Substituting a calculated range into a lookup - excel

In the contents of cell F3 I have the following formula (which takes one value on the current row and looks it up in another sheet, returning a range based upon where it was found):
="'OBS Procedures'!" & ADDRESS(MATCH(INDIRECT(ADDRESS(ROW(),1)),'OBS Procedures'!A:A,0),3) & ":" & ADDRESS(MATCH(INDIRECT(ADDRESS(ROW(),1)),'OBS Procedures'!A:A,0),50)
which outputs, as it ought, the text : 'OBS Procedures'!$C$1:$AX$1
All good so far.
I have in another cell (which outputs the rightmost filled cell of the range generated by cell F3):
=LOOKUP(2,1/(INDIRECT(F3)<>""),INDIRECT(F3))
And this outputs , as it ought, the text : 5 : 18/07/2016
Great.
But I'm wanting to get rid of cell F3 entirely, and incorporate the formula for F3 into the second formula above.
Simply copying in the F3 formula between the second INDIRECT() works fine. But copying it into the first F3 generates #N/A.
Specifically :
=LOOKUP(2,1/(INDIRECT("'OBS Procedures'!" & ADDRESS(MATCH(INDIRECT(ADDRESS(ROW(),1)),'OBS Procedures'!A:A,0),3) & ":" & ADDRESS(MATCH(INDIRECT(ADDRESS(ROW(),1)),'OBS Procedures'!A:A,0),50))<>""),INDIRECT(F3))
generates #N/A
Whereas even
=LOOKUP(2,1/(INDIRECT("'OBS Procedures'!$C$1:$AX$1")<>""),INDIRECT(F3))
and generates what I expect
(Keeping the intermediate cell or doing this in VBA, which is my usual go-to for anything more than simple formulae, isn't an option in this case)
I'm simply not seeing what I am doing wrong here - can anyone enlighten me, please? :)

As hinted at in my comments, I'm afraid to say that the construction you are currently using is a very poor one indeed, and could be replaced with a set-up which is both non-volatile and far more efficient.
The reason for your error is due to the manner in which you are using the ROW function. In fact, for generating incremental integers in this manner, ROW is, for several reasons, inferior to ROWS (https://excelxor.com/2014/08/25/row-vs-rows-for-consecutive-integer-generation/).
Despite its inferiority in this respect, however, this does not usually lead to errors. Here, you are a little unfortunate in that, due to the nature of your construction, Excel is expecting an array output from the portion:
ROW()
As such, and assuming for the sake of argument that the formula we are discussing is in row 1, this part:
ADDRESS(ROW(),1)
which, under different circumstances, would evaluate to:
"$A$1"
here evaluates instead to:
{"$A$1"}
since the LOOKUP is lending the necessary array-coercion to the overall construction such that the ROW() portion is expected to deliver an array output, albeit one containing just a single value. In fact, here (and you can see this by using the Evaluate Formula feature), this part evaluates to (for row 1), not 1, but {1}.
And so here:
INDIRECT(ADDRESS(ROW(),1))
is:
INDIRECT({"$A$1"})
and since, in general, INDIRECT is incapable of resolving an array of values (though this can be achieved via further manipulation), this part errors.
To avoid this, you can use ROWS, e.g. (for row 1):
ADDRESS(ROWS($1:1),1)
or else coerce the array output from ROW into a non-array type via some suitable additional function, e.g. SUM, viz:
ADDRESS(SUM(ROW()),1)
That said, I really think that you need to rethink your whole approach here. For example, this:
=LOOKUP(2,1/(INDEX('OBS Procedures'!$C:$AX,MATCH(A1,'OBS Procedures'!A:A,0),)<>""),INDEX('OBS Procedures'!$C:$AX,MATCH(A1,'OBS Procedures'!A:A,0),))
assumed to be in row 1, would be equivalent to your:
=LOOKUP(2,1/(INDIRECT("'OBS Procedures'!" & ADDRESS(MATCH(INDIRECT(ADDRESS(ROW(),1)),'OBS Procedures'!A:A,0),3) & ":" & ADDRESS(MATCH(INDIRECT(ADDRESS(ROW(),1)),'OBS Procedures'!A:A,0),50))<>""),INDIRECT(F3))
(again assumed to be in row 1), and not only does not require the prior construction of a text string representing a range, but is also concise and, importantly, non-volatile.
Regards

