How can I add a delay to a mouse click in pygame? - python-3.x

Question

I'm attempting to make a store in my game, but am having issues with pygame.mouse.get_pressed(). When the user clicks on a button, the program thinks that they clicked on it more than once, therefore using more credits than the user intended. I would like to add a delay so that the game doesn't do this. I would like 1 click to represent them buying one object. I have tried reducing the framerate for that window, but the result is the same. Here is the code I currently have.
This is where all the mouse action occurs.
def button(x, y, w, h, ic, ac, action = None):
global paused
mouse = pygame.mouse.get_pos()
click = pygame.mouse.get_pressed()
if x + w > mouse[0] > x and y + h > mouse[1] > y:
pygame.draw.rect(gameDisplay, ac, (x, y, w, h))
if click[0] == 1 and action == Game:
Game()
if click[0] == 1 and action == quitgame:
sys.exit()
if click[0] == 1 and action == None:
paused = False
if click[0] == 1 and action == StartScreen:
save()
StartScreen()
if click[0] == 1 and action == LootScreen:
LootScreen()
if click[0] == 1 and action == open_common_drop:
open_common_drop()
if click[0] == 1 and action == open_rare_drop:
open_rare_drop()
else:
pygame.draw.rect(gameDisplay, ic, (x, y, w, h))
This is where the loot store is currently at.
def LootScreen():
global current_drops
loot = True
while loot:
for event in pygame.event.get():
if event.type == pygame.QUIT:
save()
pygame.quit()
sys.exit()
if event.type == pygame.KEYDOWN:
if event.key == pygame.K_t:
open_common_drop()
elif event.key == pygame.K_y:
open_rare_drop()
if event.key == pygame.K_ESCAPE:
StartScreen()
gameDisplay.fill(gray)
title('Loot Chests!')
button(400, 150, 260, 50, blue, bright_blue, open_common_drop)
button(695, 150, 260, 50, red, bright_red, open_rare_drop)
button(display_width * 0.42, display_height / 1.15, 255, 50, red, bright_red, StartScreen)
game_display_text('Open Common Chest (T)', 407, 165)
game_display_text('Open Rare Chest (Y)', 725, 165)
game_display_text('You Got: %s' % current_drops, 50, display_height / 2)
game_display_text('Credits: %.2f' % player_loot_data['credit_count'], 15, 15)
game_display_text('Main Menu', display_width * 0.47, display_height / 1.13)
game_display_text('Janus\': %s' % player_loot_data['loot_data_one'] , 950, 500)
game_display_text('Peace of Minds: %s' % player_loot_data['loot_data_two'], 950, 535)
pygame.display.update()
clock.tick(30)

Answer 1

You will need to use a bool switch in your button function. Here I re-worked the function in a way that should work.
def button(x, y, w, h, ic, ac, action = None, held):
global paused
mouse = pygame.mouse.get_pos()
click = pygame.mouse.get_pressed()
if x + w > mouse[0] > x and y + h > mouse[1] > y:
pygame.draw.rect(gameDisplay, ac, (x, y, w, h))
if click[0] == 1:
if held == False:
if action == Game:
Game()
elif action == quitgame:
sys.exit()
elif action == None:
paused = False
elif action == StartScreen:
save()
StartScreen()
elif action == LootScreen:
LootScreen()
elif action == open_common_drop:
open_common_drop()
elif action == open_rare_drop:
open_rare_drop()
held = True
else:
held = False
else:
pygame.draw.rect(gameDisplay, ic, (x, y, w, h))
return held
As you see, there is a new variable held added to the function to process whether the button is held or not. Held is taken and returned here, so it won't reset every time the function is called.
With that down, let me show you why I wrote it that way, and just how this logic works at its core.
import pygame
#
display = pygame.display.set_mode((800,600))
clock = pygame.time.Clock()
#
held = False # Variable to handle if mouse button is held
#
RUNNING = True
while RUNNING:
clock.tick(60)
for event in pygame.event.get():
if event.type == pygame.QUIT:
RUNNING = False
#
button = pygame.mouse.get_pressed() # Get mouse state
if button[0]: # Check if left mouse button is pressed
if held == False: # Check if button is held down
print(True) # If button is not held down, print true
held = True # Set held eqaual to true for next iteration
else: # If left mouse button is not pressed
held = False # held is set to false, alowing event to happen again
#
display.fill((0,0,0))
#
pygame.display.flip()
#
pygame.quit()
The above is a very simple stand alone program that also implements the held variable to monitor if the mouse button is held. In this program, the variable held is first declared as False as the mouse is not being pressed. Then, within the main loop, pygame.mouse.get_pressed() is called to get the mouse input, and is immediately followed by a check for the left mouse button. If the left mouse button is pressed, a check for held will happen. If it is false, the program will print True. held is then set to True for the next iteration. The else: statement will fire if the left mouse button is not held down and reset held to its default False state.

Answer 2

I would suggest a timed bool switch. Here's an example that should help out.
import time
boolswitch = False
timer = 0.0
clock = time.time()
x = time
while True:
if timer > 0.25:
boolswitch = True
timer = 0.0
else:
x = time.time()
timer += (x-clock)
clock = x
if boolswitch:
click = pygame.mouse.get_pressed()
if click[0] == 1:
boolswitch = False
clock = time.time()