(I'm new in shell script.)
I've been stuck with this issue for a while. I've tried different methods but without luck.
Description:
When my script attempt to run another script (SiebelMessageCreator.sh, which I don't own) it prompts:
-bash: ./SiebelMessageCreator.sh: No such file or directory
But the file exists and has execute permissions:
-rwxr-xr-x 1 owner ownergrp 322 Jun 11 2015 SiebelMessageCreator.sh
The code that is performing the script execution is:
(cd $ScriptPath; su -c './SiebelMessageCreator.sh' - owner; su -c 'nohup sh SiebelMessageSender.sh &' - owner;)
It's within a subshell because I first thought that it was throwing that message because my script was running in my home directory (When I run the script I'm root and I've moved to my non-root home directory to run the script because I can't move my script [ policies ] to the directory where the other script resides).
I've also tried with the sh SCRIPT.sh ./SCRIPT.sh. And changing the shebang from bash to ksh because the SiebelMessageCreator.sh has that shell.
The su -c 'sh SCRIPT.sh' - owner is necessary. If the script runs as root and not as owner it brokes something (?) (that's what my partners told me from their experience executing it as root). So I execute it as the owner.
Another thing that I've found in my research is that It can throw that message if it's a Symbolic link. I'm really not sure if the content of the script it's a symbolic link. Here it is:
#!/bin/ksh
BASEDIRROOT=/path/to/file/cpp-plwsutil-c
ore-runtime.jar (path changed on purpose for this question)
java -classpath $BASEDIRROOT com.hp.cpp.plwsutil.SiebelMessageCreator
exitCode=$?
echo "`date -u '+%Y-%m-%d %H:%M:%S %Z'` - Script execution finished with exit code $exitCode."
exit $exitCode
As you can see it's a very siple script that just call a .jar. But also I can't add it to my script [ policies ].
If I run the ./SiebelMessageCreator.sh manually it works just fine. But not with my script. I suppose that discards the x64 x32 bits issue that I've also found when I googled?
By the way, I'm automating some tasks, the ./SiebelMessageCreator.sh and nohup sh SiebelMessageSender.sh & are just the last steps.
Any ideas :( ?
did you try ?
. ./SiebelMessageCreator.sh
you can also perform which sh or which ksh, then modify the first line #!/bin/ksh
Related
The below script executing with root user.After switch user Unix function showing error.
test.sh
#!/bin/bash
fn_test()
{
echo "This is function"
}
whoami
fn_test
su - oracle<<EOF
whoami
fn_test #This function not called
EOF
exit 0
O/P
root $ ./test.sh
root
This is function
oracle
-ksh[2]: fn_test: not found [No such file or directory]
You have a confusion on what su actually does: you hope it to just swith user when it does start a new process. You can control it with ps in an interactive session: you see the original shell, the su command, the new shell launched by su and the current ps command.
As a shell function is local to the shell it cannot be used in a (grand) child shell.
The best that you can hope is to pass something through the environment. I know that aliases can be put there unsure for functions. Moreover, this is absolutely shell dependant and might not be portable.
I have an etc/init.d script that tries to call a shell script in a /home/myuser directory. One shell script for startup, another shell script for shutdown.
The start script gets called just fine ( from rc3.d/S99cslink , rc5.d/S99cslink ) but when I try to call the stop script ( from rc0.d/K01cslink ) I get the message that /home/myuser/bin/stop_service.sh cannot be found.
/etc/rc.d/init.d/cslink: line 42: /home/myuser/bin/stop_service.sh: No such file or directory
I verified that at the point in time when I am trying to run /home/myuser/bin/stop_service.sh , /home/myuser is unavailable (an ls -l /home/myuser >/tmp/mylog.log 2>&1 from inside the init.d script shows the error
ls: cannot access /home/myuser: No such file or directory
Both the start) script and the stop) script in init.d are run with runuser -l myuser, so I don't think it's a permissions problem.
Why would /home/myuser be unavailab.e, and can I run my script at a different point in time when /home/myuser is still available?
All the answers I see through searching are saying that I should check for Windows-style carriage returns in my stop_service.sh script, but I have checked and that's not the issue here.
Why the output file from this is owned by root and not w3svcsadm?
sudo -u w3svcsadm echo "TEST ran" > /home/your/emaildigest/TEST_$( date +%Y%m%d%H%M%S ).output
I'm running into some issues with cron, and I believe this is the key to my problems.