Related

How to convert code formula to excel data validation formula

I don't have any experience with creating excel data validation formulas.
I have 2 code formulas, which are generated in java code, which are coming from excel data validations:
COUNTA('User Input Sheet'!A:A)-4
IF(COUNTA(INDIRECT(ADDRESS(ROW(A5),COLUMN(A5),1,1,"User Input Sheet") & ":" & ADDRESS(ROW(AJ5),COLUMN(AJ5))))=0, "","POP")
Can someone help me how to write the data validation formula for the above two, as I have to use for different cells, but don't know how to put in cell data validation ?
Providing more information on what it is you're actually trying to do, will help you, as well as helping anyone who's trying to help you. e.g.:
Your 1st formula returns the number of non-empty cells in column A of a sheet, less 4.
But you don't say if the cell being validated needs to be more, less, the same or not the same as that. If you know the answer to that, the formula as is (with = in front) will work directly in the Data Validation 'value range' fields. e.g.:
The above example validates that a cell value is between zero and the results of the formula.
Suggest adapting and applying that, and if you're not getting the expect result, explain what you were aiming for, what you did, and what the results are.
=====================================================
The second formula is more problematic in terms of trying to guess what it is you're trying to do.
One thing I'll point out first thought: it uses INDIRECT in a completely unnecessary way (and that's inherently unwise). So the first thing to do is covert to a direct reference per:
=IF(COUNTA('User Input Sheet'!A5:J5)=0, "","POP")
But even then, you have a formula that returns a zero-length string ("") or literal 'POP' (based on A5:J5 being empty or not).
And it's unclear how you intend to use that to validate a cell. One guess would be the user has to enter "POP" or nothing (depending on A5:J5 being populated or not). But that seems to be an odd thing to do.

Can these formulas be simplified? Why does INDIRECT function seem to not work inside an ISBLANK test within a MATCH formula?

