I have an excel document I have to process regularly, while awaiting my company to build an automated process for this, and the issue we recently found is that the formula I'm using strips can't return a result other than #VALUE! when the FIND formula fails to find the text I need it to.
the formula we currently have is:
=IF(FIND("-",M2,3),RIGHT(M2,2))
The cells this formula checks have states, & provinces in them which look like so "CA-ON" or "US-NV".
The problem is that regions for the UK don't fillout as "UK-XX" it inputs the actual county for example "Essex" or "Merryside"
What I need the formula to do is, if it can't find the hyphen(-) in the cell, then it should just take whatever value is there and write it in the cell the formula is in.
I should also mention that some of the cells are also blank, since this is an optional field. Is there anyway to run this formula where if it doesn't find the "-" it just writes whats there?
What about using mid() to see if the third character is "-"
=IF(MID(A1,3,1)="-",RIGHT(A1,2),A1)
If you really want to use the find() function then:
=IF(ISNUMBER(FIND("-",A1)),RIGHT(A1,2),A1)
The IFERROR Function should help here. And there isn't a reason to use the if statement anymore. The formula below will find the hyphen if it is in the first 3 characters, and find the length of the string minus the location of the hyphen and return that string. The IFERROR will catch the instances where there is no hyphen and return your original cell.
=IFERROR(RIGHT(M2,LEN(M2)-FIND("-",LEFT(M2,3),1)),M2)
Related
My question is, I want to find a specific characters "V-", "C-", or "To", from the value in the cell B2,
The logic is: if either of these characters are found in the cell B2, the excel should take value from D2, and put into new column say E
Here is my if formula:
=IF(MID(B2,FIND("V-",B2),2)="V-",D2,
IF(MID(B2,FIND("C-",B2),2)="C-",D2,
IF(MID(B2,FIND("To",B2),2)="To",D2," ")))
This formula is working for only first occurrence "V-" in this case , the rest of the values it displays "#VALUE!". Can I get any help please.
And return a blank otherwise?
=IF(COUNT(FIND({"V-";"C-";"To"},B2)),D2,"")
Just to spell out what's happening, if it Find fails to find "V-", it immediately returns a #VALUE! error and the formula doesn't proceed any further.
You could fix it like this while preserving your logic
=IF(ISNUMBER(FIND("V-",B2)),D2,
IF(ISNUMBER(FIND("C-",B2)),D2,
IF(ISNUMBER(FIND("To",B2)),D2," ")))
but as you can see from the other answers there are much shorter ways of doing it.
Try this way:
`=IFERROR(FIND("V-",B2),IFERROR(FIND("C-",B2),IFERROR(FIND("To-",B2)," ")))`
returning a positive number when found or " " when no match.
(I could not test it because I use a localised version of Excel but the logic is fine)
Is the following possible and if so what formula would I use to pull this off?
Column A has rows of Summary data from problem tickets which will contain the problem ticket ID and other text.
The problem ID will always be 15 characters in length
The format of the Problem ID is USPM followed by the number for example USPM12345678911
Is there a formula that will look at for example cell A2 for *USPM* and return everything within the * * IN CELL b2? For example A2= (hehegdyyff USPM12345678911 ididuufffuf) the formula looks at A2 to see if it contains USPM and if it does it returns USPM and the next 11 characters to its right.
Yes. You use the FIND() and MID() commands. Something like this:
=MID(A2,FIND("USPM",A2),15)
Check out the help pages for both functions for additional details.
In case USPM is not present in your input, you may want to use a condition to avoid the error:
=IF(ISERROR(FIND("USPM",A2)),"",MID(A2,FIND("USPM",A2),15))
IMPORTANT NOTE: The FIND() command searches for a word in a case sensitive manner. If you may have lowercase characters in your "USPM" marker, you may want to use SEARCH() instead.
I am trying to convert text of the month to the number
B2 cell:
BirthMonth_Jan
BirthMonth_Feb
BirthMonth_mar
BirthMonth_Apr
BirthMonth_May
BirthMonth_Jun, ect to december
for example, BirthMonth_Jan will output 1 based on the search of Jan, so i can compare this to another set of numbers
I have this, and tried this, but only works with two if statements, is there anyway i can do this with 12?
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
I get #Value!
If i try this, it also doesn't work
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
the second option only works with two but if i add more it throws an error
The questioner is trying to obtain a numeral equivalent to a partial month name extracted from a string. There are any number of examples in stackoverflow and the net generally on this theme. What is special in this case is the partial month name in the target cell, and use of the IF statement. The questioner is right to use search since it is not case-sensitive
Two formula are offered:
Formula 1
=(IF(ISNUMBER(SEARCH("sep",B2)),"9")),(IF(ISNUMBER(SEARCH("aug",B2)),"8")),(IF(ISNUMBER(SEARCH("jul",B2)),"7")),(IF(ISNUMBER(SEARCH("jun",B2)),"6")),(IF(ISNUMBER(SEARCH("may",B2)),"5")),(IF(ISNUMBER(SEARCH("apr",B2)),"4")),(IF(ISNUMBER(SEARCH("mar",B2)),"3")),(IF(ISNUMBER(SEARCH("feb",B2)),"2")),(IF(ISNUMBER(SEARCH("jan",B2)),"1"))
The questioner said "I get #Value!"
