Calculate the number of biweekly pays in 1 month - excel

To create a monthly budget in Google Sheets, biweekly pay needs to be calculated. Some months there are three paydays and some there are two. Paydays are every second Wednesday night.
The below formula worked previously, and now it does not.
Before being rounded, the formula calculates to =ROUNDDOWN(1.14)*1000 which multiplies the pay amount by one except there is never only one payday in a month. This month there are two pay days, 14/09/16 and 28/09/16.
=ROUNDDOWN((EOMONTH(TODAY(),0)-(MOD(DATE(2016,8,31)-DATE(YEAR(TODAY()),MONTH(TODAY()),1),14)+DATE(YEAR(TODAY()),MONTH(TODAY()),1)))/14)*1000
Where is the error in my formula?

Consider this formula:
=(INT((EOMONTH(TODAY(),0)-DATE(2016,8,31))/14)-INT((EOMONTH(TODAY(),-1)-DATE(2016,8,31))/14))*1000
It calculates all the paydays from the end of the current month back to your date of 8/31/2016 and subtracts all the paydays from the prior month back to the same date.
In march of 2017 it will give the correct 3 paydays.

Related

Excel Formula to Identify 3rd "full" week of Month

I'm creating a workplace calendar which uses formulas to identify the dates of key department events. One event I am trying to create on the calendar is the monthly department Town Hall, which is scheduled to occur on Wednesday of the 3rd "full" week of each month. I say the third full week because some months start off on a Wednesday or later which results in a partial week.
Is there a complex nested (or simple) formula I could use to identify the Wednesday of third "full" week of a new month, based of a date value in the first column of a table. Using Monday or Tuesday as the baseline to determine if the first week is a "full" week, since weekends wouldn't count for business purposes.
Sincerely,
Kristopher
Using A19 as the reference data as it has the 1st day of the month desired:
=A19+CHOOSE(WEEKDAY(a19-1),1,7,6,5,4,3,2)+15
This assumes that the first full week starts one or before a Monday.
I took ScottCramers suggestion, which worked well on the first days of the month for identifying the Wednesday of 3rd full week, then edited it a but to meet my exact needs. His formula worked perfectly on the first day of a month, in identifying the 3rd Wednesday in comparison. So I added the following to maintain the first day in relation to the row throughout the table
=DATE($A$16,MONTH([#Date]),1)+CHOOSE(WEEKDAY(DATE($A$16,MONTH([#Date]),1)-1),1,7,6,5,4,3,2)+15
This maintained the first day of month for every row. Then I added the following to compare the rows date to the formulated date, and if it was a match then that day is the TownHall event.
=IF([#Date]=DATE($A$16,MONTH([#Date]),1)+CHOOSE(WEEKDAY(DATE($A$16,MONTH([#Date]),1)-1),1,7,6,5,4,3,2)+15,"TownHall","")

Excel Date table to determine next Bi-annual date from Input date

I am creating a Table in excel to help determine what the Bi-annual dates would be from an input date.
Example: If the start date of an agreement is 9/1/2017 and Ends 8/31/2018, the Bi-annual dates would be 2/28/18 and 8/31/2018. Dates of service would be 2 months before the end of the agreement period, and six months before the second service date (so 6/30/2018 and 12/31/2017 respectively).
Formula for this:
=IF(ISBLANK(O3), "",IF(EOMONTH(A1, 0)=EOMONTH(O3, -2), "BIANNUAL", IF(EOMONTH(A1, 0)=EOMONTH(O3, -8), "BIANNUAL", "")))
Where A1 refers to January, B1 would be February, and so on thru to December (L1). O3 is the Agreement End Date box, and will be static on the sheet. This formula work perfect for me.
What I am trying to get is a formula for the cells at the top that list the months (Jan-Dec). I need a formula that will put the date as 1/31/2018 for Jan, 2/28/2018 for Feb, 9/30/2017 for September (for the current year since September has not passed). The actual day needs to be the last day of the month, and if that month has passed, then the year should be for next year. I have been playing with the DATE function, but cannot get it nailed down.
What I have so far - January 2018:
=DATE(YEAR(TODAY()+365), MONTH(42766), DAY(EOMONTH(42766, 0)))
This works, but not each month will be in 2018. I need the year to change only after the month has passed.
I feel like I'm either over complicating things, or I need a way more complex formula. Please help.
In A1 place the following formula and copy right to L1 or as far as you need to go
=EOMONTH($O$2,COLUMN(A1)-1)
It will display the end of month dates starting with the starting month of the contract and increasing by 1 month for each column you move right.
In the image below, it is the same formula in row 1 and row 2. Row one I choose custom format instead of date and set the custom format to mmmm. 4 m's will give you the full month, and 3 m's will give you the 3 starting letters of the month.
I actually figured this out this morning just playing with the IF function. My goal was to have the sheet update itself without having to change the dates every time your open it. So that the file could be shared with others and all you would have to enter is the end of the contract date, and it will list out Biannual, Tri-annual, and Quarterly months (see image).
Formula:
=IF(DATE(YEAR(TODAY()), MONTH(42766), DAY(EOMONTH(42766, 0)))<TODAY(), DATE(YEAR(TODAY()+365), MONTH(42766), DAY(EOMONTH(42766, 0))), DATE(YEAR(TODAY()), MONTH(42766), DAY(EOMONTH(42766, 0))))
Where I used the serial for each month (in this case 1/31/2017, as I didn't need to worry about the year)
Results