Summary
I need an array formula that takes a row of data of certain length from Sheet1. For that row, in each column that is not blank, I need to grab the Sheet1 header value for that column and display that data in a continuous row on Sheet2 (without any spaces in between the row's cells).
Background
I have a table of data (employees and industry certifications with expiration date being the table's cell data) on sheet 1, with a row for each employee the spreadsheet is tracking. The certifications are the columns.
We are using this information to link to ID Badge Printer software (Bodno Silver), where we are limited to linking columns of data to a particular textbox.
The problem lies in the fact that not everyone has every certification. The rows are peppered with blanks separating the certifications that each employee does have. While setting up the required text boxes in the badge software template, that each link to a specific column, I quickly realized that since not everyone has every certification if we used the data how it was we would have a bunch of strange looking blanks in between the listed certifications rather than a continuous list.
What I did
My solution to this (which I'm open to a better one if anyone knows of one, other than "use better software"), was to create a new sheet and array formulas that no one would use except for me and the id printer software. This sheet would have a similar data table that took the rows of data interspersed with blank cells between expiration dates, and put the matching column headers for cells that had a date in them into a continuous row of the same maximum length (eliminating the blank cells).
Essentially, this would allow me to circumvent the restrictions of the badge software and each textbox would be MatchedCert1, MatchedCert2, MatchedCert3, etc. up to the original maximum number of certifications.
Pictures are probably better than my words at explaining what I am going for:
Sheet1 (source)
Sheet2 (result)
The array formulas
I worked on this one for a while. What I thought would be a simple INDEX, MATCH, ISBLANK formula (that I could create using the appropriate relative and absolute cell linking) and then expand to the whole sheet turned into a witch hunt and me praying for forgiveness for my sins to all that may be holy. Also a lot of googling.... I realized quickly that this one may not be so simple after all.
Finally, I arrived at the following two array formulas in order to correctly show what I was going for:
First Column of training section
{=IFERROR(INDEX(Sheet1!$E$2:$P3,1,MATCH(FALSE,ISBLANK(Sheet1!E3:Q3),0)),"")}
(easy enough, right? I thought so...)
I felt good about this until I tried to think through what would be required to get the formula to be universal so that I could use it on the entire table.
I feel dirty just putting the following in public, but here goes...
Second column through last column array formula
{=IFNA(INDEX(INDIRECT(ADDRESS(ROW($E$2),(MATCH(E3,Sheet1!$2:$2,0)+1),1,1, "Sheet1")&":"&ADDRESS(ROW(E3),COLUMN($Q3),1)),1,MATCH(FALSE, ISBLANK(INDEX(INDIRECT("Sheet1!"&ADDRESS(ROW(E3),(MATCH(E3,Sheet1!$2:$2,0)+1),1)&":"&ADDRESS(ROW(E3),COLUMN($Q3),1)),0,0)), 0)),"")}
(please don't call the police...)
[ninja edit] While this array formula works for 2nd result column through the final column, it doesn't work if there's not a blank column following the result range. The actual spreadsheet has 4 different groups of certifications that run horizontally, but I was able to just add a blank column in the corresponding data from the other sheet easily enough, so I just let it go. I'd give somebody a nickle for the answer to why that's the case here too [/edit]
Results
The first array formula, and INDEX MATCH using ISBLANK is rather straightforward.
The biggest question for me here, and the thing that drove me absolutely nuts for a couple of days, is why the second array formula requires the additional INDEX function nested inside of the ISBLANK function.
While taking the function apart and experimenting I realized that if I have any INDIRECT reference inside a ISBLANK function, which is itself inside of a MATCH function, the result of the match was ALWAYS 1:
{=MATCH(FALSE,ISBLANK(INDIRECT("$E3:$Q3")), 0)}
The above ALWAYS returns 1, whereas if I put the range in explicitly, the function would work just fine. That wasn't an option for me, since I needed to dynamically return the starting position for the match using the previous cell's address.
However, adding an INDEX function (with a column and row value of 0) to encapsulate the INDIRECT function provides the correct answer. I figured this out just by trial and error.
Questions
Can someone with more knowledge please let me know what is causing this behavior?
As a broader question, given I am limited to using formulas (no VBA), I would also like to know if I'm going about this in the wrong way or if there is a much simpler way of accomplishing this without this behemoth of a formula?
I know this sheet will probably require maintenance in a year - good luck future self!
Put this in E3, Copy over and down
=IFERROR(INDEX(Sheet1!$2:$2,AGGREGATE(15,6,COLUMN(INDEX($E:$P,MATCH($C3,Sheet1!$C:$C,0),0))/(INDEX(Sheet1!$E:$P,MATCH($C3,Sheet1!$C:$C,0),0)<>""),COLUMN(A:A))),"")
As to why your formula is not working, it is too convoluted to parse. One note, unless the sheets is the variable, one should avoid INDIRECT as much as possible. INDEX can almost always be used in its place.
Both INDIRECT and ADDRESS are volatile functions. Volatile functions will re-calculate every time Excel re-calculates, leading to a lot of unnecessary computations.
Not a solution but to answer why you are seeing this behavior:
EDIT: PREVIOUS EXPLANATION WAS JUST PLAIN WRONG
This confused me so, I did a bit of investigation:
I think that your problem is actually coming from the ISBLANK function because it is intended to be used with single values, and cannot handle ranges. Any BLANKs which are returned by functions are only converted to numeric values (0), when the BLANK is returned to (or displayed on) the sheet. If the function is returning to another function, the BLANK value seems to be preserved.
EDIT: ADDING A SOLUTION WITHOUT ARRAY FORMULAS
This is probably more complex than using an array formula... but I strongly dislike them, so do all I can to remove them.
Firstly, I would add an index to your positions in the results sheet:
=IF(F$7>COUNTIFS($F3:$L3,"<>"),
"",
IF(
MINIFS(
$F$7:$L$7,$F$7:$L$7,
">" & IFNA(INDEX($F$7:$L$7,MATCH(E9,$F$2:$L$2,0)),0),
$F3:$L3,
"<>"
)=0,
"",
INDEX(
$F$2:$L$2,
MATCH(
MINIFS(
$F$7:$L$7,$F$7:$L$7,
">" & IFNA(INDEX($F$7:$L$7,MATCH(E9,$F$2:$L$2,0)),0),
$F3:$L3,
"<>"
),
$F$7:$L$7,
0
)
)
)
)
Basically, the formula looks at the cert in the previous cell, and looks for the next, minimum index, greater than that.

