I am trying to recover some BMP image header, and the all information I got is this:
the bytes of the header that have been deleted are 54
the start offset is 1130 (decimal)
the width is 350 (decimal).
bits per pixel is 8
no compression
So I read little bit (mostly from here) and I saw which bytes present what, and I got the next first 54 bytes of the BMP header:
42 4D 6E 7F 0C 00 00 00 00 00 36 00 00 00 28 00 00 00 F4 01 00 00 22 02 00 00 01 00 18 00 00 00 00 00 38 7F 0C 00 13 0B 00 00 13 0B 00 00 00 00 00 00 00 00 00 00
But for some reason, when I am trying to open my all BMP images and my header, I get just a black image. Did I do something wrong? Do I build the
wrong header from the information above?
I'm trying to change the card manager AID on a JavaCard 3.x smartcard by using a STORE DATA command. The current card manager AID is the factory default of A0 00 00 01 51 00 00 00. After authenticating with the card manager, the command I'm sending is:
=> 80 E2 80 00 0A 4F 08 A0 00 00 00 03 00 00 00
<= 6A 88
This command executes successfully on a JavaCard 2.2.x card - has this feature been deprecated on JC 3.x?
Looks like the JavaCard 3 needs the command data in DGI format for this to work:
=> 80 E2 80 00 0D 00 70 0A 4F 08 A0 00 00 00 03 00 00 00
<= 90 00
I wrote a basic helloworld.exe with C with the simple line printf("helloworld!\n");
Then I used UltraEdit to view the bytes of the EXE file and used also PE Explorer to see the header values. When it comes to Address of Entry Point, PE Explorer displays 0x004012c0.
Magic 010Bh PE32
Linker Version 1902h 2.25
Size of Code 00008000h
Size of Initialized Data 0000B000h
Size of Uninitialized Data 00000C00h
Address of Entry Point 004012C0h
Base of Code 00001000h
Base of Data 00009000h
Image Base 00400000h
But in UltraEdit I see 0x000012c0 after counting 16 bytes after magic 0x010B.
3F 02 00 00 E0 00 07 03 0B 01 02 19 00 80 00 00
00 B0 00 00 00 0C 00 00 C0 12 00 00 00 10 00 00
00 90 00 00 00 00 40 00 00 10 00 00 00 02 00 00
04 00 00 00 01 00 00 00 04 00 00 00 00 00 00 00
00 10 01 00 00 04 00 00 91 F6 00 00 03 00 00 00
00 00 20 00 00 10 00 00 00 00 10 00 00 10 00 00
00 00 00 00 10 00 00 00 00 00 00 00 00 00 00 00
00 E0 00 00 C0 06 00 00 00 00 00 00 00 00 00 00
Which one is correct?
simply read about IMAGE_OPTIONAL_HEADER structure
AddressOfEntryPoint
A pointer to the entry point function, relative to the image base
address. For executable files, this is the starting address. For
device drivers, this is the address of the initialization function.
The entry point function is optional for DLLs. When no entry point is
present, this member is zero.
so absolute address of EntryPoint is AddressOfEntryPoint ? ImageBase + AddressOfEntryPoint : 0
in your case AddressOfEntryPoint == 12c0 and ImageBase == 400000
as result absolute address of EntryPoint is 12c0+400000==4012c0
So I've got really big .bin files with bytes written in them. They have 96-bit numbers written in them as two's complement numbers (still no ASCII, only bytes). Now I have to write an assembly program to sort the numbers in this files and save it to another file (don't ask why, assembly class). I've done it for a file with 32k numbers, like this:
./main < inSort32Kx96b.bin > XD.bin
diff outSort32Kx96b.bin XD.bin
The file outSort32Kx96b.bin is given to me by my teacher. So now diff doesn't output anything, they are identical (I can check that with hexdump or mcview). But I got another file inSort1Kx96b.bin. And I also sort it. But then diff says:
Binary files outSort1Kx96b.bin and XD.bin differ
#Edit:
cmp gave the number of byte where those 2 files differ. Now I can see the difference:
So the difference appears from 0x000017C0. Then I don't know now. If they are written as two's complement numbers in little endian order, then which one is bigger, f.e
00 00 00 00 00 00 00 81 00 00 00 00
or
00 00 00 00 00 00 00 7F 00 00 00 00
?
A hexdump shows you the single bytes in big endian order. If a bunch of bytes have to be interpreted as a number, only the byte order is reversed.
little endian big endian (C notation)
AB CD EF = 0xEFCDAB
01 02 03 04 05 06 07 08 09 10 11 12 = 0x121110090807060504030201
Let's translate your examples to big endian order:
0x000000008100000000000000
0x000000007F00000000000000
You can see that the first number is bigger.