Calculate the first week of year which starts from first Sunday of every Feb

I have an issue here. I want to calculate the week nummber of first sunday of business year. Where I work their calendar starts on February 1st. To calculate i have a column A2 in excel which has the date in mm/dd/yyyy format. I want to generate the corresponding fiscal week for the column.
example of my result set:
for 2/1/15 the week of year number should be 1
For 2/7/16 the week number of year should be 1
I tried the below formula, but its starting the week from the first day of the fiscal year and not the first sunday of the year.
=INT((A1-WEEKDAY(E9165)-DATE(YEAR(A1+7-WEEKDAY(A1))-(MONTH(A1)<2),2,1))/7)+2
Please help...
-Sandra
Assuming that your work years always start on the first sunday after February 1st:
=IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))
We first determine the week number of the date starting from the first Sunday of February. To do this I have used WEEKNUM()-WEEKNUM(02/01/SAMEYEAR) taking 1 day from the date to force week 1 as Excel begins counting from week 0 by default. Using IF() we state that if the outcome is 0 or less then add the result to 52, which will give us the correct result for dates in January as they produce negative values.
Edit - Very long formula but gives you the week of the quarter in Q1 W1 format:
=SUBSTITUTE(CONCATENATE("Q",INT(IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))/13)+(IF(INT(IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))-INT((IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))/13))*13)=0,0,1))," W",INT(IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))-INT((IF(WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1)<=0,52+WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1),WEEKNUM(A1)-WEEKNUM(DATE(YEAR(A1),2,1)-1))/13))*13)),"W0","W1")
Apologies for the length, I tried multiple methods to try to find a neater solution, but this was all that I could get to work. It would be a lot neater if there were multiple columns used.
Use this formula:
=IF(A1>=IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2)),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1),2,1),DATE(YEAR(A1),2,7-WEEKDAY(DATE(YEAR(A1),2,1),1)+2))+1)/7,0),ROUNDUP((A1-IF(WEEKDAY(DATE(YEAR(A1),2,1),1)=1,DATE(YEAR(A1)-1,2,1),DATE(YEAR(A1)-1,2,7-WEEKDAY(DATE(YEAR(A1)-1,2,1),1)+2))+1)/7,0))
Way late to the party but was looking for the answer and found this thread. Ended up play around with the function myself and it's much easier to just deduct the dates; =WEEKNUM("date"- days you wish to offset)
Ex; If cell A1 holds my date, 2/1/2021 I wish to convert; =WEEKNUM(A1-31) result "1".

Excel display nth day of current month

I have a list of recurring bills. Some are on the 1st of every month, and some are on the 15th or 16th etc. What I want to be able to do is display this day within the current month. So if it is February, and the bill recurs on the 9th every month, my cell will show 02/09/12, and if it was march, it would show 03/09/12. Is there a formula or macro to accomplish this?
Found it to be: =DATE(YEAR(TODAY()),MONTH(TODAY()),18)
If you have the number 9 in A1 this formula will show the 9th of the current month (whether that be in the future or the past)
=TODAY()-DAY(TODAY())+A1
edate(start-date),1)
ie edate(B3,1)
b3= 1/5/13
Result = 5th of 1 month later - 2/5/13
3 for quarterly, 12 for annual