Inserted formula with cell reference does not recognize new input

I swear this just worked yesterday...
I have a program that creates formulas within certain cells that depend on subsequent data entries into other cells:
Cells(i, 40).Formula = "= (N" & i & ")/AP" & i
So, APi can be input and/or changed after the fact, and the formula should give you the result for whatever value is there. However, I get a #Div/0! error no matter what value is in that cell. When I evaluate the formula (within Excel) and step through the calculations, it shows this (for one particular cell):
= (N64)/AP64 = (47.35)/AP64 = 47.35/AP64 = 47.35/9 = #DIV/0!
So, the formula recognizes that there is a value in the cell AP64, but then does not use it to properly calculate the result.
As I said at the top, this worked as I expected yesterday afternoon when I was testing it. Now that I need other people to start using it, of course, it doesn't. I changed nothing within the program relative to these lines of code.
I apologize if this is answered elsewhere - I really have no idea how to create a search for this type of problem.
Two things to check:
1) Value of the cells used is formatted to a number (i've had #Value based on that a couple times) and
2) verify that modifying the code using fixed references provides the appropriate output ("A16" for some reason wasn't recognized as a cell reference in one I had show up). E.g., "$N" & i & "/$AP" & i
If those both look alright, you might try something like:
.Range(.Cells(3,40),.Cells(lr,40)).Formula = "=$N3/$AP3" 'ensure no random spaces
This should act like a fill-down in which the # 3 is iterated with the same row as the formula.

Is there a function, that would return "" when input ref is empty, and its contents if it is not?

IMO Excel has weird treatment of empty Cells.
I am building a complex array formula. One of the referenced ranges contain cells, that may, or may not be empty, and if not empty, they can contain both numeric values and strings.
What function can I use, to get the value of the cell if the cell is not empty, and "" (or anything other non-numeric, e.g. #N/A) if the cell is empty?
I want to get something like this working:
=MIN(OFFSET(<column vector that contains text, numbers and empty cells>;<row vector of indices>-1;0))
This form of formula returns an #ARG error, as was explained in the answer to Why this array formula doesn't work?.
But when I prefix the OFFSET with N, it transforms any empty cell into 0, so the net result is 0 (unless there are negative numbers in the column vector).
=MIN(L(OFFSET(<column vector>;<row vector of indices>-1;0)))
Is there any formula, that only dereferences the reference returned by OFFSET preserving the "emptyness" of the empty cell? Or maybe there is an alternate way of solving the problem, like
=MIN(IF(OFFSET(<column vector>;<row vector of indices>-1;0)="",L(OFFSET(<column vector>;<row vector of indices>-1;0)),""))
(This example also fails with #ARG, because, as I understand, I need to dereference the array reference for the = test as well).
If it is at all possible, I prefer to keep with Excel 2007 set of built-in functions. And no VBA.
I would accept any solution, that uses constant number of cells irregardless of the size of each input array.
EDIT:
As a side remark I wonder what is wrong with the arrays returned by OFFSET anyway? This simple example works perfectly:
...while the array returned by OFFSET somehow wants to be alone in the formula.
There may be another option but I don't see it at the moment.....
You can filter out zeroes by using an IF like this
=MIN(IF(N(OFFSET(INDIRECT($A$2),$C4:$G4-1,0))<>0,N(OFFSET(INDIRECT($A$2),$C4:$G4-1,0))))
but that won't distinguish between any actual zeroes in your range and those produced when the N function encounters blanks or text
Edit
This version should work
=MIN(IF(COUNTBLANK(OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1))+LEN(T(OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1))),"",N(OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1))))
Perhaps not completely relevant here but the problem is finding functions that can deal with the "array of references" returned by OFFSET with this type of setup - N and T work as shown here and also COUNTBLANK. Other functions that can be used on the OFFSET output are SUBTOTAL and COUNTIF. Note that COUNTBLANK (along with SUBTOTAL and COUNTIF) can work on ranges while T and N will only work with single values - if the latter functions are applied to ranges they simply look at the first value in the range - because of that I was able to use OFFSET without the "height" parameter but you need that with COUNTBLANK (and it's a good habit to get in to so OFFSET should have the final 1 as here
=OFFSET(INDIRECT($A$2),$C4:$G4-1,0,1)
Consider in B1:
=IF(ISBLANK(A1),"nothing there",A1)
So if A1 contains the formula:
=""
Then B1 will also display the null.
Another possibility:
=MIN(CELL("contents",OFFSET(INDIRECT($A$2),N(INDEX($C4:$G4-1,)),0)))
Note: The N(INDEX(...)) part is a trick used to enforce array evaluation.

