I need to compare the sets of numbers on the left (six numbers row) to the ones on the right (six numbers per row). I need to find combinations that are the same; for example, notice that row 1 on the left is the same as row 3 on the right. The program must identify this and highlight on the left set on numbers.
LEFT HAND SIDE
2 15 26 27 36 48
1 12 13 15 24 34
3 5 20 28 37 40
RIGHT HAND SIDE
3 15 19 29 39 35
1 2 27 48 24 37
15 2 26 47 27 48
Here's one way of doing it: combine the numbers (assumed to be a maximum of 2 digits - they look like lottery numbers) in the correct order into a single large number in another column and match on this column. In column G and copied to column N:-
=SUMPRODUCT(SMALL(A2:F2,COLUMN(A2:F2)-COLUMN(A2)+1)*100^(COLUMN(A2:F2)-COLUMN(A2)))
Then in Conditional Formatting| New Rule | Use a formula :-
=MATCH($G2,$N$2:$N$4,0)
If you wish you can also do a reverse lookup on each right-hand set of numbers as shown below.
Related
I have SET 1
CLASS
Student
TEST
SCORE
A
1
1
46
A
1
2
50
A
1
3
45
A
2
1
45
A
2
2
47
A
2
3
31
A
3
1
34
A
3
2
45
B
1
1
36
B
2
1
31
B
2
2
41
B
3
1
50
C
1
1
42
C
3
1
31
and SET 2
CLASS
SIZE
YEARS
A
39
7
B
20
12
C
31
6
and wish to COMBINE to make SET 3
CLASS
STUDENT
TEST
SCORE
SIZE
YEARS
A
1
1
46
39
7
A
1
2
50
39
7
A
1
3
45
39
7
A
2
1
45
39
7
A
2
2
47
39
7
A
2
3
31
39
7
A
3
1
34
39
7
A
3
2
45
39
7
B
1
1
36
20
12
B
2
1
31
20
12
B
2
2
41
20
12
B
3
1
50
20
12
C
1
1
42
31
6
C
3
1
31
31
6
so basically add the SIZE and YEARS columns from SET 2 and merge on CLASS onto SET 1. In excel how you can do this? I need to match on CLASS
Define both sets as tables and “left join” in PowerQuery. There you can choose the columns of the resulting table.
https://learn.microsoft.com/en-us/power-query/merge-queries-left-outer
If you have Set 1 on the top left of a worksheet "Set1" and Set 2 on the top left of a worksheet "Set2", then you can use the formula
=VLOOKUP(A2;'Set2'!$A$2:$C$4;2;FALSE), where $A$2:$C$4 is the range of Set2, and A2 is the class value from Set1, which is what is used to do the lookup in Set2. The next argument, 2, means to take the second row from Set2, and the FALSE at the end means that you only want exact matches on the CLASS. You can do auto-fill with this formula, and do similar steps for the years. If you look up the help for VLOOKUP within Excel, that should help you to understand how it works.
Your first set of data is essentially your primary set of data that you just want to add attribute columns to. I built this example on Google Sheets which should help explain. Using spill formulas, only a few cells are needed with their own formulas. You can see them as they are highlighted in yellow. When you use in Excel, obviously make sure you change the column references, but this would get you the answer.
Note you have to have SpillRange in Excel for this to work. To test, see if you have the formula =unique()
This solution may work for you if both sets start in the same column. As example in my image, both of them start at column A. You can get all data with a single VLOOKUP formula:
Formula in cell E2 is:
=VLOOKUP($A2;$A$22:$R$25;COLUMN($B22);FALSE)
Notice the mixed references at first and third argument and absolute references in the second one. Third argument is critical, because is the relational position between both sets, that's the reason it's easier if both sets start at same column. If not, you'll need to adjust this argument substracting or adding, depending on the case.
Anyways, with a single formula, you can get any number of columns. The only disavantage of this formula is that you need to manually drag to right until you got all the columns (10, 30 or whatever). You'll notice you are done because the formula will raise an error:
This error means you are trying to get a referenced outside of your column area.
I have a table of values with each value in a different cell
e.g.
2 9 12 19 41 45 14 39
12 14 19 27 39 40 30 44
6 9 13 15 16 41 7 20
8 16 14 34 13 44 5 15
10 11 20 24 27 36 9 41
Is there a way to find which pairs of numbers are most common.
i.e.
13 & 15 appear 2 times
14 & 44 appear 2 times
24 & 27 appear 1 time
I was hoping for a formula as the table has over a hundred rows in it so would be time consuming to count manually.
The formula you would want would be the one for the row totals of a pair of numbers in A2 and B2:
=SUM(MMULT(--($E$2:$L$6=A2),TRANSPOSE(COLUMN(E:L))^0)*MMULT(--($E$2:$L$6=B2),TRANSPOSE(COLUMN(E:L))^0))
entered as an array formula using CtrlShiftEnter
There will be formulas for for listing distinct pairs up to a certain number out there - I used
=IF(ROW()=2,1,IF(B1<45,A1,A1+1))
for A2 and
=IF(B1<45,B1+1,2+COUNTIF(B$1:B1,45))
for B2.
If you scroll down this list you can see that 13,16 occurs twice as well as 13,15.
9,41 occurs three times.
Note - I am assuming the numbers are like lottery numbers and any one number can only occur once in a row. The formula could easily be modified to account for duplicates within a row.
