Node-php is an npm package:
https://www.npmjs.com/package/node-php#nodephp---run-wordpress-and-other-php-scripts-with-node
My problem: Up until now I only needed static html files for my webpage, which were delivered okay.
However, now I want to deliver a php file as well. If i simply try to send it like a static file a popup to save the file appears instead of displaying it. So i set up node-php which claims to be able to deliver php files correctly as well. But, it's not working.
How the webpage looks with the below code, going to either the html page or the php page
Either help to make node-php work, or another method to fix this are appreciated.
var express = require('express');
var php = require("node-php"); //Required by node-php
var path = require("path"); //Required by node-php
var app = express();
var http = require('http').Server(app);
var io = require('socket.io')(http);
app.use("/", php.cgi("/usr/bin/php")); //Required by node-php
//LISTEN
app.set('port', process.env.OPENSHIFT_NODEJS_PORT || 8080);
app.set('ip', process.env.OPENSHIFT_NODEJS_IP || '127.0.0.1');
http.listen(app.get('port'), app.get('ip'), function () {
console.log('LISTENING!');
});
app.use(express.static('public'));
//SEND FILES
app.get('/', function (req, res) {
res.sendFile(__dirname + '/index.html');
});
app.get('/phpfile', function (req, res) {
res.sendFile(__dirname + '/phpfile.php');
});
The argument passed to php.cgi() is supposed to be your PHP root directory (where your PHP files are located), not the path to a PHP binary.
just in case you need only one server node and need to build around an node + php app i put here a method https://stackoverflow.com/a/68422021/5781320 that not involve this plugin (node-php) .so basically you can use node server and get post from a specific page(you can improve the node.js part , cause its only a prototype)
Related
I want to serve index.html and /media subdirectory as static files. The index file should be served both at /index.html and / URLs.
I have
web_server.use("/media", express.static(__dirname + '/media'));
web_server.use("/", express.static(__dirname));
but the second line apparently serves the entire __dirname, including all files in it (not just index.html and media), which I don't want.
I also tried
web_server.use("/", express.static(__dirname + '/index.html'));
but accessing the base URL / then leads to a request to web_server/index.html/index.html (double index.html component), which of course fails.
Any ideas?
By the way, I could find absolutely no documentation in Express on this topic (static() + its params)... frustrating. A doc link is also welcome.
If you have this setup
/app
/public/index.html
/media
Then this should get what you wanted
var express = require('express');
//var server = express.createServer();
// express.createServer() is deprecated.
var server = express(); // better instead
server.configure(function(){
server.use('/media', express.static(__dirname + '/media'));
server.use(express.static(__dirname + '/public'));
});
server.listen(3000);
The trick is leaving this line as last fallback
server.use(express.static(__dirname + '/public'));
As for documentation, since Express uses connect middleware, I found it easier to just look at the connect source code directly.
For example this line shows that index.html is supported
https://github.com/senchalabs/connect/blob/2.3.3/lib/middleware/static.js#L140
In the newest version of express the "createServer" is deprecated. This example works for me:
var express = require('express');
var app = express();
var path = require('path');
//app.use(express.static(__dirname)); // Current directory is root
app.use(express.static(path.join(__dirname, 'public'))); // "public" off of current is root
app.listen(80);
console.log('Listening on port 80');
express.static() expects the first parameter to be a path of a directory, not a filename. I would suggest creating another subdirectory to contain your index.html and use that.
Serving static files in Express documentation, or more detailed serve-static documentation, including the default behavior of serving index.html:
By default this module will send “index.html” files in response to a request on a directory. To disable this set false or to supply a new index pass a string or an array in preferred order.
res.sendFile & express.static both will work for this
var express = require('express');
var app = express();
var path = require('path');
var public = path.join(__dirname, 'public');
// viewed at http://localhost:8080
app.get('/', function(req, res) {
res.sendFile(path.join(public, 'index.html'));
});
app.use('/', express.static(public));
app.listen(8080);
Where public is the folder in which the client side code is
As suggested by #ATOzTOA and clarified by #Vozzie, path.join takes the paths to join as arguments, the + passes a single argument to path.
const path = require('path');
const express = require('express');
const app = new express();
app.use(express.static('/media'));
app.get('/', (req, res) => {
res.sendFile(path.resolve(__dirname, 'media/page/', 'index.html'));
});
app.listen(4000, () => {
console.log('App listening on port 4000')
})
If you have a complicated folder structure, such as
- application
- assets
- images
- profile.jpg
- web
- server
- index.js
If you want to serve assets/images from index.js
app.use('/images', express.static(path.join(__dirname, '..', 'assets', 'images')))
To view from your browser
http://localhost:4000/images/profile.jpg
If you need more clarification comment, I'll elaborate.
use below inside your app.js
app.use(express.static('folderName'));
(folderName is folder which has files) - remember these assets are accessed direct through server path (i.e. http://localhost:3000/abc.png (where as abc.png is inside folderName folder)
npm install serve-index
var express = require('express')
var serveIndex = require('serve-index')
var path = require('path')
var serveStatic = require('serve-static')
var app = express()
var port = process.env.PORT || 3000;
/**for files */
app.use(serveStatic(path.join(__dirname, 'public')));
/**for directory */
app.use('/', express.static('public'), serveIndex('public', {'icons': true}))
// Listen
app.listen(port, function () {
console.log('listening on port:',+ port );
})
I would add something that is on the express docs, and it's sometimes misread in tutorials or others.
app.use(mountpoint, middleware)
mountpoint is a virtual path, it is not in the filesystem (even if it actually exists). The mountpoint for the middleware is the app.js folder.
