I have an excel sheet with text in a cell - I'd like to extract the specific text and an additional 5 characters alongside it.
For example:
Cell A1 contains the text - 'Here is the cell for widget 1A1A and its content'. I'd like to find any cell that contains the word 'widget' and extract that and the following 5 characters (including space). So the result would be 'Widget 1A1A'.
This is quite straightforward. Use the SEARCH command to find the word "widget" (FIND is the same but case-sensitive):
=SEARCH("widget",A1)
This gives you the character number in the cell where the match is found [if no match is found it returns "#N/A".
Then match this with the MID function to pull in the text "Widget" + the following 5 characters, as follows:
=MID(A1,SEARCH("widget",A1), LEN("widget") + 5)
Related
How to extract text string after specific word or selected word in excel
ishue type: some text.
Solution: NA#
Remarks: NA
I want to extract text after solution:
If you dont want to include the word solution in your output you can use the following formula, if your text value is in cell A1
=MID(A1,(FIND("Solution:",A1)+10),LEN(A1))
The +10 will remove the value Solution: from the export.
If you want to include the word solution you can use
=MID(A1,(FIND("Solution:",A1)),LEN(A1))
The find element will find the word you are looking for, while the mid element will look for the element within the string. Finally the len function will extract everything after the selected word, to the length of the original string
I have a cell that I want to use and IF statement to tell return information based on characters in the cell. I.E the cell has =M=WRFY, I want the statement to give me a start time based on the day within. I used this formula for the first set and it worked but for the next day it fails.
=IF(LEFT(I44,1)="S",H44,"")
I've tried entering the 2 where the 1 is to make it look at character 2 but its not working. Help!!
With Mid or Left or Rightyou need to specify a position in the string, which isn't a big deal in this case since it's not changing. Either way I prefer to use FIND, which returns either a number (the position that the string1 was found in string2, or else an Error if it's not found.
The location is irrelevant in this case so this just checks if there's an error. If so, it wasn't found (and we get a "" blank string); if not, it was found (and returns the value of cell H44).
=IF(ISERROR(FIND("S",$E6)),"",H44)
You said something about it only working for a few cells. If you're copying the formula to other cells but want to keep on referring to column "E" then putting a $ in front of E keeps that letter "locked in" whereever you copy it.
(Reference)
Splitting up a cell
A combination of the Find, Left, Right, and Len functions will handle many common tasks like splitting a single text value 2:30 PM-3:30 PM into two cells.
We already know that Find will locate one string inside another, like FIND("-",A2) would return 8 in this example. And, we know that Left returns characters from the left side of a string.
We don't want the first 8 because that would include the "-" that was "found". So, we'll subtract one. Assuming your text to split is in cell A2, this place this formula where you want the left part of the string:
=LEFT(A2,FIND("-",A2)-1)
and we know Right returns the right-side number of characters we specify. Len will tell us the total length of the string. Therefore, total length minus the left part that we don't want in this part...
Place this formula where you want to right part of the string:
=RIGHT(A2,LEN(A2)-FIND("-",A2))
Basic text functions worth learning
A little bit of homework for you. Once you start practicing with functions they will make a lot more sense, and "nesting" (combining) them will become second nature! :-)
CHAR : Returns the character specified by the code number
CLEAN : Removes all nonprintable characters from text
CODE : Returns a numeric code for the first character in a text string
CONCATENATE : Joins several text items into one text item
FIND : Finds one text value within another (case-sensitive)
LEFT : Returns the leftmost characters from a text value
LEN : Returns the number of characters in a text string
LOWER : Converts text to lowercase
MID : Returns a specific number of characters from a text string starting at the position you specify
PROPER : Capitalizes the first letter in each word of a text value
REPLACE : Replaces characters within text
REPT : Repeats text a given number of times
RIGHT : Returns the rightmost characters from a text value
SEARCH : Finds one text value within another (not case-sensitive)
SUBSTITUTE : Substitutes new text for old text in a text string
TEXT : Formats a number and converts it to text
TRIM : Removes spaces from text
UPPER : Converts text to uppercase
VALUE : Converts a text argument to a number
(Source)
Also valuable: Excel Functions Listed By Category
Given a spreadsheet cell containing a string that consists of a hyphenated series of character segments, I need to extract the last segment.
For example, consider column A containing data strings like XX-XXX-X-XX-XX-G10, where X denotes any character. What formula would I need to place in column B to get G10 as a result?
A B
1 XX-XXX-X-XX-XX-G10 G10
I'm looking for a formula that could work in in Libre Office Calc, Open Office Calc, MS Excel, or Google Sheets.