I have a set of data that has two columns, one for enumerating entries, and the second for storing a value:
1 0.000000000
2
3
4
5
6
7
8
9 0.664076596
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34 0.668394223
The values in column 2 are separated by varying numbers of rows throughout my data sheet. I want to subtract each value (Value B) in column 2 by the previous value above it (Value A) (ie 0.664076596 - 0.000000000, and 0.668394223 - 0.664076596 etc.). I want to put these results in the third column and next to Value B. How would I do this in Excel?
Use this which will find the last number value in the column before the current row.
=IF(B2="","",IFERROR(B2-INDEX($B$1:B1,MATCH(1E+99,$B$1:B1)),B2))
I need to generate 13 numbers from 13 different intervals which will add up to 1360. In the chart below, "index" means the index of the 13 different numbers. Mean means the mean (average) of the intervals. The range will be plus or minus 15% of the mean as shown below. I will prefer to have the random numbers generated based on the normal distribution with N(mean, 7.5% of mean). I take it back. No normal distribution. Please use +- 15% as hard limits of the intervals.
It will be great if anyone could figure out how to do it in excel. Algorithms will be appreciated as well.
Index mean 15% low high
A 288 43 245 331
B 50 8 43 58
C 338 51 287 389
D 50 8 43 58
E 16 2 14 18
F 66 10 56 76
G 118 18 100 136
H 17 3 14 20
I 91 14 77 105
J 26 4 22 30
K 117 18 99 135
L 165 25 140 190
M 18 3 15 21
I would sort the table by increasing mean:
and use a column for a helper value (column H above).
The idea is to maintain -- while going to the next row -- the current deviation from a perfect aim for the final target. Perfect would mean that every random value coincides with the mean for that row. If a value is 2 less than the mean, then that 2 will appear in the H column for the next row. The random number generated for that next row will then not aim for the given mean, but for 2 less than the mean. The range for the random number will appropriately be reduced so that the low/high values will never be crossed.
By first sorting the rows, we can be sure that this corrected mean will always fall within the next row's low/high range, and so it will always be possible to generate an acceptable random number there.
The final value will be calculated differently: it will be the remainder that is needed to achieve the target sum. For the same reason as above, this value is guaranteed to be within the low/high range.
The formulas used are as follows:
| F | H
--+--------------------------------------------------+------------------------------
2 | =RANDBETWEEN(D2, E2) |
3 | =RANDBETWEEN(B3+H3-C3+ABS(H3), B3+H3+C3-ABS(H3)) | =SUM($B$2:$B2)-SUM($F$2:$F2)
4 | (copy above formula) | (copy above formula)
...| ... | ...
13 | (copy above formula) | (copy above formula)
14 | =SUM($B$2:$B14)-SUM($F$2:$F13) |
In theory the rows do not need to be sorted first, but then the formulas cannot be copied down like above, but must reference the correct rows. That would make it quite complicated.
If it is absolutely necessary that the rows are presented in order of the Index column (A, B, C...), then use another sheet to do the above. Then in the main sheet read the value into the F column with a VLOOKUP from the other sheet. So in F2 you would have:
=VLOOKUP(A2, OtherSheet!$A$2:$F$14, 6, 0)
Get the random number like this
num = Int ((300 - 200 + 1) * Rnd + 200) //between 200 and 300
Click here for more information
and the random number need to be the total sum minus the sum that you already got and the last one will be that left.
for example: (if we have 4 numbers sum up to 100)
A is a random number between 0 to 100 //lets say 42
then B is a random number between 0 to (100-42) => 0 to 78 //lets say 18
then C is a random number between 0 to (100-42-18) => 0 to 40 //lets say 25
then, in the end D is 100-42-18-25 => D is 15
*100-42-18-25 is the same as 100-Sum(A,B,C)
Here is my example generate random number based on low and high.
The formula in column F is just a RANDBETWEEN:
=RANDBETWEEN($D2,$E2)
Then you can get the result always equal to 1360 with the formula below for column G:
=F2/SUM($F$2:$F$14)*1360
So cell G15 will always be 1360 which is the sum of all those 13 intervals.
I have the following Excel spreadsheet:
A B C D E
1 ProdID Price Unique ProdID 1. Biggest 2. Biggest
2 2606639 40 2606639 50 50
3 2606639 50 4633523 45 35
4 2606639 20 3911436 25 25
5 2606639 50
6 4633523 45
7 4633523 20
8 4633523 35
9 3911436 20
10 3911436 25
11 3911436 25
12 3911436 15
In Cells D2:E4 I want to show the 1. biggest and 2. biggest price of each ProdID in Column A. Therefore, I use the following formula:
D2 =AGGREGAT(14,6,$B$2:$B$12/($A$2:$A$12=$C2),1)
E2 =AGGREGAT(14,6,$B$2:$B$12/($A$2:$A$12=$C2),2)
This formula works as long as the prices are unique in Column B as you can see on the second ProdID (4633523).
However, once the price is not unique in Column B (for example 50 for ProdID 26026639 and 25 for ProdID 3911436) the functions in Cells D2:E4 does not show the right results.
Do you have an idea if you can solve this issue with the AGGREGAT-Formula and wihtout using an ARRAY-Formula?
you could check number of occurences of the first ProdID-price combinations and use that in the last argument of the AGGREGAT function. So instead of
=AGGREGAT(14,6,$B$2:$B$12/($A$2:$A$12=$C2),2)
you would have
=AGGREGAT(14,6,$B$2:$B$12/($A$2:$A$12=$C2),2+COUNTIFS(A:A,C2,B:B,D2)-1)
of course you can just put "1+COUNTIFS..." but I put it this way so it can be better understood that it uses position 2 + number of occurences of the combination of ProdID with biggest number after the first occurence.