I'm using nightwatch to check that a table cell on a page contains a number greater than 0.
To achieve this I have to use the node assert package:
const assert = require('assert');
So first, I get the table cell element text, and in the callback I parse it to an int and use assert to check it's value:
...
.getText("//table[#id='topology-summary-table']/tbody/tr/td[7]", function(el){
assert(parseInt(el.value) > 0, "Num Executors == 0!");
}).end()
...
The only problem with this is that if assert throws an AssertionError (ie: if the number in the table cell is 0), then the test halts, and .end() never gets called, thus leaving the browser process open and hanging around. Not ideal.
I have got around that fact by doing the following:
...
.getText("//table[#id='topology-summary-table']/tbody/tr/td[7]", function(el){
try {
assert(parseInt(el.value) > 0, "Num Executors == 0!");
} catch(e){
this.end();
throw e;
}
})
...
but for some reasons this makes me feel bad. :(
My question is: Is there a better way?
The nightwatch api actually extends the assert api, so there is no need to require it.
Instead, do this:
.getText("//table[#id='topology-summary-table']/tbody/tr/td[7]", function(el){
this.assert.ok(parseInt(el.value) > 0, "Num Workers == 0!");
})
Answer provided by beatfactor here: https://github.com/nightwatchjs/nightwatch/issues/1002#issuecomment-223240103
Related
so i have the following code
data.push(commands.map(
command => {
if (!command.devOnly) { return command.name; } // first condition
if (command.devOnly && message.author.id != '3251268789058714880') {} // second condition
},
).join('\n'));
if the second condition is true it returns null but then when I run console.log(data) it has a blank line for all the commands where the second condition is true.
Is there a way to stop the second condition from returning anything, and not leaving the blank line
.map() is a 1-for-1 transformation so the output array will have EXACTLY the same number of elements in it as the input array. If you don't return anything, that element in the array will have an undefined value (which is the return value when you don't actively return something).
To transform the array and eliminate some elements, you cannot use .map(). You can either do .filter().map() where you first filter out the items you don't want and then map the others or you can use a regular for loop and just push the items into output array that you want to keep using either a regular for loop iteration or a .reduce() or .forEach() iteration.
One example:
const results = commands.filter(command => !command.devOnly).map(command => command.name);
console.log(results);
const results = [];
for (let command of commands) {
if (!command.devOnly) results.push(command.name);
}
console.log(results);
Note, your second condition doesn't do anything at all in your code example so I wasn't sure how to account for that in these examples.
P.S. I've often wished Javascript had a .filterMap() feature that let you return undefined to leave that value out of the result - otherwise work like .map(). But, it doesn't have that feature built in. You could build your own.
Per your comments, you can filter on two conditions like this:
const results = commands
.filter(command => !command.devOnly || message.author.id === '3251268789058714880')
.map(command => command.name);
console.log(results);
you could use Array.reduce
commands.reduce((prev,command)=>{
if (!command.devOnly)
return [...prev,command.name]
// this if, is useless but shows that you can use more conditions.
if (command.devOnly && message.author.id != '3251268789058714880')
return prev
// add more conditions as you need here
return prev
},[])
another options could be by doing map then filter the undefined values, or use for-loop
like jfriend00 explained in his answer. the filterMap() he wished could be implemented with Array.reduce
I have a JSON file of 2 discord client IDs `{
{
"premium": [
"a random string of numbers that is a client id",
"a random string of numbers that is a client id"
]
}
I have tried to access these client IDs to do things in the program using a for loop + if statement:
for(i in premium.premium){
if(premium.premium[i] === msg.author.id){
//do some stuff
}else{
//do some stuff
When the program is ran, it runs the for loop and goes to the else first and runs the code in there (not supposed to happen), then runs the code in the if twice. But there are only 2 client IDs and the for loop has ran 3 times, and the first time it runs it goes instantly to the else even though the person who sent the message has their client ID in the JSON file.
How can I fix this? Any help is greatly appreciated.
You may want to add a return statement within your for loop. Otherwise, the loop will continue running until a condition has been met, or it has nothing else to loop over. See the documentation on for loops here.
For example, here it is without return statements:
const json = {
"premium": [
"aaa-1",
"bbb-1"
]
}
for (i in json.premium) {
if (json.premium[i] === "aaa-1") {
console.log("this is aaa-1!!!!")
} else {
console.log("this is not what you're looking for-1...")
}
}
And here it is with return statements:
const json = {
"premium": [
"aaa-2",
"bbb-2"
]
}
function loopOverJson() {
for (i in json.premium) {
if (json.premium[i] === "aaa-2") {
console.log("this is aaa-2!!!!")
return
} else {
console.log("this is not what you're looking for-2...")
return
}
}
}
loopOverJson()
Note: without wrapping the above in a function, the console will show: "Syntax Error: Illegal return statement."
for(i in premium.premium){
if(premium.premium[i] === msg.author.id){
//do some stuff
} else{
//do some stuff
}
}
1) It will loop through all your premium.premium entries. If there are 3 entries it will execute three times. You could use a break statement if you want to exit the loop once a match is found.
2) You should check the type of your msg.author.id. Since you are using the strict comparison operator === it will evaluate to false if your msg.author.id is an integer since you are comparing to a string (based on your provided json).