Last non-empty cell in a column

Does anyone know the formula to find the value of the last non-empty cell in a column, in Microsoft Excel?
Using following simple formula is much faster
=LOOKUP(2,1/(A:A<>""),A:A)
For Excel 2003:
=LOOKUP(2,1/(A1:A65535<>""),A1:A65535)
It gives you following advantages:
it's not array formula
it's not volatile formula
Explanation:
(A:A<>"") returns array {TRUE,TRUE,..,FALSE,..}
1/(A:A<>"") modifies this array to {1,1,..,#DIV/0!,..}.
Since LOOKUP expects sorted array in ascending order, and taking into account that if the LOOKUP function can not find an exact match, it chooses the largest value in the lookup_range (in our case {1,1,..,#DIV/0!,..}) that is less than or equal to the value (in our case 2), formula finds last 1 in array and returns corresponding value from result_range (third parameter - A:A).
Also little note - above formula doesn't take into account cells with errors (you can see it only if last non empty cell has error). If you want to take them into account, use:
=LOOKUP(2,1/(NOT(ISBLANK(A:A))),A:A)
image below shows the difference:
This works with both text and numbers and doesn't care if there are blank cells, i.e., it will return the last non-blank cell.
It needs to be array-entered, meaning that you press Ctrl-Shift-Enter after you type or paste it in. The below is for column A:
=INDEX(A:A,MAX((A:A<>"")*(ROW(A:A))))
Here is another option: =OFFSET($A$1;COUNTA(A:A)-1;0)
I know this question is old, but I'm not satisfied with the answers provided.
LOOKUP, VLOOKUP and HLOOKUP has performance issues and should really never be used.
Array functions has a lot of overhead and can also have performance issues, so it should only be used as a last resort.
COUNT and COUNTA run into problems if the data is not contiguously non-blank, i.e. you have blank spaces and then data again in the range in question
INDIRECT is volatile so it should only be used as a last resort
OFFSET is volatile so it should only be used as a last resort
any references to the last row or column possible (the 65536th row in Excel 2003, for instance) is not robust and results in extra overhead
This is what I use
when the data type is mixed: =max(MATCH(1E+306,[RANGE],1),MATCH("*",[RANGE],-1))
when it's known that the data contains only numbers: =MATCH(1E+306,[RANGE],1)
when it's known that the data contains only text: =MATCH("*",[RANGE],-1)
MATCH has the lowest overhead and is non-volatile, so if you're working with lots of data this is the best to use.
Inspired by the great lead given by Doug Glancy's answer, I came up with a way to do the same thing without the need of an array-formula. Do not ask me why, but I am keen to avoid the use of array formulae if at all possible (not for any particular reason, it's just my style).
Here it is:
=SUMPRODUCT(MAX(($A:$A<>"")*(ROW(A:A))))
For finding the last non-empty row using Column A as the reference column
=SUMPRODUCT(MAX(($1:$1<>"")*(COLUMN(1:1))))
For finding the last non-empty column using row 1 as the reference row
This can be further utilized in conjunction with the index function to efficiently define dynamic named ranges, but this is something for another post as this is not related to the immediate question addressed herein.
I've tested the above methods with Excel 2010, both "natively" and in "Compatibility Mode" (for older versions of Excel) and they work. Again, with these you do not need to do any of the Ctrl+Shift+Enter. By leveraging the way sumproduct works in Excel we can get our arms around the need to carry array-operations but we do it without an array-formula. I hope someone out there may appreciate the beauty, simplicity and elegance of these proposed sumproduct solutions as much as I do. I do not attest to the memory-efficiency of the above solutions though. Just that they are simple, look beautiful, help the intended purpose and are flexible enough to extend their use to other purposes :)
