Find Instagram media url by ID - instagram

Question

Thanks to a HTTP call not very official, I find media ID, image URL, and user name of Instagram posts.
But I need the URL of each post on Instagram, and I don't know how to find it.
Is there an URL like instagram.com/something/{mediaID} which redirect to instagram.com/p/{mediaSlug}, or another method to find slug by media ID (without using the official API of course!) ?
For example, I've got :
Unique number : 1238578393243739028_1408429375
Media ID : 1238578393243739028
User ID : 1408429375
And I would :
https://www.instagram.com/p/BEwUHyDxGOU/
Thanks for your help !

Answer 1

Java Solution:
public static String getInstagramPostId(String mediaId) {
String postId = "";
try {
long id = Long.parseLong(mediaId.substring(0, mediaId.indexOf('_')));
String alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_";
while (id > 0) {
long remainder = (id % 64);
id = (id - remainder) / 64;
postId = alphabet.charAt((int)remainder) + postId;
}
} catch (Exception e) {
e.printStackTrace();
}
return postId;
}

Answer 2

This can be helpful:
1) The algorithm to generate URL by yourself
http://carrot.is/coding/instagram-ids
2) Also, Instagram has private API endpoint to generate URLs by media_id:
https://i.instagram.com/api/v1/media/1212073297261212121_121212123111/permalink/
but it is protected with cookie sessionid

Answer 3

Sharing the implementation in JavaScript, using big-integer package (https://www.npmjs.com/package/big-integer)
var bigInt = require('big-integer');
function getShortcodeFromTag(tag) {
let id = bigInt(tag.split('_', 1)[0]);
const alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_";
let remainder;
let shortcode = '';
while (id.greater(0)) {
let division = id.divmod(64);
id = division.quotient;
shortcode = `${alphabet.charAt(division.remainder)}${shortcode}`;
}
return shortcode;
}

Answer 4

I found a solution for iOS objective-C:
-(NSString *) getInstagramPostId:(NSString *)mediaId {
NSString *postId = #"";
#try {
NSArray *myArray = [mediaId componentsSeparatedByString:#"_"];
NSString *longValue = [NSString stringWithFormat:#"%#",myArray[0]];
long itemId = [longValue longLongValue];
NSString *alphabet = #"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_";
while (itemId > 0) {
long remainder = (itemId % 64);
itemId = (itemId - remainder) / 64;
unsigned char charToUse = [alphabet characterAtIndex:(int)remainder];
postId = [NSString stringWithFormat:#"%c%#",charToUse , postId];
}
} #catch(NSException *exception) {
NSLog(#"%#",exception);
}
return postId;}

Answer 5

Swift 4.2 Solution:
func getInstagramPostId(_ mediaId: String?) -> String? {
var postId = ""
do {
let myArray = mediaId?.components(separatedBy: "_")
let longValue = "\(String(describing: myArray?[0]))"
var itemId = Int(Int64(longValue) ?? 0)
let alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_"
while itemId > 0 {
let remainder: Int = itemId % 64
itemId = (itemId - remainder) / 64
let charToUse = alphabet[alphabet.index(alphabet.startIndex, offsetBy: Int(remainder))]
postId = "\(charToUse)\(postId)"
}
}
return postId
}
C# Solution:
public static string getInstagramPostId(string mediaId)
{
string postId = "";
try
{
long id = long.Parse(mediaId.Substring(0, mediaId.IndexOf('_')));
string alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_";
while (id > 0)
{
long remainder = (id % 64);
id = (id - remainder) / 64;
int a = (int)remainder + int.Parse(postId);
postId = "" + alphabet[a];
}
}
catch (Exception e)
{
Console.Write(e.StackTrace);
}
return postId;
}

Answer 6

Based on great http://carrot.is/coding/instagram-ids article, here is the example ruby implementation on converting numeric to string ids:
def translate(post_id)
dict = [?A..?Z, ?a..?z, 0..9].map(&:to_a).flatten
dict += ['-', '_']
post_id = post_id.split('_').first.to_i
to_radix(post_id, 64).map { |d| dict[d] }.join
end
def to_radix(int, radix)
int == 0 ? [] : (to_radix(int / radix, radix) + [int % radix])
end
Where you'd just call translate('1238578393243739028_1408429375') and get back BEwUHyDxGOU.

Answer 7

C# Solution (Tested)
public static string getInstagramPostId(string mediaId)
{
string postId = "";
try
{
long id = long.Parse(mediaId.Substring(0, mediaId.IndexOf('_')));
string alphabet = "ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789-_";
while (id > 0)
{
long remainder = (id % 64);
id = (id - remainder) / 64;
postId = alphabet.ElementAt((int)remainder) + postId;
}
}
catch (Exception e)
{
Console.Write(e.StackTrace);
}
return postId;
}

Answer 8

Just add one more field which is 'permalink'
List<String> mediaFields = [
'id',
'media_type',
'media_url',
'username',
'permalink'
];