) as src, open(filename_new, 'w') as dst:
for line in src:
if line.startswith(search_term):
items = line.split(",")
items[4-1] = items[4-1].replace("old", "new")
line = ",".join(items)
dst.write(line)
If you work with a csv-file you should have a look at the csv module.
PS My files contain the following data (the filenames are not in the files!!!):
SampleFile.txt SampleFile_new.txt
Adams,George,m,old,34 Adams,George,m,old,34
Adams,Tracy,f,old,32 Adams,Tracy,f,old,32
Smith,John,m,old,53 Smith,John,m,new,53
Man,Emily,w,old,44 Man,Emily,w,old,44
I have the following problem:
I want to convert a tab delimited text file to a csv file. The text file is the SentiWS dictionary which I want to use for a sentiment analysis ( https://github.com/MechLabEngineering/Tatort-Analyzer-ME/tree/master/SentiWS_v1.8c ).
The code I used to do this is the following:
txt_file = r"SentiWS_v1.8c_Positive.txt"
csv_file = r"NewProcessedDoc.csv"
in_txt = csv.reader(open(txt_file, "r"), delimiter = '\t')
out_csv = csv.writer(open(csv_file, 'w'))
out_csv.writerows(in_txt)
This code writes everything in one row but I need the data to be in three rows as normally intended from the file itself. There is also a blank line under each data and I don´t know why.
I want the data to be in this form:
Row1 Row2 Row3
Word Data Words
Word Data Words
instead of
Row1
Word,Data,Words
Word,Data,Words
Can anyone help me?
import pandas
It will convert tab delimiter text file into dataframe
dataframe = pandas.read_csv("SentiWS_v1.8c_Positive.txt",delimiter="\t")
Write dataframe into CSV
dataframe.to_csv("NewProcessedDoc.csv", encoding='utf-8', index=False)
Try this:
import csv
txt_file = r"SentiWS_v1.8c_Positive.txt"
csv_file = r"NewProcessedDoc.csv"
with open(txt_file, "r") as in_text:
in_reader = csv.reader(in_text, delimiter = '\t')
with open(csv_file, "w") as out_csv:
out_writer = csv.writer(out_csv, newline='')
for row in in_reader:
out_writer.writerow(row)
There is also a blank line under each data and I don´t know why.
You're probably using a file created or edited in a Windows-based text editor. According to the Python 3 csv module docs:
If newline='' is not specified, newlines embedded inside quoted fields will not be interpreted correctly, and on platforms that use \r\n linendings on write an extra \r will be added. It should always be safe to specify newline='', since the csv module does its own (universal) newline handling.
How do I split a text string according to an explicit newline ('\n')?
Unfortunately, instead of a properly formatted csv file, I am dealing with a long string of text with "\n" where the newline would be. (example format: "A0,B0\nA1,B1\nA2,B2\nA3,B3\n ...") I thought a simple bad_csv_list = text.split('\n') would give me a list of the two-valued cells (example split ['A0,B0', 'A1,B1', 'A2,B2', 'A3,B3', ...]). Instead I end up with one cell and "\n" gets converted to "\\n". I tried copy-pasting a section of the string and using split('\n') and it works as I had hoped. The print statement for the file object tells me the following:
<_io.TextIOWrapper name='stats.csv' mode='r' encoding='cp1252'>
...so I suspect the problem is with the cp1252 encoding? Of note tho: Notepad++ says the file I am working with is "UTF-8 without BOM"... I've looked in the docs and around SO and tried importing io and codec and prepending the open statement and declaring encoding='utf8' but I am at a loss and I don't really grok text encoding. Maybe there is a better solution?
from sys import argv
# import io, codec
filename = argv[1]
file_object = open(filename, 'r')
# file_object = io.open(filename, 'r', encoding='utf8')
# file_object = codec.open(filename, 'r', encoding='utf8')
file_contents = file_object.read()
file_list = file_contents.split('\n')
print("1.) Here's the name of the file: {}".format(filename))
print("2.) Here's the file object info: {}".format(file_object))
print("3.) Here's all the files contents:\n{}".format(file_contents))
print("4.) Here's a list of the file contents:\n{}".format(file_list))
Any help would be greatly appreciated, thank you.
