Within a nodejs script I have the following code which makes the call synchronously and returns the stdout from the shell script I am calling:
var sh = require('shelljs');
... some code
var output = sh.exec('./someshellscript.sh', {silent:true}).stdout;
console.log(output);
... some more code (that shouldnt run until the script is complete)
I can also run the following script which will instead return the stderr:
var sh = require('shelljs');
... some code
var output = sh.exec('./someshellscript.sh', {silent:true}).stderr;
console.log(output);
... some more code (that shouldnt run until the script is complete)
However I want to receive both stdout and stderr in a sync call. Its probably something pretty obvious I am missing herebut I cant work it out.
I think you used to be able run the following command in previous versions but this just returns undefined now:
var sh = require('shelljs');
... some code
var output = sh.exec('./someshellscript.sh', {silent:true}).output;
console.log(output);
... some more code (that shouldnt run until the script is complete)
Relevant software versions are:
Ubuntu: 14.04.3 LTS
node: 4.4.4
npm: 2.15.1
shelljs: 0.7.0
Any help appreciated thanks.
From the README for the method exec(command [, options] [, callback])
Executes the given command synchronously, unless otherwise specified. [...], returns an object of the form { code:..., stdout:... , stderr:... }).
Therefore
const { stdout, stderr, code } = sh.exec('./someshellscript.sh', { silent: true })
Related
Imagine this contrived scenario:
./main.sh
source ./config.sh
SOME_CONFIG="${SOME_CONFIG}bar"
./output.sh
./config.sh
export SOME_CONFIG='foo'
./output.sh
echo "Config is: ${SOME_CONFIG}"
I am trying to replace ./main.sh with a Node.js powered ./main.js WITHOUT replacing the other shell files. The exported ./config.sh functions/variables must also be fully available to ./output.sh
Here is a NON working ./main.js. I have written this for the sole purpose to explain what I want the final code to look like:
const terminal = require('child_process').spawn('bash')
terminal.stdin.write('source ./config.sh\n')
process.env.SOME_CONFIG = `${process.env.SOME_CONFIG}bar` // this must be done in JS
terminal.stdin.write('./output.sh\n') // this must be able to access all exported functions/variables in config.sh, including the JS modified SOME_CONFIG
How can I achieve this? Ideally if there's a library that can do this I'd prefer that.
While this doesn't fully answer my question, it solves the contrived problem I had at hand and could help others if need be.
In general, if bash scripts communicate with each other via environment variables (eg. using export/source), this will allow you to start moving bash code to Node.js.
./main.js
const child_process = require("child_process");
const os = require("os");
// Source config.sh and print the environment variables including SOME_CONFIG
const sourcedConfig = child_process
.execSync(". ./config.sh > /dev/null 2>&1 && env")
.toString();
// Convert ALL sourced environment variables into an object
const sourcedEnvVars = sourcedConfig
.split(os.EOL)
.map((line) => ({
env: `${line.substr(0, line.indexOf("="))}`,
val: `${line.substr(line.indexOf("=") + 1)}`,
}))
.reduce((envVarObject, envVarEntry) => {
envVarObject[envVarEntry.env] = envVarEntry.val;
return envVarObject;
}, {});
// Make changes
sourcedEnvVars["SOME_CONFIG"] = `${sourcedEnvVars["SOME_CONFIG"]}bar`;
// Run output.sh and pass in the environment variables we got from the previous command
child_process.execSync("./output.sh", {
env: sourcedEnvVars,
stdio: "inherit",
});
I am using a function from one file, in another file, and calling it there. This is causing the function to run twice at the same time when run from the command line, but not when I run it in VSCode.
Here is an example:
// fileOne
async function task() {
console.log('Hello')
}
module.exports = { task }
// fileTwo
const fileOne = require('./fileOne');
fileOne.task();
Output when ran in VSCode:
Hello
Output when ran in Command Line:
Hello
Hello
I'm not sure why this is happening... No I am not calling it in fileOne by accident because then it would also run twice in VSCode.
Thanks.
If your fileOne and fileTwo look exactly as in your problem statement, i.e.:
fileOne.js:
async function task() {
console.log('Hello')
}
module.exports = { task }
fileTwo.js:
const fileOne = require('./fileOne');
fileOne.task();
the output is 1 single 'Hello' when run in the following ways:
in Command Prompt
node fileTwo.js
in Windows PowerShell
node .\fileTwo.js
in Linux Bash Terminal
$ nodejs fileTwo.js
The same applies if you run the script having both files within 1 file (as you mention in the comments).
There were some cases where Node.js would print the output twice, but those were different scenarios.
You can try running just the fileTwo.js separately, but as already mentioned, it worked well also under a common file (e.g. your my_program_here.js in case it is just a combination of fileOne.js and fileTwo.js).
const fileOne = require('./fileOne');
This is based on the './' in different command lines.
I'd like to use the execSync method which was added in NodeJS 0.12 but still have the output in the console window from which i ran the Node script.