Now
app.use('/static', express.static('public')`
will send files with path /static/hell/meow/a.js to /public/hell/meow/a.js
This is the error in my case when I provide links to HTML files.
before:
<link rel="stylesheet" href="/public/style.css">
After:
<link rel="stylesheet" href="/style.css">
I just removed the static directory path from the link and the error is gone. This solves my error one thing more don't forget to put this line where you are creating the server.
var path = require('path');
app.use(serveStatic(path.join(__dirname, 'public')));
You can achieve this by just passing the second parameter express.static() method to specify index files in the folder
const express = require('express');
const app = new express();
app.use(express.static('/media'), { index: 'whatever.html' })
I want to serve index.html and /media subdirectory as static files. The index file should be served both at /index.html and / URLs.
I have
web_server.use("/media", express.static(__dirname + '/media'));
web_server.use("/", express.static(__dirname));
but the second line apparently serves the entire __dirname, including all files in it (not just index.html and media), which I don't want.
I also tried
web_server.use("/", express.static(__dirname + '/index.html'));
but accessing the base URL / then leads to a request to web_server/index.html/index.html (double index.html component), which of course fails.
Any ideas?
By the way, I could find absolutely no documentation in Express on this topic (static() + its params)... frustrating. A doc link is also welcome.
If you have this setup
/app
/public/index.html
/media
Then this should get what you wanted
var express = require('express');
//var server = express.createServer();
// express.createServer() is deprecated.
var server = express(); // better instead
server.configure(function(){
server.use('/media', express.static(__dirname + '/media'));
server.use(express.static(__dirname + '/public'));
});
server.listen(3000);
The trick is leaving this line as last fallback
server.use(express.static(__dirname + '/public'));
As for documentation, since Express uses connect middleware, I found it easier to just look at the connect source code directly.
For example this line shows that index.html is supported
https://github.com/senchalabs/connect/blob/2.3.3/lib/middleware/static.js#L140
In the newest version of express the "createServer" is deprecated. This example works for me:
var express = require('express');
var app = express();
var path = require('path');
//app.use(express.static(__dirname)); // Current directory is root
app.use(express.static(path.join(__dirname, 'public'))); // "public" off of current is root
app.listen(80);
console.log('Listening on port 80');
express.static() expects the first parameter to be a path of a directory, not a filename. I would suggest creating another subdirectory to contain your index.html and use that.
Serving static files in Express documentation, or more detailed serve-static documentation, including the default behavior of serving index.html:
By default this module will send “index.html” files in response to a request on a directory. To disable this set false or to supply a new index pass a string or an array in preferred order.
res.sendFile & express.static both will work for this
var express = require('express');
var app = express();
var path = require('path');
var public = path.join(__dirname, 'public');
// viewed at http://localhost:8080
app.get('/', function(req, res) {
res.sendFile(path.join(public, 'index.html'));
});
app.use('/', express.static(public));
app.listen(8080);
Where public is the folder in which the client side code is
As suggested by #ATOzTOA and clarified by #Vozzie, path.join takes the paths to join as arguments, the + passes a single argument to path.
const path = require('path');
const express = require('express');
const app = new express();
app.use(express.static('/media'));
app.get('/', (req, res) => {
res.sendFile(path.resolve(__dirname, 'media/page/', 'index.html'));
});
app.listen(4000, () => {
console.log('App listening on port 4000')
})
If you have a complicated folder structure, such as
- application
- assets
- images
- profile.jpg
- web
- server
- index.js
If you want to serve assets/images from index.js
app.use('/images', express.static(path.join(__dirname, '..', 'assets', 'images')))
To view from your browser
http://localhost:4000/images/profile.jpg
If you need more clarification comment, I'll elaborate.
use below inside your app.js
app.use(express.static('folderName'));
(folderName is folder which has files) - remember these assets are accessed direct through server path (i.e. http://localhost:3000/abc.png (where as abc.png is inside folderName folder)
npm install serve-index
var express = require('express')
var serveIndex = require('serve-index')
var path = require('path')
var serveStatic = require('serve-static')
var app = express()
var port = process.env.PORT || 3000;
/**for files */
app.use(serveStatic(path.join(__dirname, 'public')));
/**for directory */
app.use('/', express.static('public'), serveIndex('public', {'icons': true}))
// Listen
app.listen(port, function () {
console.log('listening on port:',+ port );
})
I would add something that is on the express docs, and it's sometimes misread in tutorials or others.
app.use(mountpoint, middleware)
mountpoint is a virtual path, it is not in the filesystem (even if it actually exists). The mountpoint for the middleware is the app.js folder.
