Express.js - export/access function within route file - node.js

Question

I am trying to export function within route file. Here is my code
app.js file
var express = require('express');
var bodyParser = require('body-parser');
var users = require('./routes/users');
var others=require('./routes/others')
var app = express();
app.set('views', path.join(__dirname, 'views'));
app.set('view engine', 'jade');
app.use(bodyParser.json());
app.use(bodyParser.urlencoded({ extended: false }));
app.use(cookieParser());
app.use(express.static(path.join(__dirname, 'public')));
app.use('/', routes);
app.use('/others', others);
app.use('/users', users);
module.exports = app;
others.js file
var express = require('express');
var router = express.Router();
router.post("/test", function (req, res, next) {
res.send("success");
});
//Here i want to export function to users js file
var funDef=function(){
console.log("export a function")
}
moudle.exports=router;
How can I export or call funDef in users.js file. I tried the following way but it is not working
users.js file
var express = require('express');
var router = express.Router();
var readFun= require("./others.js");
router.post("/testUsers", function (req, res, next) {
res.send("suceess");
});
//getting undefined
readFun.funDef();
module.exports=router;
Can anyone guide me?

Answer 1

Try for the following:
function router() {}
router.prototype.funDef=function(){
console.log("export a function")
}
moudle.exports.router=router;
Another file:
var router = require('router').router;
var Router = new router();
Router.funDef();
EDIT:
// module.js
'use strict';
var temp = "this is a test";
module.exports.func = function() {
return temp;
}
// app.js
'use strict';
var module = require('./module');
console.log(module.func());