This is not a surprise because it is essentially a series of nine, self-contained, unrelated if statements, each separated by a comma. It is an invalid statement.
However, if the if statements were nested, then the formula would work. Something along these lines:
=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3")))
Formula 2
=IF(ISNUMBER(SEARCH("dec",B2)),"12",IF(ISNUMBER(SEARCH("nov",B2)),"11")),IF(ISNUMBER(SEARCH("DSH_KnowBe4_BirthMonth_Oc",B2)),"10"))
So close and yet so far... This statement uses the nested approach mentioned above. There is a major typo for the October search (instead of searching for "oct", the formula searches for "DSH_KnowBe4_BirthMonth_Oc") though this doesn't cause the formula to fail.
Failure is caused by two things:
1) The double bracket following "11")) in the "November" search. There should be zero brackets here.
2) The formula needs an additional closing bracket.
Two other things to note:
1) in the event of a match, the value returned is a string not an integer.
2) there's no provision to return a value in the event of a failure to match.
Working IF statement formula
The following formula, consisting of nested IF statements, works as intended by the questioner.
=IF(ISNUMBER(SEARCH("jan",B2)),"1",IF(ISNUMBER(SEARCH("feb",B2)),"2",IF(ISNUMBER(SEARCH("mar",B2)),"3",IF(ISNUMBER(SEARCH("apr",B2)),"4",IF(ISNUMBER(SEARCH("may",B2)),"5",IF(ISNUMBER(SEARCH("jun",B2)),"6",IF(ISNUMBER(SEARCH("jul",B2)),"7",IF(ISNUMBER(SEARCH("aug",B2)),"8",IF(ISNUMBER(SEARCH("sep",B2)),"9",IF(ISNUMBER(SEARCH("oct",B2)),"10",IF(ISNUMBER(SEARCH("nov",B2)),"11",IF(ISNUMBER(SEARCH("dec",B2)),"12",NA()))))))))))))
Note, the formula uses the NA() function to return #N/A if there is no match.
VLOOKUP alternative
Though the above-mentioned formula works, I find it complicated and inflexible. My preference in situations like this is VLOOKUP. My equivalent formula would be:
=VLOOKUP(RIGHT(B2,LEN(B2)-SEARCH("_",B2)),Sheet2!$A$2:$B$13,2,FALSE)
Using January as an example: BirthMonth_Jan, the formula lookup works like this:
RIGHT(B2,LEN(B2)-SEARCH("_",B2))
1) search for the underline character SEARCH("_",B2),
2) deduct the result from the total length LEN(B2)-SEARCH("_",B2) to give the number of characters to the right of the underline.
3) get all the characters to the right of the underline RIGHT(B2,LEN(B2)-SEARCH("_",B2)). This is the lookup value
4) Create a reference table on another sheet (refer screenshot); lookup this table and return column 2 (the number for that month).
5) If there is no valid result, VLOOKUP automatically returns #N/A.
The reference table on a separate sheet:
Not sure what you are trying to do with the formula but if your "BirthMonth_" text is consistent, you can use :
=MONTH(DATEVALUE("1 "&SUBSTITUTE(A12,"BirthMonth_","")&" 2018"))
Having a view of your data and expected result would help if this is not what you're after.
It is seems just possible what you might want is:
=MONTH(MID(B2,SEARCH("BirthMonth_",B2)+11,3)&0)
Returns a Number.
How could I extract only the numbers from a text string in Excel or Google Sheets? For example:
A1 - a1b23eg67
A2 - 15dgrgr156
Result desired is
B1 - 12367
B2 - 15156
You can do it with capture groups in Google Sheets
=REGEXREPLACE(A1,ʺ(\d)|.ʺ,ʺ$1ʺ)
Anything which matches the contents of the brackets (a digit) will be copied to the output, anything else replaced by an empty string.
Please see #Max Makhrov's answer to this question
or
=regexreplace(A1,ʺ[^\d]ʺ,ʺʺ)
to remove anything which isn't a digit.
Because you asked for Excel also,
If you have a subscription to office 365 Excel then you can use this array formula:
=--TEXTJOIN("",TRUE,IF(ISNUMBER(--MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1)),MID(A1,ROW(INDIRECT("1:"&LEN(A1))),1),""))
Being an array formula it needs to be confirmed with Ctrl-Shift-Enter instead of Enter when exiting edit mode. If done correctly then Excel will put {} around the formula.
I would imagine there is a way to pull this off with =RegexExtract but I can't figure out how to get it to repeat the search after the first hit. Often with these regex function implementations there is a third parameter to repeat, but it doesn't look like google implemented it.