Now
app.use('/static', express.static('public')`
will send files with path /static/hell/meow/a.js to /public/hell/meow/a.js
This is the error in my case when I provide links to HTML files.
before:
<link rel="stylesheet" href="/public/style.css">
After:
<link rel="stylesheet" href="/style.css">
I just removed the static directory path from the link and the error is gone. This solves my error one thing more don't forget to put this line where you are creating the server.
var path = require('path');
app.use(serveStatic(path.join(__dirname, 'public')));
You can achieve this by just passing the second parameter express.static() method to specify index files in the folder
const express = require('express');
const app = new express();
app.use(express.static('/media'), { index: 'whatever.html' })
Been having some issues with express, I can't seem to serve static files.
If I do :
app.use('/*', express.static(DIST_FILEPATH));
it gives me a 301 or something, basically doesn't find the file (I have tried it in incognito mode also to avoid chasing/whatever issues).
But for some reason if I do:
app.use('/*', function (req, res, next) {
console.log(req.originalUrl);
console.log(DIST_FILEPATH);
res.sendFile(path.join(DIST_FILEPATH, req.originalUrl));
});
It works just fine and both paths are correct. Why is this happening and how can I solve it?
Express version: 4.14.1
Your issue is that you have the syntax slightly off. What you can do if you want to only server static files is use app.use(express.static(path.join(__dirname))); then when you go to http://localhost:3000/ you can add things like index.html so that you can see your html file. Here is an example of a simple express server that serves static files:
var express = require('express');
var path = require('path');
var app = express();
app.set('port', 3000);
app.use(express.static(path.join(__dirname))); //here you can change your path. for example you could add + 'public' if all of your files where in the 'public' directory
var server = app.listen(app.get('port'), function() {
var port = server.address().port;
});
You can run this with node <filename>.js then just go to http://localhost:3000/index.html or http://localhost:3000/myMusicFile.mp3 for example.
hope this helps!
I am integrating a 3rd party template which has a slideshow written using Mootools. The nodejs is configured with express and ejs
The data for the slideshow comes from a few xml files. For example data.xml. I placed the data.xml in public folder and added the following code to server.js (the main file)
app.use(express.static(__dirname + '/public'));
app.post('/data.xml', function(req, res){
res.contentType('application/xml');
res.sendFile('/data.xml');
});
Unfortunately this does not seems to work. I can see the file if I type the url
http://localhost:8080/data.xml
But the response I see in firebug is
" Cannot POST /data.xml "
I am assuming Mootools is trying to access the file using some POST method. Any suggestions for this problem?
when you are sending the file with sendFile() you need to point to the absolute address check this. note that I have the data.xml in the main folder.
you can access the file with localhost:8080/data (not localhost:8080/data.xml) and also as this is a post, you cannot access it through browser. use postman instead. or if you need it to be accessible on browser you need to change the protocol to get.
var express = require('express');
var path = require('path');
var app = express();
// you don't need this line!
// app.use(express.static(path.join(__dirname)));
app.post('/data', function(req, res){
res.contentType('application/xml');
res.sendFile(path.join(__dirname , 'data.xml'));
});
var server = app.listen(8080, () => {
console.log('Started listening on 8080');
});
I am hosting a single page app with Node and Express. I use the static middleware for the client. I am using path URLs to navigate the app, for example domain.com/profile/134. I am using history.pushState to change pages internally on the client, and this works fine. What I am missing is a wildcard rule on the server to catch all possible paths when the user accesses my page directly to a path that is not root. If I try to access domain.com/profile/134 directly I get this: "Cannot GET /profile/134". I have tried to insert a wildcard get at the end of server.js, but it seems to be hit every time, also when I access the page root. This is my relevant code:
var express = require('express');
var app = express();
app.use(express.static(__dirname + '/../client'));
app.get('/*', function(req, res) {
console.log('wildcard');
});
Is this the correct GET wildcard rule to achieve what I need, and how can I serve the static client inside this handler? My client side will find the right page afterwards as long as the initial path is preserved. I basically want this wildcard rule to behave the same as the static rule, but keep the initial path.
You can use a hack
app.get('/:url', function(req, res) {
console.log('wildcard');
});
or try this one
app.get('/(.*)', function(req, res) {
console.log('wildcard');
});
[edited]: this should work as you expect:
var express = require('express');
var app = express();
app.get(/(.*)/, function(req, res) {
console.log("req.path", req.path);
res.send('success');
});
var server = app.listen(3000, function () {
var host = server.address().address;
var port = server.address().port;
console.log('Example app listening at http://%s:%s', host, port);
});
I ended up using an npm module named express-history-fallback-api to solve this. Out of the box it solved both simple and advanced paths, like domain.com/settings and domain.com/profile/username
https://www.npmjs.com/package/express-history-api-fallback