Sum each element of a row from two files - linux

Question

I want to write shell script in which each row's column element from file1 and file2 are added.
file1:
A 10 12 13 14
B 2 5 6 10
C 1
file2:
A 11 13 11 15
B 3 1 1 1
C 2
output:
A 22 25 24 29
B 5 6 7 11
C 3
I have tried to write this, but it seems very chaotic.
So I'd like to get some help to make it better!
awk '{getline v < "file1"; split( v, a );
for (i = 2; i <= NF; i++)
{print a[1], a[i]+ $i}
}' file2 > temp
awk '{a[$1]=a[$1]" "$2}
END{for(i in a)print i,a[i]
}' temp > out

Answer 1

file1
A 10 12 13 14
B 2 5 6 10
C 1
file2
A 11 13 11 15
B 3 1 1 1
C 2
Programme
cat file1 file2 | cut -d" " -f1 | sort -u | while read i
do
line1="`grep ^$i file1 | sed -e "s/ */ /g" | cut -d" " -f2-` "
line2="`grep ^$i file2 | sed -e "s/ */ /g" | cut -d" " -f2-` "
(
echo $i
while [ "${line1}${line2}" != "" ]
do
v1=0`echo "$line1" | cut -d" " -f1`
v2=0`echo "$line2" | cut -d" " -f1`
line1="`echo "$line1" | cut -d" " -f2-`"
line2="`echo "$line2" | cut -d" " -f2-`"
echo `expr $v1 + $v2`
done
) | xargs
done > file3
file3
A 21 25 24 29
B 5 6 7 11
C 3
This solution remains valid if the number of column or lines are not identical, the missing values are considered 0
#file1
A 10 12 13 14
B 2 5 6
C 1 10
D 1 1
#file2
A 11 13 11 15
B 3 1 1 1 5
C 2
F 3 3
#file3
A 21 25 24 29
B 5 6 7 1 5
C 3 10
D 1 1
F 3 3