I plan to use sklearn.decomposition.TruncatedSVD to perform LSA for a Kaggle
competition, I know the math behind SVD and LSA but I'm confused by
scikit-learn's user guide, hence I'm not sure how to actually apply
TruncatedSVD.
In the doc, it states that:
After this operation,
U_k * transpose(S_k) is the transformed training set with k features (called n_components in the API)
Why is this? I thought after SVD, X, at this time X_k should be U_k * S_k * transpose(V_k)?
And then it says,
To also transform a test set X, we multiply it with V_k: X' = X * V_k
What does this mean?
I like the documentation Here a bit better. Sklearn is pretty consistent in that you almost always use some kind of combination of the following code:
#import desired sklearn class
from sklearn.decomposition import TruncatedSVD
trainData= #someArray
testData = #someArray
model = TruncatedSVD(n_components=5, random_state=42)
model.fit(trainData) #you fit your model on the underlying data
if you want to transform that data instead of just fitting it,
model.fit_transform(trainData) #fit and transform underlying data
Similarly, if you weren't transforming data, but making a prediction instead, you would use something like:
predictions = model.transform(testData)
Hope that helps...
Related
My input is time series data. I want to decompose the dataset with PCA (I dont want to do PCA on the entire dataset first because that would be overfitting) and then use feature selection on each component (fitted on a KNN Regressor model).
This is my code so far:
tscv = TimeSeriesSplit(n_splits=10)
pca = PCA(n_components=.5,svd_solver='full').fit_transform()
knn = KNeighborsRegressor(n_jobs=-1)
sfs = SequentialFeatureSelector(estimator=knn,n_features_to_select='auto',tol=.001,scoring=custom_scorer,n_jobs=-1)
pipe = Pipeline(steps=[("pca", pca), ("sfs", sfs), ("knn", knn)])
cv_score = cross_val_score(estimator=pipe,X=X,y=y,scoring=custom_scorer,cv=tscv,verbose=10)
print(np.average(cv_score),' +/- ',np.std(cv_score))
print(X.columns)
The problem is I want to make sure PCA isnt looking over the entire dataset when it calculates which features variance. I also want it to be fit transformed, but it doesnt work. With the following error codes:
TypeError: All intermediate steps should be transformers and implement fit and transform or be the string 'passthrough' '<bound method PCA.fit_transform of PCA(svd_solver='full')>' (type <class 'method'>) doesn't
or
TypeError: fit_transform() missing 1 required positional argument: 'X'
You should not use pca = PCA(...).fit_transform nor pca = PCA(...).fit_transform() when defining your pipeline.
Instead, you should use pca = PCA(...). The fit_transform method is automatically called within the pipeline during the model fitting (in cross_val_score).
I am dealing with a binary classification problem.
I have 2 lists of indexes listTrain and listTest, which are partitions of the training set (the actual test set will be used only later). I would like to use the samples associated with listTrain to estimate the parameters and the samples associated with listTest to evaluate the error in a cross validation process (hold out set approach).
However, I am not be able to find the correct way to pass this to the sklearn GridSearchCV.
The documentation says that I should create "An iterable yielding (train, test) splits as arrays of indices". However, I do not know how to create this.
grid_search = GridSearchCV(estimator = model, param_grid = param_grid,cv = custom_cv, n_jobs = -1, verbose = 0,scoring=errorType)
So, my question is how to create custom_cv based on these indexes to be used in this method?
X and y are respectivelly the features matrix and y is the vector of labels.
Example: Supose that I only have one hyperparameter alpha that belongs to the set{1,2,3}. I would like to set alpha=1, estimate the parameters of the model (for instance the coefficients os a regression) using the samples associated with listTrain and evaluate the error using the samples associated with listTest. Then I repeat the process for alpha=2 and finally for alpha=3. Then I choose the alpha that minimizes the error.
EDIT: Actual answer to question. Try passing cv command a generator of the indices:
def index_gen(listTrain, listTest):
yield listTrain, listTest
grid_search = GridSearchCV(estimator = model, param_grid =
param_grid,cv = index_gen(listTrain, listTest), n_jobs = -1,
verbose = 0,scoring=errorType)
EDIT: Before Edits:
As mentioned in the comment by desertnaut, what you are trying to do is bad ML practice, and you will end up with a biased estimate of the generalisation performance of the final model. Using the test set in the manner you're proposing will effectively leak test set information into the training stage, and give you an overestimate of the model's capability to classify unseen data. What I suggest in your case:
grid_search = GridSearchCV(estimator = model, param_grid = param_grid,cv = 5,
n_jobs = -1, verbose = 0,scoring=errorType)
grid_search.fit(x[listTrain], y[listTrain]
Now, your training set will be split into 5 (you can choose the number here) folds, trained using 4 of those folds on a specific set of hyperparameters, and tested the fold that was left out. This is repeated 5 times, till all of your training examples have been part of a left out set. This whole procedure is done for each hyperparameter setting you are testing (5x3 in this case)
grid_search.best_params_ will give you a dictionary of the parameters that performed the best over all 5 folds. These are the parameters that you use to train your final classifier, using again only the training set:
clf = LogisticRegression(**grid_search.best_params_).fit(x[listTrain],
y[listTrain])
Now, finally your classifier is tested on the test set and an unbiased estimate of the generalisation performance is given:
predictions = clf.predict(x[listTest])
I have a Naive Bayes classifier that I wrote in Python using a Pandas data frame and now I need it in PySpark. My problem here is that I need the feature importance of each column. When looking through the PySpark ML documentation I couldn't find any info on it. documentation
Does anyone know if I can get the feature importance with the Naive Bayes Spark MLlib?
