I have a column in my Excel file which contains different values. All these values begin with a letter and continues with a number.
I would like to know how to remove that letter and obtain only the number. Keep in mind that each value can have a different length.
Thanks
You can use something like this
=MID(A1,2,LEN(A1)-1)
you could do it with
=SUBSTITUTE(A1,LEFT(A1),"")
or
=RIGHT(A1,LEN(A1)-1)
There are countless ways to do that...
use simple function in excel itself
=left(cellname,no. of charcters)
=left(A1,8) will give only first left characters and same can be used right/mid
Related
I have a bunch of URLs in a column like below:
https://www.example.com/xx/yy/product-name-could-be-30238543/
https://www.example.com/xx/yy/product-name-might-70293274/
https://www.example.com/xx/yy/product-name-may-40242653/
I wish to extract the ID's from the id but not with the last / in them. The right function gives me below:
40242653/ but i wish to get rid of the ID's too within the same function so can someone suggest a way?
Otherwise, i have to use another replace function separately to get rid of ending trailing slashes.
Thanks,
If all the IDs have 8 numerals, then you can use:
=LEFT(RIGHT(A1,9),8)
If they have more or less than 8 numerals, then ignore this answer.
I have found this to be easier to use (It extracts everything after the last occurrence of - in them.
SUBSTITUTE(RIGHT(A1;LEN(A1)-FIND("#";SUBSTITUTE(A1;"-";"#";(LEN(A1)-LEN(SUBSTITUTE(A1;"-";"")))/LEN("\"))));"/";"";1)
Ok so I had a nice formula until a problem came along. Basically I needed to get rid off a zeros in the middle of a 10 characters String/Range i.e AB00005879 to do that I have used formula SUBSTITUTE(NameRange,"0","") which gave me nice AB5879 solution. Sometimes the number at the end would only be 3 digit long AB00000975 so my formula would give me AB975 All great until I stumble a problem. Some of the strings came in a form of i.e. AB00004020 So my formula extracted every zero leaving me with AB42. Is there a way to extract only first four zeros in a middle an always keep the number at the and? so the last scenario would look like AB4020. Thanks in advance
SUBSTITUTE(NameRange,"0",""))
If you always have two characters at the start and then some zeros and then some numbers, all of which you want to keep, this should work
=LEFT(A1,2) & VALUE(RIGHT(A1,LEN(A1)-2))
EDIT #2
If your string always starts with two letters such as AB following by a random number of zeros and then a number string that you want to keep, try
=LEFT(A1,2)&RIGHT(A1,11-AGGREGATE(15,6,ROW($3:$10)/(--MID(A1,ROW($3:$10),1)>0),1))
Replace A1 with your actual case.
Does any of you know if exist any function to split the double brake line to column? I do know how to split by spaces like: =SUBSTITUTE(SUBSTITUTE(B2;CHAR(13);"");CHAR(10);"|"), but I want something like the image bellow:
The solution is depend on your string. If you have only one separation as shown, you can use following equations.
for the 1st part
=LEFT(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)-1)
for the 2nd part
=MID(SUBSTITUTE(A1,CHAR(10),",",1),FIND(",",SUBSTITUTE(A1,CHAR(10),",",1),1)+1,10000)
This is independent from the number of consecutive char(10) characters between text.
Just use two different formulas, there are many ways you could go about it. Say something like =LEFT(A1,FIND(CHAR(10),A1)) for the first column and =RIGHT(A1,LEN(A1)-SEARCH(CHAR(10),A1)) for the second one.
I have a column (F) full of 11 digit numbers, what I need is to split them like the following: 12,345,6789,00
I have the following formula which adds a comma after the first two digits however I don't know how to get it to add them in after the next 3 then 4.
=LEFT(F2,2)&","&MID(F2,3,LEN(F2))
The above formula outputs like this: 12,345678900
Any suggestions?
Have you considered using the TEXT function? This is simple and would do the trick:
=TEXT(F2,"00"",""000"",""0000"",""00")
Use MID all the way:
=MID(F2,1,2)&","&MID(F2,3,3)&","&MID(F2,6,4)&","&MID(F2,10,2)
=left(F2,2)&","&mid(F2,3,3)&","&mid(F2,6,4)&","&right(F2,2)
Will give you what you want.
=LEFT(F2,2) &","&MID(F2,3,3)&","&MID(F2,6,4)&","&RIGHT(F2,2)
Try using the Text to Columns function in the Data Tab of Excel. It will allow you to split the numbers based on number of digits. For this to work though, it needs to be the case that the number ALWAYS has 11 digits... otherwise some numbers will get cut in the wrong spot.
You can then Concotenate them back together with Commas inbetween.
I have 1000's of strings similar to "CN=Joe Smith,OU=Students,DC=Domain,DC=Edu" and I want to find the first instance of OU= and remove the characters before it leaving me with "OU=Students,DC=Domain,DC=Edu". How can I do this with an Excel formula?
Many thanks
Jamie
Use this:
=RIGHT(A1,LEN(A1)-FIND("OU=",A1)+1)
I combined jevakallio's answer with How do I recognize “#VALUE!” in Excel spreadsheets? for cases when the key "OU=" doesn't exist in the cell.
Situations:
CN=Joe Smith,OU=Students,DC=Domain,DC=Edu
CN=Jane Doe,DC=Domain,DC=Edu
Right Value checking for missing key:
=IF(ISERROR(RIGHT(A2,LEN(A2)-FIND("OU=",A2)+1)),"OU= Not Found",RIGHT(A2,LEN(A2)-FIND("OU=",A2)+1))
Results:
OU=Students,DC=Domain,DC=Edu
OU= Not Found