After an HD problem and some work, I have a bunch of files with names like "f1234", "f1235", etc.
My goal is to sort this files according to their filetype. For example, I want to move all the PDF files in the "pdfs" directory.
For one file, I can do : "file f1234", and if it's a PDF, I can "mv f1234 pdfs/". But I have thousands of file... Can you help me with a bash or zsh command for sort all the PDF in one pass ? Thanks
The hard part here is reliably turning the output of file into a directory name. I think probably the best candidate for that is the mime-type of the file rather than the human readable output of file. I'd use something like:
mkdir sorted
for f in f*
do
d=$(file -b --mime-type "$f" | tr / -)
mkdir -p "sorted/$d"
mv "$f" "sorted/$d/"
done
Obviously I'd test that out a bit before running it on your files, but something pretty close to that should work.
Related
I have a folder/subfolders that contain some files with filenames that end with a random numeric extension:
DWH..AUFTRAG.20211123115143.A901.3801176
DWH..AUFTRAGSPOSITION.20211122002147.A901.3798013
I would like to remove everything after A901 from the above filenames.
For example:
DWH..AUFTRAG.20211123115143.A901 (remove this .3801176)
DWH..AUFTRAGSPOSITION.20211122002147.A901 (remove this .3798013) from the filename
How do I use rename or any other command in linux to remove only after A901 everything from finale rest file name keep as it is?
I can see there is 5 '.' (dots) before the number so I did some desi jugad.
I made some files in folder and also made a folder and created some files inside that folder accourding to the name pattern that you gave.
I created a command and it somewhat looks like this.
find "$PWD"|grep A901|while read F; do mv "${F}" `echo ${F}|cut -d . -f 1-5`;done
When executed it worked for me.
terminal output below.
rexter#rexter:~/Desktop/test$ find $PWD
/home/rexter/Desktop/test
/home/rexter/Desktop/test/test1
/home/rexter/Desktop/test/test1/DWH..AUFTRAG.20211123115143.A901.43214
/home/rexter/Desktop/test/test1/DWH..AUFTRAGSPOSITION.2021112200fsd2147.A901.31244324
/home/rexter/Desktop/test/DWH..AUFTRAG.20211123115143.A901.321423
/home/rexter/Desktop/test/DWH..AUFTRAGSPOSITION.20211122002147.A901.3124325
rexter#rexter:~/Desktop/test$ find "$PWD"|grep A901|while read F; do mv "${F}" `echo ${F}|cut -d . -f 1-5`;done
rexter#rexter:~/Desktop/test$ find $PWD
/home/rexter/Desktop/test
/home/rexter/Desktop/test/test1
/home/rexter/Desktop/test/test1/DWH..AUFTRAG.20211123115143.A901
/home/rexter/Desktop/test/test1/DWH..AUFTRAGSPOSITION.2021112200fsd2147.A901
/home/rexter/Desktop/test/DWH..AUFTRAG.20211123115143.A901
/home/rexter/Desktop/test/DWH..AUFTRAGSPOSITION.20211122002147.A901
rexter#rexter:~/Desktop/test$
I dont know if this is a proper way to do it but it just make things work.
Let me know if it is useful to you.
I am a novice Linux user. I have 892 .pdb files, I want to rename all of them in a sequential order as L1,L2,L3,L4...........,L892. And then I want a text file which contains the old names assigned to new names ( i.e L1,L2,L3). Please help me with this. Thank you for your time.
You could just do:
#!/bin/sh
i=0
for f in *.pdb; do
: $((i += 1))
mv "$f" L"$i" && echo "$f --> L$i"
done > filelist
Note that you probably want to move the files into a different directory, as that will make it easier to recover if an error occurs midway through. Also be wary that this will overwrite any existing files and potentially cause a big mess. It's not idempotent (you can't run it twice). You would probably be better off not doing the move at all and instead do something like:
#!/bin/sh
i=0
mkdir -p newfiles
for f in *.pdb; do
ln "$f" newfiles/L"$((++i))" && printf "%s\0%s\0" "$f" "L$i"
done > filelist
This latter solution creates links to the original files in a subdirectory, so you can run it multiple times without munging the original data. Also, it uses null separators in the file list so you can unambiguously distinguish names that have newlines or tabs or spaces in them. It makes for a list that is not particularly human readable, but you can easily filter it through tr to make it pretty.