Another possibility in LO Calc is to use the general purpose regular expression macro shown here: https://superuser.com/a/1072196/541756. Then the cell formula would be similar to JPV's answer:
=REFIND(A1,"([^-]+$)")
If you are using google sheets, regexextract would be possible too:
=REGEXEXTRACT(A1, "[^-]+$")
In LibreOffice Calc and OpenOffice Calc, you can use a regular expression to determine the position of the text after the last - character:
=SEARCH("-[:alnum:]+$";A1)
will return 15 if A1 contains XX-XXX-X-XX-XX-G10.
Now, you can use this value to get the text "behind" that position, using the RIGHT() function:
=RIGHT(A1;LEN(A1)-SEARCH("-[:alnum:]+$";A1))
Split up on multiple lines:
=RIGHT( ' return text beginning from the right...
A1; ' of cell A1 ...
LEN(A1) ' start at lenght(A1) = 18
- ' minus ...
SEARCH( ' position ...
"-[:alnum:]+$" ' of last "-" ...
;A1 ' in cell A1 = 15 ==> last three characters
)
)
It appears that you want the characters that appear at the end of a string, to the right of the last instance of a hyphen character, "-".
This formula, adapted from here, works in Excel, *Calc & Google Sheets:
=TRIM(RIGHT(SUBSTITUTE(A1,"-",REPT(" ",LEN(A1))),LEN(A1)))
Explanation:
SUBSTITUTE(A1,"-",new_string) will find each hyphen ("-") in the original string from cell A1 and replace it with a new_string.
REPT(" ",LEN(A1)) is a string of repeated space characters (" "), the same length as the original string in cell A1.
TRIM(RIGHT(string,count)) will get the right-most count characters, and trim off leading and trailing spaces. Since the string was previously padded out by replacing hyphens with spaces, and count is the same LEN(A1) used for that padding, the last count characters consists of a bunch of spaces followed by whatever followed the last hyphen!
In Google Sheets, an alternative approach is to use the SPLIT function to break the value from column A into an array, then select the last element. (Excel-VBA has a split() function, so you could make this work in Excel by writing VBA code to provide it as a custom function.)
=INDEX(SPLIT(A1,"-"),0,COUNTA(SPLIT(A1,"-")))
I found simply solution:
=RIGHT(A1;3)
that gives me G10 as the result too! It works because COL A always have 3 chars at the end!
I have spreadsheet, that contains a string of numbers (text) I need to extract the text within the parentheses and count how many meet the critera
I tried the follow code:
=COUNTIF(NASC!C:C,"MID(NASC!C:C,SEARCH(zv489408,NASC!C:C,22))")
But it is not returning a value.
here is the string that it must search from:
1234595250110784533 (zv489408)
and its on separate sheet that labelled NASC
Disclaimer: I work in Ubuntu and these have been tested in LibreOffice, not Excel. There may be some discrepancies between the programs.
Your core function should be SEARCH("(zv489408)", NASC!C:C). (The 22 in your example starts searching from the 22nd character in the cell; this will not find the string if it occurs earlier in the cell.) That will return the starting character of the string in that cell, or an error (probably #VALUE!).
You could set up another column, with the formula =NOT(ISERROR(SEARCH("(zv489408)", NASC!$C1))) in each cell (the 1 will change to the row relevant to each cell, of course), and then SUM that column up in another cell.
I have managed to find an array formula that works, but I'm warning you now, it's nasty:
=COUNTIF(MID(NASC!C:C, SEARCH("(", NASC!C:C) + 1, SEARCH(")", NASC!C:C, SEARCH("(", NASC!C:C)) - SEARCH("(", NASC!C:C) - 1), "zv489408")
(Hit Ctrl+Shift+Enter to save a formula as an array formula.)
It's nasty because it goes through all of these steps, and can't save the intermediate results:
Find the opening bracket.
Find the closing bracket after the opening bracket.
Subtract the position of the opening bracket from the position of the closing bracket to get the length (plus one more, to exclude the closing bracket).
Get the text between them.
How can I add space to text in Excel(2010) for full fill text length.
example
In Excel sheet have 3 column A is length, B is actual text and D is expected text.
(B)text is ABVC but require text length is (A)6
then (D)text should be " ABVC"(SpaceSpaceABVC) add space in font of old text to full fill length.
Assuming A1=6 and B1=ABVC you can insert the following formula in D1:
=IF(LEN(B1)<A1,REPT(" ",A1-LEN(B1)),"")&B1
Note: I have added a check to make sure B1 is not more than 6 characters, if it is, I use it as is. You could truncate it with the LEFT function.
If you want to add make cell of 10 characters, then you can use this formula in excel
=RIGHT(" "&E2,10)
In this formula I had added 10 spaces in between
""
marks and concatenate with the cell and after comma (,) i had specified the intended number of characters I want in that cell after execution of this formula. (space not shown in formula)