E.g. if I run a NodeJS script which has the following line I'd like to see the full output of the rsync command "live" inside the console:
require('child_process').execSync('rsync -avAXz --info=progress2 "/src" "/dest"');
I understand that execSync returns the ouput of the command and that I could print that to the console after execution but this way I don't have "live" output...
You can pass the parent´s stdio to the child process if that´s what you want:
require('child_process').execSync(
'rsync -avAXz --info=progress2 "/src" "/dest"',
{stdio: 'inherit'}
);
You can simply use .toString().
var result = require('child_process').execSync('rsync -avAXz --info=progress2 "/src" "/dest"').toString();
console.log(result);
Edit: Looking back on this, I've realised that it doesn't actually answer the specific question because it doesn't show the output to you 'live' — only once the command has finished running.
However, I'm leaving this answer here because I know quite a few people come across this question just looking for how to print the result of the command after execution.
Unless you redirect stdout and stderr as the accepted answer suggests, this is not possible with execSync or spawnSync. Without redirecting stdout and stderr those commands only return stdout and stderr when the command is completed.
To do this without redirecting stdout and stderr, you are going to need to use spawn to do this but it's pretty straight forward:
var spawn = require('child_process').spawn;
//kick off process of listing files
var child = spawn('ls', ['-l', '/']);
//spit stdout to screen
child.stdout.on('data', function (data) { process.stdout.write(data.toString()); });
//spit stderr to screen
child.stderr.on('data', function (data) { process.stdout.write(data.toString()); });
child.on('close', function (code) {
console.log("Finished with code " + code);
});
I used an ls command that recursively lists files so that you can test it quickly. Spawn takes as first argument the executable name you are trying to run and as it's second argument it takes an array of strings representing each parameter you want to pass to that executable.
However, if you are set on using execSync and can't redirect stdout or stderr for some reason, you can open up another terminal like xterm and pass it a command like so:
var execSync = require('child_process').execSync;
execSync("xterm -title RecursiveFileListing -e ls -latkR /");
This will allow you to see what your command is doing in the new terminal but still have the synchronous call.
Simply:
try {
const cmd = 'git rev-parse --is-inside-work-tree';
execSync(cmd).toString();
} catch (error) {
console.log(`Status Code: ${error.status} with '${error.message}'`;
}
Ref: https://stackoverflow.com/a/43077917/104085
// nodejs
var execSync = require('child_process').execSync;
// typescript
const { execSync } = require("child_process");
try {
const cmd = 'git rev-parse --is-inside-work-tree';
execSync(cmd).toString();
} catch (error) {
error.status; // 0 : successful exit, but here in exception it has to be greater than 0
error.message; // Holds the message you typically want.
error.stderr; // Holds the stderr output. Use `.toString()`.
error.stdout; // Holds the stdout output. Use `.toString()`.
}
When command runs successful:
Add {"encoding": "utf8"} in options.
execSync(`pwd`, {
encoding: "utf8"
})
How can I run a command line and get the outputs as soon as available to show them somewhere.
For example if a run ping command on a linux system, it will never stop, now is it possible to get the responses while the command is still processing ?
Or let's take apt-get install command, what if i want to show the progress of the installation as it is running ?
Actually i'm using this function to execute command line and get outputs, but the function will not return until the command line ends, so if i run a ping command it will never return!
var sys = require('sys'),
exec = require('child_process').exec;
function getOutput(command,callback){
exec(
command,
(
function(){
return function(err,data,stderr){
callback(data);
}
}
)(callback)
);
}
Try using spawn instead of exec, then you can tap into the stream and listen to the data and end events.
var process = require('child_process');
var cmd = process.spawn(command);
cmd.stdout.on('data', function(output){
console.log(output.toString()):
});
cmd.on('close', function(){
console.log('Finished');
});
//Error handling
cmd.stderr.on('data', function(err){
console.log(err);
});
See the Node.js documentation for spawn here: https://nodejs.org/api/child_process.html#child_process_child_process_spawn_command_args_options
Spawn in nodeJS. I have just about managed to use this to run a bash command as follows. This seems to be pretty much non-blocing and I get action on the browser screen as the command trashes through data.
ls = spawn('find',['/'] );
response.writeHead(200, { "Content-Type": "text/plain" });
ls.stdout.on('data', function (data) {
console.log('stdout: ' + data);
response.write(data);
});
But I want to run a perl script with multiple arguments.
ls = spawn('blah.pl',['--argstring here', '--arg blah'] );
Perl script is just written to get arguments using getopts CPAN lib and it using CPAN expect lib to run though a pile of stuff - outputs to stdout and stderr if I have an error but I mostly care about stdout right now.
The thing is this is giving me no output. Seems to be completely blocking at least until the program finishes execution ... and it this case it doesn't at least for 10 mins.
Am I using spawn wrong?
I like the node module "carrier"
carrier = require "carrier"
childproc = require "child_process"
find = childproc.spawn "find"
find.stdout.setEncoding "utf8"
linereader = carrier.carry find.stdout
linereader.on "line", (line) -> console.log line