Use implicit casting: if (premium.premium[i] == msg.author.id)
Use explicit casting: if (premium.premium[i] === String(msg.author.id))
The really fun and easy way to solve problems like this is to use the built-in Array methods like map, reduce or filter. Then you don't have to worry about your iterator values.
eg.
const doSomethingAuthorRelated = (el) => console.log(el, 'whoohoo!');
const authors = premiums
.filter((el) => el === msg.author.id)
.map(doSomethingAuthorRelated);
As John Lonowski points out in the comment link, using for ... in for JavaScript arrays is not reliable, because its designed to iterate over Object properties, so you can't be really sure what its iterating on, unless you've clearly defined the data and are working in an environment where you know no other library has mucked with the Array object.
Hi everyone,
I am trying to test C programs that use an user input... Like a learning app. So the avaliator(teacher) can write tests and I compile the code with a help of a docker and get back the result of the program that I send. After that I verify if one of the case tests fails..
for that I have two strings, like this:
result = "input_compiled1540323505983: /home/compiler/input/input.c:9: main: Assertion `B==2' failed. timeout: the monitored command dumped core Aborted "
and an array with case tests that is like:
caseTests = [" assert(A==3); // A must have the value of 3;", " assert(B==2); // B must have the value of 2; ", " assert(strcmp(Fulano, "Fulano")==0); //Fulano must be equal to Fulano]
I need to send back from my server something like this:
{ console: [true, true, true ] }
Where each true is the corresponding test for every test in the array of tests
So, I need to test if one string contains the part of another string... and for now I did like this:
criandoConsole = function(arrayErros, arrayResult){
var consol = arrayErros.map( function( elem ) {
var local = elem.match(/\((.*)\)/);
if(arrayResult.indexOf(local) > -1 ) {
return false;
}
else return true;
});
return consol;
}
I am wondering if there are any more efective way of doing that. I am using a nodejs as server. Does anyone know a better way?!
ps: Just do like result.contains(caseTests[0]) did not work..
I know this is changing the problem, but can you simplify the error array to only include the search terms? For example,
result = "input_compiled1540323505983: /home/compiler/input/input.c:9: main: Assertion `B==2' failed. timeout: the monitored command dumped core Aborted ";
//simplify the search patterns
caseTests = [
"A==3",
"B==2",
"strcmp(Fulano, \"Fulano\")==0"
]
criandoConsole = function(arrayErros, arrayResult){
var consol = arrayErros.map( function( elem ) {
if (arrayResult.indexOf(elem) != -1)
return false; //assert failed?
else
return true; //success?
});
return consol;
}
console.log(criandoConsole(caseTests,result));
On the page that I am testing, a user can have a single currency or multiple currencies (i.e EUR and USD)the currency/currencies will appear in the same div at the top of the page.
If a user has multiple currencies, a tab for each currency will appear further down the page, if a user has only one currency, no tabs will appear (as there is no need for the user to switch tabs).
I am able to test multi currency users by checking to see if the text contained in the header matches the text contained in the currencies tabs.
However, as no tabs appear for a single currency, I'm not sure how to test this.
For example, if I have only a 'EUR' currency, is there a way to do something like
if element(by.className("currencies"))contains 'EUR'
&& doesn't contain 'USD' && doesn't contain 'GBP'
expect element(by.className("tabs").toDisplay.toBeFalsy()
This is the code for the page object file
this.checkCurrency = function(currency) {
var checkBalance = element(by.className("balances"));
checkBalance.getText().then(function (text) {
if (text.indexOf("GBP" && "EUR")>= 0) {
expect(element.all(by.linkText("GBP")).isDisplayed()).toBeTruthy();
console.log("EUR GBP buyer");
}
else if (text.indexOf("GBP" && "USD")>= 0) {
expect(element.all(by.linkText('USD')).isDisplayed()).toBeTruthy();
console.log("USD GBP buyer");
}
else
{
console.log("false");
}
});
};
From your description I'm not quite sure where the failure is. In general you want to keep this kind of logic out of your page object. Your test should understand what state the page should be in and call different functions. I know that's not always possible, but it works out so much better if you can. Here is some general condition advise that should help.
You can catch the success state and a failed state of a promise. Most people use the pass function, but forget about the fail function.
promise.then(passFunction, failFunction)
You can use this in several different ways. If you realize that almost everything in protractor is returning a promise.
Example:
element(by.className("currencies")).getText()
.then(
function(text) {
//check on something
},function(error){
//don't check on something
if(someCondition) {
throw error;
} else {
//the test continues
}
});
You can even do it with and expect
expect(element(by.className("currencies")).getText()).not.toContain("EUR")
.then(
function(passed) {
//check on something
},function(failed){
//don't check on something
if(someCondition) {
throw failed;
} else {
//the test continues
}
});
Or a simple findElement
element(by.className("currencies"))
.then(
function(element) {
//check on something
},function(error){
//don't check on something
if(someCondition) {
throw failed;
} else {
//the test continues
}
});
I'm new to groovy and I have doubt. Lets say I have this statement:
assert "king" == "kin"
which will give me the assert failure as
Assertion failed:
assert "king" == "kin"
|
false
and stops the program. But what I want is, store the result (the failure message, if any say in GString) and proceed with the program.
Is that possible to do so?
You can catch the AssertionError exception. Something like this:
try {
assert ["hello"] == ["A"]
}
catch(AssertionError e) {
result = e.getMessage()
}
println result
This should work.