Excel function to determine the last Friday in a month

I'm looking for an Excel function to return the last Friday in a month for a given date.
ie: Any date in the month as input will give the date of the last Friday as output.
14-July-09 should give 31-July-09
7-March-05 should give 35-March-09
Building on #Toomas answer above, I had to make some amendments for Excel 2007, but came up with the following:
=EOMONTH(A1,0)-MOD(WEEKDAY(EOMONTH(A1,0))+1,7)
Which is assuming that the WEEKDAY returned for Friday is 6 and then applying a shifted MOD 7 to achieve the correct day.
Try this formula:
=IF(WEEKDAY(EOMONTH(A5;0);16)=7;EOMONTH(A5;0);EOMONTH(A5;0)-WEEKDAY(EOMONTH(A5;0);16))
Enter to A5 date value of which you are looking for the last Friday in a month.
The following formula achives this for a date in cell A1:
=DATE(YEAR(A1),MONTH(A1)+1,0)+MOD(-WEEKDAY(DATE(YEAR(A1),MONTH(A1)+1,0),2)-2,-7)
I came here looking for the formula to get the most recent Friday in the past which turned out to be =TODAY()-WEEKDAY(TODAY())-1
In case anyone needs to do this for next year (or future years):
=EOMONTH(DATE(YEAR(TODAY())+1,MONTH(TODAY()),1),0)-MOD(WEEKDAY(EOMONTH(DATE(YEAR(TODAY())+1,MONTH(TODAY()),1),0))+1,7)
Here's one that will show the last Friday of the current month.
And if the date is in the past it will show you next month's last Friday.
And if it's December right now, it'll show you next year's January's Friday.
=IF(DATE(YEAR(TODAY()),MONTH(TODAY())+1,0)+MOD(-WEEKDAY(DATE(YEAR(TODAY()),MONTH(TODAY())+1,0),2)-2,-7)>=TODAY(), DATE(IF(MONTH(TODAY())+1>12,YEAR(TODAY()+1),YEAR(TODAY())),MONTH(TODAY())+1,0)+MOD(-WEEKDAY(DATE(YEAR(TODAY()),MONTH(TODAY())+1,0),2)-2,-7), DATE(IF(MONTH(TODAY())=12,YEAR(TODAY())+1,YEAR(TODAY())),MONTH(IF(MONTH(TODAY())=12,1,MONTH(TODAY())))+1,0)+MOD(-WEEKDAY(DATE(IF(MONTH(TODAY())=12,YEAR(TODAY())+1,YEAR(TODAY())),MONTH(IF(MONTH(TODAY())=12,1,MONTH(TODAY())))+1,0),2)-2,-7))
You can try
=DATE(YEAR(A1),MONTH(A1)+1,1)-1+CHOOSE(WEEKDAY(DATE(YEAR(A1),MONTH(A1)+1,1)-1),-2,-3,-4,-5,-6,0,-1)
to find the last friday of the month. Assumes A1 has the date.
Hey the formatting is outdated so ill show what I came up with:
=EOMONTH(A1;A2)-(WEEKDAY(EOMONTH(A1;A2);15)-1)
[A1] is an interval of months later, from [A2] the stating date, that the result date should be.
We have some equipment that need maintenance last Friday of the month, an number of months since last Maintenace.
EOMONTH(A1;A2): we find the date, of the last day, of target month.
WEEKDAY([Date];15): assign a number for day of the week.
[15] makes Friday the value 1 and Thursday the value 7.
so if the last day of the month is Friday, the calculation would be:
[Date]-(1-1) = [Date] therefor the date won't change.
[Date] in my original code example, is the last day of the target month: [A2] date + [A1] number of months later.
if the last day is Wednesday, we want it to subtract 5 days: [Date]-(6-1) = [Date]-5
As a sidenote:
=WORKDAY(A2+1;-1;[hollydays])
will round a date back to the earlier Workday if it lands in a weekend or holyday
[holyday] can be an area of cells with predefined dates to skip eg: [$C$1:$C$20].
$ is so the area won't change when you extend the function to other cells.
if you don't care about holydays use =WORKDAY(A2+1;-1)
Awesome! Basically, like trying to find the first or second Monday of the month,
=DATE(TheYear,5,1)+CHOOSE(WEEKDAY(DATE(TheYear,5,1)),1,0,6,5,4,3,2)
which returns the first Monday of the month, in this case May
but to find the last weekday of the month, in the formula, you start with the next month and subtract
=DATE(TheYear,6,1)-1+CHOOSE(WEEKDAY(DATE(TheYear,6,1)),-6,-5,-4,-3,-2,-1,0)
which returns the last Monday of May
I have a cell that I named TheYear, in which I enter the year I'm working with, but you can point to whatever cell you have the year you want (e.g. A1).
I don't know why the pointers to the days of the week are in reverse order but to find the day (e.g. Tuesday instead of Monday), change the order of those numbers but they have to stay in order. For example, 4th Thursday of November:
=DATE(TheYear,11,1)+21+CHOOSE(WEEKDAY(DATE(TheYear,11,1)),4,3,2,1,0,6,5)
=EOMONTH(TODAY(),0)-WEEKDAY(EOMONTH(TODAY(),0))-1
This gives the last Friday of this month. You can replace both instances of Today() with any date you like or a cell reference that has a date to get the last Friday in any other month.
=WORKDAY.INTL((EOMONTH(A4,0)+1),-1,"1111011")

Resources