I am trying to transform below 2 statements into a shell script
cat all5.log | grep 'Opened\|Closed'> all.log
awk -F ' ' '{print }' all.log | sort | uniq > uniqueFiles.txt
Here is monitorFd.sh bash script
#!/bin/bash
if [ "" != "" ]; then
cat | grep 'Opened\|Closed' > temp.log
awk -F ' ' '{print }' temp.log | sort | uniq > uniqueFiles.txt
while IFS='' read -r line || [[ -n "$line" ]]; do
cmd1=`cat | grep Opened | grep $line | sort | wc -l`
cmd2=`cat | grep Closed | grep $line | sort | wc -l`
echo 'Opened: '$cmd1', Closed: '$cmd2' '$line
done < "uniqueFiles.txt"
rm -f temp.log
else
echo "No target file provided. (hint: trace dump of file-leak-detector.jar)" #syntax error: unexpected end of file
In notepad++ I changed this file to be of UNIX format. Also changed permission to +x, but I am getting below exception.
monitorFd.sh: line 16: syntax error: unexpected end of file
What is wrong with this program?
The Syntax for if in bash is if ... else/elif ... fi. So just add a fi at the end of your file.
Related
I would like to make array which put users in a time using for loop. For example:
y[1]="user1"
y[2]="user2"
...
y[n]="usern"
I tried to do it like this
#!/bin/bash
x=$(who | cut -d " " -f1 | sort | uniq | wc -l)
for (( i=1; i<=$x; i++ )); do
y[$i]=$(who | cut -d " " -f1 | sort | uniq | sed -n '$ip')
p[$i]=$(lsof -u ${y[$i]} | wc -l)
echo "Users:"
echo ${y[$i]}
echo -e "Number of launched files:\n" ${p[$i]}
done
Most likely I'm using command "sed" wrong.
Can you help me?
Indeed your sed command seems to be a bit off. I can't really guess what you're trying to do there. Besides that, I'm wondering why you're executing who twice. You can make use of the data first obtained in the following manner.
#!/bin/bash
# define two arrays
y=()
p=()
#x=0
while read -r username; do
y+=("$username")
p+=($(lsof -u $(id -u "$username") | wc -l))
echo -e "User:\n${y[-1]}"
echo -e "Open files:\n${p[-1]}"
# The -1 index is the last index in the array, but you
# could uncomment the x=0 variable and the line below:
#((x++))
done <<< $(who | cut -d " " -f1 | sort | uniq)
echo "Amount of users: $x"
exit 0
In linux, how to create a file with content whose single line with \n (or any line separator) is translated into multi-line.
fileA.txt:
trans_fileA::abcd\ndfghc\n091873\nhhjj
trans_fileB::a11d\n11hc\n73345
Code:
while read line; do
file_name=`echo $line | awk -F'::' '{print $1}' `
file_content=`echo $line | awk -F'::' '{print $2}' `
echo $file_name
echo $(eval echo ${file_content})
echo $(eval echo ${file_content}) > fileA.txt
The trans_fileA should be:
abcd
dfghc
091873
hhjj
You can do it this way (with bash):
# read input file line by line, without interpreting \n
while read -r line
do
# extract name
name=$(echo $line | cut -d: -f 1)
# extract data
data=$(echo $line | cut -d: -f 3)
# ask sed to replace \n with linefeed and store result in name
echo $data | sed 's/\\n/\n/g' > "$name"
# read data from given file
done < fileA.txt
You can even write a smaller code:
while read -r line
do echo $line | cut -d: -f 3 | sed 's/\\n/\n/g' > "$(echo $line | cut -d: -f 1) "
done < fileA.txt
I'm running the command below:
for line in $(cat file1.txt); do cat file2.txt | grep ${line}; done
and it´s works fine..but I'm looking a way to print the results in a file like this:
$(line) - grep result
Is there a way to customize my grep output?