The code using Python is the following. The feature importance is retrieved with .coef_
df = df.fillna(0).toPandas()
X_df = df.drop(['NOT_OPEN', 'unique_id'], axis = 1)
X = X_df.values
Y = df['NOT_OPEN'].values.reshape(-1,1)
mnb = BernoulliNB(fit_prior=True)
y_pred = mnb.fit(X, Y).predict(X)
estimator = mnb.fit(X, Y)
# coef_: For a binary classification problems this is the log of the estimated probability of a feature given the positive class. It means that higher values mean more important features for the positive class.
feature_names = X_df.columns
coefs_with_fns = sorted(zip(estimator.coef_[0], feature_names))
If you're interested in an equivalent of coef_, the property, you're looking for, is NaiveBayesModel.theta
log of class conditional probabilities.
New in version 2.0.0.
i.e.
model = ... # type: NaiveBayesModel
model.theta.toArray() # type: numpy.ndarray
The resulting array is of size (number-of-classes, number-of-features), and rows correspond to consecutive labels.
It is, probably, better to evaluate a difference
log(P(feature_X|positive)) - log(P(feature_X|negative))
as a feature importance.
Because, we are interested in the Discriminative power of each feature_X (sure-sure NB is a generative model).
Extreme example: some feature_X1 has the same value across all + and - samples, so no discriminative power.
So, the probability of this feature value is high for both + and - samples, but the difference of log probabilities = 0.
I am using sklearn's cross_val_predict for training like so:
myprobs_train = cross_val_predict(LogisticRegression(),X = x_old, y=y_old, method='predict_proba', cv=10)
I am happy with the returned probabilities, and would like now to score up a brand-new dataset. I tried:
myprobs_test = cross_val_predict(LogisticRegression(), X =x_new, y= None, method='predict_proba',cv=10)
but this did not work, it's complaining about y having zero shape. Does it mean there's no way to apply the trained and cross-validated model from cross_val_predict on new data? Or am I just using it wrong?
Thank you!
You are looking at a wrong method. Cross validation methods do not return a trained model; they return values that evaluate the performance of a model (logistic regression in your case). Your goal is to fit some data and then generate prediction for new data. The relevant methods are fit and predict of the LogisticRegression class. Here is the basic structure:
logreg = linear_model.LogisticRegression()
logreg.fit(x_old, y_old)
predictions = logreg.predict(x_new)
I have the same concern as #user3490622. If we can only use cross_val_predict on training and testing sets, why y (target) is None as the default value? (sklearn page)
To partially achieve the desired results of multiple predicted probability, one could use the fit then predict approach repeatedly to mimic the cross-validation.
If I run a basic logistic regression with 4 classes, I can get the predict_proba array.
How can i manually calculate the probabilities using the coefficients and intercepts? What are the exact steps to get the same answers that predict_proba generates?
There seem to be multiple questions about this online and several suggestions which are either incomplete or don't match up anyway.
For example, I can't replicate this process from my sklearn model so what is missing?
https://stats.idre.ucla.edu/stata/code/manually-generate-predicted-probabilities-from-a-multinomial-logistic-regression-in-stata/
Thanks,
Because I had the same question but could not find an answer that gave the same results I had a look at the sklearn GitHub repository to find the answer. Using the functions from their own package I was able to create the same results I got from predict_proba().
It appears that sklearn uses a special softmax() function that differs from the usual softmax function in their code.
Let's assume you build a model like this:
from sklearn.linear_model import LogisticRegression
X = ...
Y = ...
model = LogisticRegression(multi_class="multinomial", solver="saga")
model.fit(X, Y)
Then you can calculate the probabilities either with model.predict(X) or use the sklearn function mentioned above to calculate them manually like this.
from sklearn.utils.extmath import softmax,
import numpy as np
scores = np.dot(X, model.coef_.T) + model.intercept_
softmax(scores) # Sklearn implementation
In the documentation for their own softmax() function, they note that
The softmax function is calculated by
np.exp(X) / np.sum(np.exp(X), axis=1)
This will cause overflow when large values are exponentiated. Hence
the largest value in each row is subtracted from each data point to
prevent this.
Replicate sklearn calcs (saw this on a different post):
V = X_train.values.dot(model.coef_.transpose())
U = V + model.intercept_
A = np.exp(U)
P=A/(1+A)
P /= P.sum(axis=1).reshape((-1, 1))
seems slightly different than softmax calcs, or the UCLA stat example, but it works.