"Two's complement number" is not a very clear expression. Better is "signed integer". The sign which shows whether the number is positive or negativ, is the very first bit of the number. This bit can be found at the begginning of a big endian number and the end of a little endian number.
Positive:
00 00 00 00 00 00 00 81 00 00 00 00 = 0x000000008100000000000000
00 00 00 00 00 00 00 81 00 00 00 10 = 0x100000008100000000000000
00 00 00 00 00 00 00 81 00 00 00 7F = 0x7F0000008100000000000000
Negativ:
00 00 00 00 00 00 00 81 00 00 00 80 = 0x800000008100000000000000
00 00 00 00 00 00 00 81 00 00 00 CD = 0xCD0000008100000000000000
00 00 00 00 00 00 00 81 00 00 00 F0 = 0xF00000008100000000000000
During a fresh installation, I accidentally formatted a disk containing datas. I have tried using some tools: testdisk, foremost, but I did not get good results. (see my unsuccessful post on superuser).
So I have decided to read some docs about ext2 filesystem structure, and I could get some results:
The deleted partition have a directory tree like that:
dev
|-scripts
|-projects
|-services
|-...
Medias
|-downloads
|-Musique
|-...
backup
...
So, based on the ext2 directory entry format:
Directory Entry
Starting_Byte Ending_Byte Size_in_Bytes Field_Description
0 3 4 Inode
4 5 2 Total size of this entry (Including all subfields)
6 6 1 Name Length least-significant 8 bits
7 7 1 Type indicator (only if the feature bit for "directory entries have file type byte" is set, else this is the most-significant 8 bits of the Name Length)
8 8+N-1 N Name characters
I tried to find some datas matching this structure.
I used this script:
var bindexOf = require('buffer-indexof');
var currentOffset=0;
var deviceReadStream = fs.createReadStream("/dev/sdb");
deviceReadStream.on('error',function(err){
console.log(err);
});
deviceReadStream.on('data',function(data){
var dirs = ["dev","scripts","services","projects","Medias","downloads","Musique","backup"];
dirs.forEach(function(dir){
dirOctetFormat = new Buffer(2);
dirOctetFormat.writeUInt8(dir.length,0);
dirOctetFormat.writeUInt8(2,1);// type is directory
dirOctetFormat= Buffer.concat( [dirOctetFormat, new Buffer(dir)]);
var offset = bindexOf( data, dirOctetFormat );
if( offset >= 0 ){
console.log( dir + " entry found at offset " + (currentOffset + offset) );
}
});
currentOffset += data.length;
});
}
I found data which seems to be the directory entry of the dev directory:
===== Current offset: 233590226944 - 217.5478515625Gio ======
scripts entry found at offset 233590227030
services entry found at offset 233590227014
projects entry found at offset 233590228106
If it is the case, I got the inode numbers of its children directories: scripts, projects, services,...
But I do not know what to do with that!
I tried to deduce the location of these inodes, based on this guide,
but as I was unable to find a superblock of the deleted filesystem, I just have to make guesses about the block size, the number of blocks, ...
and that seems a little bit fuzzy to me to hope obtaining a result.
So could you have some intervals for all values needed to obtain the offset of an inode, and a more formal formula to get this offset?
If you have only erased the partition table (or modified it) you can still get your data, if data has not been reused for something else.
ext2 filesystems have a MAGIC number in superblock, so to recover your partition you have only to search for it. I did this on one machine and was able to recover not one, but seven partitions in one disk. You have some chances to get invalid numbers, but just search for that magic. Magic number is defined in include/uapi/linux/magic.h and value is #define EXT2_SUPER_MAGIC 0xEF53 (it's found at offset #define EXT2_SB_MAGIC_OFFSET 0x38 ---from file include/linux/ext2_fs.h)
To search for the superblock, just try to find 0xef53 at offset 0x38 in one sector of the disk, it will mark the first block of the partition. Be careful, that superblock is replicated several times in one partition, so you'll find all the copies of it.
Good luck! (I had when it happened to me)
Edit (To illustrate with an example)
Just see the magic number in one of my own partitions:
# hd /dev/sda3 | head -20
00000000 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
*
00000400 40 62 08 00 00 87 21 00 26 ad 01 00 f6 30 15 00 |#b....!.&....0..|
00000410 1d 31 08 00 00 00 00 00 02 00 00 00 02 00 00 00 |.1..............|
00000420 00 80 00 00 00 80 00 00 90 1f 00 00 cf 60 af 55 |.............`.U|
00000430 fc 8a af 55 2d 00 ff ff 53 ef 01 00 01 00 00 00 |...U-...S.......|<- HERE!!!