Thanks
file1="file1.txt";
file2="file2.txt";
for line in $file1; do
result=$(cat $file2 | grep $line | sed -e :a -e N -e '$!ba' -e 's/\n/ /g'));
echo "$line-$result";
done
if the result of $(cat file2.txt | grep $line) are multi lines, you should implement to echo with for statement.
for line in $(file1.txt); do
result=$(cat file2.txt | grep $line);
echo $line
for _line in $result; do
echo " -$_line";
done
done
I'm monitoring from an actively written to file:
My current solution is:
ws_trans=0
sc_trans=0
tail -F /var/log/file.log | \
while read LINE
echo $LINE | grep -q -e "enterpriseID:"
if [ $? = 0 ]
then
((ws_trans++))
fi
echo $LINE | grep -q -e "sc_ID:"
if [ $? = 0 ]
then
((sc_trans++))
fi
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
However when attempting to do this with AWK I don't get the output - the $ws_trans and $sc_trans remains 0
ws_trans=0
sc_trans=0
tail -F /var/log/file.log | \
while read LINE
echo $LINE | awk '/enterpriseID:/ {++ws_trans} END {print | ws_trans}'
echo $LINE | awk '/sc_ID:/ {++sc_trans} END {print | sc_trans}'
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
Attempting to do this to reduce load. I understand that AWK doesn't deal with bash variables, and it can get quite confusing, but the only reference I found is a non tail application of AWK.
How can I assign the AWK Variable to the bash ws_trans and sc_trans? Is there a better solution? (There are other search terms being monitored.)
You need to pass the variables using the option -v, for example:
$ var=0
$ printf %d\\n {1..10} | awk -v awk_var=${var} '{++awk_var} {print awk_var}'
To set the variable "back" you could use declare, for example:
$ declare $(printf %d\\n {1..10} | awk -v awk_var=${var} '{++awk_var} END {print "var=" awk_var}')
$ echo $var
$ 10
Your script could be rewritten like this:
ws_trans=0
sc_trans=0
tail -F /var/log/system.log |
while read LINE
do
declare $(echo $LINE | awk -v ws=${ws_trans} '/enterpriseID:/ {++ws} END {print "ws_trans="ws}')
declare $(echo $LINE | awk -v sc=${sc_trans} '/sc_ID:/ {++sc} END {print "sc_trans="sc}')
printf "\r WSTRANS: $ws_trans \t\t SCTRANS: $sc_trans"
done
Can I use hexdump in a shell script?
When I use it I keep getting an error .
syntax error near unexpected token 'hexdump'
#!/bin/bash
#bash-hexdump
# Quick script to check delay of the shotpoints
echo " please enter the complete line name as mentioned in the RAID2 "
read $line
cd /argus/raid2/"$line"
echo
echo " Entering the directory "
echo
for file in /argus/raid2/"$line"/*.ffid
hexdump -e "16 \"%_p\" \"\\n\"" $FFID | sed -n '68,73p' > list1
done
for filename in 'cat list1'
do
sed -n 6p | awk '{print $1}' = $wd
cat list.txt | sed -n 1p | cut -c13-14 = $hh
cat list.txt | sed -n 1p | cut -c15-16 = $mm
cat list.txt | sed -n 2p | cut -c1-2 = $ss
done
while [ true ]
do
$FFID=`ls -1rt $1 | grep -i ffid | tail -1`
echo " FFID value is : $FFID"
while [ $FFID = `ls -1rt $1 | grep -i ffid | tail -1` ]
do
hexdump -e "16 \"%_p\" \"\\n\"" $FFID | sed -n '68,73p' > list
done
for filename in 'cat list'
do
cat list.txt | sed -n 1p | cut -c13-14 = $hh1
cat list.txt | sed -n 1p | cut -c15-16 = $mm1
cat list.txt | sed -n 2p | cut -c1-2 = $ss1
done
$time1 = "$hh"":""$mm"":""$ss" ;
$time2 = "$hh1"":""$mm1"":""$ss1" ;
$former_seconds = $(date --date= "$time1" +%s);
$later_seconds = $(date --date= "$time2" +%s);
$time_delay = ( "$later_seconds" - "$former_seconds" )
$wb_time = ( "$wd" * 1.33 )
if
(("$wb_time" + "$time_delay")) < 12.0
then
echo "please slow down"
fi
if [ -e EOL.ffid ]
then
echo "EOL.ffid detected, exiting script"
exit
fi
done
I am not able to figure out why the hexdump code is giving me an error . Please help .
You are missing the do in your for loop:
for file in /argus/raid2/"$line"/*.ffid
do
hexdump -e "16 \"%_p\" \"\\n\"" $FFID | sed -n '68,73p' > list1
done