Using the -u flag with sudo executes the command 'echo "TEST ran"' as the user w3svcasadm, but that command isn't the thing doing the work of outputting to a file, which is done by the '>' operator. By the time bash is using that operator, it's already switched back to the user running the shell. If that user is root, then the file will be created under root. In your script, you could use "su w3svcsadm" to switch the shell user before executing that command, then you wouldn't have to use that -u flag at all.
I have a script that needs to check if a lockfile exists that only root can access and then the script runs the actual test script that needs to be run as a different user.
The problem is the test script is supposed to generate xml files and those files do not exist. (aka I can't find them)
Relevant part of the script
if (mkdir ${lockdir} ) 2> /dev/null; then
echo $$ > $pidfile
trap 'rm -rf "$lockdir"; exit $?' INT TERM EXIT
if [ -f "$puppetlock" ]
then
su -c "/opt/qa-scripts/start-qa-test.sh > /var/log/qaTests/test-$(date +\"m-%d-%T\".log" -m "qaUser"
lockdir is what gets created when the test is run to signify that the test process has begun.
puppetlock checks if puppet is running by looking for the lock file puppet creates.
qaUser does not have the rights to check if puppetlock exists.
start-qa-test.sh ends up calling java to execute an automated test. My test-date.log file displays what console would see if the test was run.
However the test is supposed to produce some xml files in a directory called target. Those files are missing.
In case it's relevant start-qa-test.sh is trying to run something like this
nohup=true
/usr/bin/java -cp .:/folderStuff/$jarFile:/opt/folderResources org.junit.runnt.JUNITCore org.some.other.stuff.Here
Running start-qa-test.sh produces the xml output in the target folder. But running it through su -c it does not.
Edit
I figured out the answer to this issue.
I changed the line to
su - qaUser -c "/opt/qa-scripts/start-qa-test.sh > /var/log/qaTests/test-$(date +\"m-%d-%T\".log"
That allowed the output to show up at the /home/qaUser
Try redirecting the output of stout and stderr in the line:
su -c "/opt/qa-scripts/start-qa-test.sh > /var/log/qaTests/test-$(date +\"m-%d-%T\".log" -m "qaUser" 2>&1
I am new to linux and the script below is just an example of my issue:
I have a script which works as expected when I execute it however when I set it to run via crontab it doesn't work as expected because it doesn't read the file content into the variable.
I have a file 'test.txt' which has 'abc' in it. My script puts the text into a variable 'var' and then I echo it out to a log file:
var=$(</home/pi/MyScripts/test.txt)
echo "$var" >/home/pi/MyScripts/log.log
This works perfectly fine when I execute it and it echo's into the log file but not when I set it via crontab:
* * * * * /home/pi/MyScripts/test.sh
The cron job runs, and it sent me the following error message:
/bin/sh: 1: /home/pi/MyScripts/test.sh: Permission denied.
But I have given it 777 permissions:
-rwxrwxrwx 1 pi pi 25 Jun 10 15:31 test.txt
-rwxrwxrwx 1 pi pi 77 Jun 10 15:34 test.sh
Any ideas?
This happens when you run the script with a different shell. It's especially relevant for systems where /bin/sh is dash:
$ cat myscript
echo "$(< file)"
$ bash myscript
hello world
$ sh myscript
$
To fix it, add #!/bin/bash as the first line in your script.
Others have provided answers, but I will give you a big clue from your error message; emphasis mine:
/bin/sh: 1: /home/pi/MyScripts/test.sh: Permission denied.
Note how the cron job was trying to use /bin/sh to run the script. That’s solved by always indicating which shell you want to use at the top of your script like this.
#!/bin/bash
var=$(</home/pi/MyScripts/test.txt)
echo "$var" >/home/pi/MyScripts/log.log
If your script is using bash, then you must explicitly set /bin/bash in some way.
Also, regarding permissions you say this:
But I have given it 777 permissions:
First, 777 permissions is a massive security risk. If you do that it means that anyone or anything on the system can read, write & execute the file. Don’t do that. In the case of a cron job the only entity that needs 7 permissions on a file is the owner of the crontab running that file.
Meaning if this is your crontab, just change the permissions to 755 which allows others to read & execute but not write. Or maybe better yet change it to 700 so only you—as the owner of the file—can do anything to the file. But avoid 777 permissions if you want to keep your system safe, stable & sane.
You have two options. In the first line of your file, tell what program you want to interpret the script
#!/bin/bash
...more code...
Or in your crontab, tell what program you want to interpret the script
* * * * * bash /home/pi/MyScripts/test.sh
In this option, you do not need to make the script executable