00000440 36 38 9d 55 00 00 00 00 00 00 00 00 01 00 00 00 |68.U............|
00000450 00 00 00 00 0b 00 00 00 00 01 00 00 3c 00 00 00 |............<...|
00000460 46 02 00 00 7b 00 00 00 5a bf 87 15 12 8f 44 3b |F...{...Z.....D;|
00000470 97 e7 f3 74 4d 75 69 12 72 6f 6f 74 00 00 00 00 |...tMui.root....|
00000480 00 00 00 00 00 00 00 00 2f 00 61 72 67 65 74 00 |......../.arget.|
00000490 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
*
000004c0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 18 02 |................|
000004d0 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 |................|
000004e0 08 00 00 00 00 00 00 00 00 00 00 00 93 54 99 ab |.............T..|
000004f0 aa 64 46 b3 a6 73 94 34 a3 79 46 28 01 01 00 00 |.dF..s.4.yF(....|
00000500 0c 00 00 00 00 00 00 00 e5 61 92 55 0a f3 02 00 |.........a.U....|
00000510 04 00 00 00 00 00 00 00 00 00 00 00 ff 7f 00 00 |................|
00000520 00 80 10 00 ff 7f 00 00 01 00 00 00 ff ff 10 00 |................|
Remember it is on offset 0x38 counted from the block origin, and assume the super block is the second block (block 0 reserved for bootcode, so it will be block 1, with two sectors per block, to make 1k blocksize) in the partition, so you'll have to rewind 0x438 bytes from the beginning of the magic number to get the partition origin.
I have run the command on my whole disk, getting the following result:
# hd /dev/sda | grep " [0-9a-f][0-9a-f] 53 ef" | sed -e 's/^/ /' | head
006f05f0 ee 00 00 11 66 0a 00 00 53 ef 00 00 11 66 2d 00 |....f...S....f-.|
007c21d0 55 2a aa 7d f4 aa 89 55 53 ef a4 91 70 40 c1 00 |U*.}...US...p#..|
20100430 fc 8a af 55 2d 00 ff ff 53 ef 01 00 01 00 00 00 |...U-...S.......|
2289a910 0f 8f 4f 03 00 00 81 fe 53 ef 00 00 0f 84 ce 04 |..O.....S.......|
230d4c70 0a 00 00 00 1c 00 00 00 53 ef 01 00 00 00 00 00 |........S.......|
231b7e50 a0 73 07 00 00 00 00 00 53 ef 0d 00 00 00 00 00 |.s......S.......|
23dbd230 d5 08 ad 2b ee 71 07 8a 53 ef c2 89 d4 bb 09 1f |...+.q..S.......|
25c0c9e0 06 00 00 00 00 4f 59 c0 53 ef 32 c0 0e 00 00 00 |.....OY.S.2.....|
25d72ca0 b0 b4 7b 3d a4 f7 84 3b 53 ef ba 3c 1f 32 b9 3c |..{=...;S..<.2.<|
25f0eab0 f1 fd 02 be 28 59 67 3c 53 ef 9c bd 04 30 72 bd |....(Yg<S....0r.|
Clearly, there are much more uninteresting lines in this listing than the ones we need. To locate the one interesting here, we have to do some computing with the numbers. We have seen that sectors are 512 bytes long (this is 0x200 in hex) and we can have the superblock magic at offset 0x438, so we expect valid offsets to be at 0xXXXXXX[02468ace]38 only. Just select the lines with offsets ending in that expression, and you'll get the first superblock valid (in the third line) at offset 0x20100430.
Substract 0x430 to give the byte offset of the partition (0x20100000, and then, divide the result by 0x200, giving 0x100800, or 1050624)
# fdisk -l /dev/sda | sed -e 's/^/ /'
Disk /dev/sda: 931.5 GiB, 1000204886016 bytes, 1953525168 sectors
Units: sectors of 1 * 512 = 512 bytes
Sector size (logical/physical): 512 bytes / 4096 bytes
I/O size (minimum/optimal): 4096 bytes / 4096 bytes
Disklabel type: gpt
Disk identifier: DF97DAD4-727D-4BB3-BD7B-3C5A584A2747
Device Start End Sectors Size Type
/dev/sda1 2048 526335 524288 256M EFI System
/dev/sda2 526336 1050623 524288 256M BIOS boot
/dev/sda3 1050624 18628607 17577984 8.4G Linux filesystem <-- HERE!!!
/dev/sda4 18628608 77221887 58593280 28G Linux filesystem
/dev/sda5 77221888 85035007 7813120 3.7G Linux filesystem
/dev/sda6 85035008 104566783 19531776 9.3G Linux filesystem
/dev/sda7 104566784 135817215 31250432 14.9G Linux swap
/dev/sda8 135817216 155348991 19531776 9.3G Linux filesystem
/dev/sda9 155348992 1953523711 1798174720 857.4G Linux filesystem