At any rate, the following formula will do the trick. It's just a little roundabout:
=concatenate(SPLIT( LOWER(A1) , "abcdefghijklmnopqrstuvwxyz" ))
This is converting the string to lower case, then splitting the string using any letter of the alphabet. This will return an array of the numbers left over, which we concatenate back together.
Update, switched over to =REGEXREPLACE() instead of extract...:
=regexreplace(A1, "[a-z]", "")
That's a much cleaner and obvious way of doing it than that concat(split()) nonsense.
Column A has a sorted-descending list of some bum's Top-250 movies, in the following format: Apocalypse Now (1979)
Column B has a sorted list of My Top-100, in the same format.
Both lists have been copied and pasted into a Notepad text doc to confirm they are similar simple ASCI text – no extra spaces at the end – etc. - and then pasted back into LibreofficeCalc.
I need a function for Column C that shows any of MY movies (B) that he has NOT listed in (A).
Psudo code:
C1 = The cell value in B1 – is it anywhere in A1:A8000? If not – put B1 value into C1, otherwise leave blank.
C2 = The cell value in B2 – is it anywhere in A1:A8000? If not – put B2 value into C2, otherwise leave blank.
Etc.
I have searched and found these functions – none of which work, for whatever reason. I've modified them to 8000 as the upper range which I don't think I'll ever approach.
=IF(ISERROR(MATCH(B1,$A$1:$A$8000,0))=1,B1,"")
=IFERROR(MATCH(B1;$A$1:$A$8000;0);"")
=IFNA(VLOOKUP($B1;$A$1:$A$8000;1;0);"")
=IF(ISNA(VLOOKUP($B1;$A$1:$A$8000;1;0));"";VLOOKUP($B1;$A$1:$A$8000;1;0))
=IF(ISNA(VLOOKUP($B1,$A$1:$A$8000,1,0)),"",VLOOKUP($B1,$A$1:$A$8000,1,0))
=VLOOKUP(B1,$A$1:$A$8000,1,)
=MATCH($B1;$A$1:$A$999;0)
I'd prefer it to be a single cell function, and not VBA.
I actually solved this back in like 2001 using Excel. The trick then was I had to edit the cell and use Ctrl-Shift-Enter to create a “dynamic array”, so the function was bracketed in {} curly brackets. But now I'm using the latest LibreOffice Calc and can't get the ##$# syntax correct.
Thank you!!
Edit NOTE: testing with "A" and "00001" numbers produces very different results. Values have to look like this in both columns:
Alice (1988)
Barfly (1987)
Clueless (1995)
etc.
OK I've tested these in Open Office with the following results:-
=IF(ISERROR(MATCH(B1,$A$1:$A$8000,0))=1,B1,"")
Gives Error 508 because the commas need changing to semicolons.
**=IF(ISERROR(MATCH(B1;$A$1:$A$8000;0))=1;B1;"")**
is fine.
=IFERROR(MATCH(B1;$A$1:$A$8000;0);"")
Gives #Name? because IFERROR isn't recognised.
=IFNA(VLOOKUP($B1;$A$1:$A$8000;1;0);"")
Gives #Name? because IFNA isn't recognised.
=IF(ISNA(VLOOKUP($B1;$A$1:$A$8000;1;0));"";VLOOKUP($B1;$A$1:$A$8000;1;0))
Works but gives the opposite result.
**=IF(ISNA(VLOOKUP($B1;$A$1:$A$8000;1;0));B1;"")**
would be fine.
=IF(ISNA(VLOOKUP($B1,$A$1:$A$8000,1,0)),"",VLOOKUP($B1,$A$1:$A$8000,1,0))
Commas
=VLOOKUP(B1,$A$1:$A$8000,1,)
Commas
=MATCH($B1;$A$1:$A$999;0)
Works but just gives the position of the match.
Probably the easiest way of doing it is:-
**=IF(COUNTIF(A$1:A$8000;B1);"";B1)**
Unfortunately it does seem that strings with brackets in are giving spurious matches in Libre/Open Office. You could get round it by a substitution I guess
=IF(COUNTIF(SUBSTITUTE(SUBSTITUTE(A$1:A$10;"(";"<");")";">");SUBSTITUTE(SUBSTITUTE(B1;"(";"<");")";">"));"";B1)
entered as an array formula and copied (rather than pulled) down or of course global edit all the brackets :-(.
Now that I know the root cause of this thanks to #Lyrl, there is a further option of turning off the regular expressions as suggested or you could escape the brackets:-
=IF(COUNTIF(A$2:A$11;SUBSTITUTE(SUBSTITUTE(B2;"(";"\(");")";"\)"));"";B2)
See documentation on Regex in Open Office here
This should do it,
=IF(ISNUMBER(MATCH(B1,$A$1:$A$8000,0)),"",B1)
Tested formula
=IF(ISNA(MATCH(B1,$A$1:$A$8000,0))=TRUE(),B1,"")