If it helps to explain what I am dealing with, here's the contents of the stats.csv file:
Albuquerque,749\nAnaheim,371\nAnchorage,828\nArlington,503\nAtlanta,1379\nAurora,425\nAustin,408\nBakersfield,542\nBaltimore,1405\nBoston,835\nBuffalo,1288\nCharlotte-Mecklenburg,647\nCincinnati,974\nCleveland,1383\nColorado Springs,455\nCorpus Christi,658\nDallas,675\nDenver,615\nDetroit,2122\nEl Paso,423\nFort Wayne,362\nFort Worth,587\nFresno,543\nGreensboro,563\nHenderson,168\nHouston,992\nIndianapolis,1185\nJacksonville,617\nJersey City,734\nKansas City,1263\nLas Vegas,784\nLexington,352\nLincoln,397\nLong Beach,575\nLos Angeles,481\nLouisville Metro,598\nMemphis,1750\nMesa,399\nMiami,1172\nMilwaukee,1294\nMinneapolis,992\nMobile,522\nNashville,1216\nNew Orleans,815\nNew York,639\nNewark,1154\nOakland,1993\nOklahoma City,919\nOmaha,594\nPhiladelphia,1160\nPhoenix,636\nPittsburgh,752\nPlano,130\nPortland,517\nRaleigh,423\nRiverside,443\nSacramento,738\nSan Antonio,503\nSan Diego,413\nSan Francisco,704\nSan Jose,363\nSanta Ana,401\nSeattle,597\nSt. Louis,1776\nSt. Paul,722\nStockton,1548\nTampa,616\nToledo,1171\nTucson,724\nTulsa,990\nVirginia Beach,169\nWashington,1177\nWichita,742
And the result from the split('\n'):
['Albuquerque,749\\nAnaheim,371\\nAnchorage,828\\nArlington,503\\nAtlanta,1379\\nAurora,425\\nAustin,408\\nBakersfield,542\\nBaltimore,1405\\nBoston,835\\nBuffalo,1288\\nCharlotte-Mecklenburg,647\\nCincinnati,974\\nCleveland,1383\\nColorado Springs,455\\nCorpus Christi,658\\nDallas,675\\nDenver,615\\nDetroit,2122\\nEl Paso,423\\nFort Wayne,362\\nFort Worth,587\\nFresno,543\\nGreensboro,563\\nHenderson,168\\nHouston,992\\nIndianapolis,1185\\nJacksonville,617\\nJersey City,734\\nKansas City,1263\\nLas Vegas,784\\nLexington,352\\nLincoln,397\\nLong Beach,575\\nLos Angeles,481\\nLouisville Metro,598\\nMemphis,1750\\nMesa,399\\nMiami,1172\\nMilwaukee,1294\\nMinneapolis,992\\nMobile,522\\nNashville,1216\\nNew Orleans,815\\nNew York,639\\nNewark,1154\\nOakland,1993\\nOklahoma City,919\\nOmaha,594\\nPhiladelphia,1160\\nPhoenix,636\\nPittsburgh,752\\nPlano,130\\nPortland,517\\nRaleigh,423\\nRiverside,443\\nSacramento,738\\nSan Antonio,503\\nSan Diego,413\\nSan Francisco,704\\nSan Jose,363\\nSanta Ana,401\\nSeattle,597\\nSt. Louis,1776\\nSt. Paul,722\\nStockton,1548\\nTampa,616\\nToledo,1171\\nTucson,724\\nTulsa,990\\nVirginia Beach,169\\nWashington,1177\\nWichita,742']
Why does it ADD a \ ?
dOh!!! ROYAL FACE PALM! I just wrote all this out an then realized that all I needed to do was put an escape slash before the \newline:
file_list = file_contents.split('\\n')
I'm gonna post this anyways so y'all can have a chuckle ^_^
Ive a csv file that I would like to get all the rows in one column. Ive tried importing into MS Excel or Formatting it with Notedpad++ . However with each try it considers a piece of data as a new row.
How can I format file with pythons csv module so that it removes a string "BRAS" and corrects the format. Each row is found between a quote " and delimiter is a pipe |.
Update:
"aa|bb|cc|dd|
ee|ff"
"ba|bc|bd|be|
bf"
"ca|cb|cd|
ce|cf"
The above is supposed to be 3 rows, however my editors see them as 5 rows or 6 and so forth.
import csv
import fileinput
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
if 'BRAS' not in line:
w.write(line)
N.B I get a unicode error when trying to use in python.
return codecs.charmap_decode(input,self.errors,decoding_table)[0]
UnicodeDecodeError: 'charmap' codec can't decode byte 0x8f in position 18: character maps to <undefined>
This is a quick hack for small input files (the content is read to memory).
#!python2
fnameIn = 'ventoya.csv'
fnameOut = 'ventoya2.csv'
with open(fnameIn) as fin, open(fnameOut, 'w') as fout:
data = fin.read() # content of the input file
data = data.replace('\n', '') # make it one line
data = data.replace('""', '|') # split char instead of doubled ""
data = data.replace('"', '') # remove the first and last "
print data
for x in data.split('|'): # split by bar
fout.write(x + '\n') # write to separate lines
Or if the goal is only to fix the extra (unwanted) newline to form a single-column CSV file, the file can be fixed first, and then read through the csv module:
#!python2
import csv
fnameIn = 'ventoya.csv'
fnameFixed = 'ventoyaFixed.csv'
fnameOut = 'ventoya2.csv'
# Fix the input file.
with open(fnameIn) as fin, open(fnameFixed, 'w') as fout:
data = fin.read() # content of the file
data = data.replace('\n', '') # remove the newlines
data = data.replace('""', '"\n"') # add the newlines back between the cells
fout.write(data)
# It is an overkill, but now the fixed file can be read using
# the csv module.
with open(fnameFixed, 'rb') as fin, open(fnameOut, 'wb') as fout:
reader = csv.reader(fin)
writer = csv.writer(fout)
for row in reader:
writer.writerow(row)
For solving this you need not to go to even code.
1: Just open file in Notepad++
2: In first line select from | symble till next line
3: go to replace and replace the selected format with |
Search mode can be normal or extended :)
Well, since the line breaks are consistent, you could go in and do find/replace as suggested, but you could also do a quick conversion with your python script:
import csv
import fileinput
linecount = 0
with open('ventoya.csv') as f, open('ventoya2.csv', 'w') as w:
for line in f:
line = line.rstrip()
# remove unwanted breaks by concatenating pairs of rows
if linecount%2 == 0:
line1 = line
else:
full_line = line1 + line
full_line = full_line.replace(' ','')
# remove spaces from front of 2nd half of line
# if you want comma delimiters, uncomment next line:
# full_line = full_line.replace('|',',')
if 'BRAS' not in full_line:
w.write(full_line + '\n')
linecount += 1
This works for me with the test data, and if you want to change the delimiters while writing to file, you can. The nice thing about doing with code is: 1. you can do it with code (always fun) and 2. you can remove the line breaks and filter content to the written file at the same time.