Hope this helps!
All the best!
This works in Excel 2003 (& later with minor edit, see below). Press Ctrl+Shift+Enter (not just Enter) to enter this as an array formula.
=IF(ISBLANK(A65536),INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535)))),A65536)
Be aware that Excel 2003 is unable to apply an array formula to an entire column. Doing so yields #NUM!; unpredictable results may occur! (EDIT: Conflicting information from Microsoft: The same may or may not be true about Excel 2007; problem may have been fixed in 2010.)
That's why I apply the array formula to range A1:A65535 and give special treatment to the last cell, which is A65536 in Excel 2003. Can't just say A:A or even A1:A65536 as the latter automatically reverts to A:A.
If you're absolutely sure A65536 is blank, then you can skip the IF part:
=INDEX(A1:A65535,MAX((A1:A65535<>"")*(ROW(A1:A65535))))
Note that if you're using Excel 2007 or 2010, the last row number is 1048576 not 65536, so adjust the above as appropriate.
If there are no blank cells in the middle of your data, then I would just use the simpler formula, =INDEX(A:A,COUNTA(A:A)).
An alternative solution without array formulas, possibly more robust than that of a previous answer with a (hint to a) solution without array formulas, is
=INDEX(A:A,INDEX(MAX(($A:$A<>"")*(ROW(A:A))),0))
See this answer as an example.
Kudos to Brad and barry houdini, who helped solving this question.
Possible reasons for preferring a non-array formula are given in:
An official Microsoft page (look for "Disadvantages of using array formulas").
Array formulas can seem magical, but they also have some disadvantages:
You may occasionally forget to press CTRL+SHIFT+ENTER. Remember to press this key combination whenever you enter or edit an array formula.
Other users may not understand your formulas. Array formulas are relatively undocumented, so if other people need to modify your workbooks, you should either avoid array formulas or make sure those users understand how to change them.
Depending on the processing speed and memory of your computer, large array formulas can slow down calculations.
Array Formula Heresy.
if you search in Column (A) use :
=INDIRECT("A" & SUMPRODUCT(MAX((A:A<>"")*(ROW(A:A)))))
if your range is A1:A10 you can use:
=INDIRECT("A" & SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10)))))
in this formula :
SUMPRODUCT(MAX(($A$1:$A10<>"")*(ROW($A$1:$A10))))
returns last non blank row number ,and indirect() returns cell value.
=INDEX(A:A, COUNTA(A:A), 1) taken from here
=MATCH("*";A1:A10;-1) for textual data
=MATCH(0;A1:A10;-1) for numerical data
Ive tried all the non-volatile versions but Not one version given above has worked.. excel 2003/2007update. Surely this can be done in excel 2003. Not as an array nor standard formula.
I either get just a blank, 0 or #value error.
So I resort to the volatile methods .. This worked..
=LOOKUP(2,1/(T4:T369<>""),T4:T369)
#Julian Kroné .. Using ";" instead of "," does NOT work! I think you are using Libre Office not MS excel?
LOOKUP is so annoyingly volitile I use it as a last resort only
For Microsoft office 2013
"Last but one" of a non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-2,0)
"Last" non empty row:
=OFFSET(Sheet5!$C$1,COUNTA(Sheet5!$C:$C)-1,0)
Place this code in a VBA module. Save. Under functions, User defined look for This function.
Function LastNonBlankCell(Range As Excel.Range) As Variant
Application.Volatile
LastNonBlankCell = Range.End(xlDown).Value
