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I have this code but it is not compiling correctly. I want to create a user with a default shell of bin/sh with the group adults. Any suggestions?
Command: useradd -s /bin/sh –g adults michael
Thank you.
First of all the code given is not being compiled, but rather executed by a shell. Then your command is perfectly fine, given that the adults group already exists before you type the command into your shell.
So without error, or more context, nobody will be able to tell you more than what I'm telling you:
there's no issue with your command.
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I have registered some linux machines intro AD with sssd and it works great, but I have an issue with the bash prompt. Some AD usernames start with $ and the prompt refuses to display it, so now I'm left with the string similar to #servername:~$
If I do an export PS1="\$USER#\H" it gets displayed correctly.
Any ideas on how to make bash prompt either escape the special character, or make sssd edit the bashrc with the "correct" format?
This is more of a Linux configuration question and would work better in unix.stackexchange.com or askubuntu, but generally to change default user configuration you'd want to edit the files in /etc/skel.
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I have just started learning the Linux system and I need some help to translate the following to English:
grep WARNING readme.txt
and
grep WARNING readme.txt > warnings.txt
This is a homework question that i have researched myself but having trouble learning exactly what it means.
thanks in advance.
Try making a file on your computer named readme.txt. Put some lines of text in there, and make sure that some lines say "WARNING" while other lines do not.
Then run your first command and observe its output.
Then run your second command and observe its output and observe what was written to warnings.txt.
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What command line would give me a list of programs each logged in user is executing for a Linux server using bash?
You can use the w command for this.
As #ivanivan mentioned, a more complete listing can be accomplished using ps, usually coupled with grep to filter out what you don't want.
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I am looking for a command in bash to change the last modified and created timestamp to be changed to present time.
How do I do it using shell command/script?
Thanks!
touch will update the access and modification times (or only one of the two with -a or -m respectively).
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I have used a command called 'cat /etc/group' what does this command mean and do.Can you tell me what each part of the command does please use simple terms.
You can find the answer to your question explained better than any of us ever could with this command:
man cat
It prints to standard output the contents of the file at the location /etc/group
Ok so cat outputs the file, which (in your case) contains basic info about groups.
If you are interested in what are the groups just click here