I need to execute a cronjob to run once for 7 days alone.I have tried like this:
0 0 * * 0-6 myscript.sh
It gets run for once a day and running every day of the week since i gave as 0-6.
But i need to run a job for one week alone not followed by multiple days.I donot want to mention the date of the month,since i need randomly.
(or)
Is it possible through "at" command if it is not through "cron"???
How can i set job to run for 7 days alone guys????
Thanks
Related
I am using cron and I need to schedule my workflow, so that it runs every day hourly, just except 2 hours from 12 AM until 2 AM. Meaning it needs to run daily from 2 AM and kick off every hour, but just when the clock hits 12 AM it should't run for 2 hours. And then starts back at 2 AM to run every hour.
Would appreciate a solution.
This is a CRON job
0 0 2-23 ? * * *
Description: Job will start at second:00, at the minute:00, every hour between 02 am and 23 pm, of every day
I have found this website useful to create CRON job
I tried using both npm packages "cron" and "node-schedule" to make this work, but i couldn't.
Let's say i want to start the cron job at 6.30PM, and starting from 6PM i want it to be executed every 2 hours.
First is that i couldn't make it work if it is not an exact hour , meaning if it is not (1PM,2PM,8PM.....)
So i supposed that it will run at 6PM sharp and not 6.30PM
I tried this pattern:
"0 18-23/2 * * *" which is supposed to work from 18 to 23, escaping two hours [18,20,22,00] but once it's past midnight it will stop til it's 18h again. i want it to keep executing every 2 hours (meaning it executes at 2AM and so on ...)
IS that possible with cron jobs ?
You could do a basic shell script to check if the current date and time are greater than or equal to the date and time you specify before executing the command.
Please note that the date and time are specified in UTC. This will cause the cron to run every 2 hours 30 minutes past the top of the hour but it wont actually activate until after 6PM December 3rd 2019 UTC. Also note that the date command may vary with different flavors of nix* / BSD / OSX.
30 */2 * * * if [ $(date --utc +%s) -ge $(date --utc --date "2019-12-03T18:00:00" +%s) ]; then (command) fi
I believe you are talking about using crontab to schedule jobs.
crontab is designed to let you set the frequency based on many things but it is not designed to become "enabled" a certain time.
so the following will run every two hours
0 0,2,4,6,8,10,12,14,16,18,20,22 * * * (command)
Lets say it is 1st of the month and you want it to run every two hours starting at 6 pm
I would do the following
0 18,20,22 1 * * (command)
0 0,2,4,6,8,10,12,14,16,18,20,22 2 * * (command)
This means that today (based on day of month it would run starting at 6 and tomorrow it will run every two hours. Then sometime tomorrow I would edit the file and remove the first line and change the '2' for the day of month to a '*' (to match the first line I showed you) -- now it will always run every two hours.
tldr; edit crontab to work for two days and then edit it after the go live to work for every day.
I am trying to run a method every 10 minutes for the next 3 days and only that.
I have tried this :
cron.expression=0 */10 * * * ?
This will run every 10 minutes every day, every month.
But I only want it to be limited to the next 3 days starting from NOW.
I just can't find how to use (now -> 3 days) in cron
I am using this website and Spring scheduler Spring scheduler doc without success
Based on the Spring specs you can't define this logic directly in to the cron record. You should add such logic in to the program you run with this cron
For example, if I have a cron job that I want to run every 9 hours:
0 */9 * * * my_script
The job is executed at 00:00, 9:00, and 18:00; and then the same hours the next day.
What I want is for the job to execute at 00:00, 9:00, 18:00; then 03:00, 12:00, 21:00 the next day -- a true "every 9 hours".
Is there any way make cron job run EVERY 9 hours?
Specifying */9 means that the job runs every 9 hours starting at 00:00. It starts again at 00:00 every day.
There is no syntax in cron to run a job every 9 hours.
What you can do is run a job every 3 hours, and have the command itself examine the current time and only execute 1 time out of 3. Or it can run every hour and execute one time out of every 9. Don't assume that the current time will be exact; it might run a few seconds after the hour.
I want to run a script through linux cron which will run after 9 hour.
For example: If current time is 00:34 and I start the cron now, then my shell script should run at 00:34 and then at 09:34 and at 18:34 and so on. For this I have entered the below cron :
34 */9 * * * /path/to/script/foo.sh
But this is not working as expected. So, Any help would be helpful.
I don't think its possible to do that for every 9 hour window. The way you have currently scheduled it, it will run at 00:34, 09:34, 18:34 every day and not in 00:34, 09:34, 18:34, 3:34, 12:34 fashion.
You should instead run it every 3 hours (24 hours/day, 3 is the highest common factor between 24 and 9), using an interim file for storing whether it is the first, second or third 3-hour window of the 9 hours. Based on this value, run the task whenever its the first such window.