I have lost of xmls in Unix env, and I want to get list of the files which include the next string:
Value value="99.00"
My problem is that this string include quotes, which causing me truobles with the grep command. any idea which command I should use?
SHELL=/bin/ksh
Use backslash to escape the ":
grep Value\ value=\"99.00\" *.xml
Or enclose it in single quotes:
grep 'Value value="99.00"' *.xml
Related
I have a path like this:
dirname=../2Reconnaissance-annoted/J39/IMG_2208.json
I want to get a new path by replacing ".json" with "_json", so I tried this command:
tr "\.json" "_json" <<<$dirname
The problem is that I get:
__/2Reconnaissance-annoted/J39/IMG_2208_json
Rather than
../2Reconnaissance-annoted/J39/IMG_2208_json
How do you fix it, please?
tr does transliteration, i.e. it replaces a character by a character, not a string by a string. What you need is substitution.
Most shells support substitution directly:
dirname=${dirname/.json/_json}
(${dirname/%.json/_json} would only substitute the substrings at the end of the string).
If your shell doesn't support it, you can use sed:
echo "$dirname" | sed -e 's/\.json$/_json/'
Below is the string I am trying to grep for this in the bash shell:
'#Hostname=sometext.company.com, sometext.company.com' filename
I want to only find the string if it matches that exact pattern. I already tried the command below and a few others.
grep -Fx "#Hostname=sometext.company.com, sometext.company.com" filename
Did you specify the -xoption on purpose?
grep -F '#Hostname=sometext.company.com, sometext.company.com' filename
most likely is what you want. Also, it's better to put single quotes instead of double quotes, just in case your search pattern happens to contain special shell characters.
I need to execute a sed command with pattern /^03.06.2014/ in a .sh script & command line. The date is a variable not a constant. How could i implement this? When I use a variable inside a regex pattern, the command breaks. Do I need to escape something here? Any help is appreciated. Thanks!
date=$(date +%m.%d.%Y)
sed -n '/^$date/,$p' filename
Use double quotes for variable expansion in sed
sed -n "/^$date/,\$p" filename
You need to use double quotes to allow for shell expansion. You'll need to escape the $ meaning EOF.
sed -n "/^$date/,\$p" filename
I have to find the following patterns in a text file
\xc2d
d\xa0
\xe7
\xc3\ufffdd
\xc3\ufffdd
\xc2\xa0
\xc3\xa7
\xa0\xa0
I start with finding \x occurrences and do this
grep "\\x" *.log | more
and nothing returns, is this query correct?
I think you'll want to use single quotes instead of double quotes.
grep '\\x' *.log | more
Your shell is likely stripping that first backslash as part of the processing it does for strings in double quotes, which grep needs.
HI
I am not very good with linux shell scripting.I am trying following shell script to replace
revision number token $rev -<rev number> in all html files under specified directory
cd /home/myapp/test
set repUpRev = "`svnversion`"
echo $repUpRev
grep -lr -e '\$rev -'.$repUpRev.'\$' *.html | xargs sed -i 's/'\$rev -'.$repUpRev.'\$'/'\$rev -.*$'/g'
This seems not working, what is wrong with the above code ?
rev=$(svnversion)
sed -i.bak "s/$rev/some other string/g" *.html
What is $rev in the regexp string? Is it another variable? Or you're looking for a string '$rev'. If latter - I would suggest adding '\' before $ otherwise it's treated as a special regexp character...
This is how you show the last line:
grep -lr -e '\$rev -'.$repUpRev.'\$' *.html | xargs sed -i 's/'\$rev -'.$repUpRev.'\$'/'\$rev -.*$'/g'
It would help if you showed some input data.
The -r option makes the grep recursive. That means it will operate on files in the directory and its subdirectories. Is that what you intend?
The dots in your grep and sed stand for any character. If you want literal dots, you'll need to escape them.
The final escaped dollar sign in the grep and sed commands will be seen as a literal dollar sign. If you want to anchor to the end of the line you should remove the escape.
The .* works only as a literal string on the right hand side of a sed s command. If you want to include what was matched on the left side, you need to use capture groups. The g modifier on the s command is only needed if the pattern appears more than once in a line.
Using quote, unquote, quote, unquote is hard to read. Use double quotes to permit variable expansion.
Try your grep command by itself without the xargs and sed to see if it's producing a list of files.
This may be closer to what you want:
grep -lr -e "\$rev -.$repUpRev.$" *.html | xargs sed -i "s/\$rev -.$repUpRev.$/\$rev -REPLACEMENT_TEXT/g"
but you'll still need to determine if the g modifier, the dots, the final dollar signs, etc., are what you intend.