End Function
for textual data:
EQUIV("";A1:A10;-1)
for numerical data:
EQUIV(0;A1:A10;-1)
This give you the relative index of the last non empty cell in the range selected (here A1:A10).
If you want to get the value, access it via INDIRECT after building -textually- the absolute cell reference, eg:
INDIRECT("A" & (nb_line_where_your_data_start + EQUIV(...) - 1))
I had the same problem too. This formula also works equally well:-
=INDIRECT(CONCATENATE("$G$",(14+(COUNTA($G$14:$G$65535)-1))))
14 being the row number of the first row in the rows you want to count.
Chronic Clawtooth
I used HLOOKUP
A1 has a date;
A2:A8 has forecasts captured at different times, I want the latest
=Hlookup(a1,a1:a8,count(a2:a8)+1)
This uses a standard hlookup formula with the lookup array defined by the number of entries.
If you know that there are not going to be empty cells in between, the fastest way is this.
=INDIRECT("O"&(COUNT(O:O,"<>""")))
It just counts the non-empty cells and refers to the appropriate cell.
It can be used for a specific range as well.
=INDIRECT("O"&(COUNT(O4:O34,"<>""")+3))
This returns the last non empty cell in the range O4:O34.
This formula worked with me for office 2010:
=LOOKUP(2;1/(A1:A100<>"");A1:A100)
A1: the first cell
A100: refer to the last cell in comparing
I think the response from W5ALIVE is closest to what I use to find the last row of data in a column. Assuming I am looking for the last row with data in Column A, though, I would use the following for the more generic lookup:
=MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0))
The first MATCH will find the last text cell and the second MATCH finds the last numeric cell. The IFERROR function returns zero if the first MATCH finds all numeric cells or if the second match finds all text cells.
Basically this is a slight variation of W5ALIVE's mixed text and number solution.
In testing the timing, this was significantly quicker than the equivalent LOOKUP variations.
To return the actual value of that last cell, I prefer to use indirect cell referencing like this:
=INDIRECT("A"&MAX(IFERROR(MATCH("*",A:A,-1),0),IFERROR(MATCH(9.99999999999999E+307,A:A,1),0)))
The method offered by sancho.s is perhaps a cleaner option, but I would modify the portion that finds the row number to this:
=INDEX(MAX((A:A<>"")*(ROW(A:A))),1)
the only difference being that the ",1" returns the first value while the ",0" returns the entire array of values (all but one of which are not needed). I still tend to prefer addressing the cell to the index function there, in other words, returning the cell value with:
=INDIRECT("A"&INDEX(MAX((A:A<>"")*(ROW(A:A))),1))
Great thread!
If you are not afraid to use arrays, then the following is a very simple formula to solve the problem:
=SUM(IF(A:A<>"",1,0))
You must press CTRL + SHIFT + ENTER because this is an array formula.
INDEX returns a value by index position in an array and ROWS then is used to specify the last position of the array.
=LET(array,A1:A10,INDEX(array,ROWS(array)))
Also works for multiple columns when setting the parameter [column_num] of INDEX to 0:
=LET(array,A1:C10,INDEX(array,ROWS(array),0))
A simple one which works for me:
=F7-INDEX(A:A,COUNT(A:A))
Okay, so I had the same issue as the asker, and tried both top answers. But only getting formula errors. Turned out that I needed to exchange the "," to ";" for the formulas to work. I am using XL 2007.
Example:
=LOOKUP(2;1/(A:A<>"");A:A)
or
=INDEX(A:A;MAX((A:A<>"")*(ROW(A:A))))
For version tracking (adding the letter v to the beginning of the number), I found this one to work well in Xcelsius (SAP Dashboards)
="v"&MAX(A2:A500)

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