How to rename files without changing extension in Linux \
102221.pdf to 102221_name.pdf
This is what you want I think:
for x in *; do mv "$x" "${x%.*}_name.${x##*.}"; done
${x%.*} will give the name of the file without extention
${x##*.} will extract the extentions
ls * | sed -r 'p;s/\.pdf$/_name\.pdf/g' | xargs -n2 mv
list all the files with ls and pipe the output to sed. sed replaces .pdf with _name.pdf and outputs both the original file name and the new file name to xargs with will call mv with the 2 parameters.
you can also use the rename command which is simpler
rename 's/\.pdf$/_name\.pdf/g' ./*
The regex pattern remains the same though
well i am not so good in linux.. but still found a working answer for you.. hope it will solve ur purpose..
check the given link.. you might need a light weighted tool called as jhead mainly its to get the header information about the file link created date and time and other.. you can find the information which suits you..
Answer
https://superuser.com/questions/90057/linux-rename-file-but-keep-extension
jhead
http://www.sentex.net/~mwandel/jhead/
I have 25 files in a directory. I need to amass 25000 files for testing purposes. I thought I could just replicate these files over and over until I get 25000 files. I could manually copy paste 1000 times but that seemed tedious. So I thought I could write a script to do it for me. I tried
cp * .
As a trial but I got an error that said the source and destination file are the same. If I were to automate it how would i do it so that each of the 1000 times the new files are made with unique names?
As discussed in the comments, you can do something like this:
for file in *
do
filename="${file%.*}" # get everything up to last dot
extension="${file##*.}" # get extension (text after last dot)
for i in {00001..10000}
do
cp $file ${filename}${i}${extension}
done
done
The trick for i in {00001..10000} is used to loop from 1 to 10000 having the number with leading zeros.
The ${filename}${i}${extension} is the same as $filename$i$extension but makes more clarity over what is a variable name and what is text. This way, you can also do ${filename}_${i}${extension} to get files like a_23.txt, etc.
In case your current files match a specific pattern, you can always do for file in a* (if they all are on the a + something format).
If you want to keep the extension of the files, you can use this. Assuming, you want to copy all txt-files:
#!/bin/bash
for f in *.txt
do
for i in {1..10000}
do
cp "$f" "${f%.*}_${i}.${f##*.}"
done
done
You could try this:
for file in *; do for i in {1..1000}; do cp $file $file-$i; done; done;
It will append a number to any existing files.
The next script
for file in *.*
do
eval $(sed 's/\(.*\)\.\([^\.]*\)$/base="\1";ext="\2";/' <<< "$file")
for n in {1..1000}
do
echo cp "$file" "$base-$n.$ext"
done
done
will:
take all files with extensions *.*
creates the basename and extension (sed)
in a cycle 1000 times copyes the original file to file-number.extension
it is for DRY-RUN, remove the echo if satisfied
I want to write a script that do specific thing:
I have a txt file e.g.
from1/from2/from3/apple.file;/to1/to2/to3;some not important stuff
from1/from2/banana.file;/to1/to5;some not important stuff
from1/from10/plum.file;/to1//to5/to100;some not important stuff
Now i want to copy file from each line (e.g. apple.file), from original directory tree to new, non existing directories, after first semicolon (;).
I try few code examples from similar questions, but nothing works fine and I'm too weak in bash scripting, to find errors.
Please help :)
need to add some conditions:
file not only need to be copy, but also rename. Example line in file.txt:
from1/from2/from3/apple.file;to1/to2/to3/juice.file;some1
from1/from2/banana.file;to1/to5/fresh.file;something different from above
so apple.file need to be copy and rename to juice.file and put in to1/to2/to3/juice.file
I think thaht cp will also rename file but
mkdir -p "$to"
from answer below will create full folder path with juice.file as folder
In addidtion after second semicolon in each line will be something different, so how to cut it off?
Thanks for all help
EDIT: There will be no spaces in input txt file.
Try this code..
cat file | while IFS=';' read from to some_not_important_stuff
do
to=${to:1} # strip off leading space
mkdir -p "$to" # create parent for 'to' if not existing yet
cp -i "$from" "$to" # option -i to get a warning when it would overwrite something
done
Using awk
(run the awk command first and confirm the output is fine, then add |sh to do the copy)
awk -F";" '{printf "cp %s %s\n",$1,$2}' file |sh
Using shell (get updated that need manually create folder, base on alfe's
while IFS=';' read from to X
do
mkdir -p $to
cp $from $to
done < file
I had this same problem and used tar to solve it! Posted here:
tmpfile=/tmp/myfile.tar
files="/some/folder/file1.txt /some/other/folder/file2.txt"
targetfolder=/home/you/somefolder
tar --file="$tmpfile" "$files"
tar --extract --file="$tmpfile" --directory="$targetfolder"
In this case, tar will automatically create all (sub)folders for you! Best,
Nabi